Turner Syndrome occurs when an individual inherits one X chr.pdf

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Turner Syndrome occurs when an individual inherits one X chromosome but lacks a second sex chromosome. If a phenotypically normal couple has a child with Turner syndrome that is also color-blind (a recessive X-linked allele), did nondisjunction occur during oogenesis or spermatogenesis in this child's parent? oogenesis Meiosis I oogenesis Meiosis II spermatogenesis Meiosis I spermatogenesis Meiosis IIA phenotypically abnormal individual has a phenotypically normal father with one abnormal copy of chromosome 7 and a normal mother without any changes in chromosome structure. The order of genes along chromosome 7 in the father is as follows: RTD M centromere PU XZC (normal 7) RTD UP centromere M XZC (abnormal 7) Use this information for the next 2 questions. The fathers abnormal chromosome is the result of what type of event? Pericentric inversion Paracentric inversion balanced translocation unbalanced translocationA phenotypically abnormal individual has a phenotypically normal father with one abnormal copy of chromosome 7 and a normal mother without any changes in chromosome structure. The order of genes along chromosome 7 in the father is as follows: RTD M centromere PU XZC (normal 7) RTD UP centromere M XZC (abnormal 7) The phenotypically abnormal offspring has a chromosome 7 with the following order of genes: RTD M centromere PU DTR How was this chromosome formed? During the the mother's gamete production, an inversion of RTD. During the father's gamete production, a crossover between sections D and T. During the mother's gamete production, a crossover between sections D and M. During the father's gamete production, a crossover between centromere and section P. During the mother's gamete production, a crossover between centromere and section P. During the the father's gamete production, an inversion of RTD..

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A wild-type chromosome has the following segments: A B C middot D E F G H I An individual is heterozygous for the following chromosome mutation: A B C middot D H I How would the mutated and wild-type chromosomes pair in prophase I of meiosis? D E F G H of the wild-type chromosome will form a deletion loop. E F G of the wild-type chromosome will form a deletion loop. D E F G H of the wild-type chromosome will form an Inversion loop. E F G of the wild- type chromosome will form an inversion loop. Red-green color blindness is a human x-linked recessive disorder. A young man with a 47, XXY karyotype (Klinefelter syndrome) is color Wind. His 46, XY brother also is color blind. Both parents have normal color vision. Where did the no disjunction that gave rise to the young man with Klinefelter syndrome take place? Assume that no crossing over took place In prophase I of meiosis. Mother - meiosis I Mother - meiosis II Father - meiosis I Father - meiosis II Both parents Functional epidermal lies bull nose (JEB) Is a severe skin disorder that results in blisters over the entire body. The disorder is caused by autosomal recessive mutations at any one of three loci that help to encode lamina 5, a major component In the dermal-epidermal basement membrane. Leena Pulicine and colleagues described a male newborn who was born with JEB and died at 2 months of age (L. Pulkkinen et al. 1997. American Journal of Human Genetics 61:611-619); the child had healthy unrelated parents. Chromosome analysis revealed that the infant had 46 normal-appearing chromosomes. Analysis of DNA showed that his mother was heterozygous for a JEB-causing allele at the LAMB3 locus, which is on chromosome 1. The father had two normal alleles at this locus. DNA fingerprinting demonstrated that the male assumed to be the father had, In fact, conceived the child. Assuming that no new mutations occurred in this family, what might best explain the presence of an autosomal recessive disease in the child when the mother is heterozygous and the father Is homozygous normal? The infant inherited both copies of chromosome 1 from the mother, which is an example of unit parental disomic. The infant is monatomic for chromosome 1, which he received from his mother but did not receive a chromosome 1 from his father. Epitasis masked the disease phenotype in the father, but complementation of the parental alleles gave rise to a child with functional epidermal lies bull nose. The infant has tiresome 1, where he inherited two recessive alleles from his mother. A translocation between chromosome 1 and chromosome 22 generated a recessive phenotype. Plasmid DNA, like bacterial DNA: is circular. is single stranded. comes in homologous pairs. All of the above. None of the above. Solution 10. Answer is B. EFG of the wild type will form a deletion loop. Because EFG in one chromosome has no matching pair in other chromosome. So EFG loop will be formed and it will be removed. 13. Answer is A. Plasmid DNA like bacte.

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