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TRANSPORTATION
PROBLEM
HEMANT GUPTA
MBA/45007/19
VANISHRI KORNU
MBA/45016/19
TRANSPORTATION PROBLEM
This is a type of linear programming problem that may be solved using a
simplified version of the simplex technique called transportation method.
Because of its major application in solving problems involving several product
sources and several destinations of products, this type of problem is
frequently called the transportation problem.
MODELLINGTHETRANSPORTATION PROBLEM
The transportation problem is concerned with finding the minimum cost of
transporting a single commodity from a given number of sources (e.g.
factories) to a given number of destinations (e.g. warehouses) here we use a
specific transportation algorithm.
The data of the model include
1.The level of supply at each source and the amount of demand at each
destination.
2.The unit transportation cost of the commodity from each source to each
destination.
Since there is only one commodity, a destination can receive its demand from more
than one source.The objective is to determine how much should be shipped from
each source to each destination so as to minimize the total transportation cost.
BALANCEDV/S UNBALANCED
When the total supply is equal to the total demand
m ∑i=1 ai = n ∑j=1 bj
then the transportation model is said to be balanced.
A transportation model in which the total supply and total demand are unequal
m ∑i=1 ai = n ∑j=1 bj
then the transportation model is called unbalanced.
It is always possible to balance an unbalanced transportation problem.
If the total supply exceeds the total demand, then an additional dummy column is
added and if total demand exceeds the total supply, then an additional dummy row
is added.
SOLUTION ALGORITHM OFTRANSPORTATION
PROBLEM
TWO METHODS OF INITIAL FEASIBLE SOLUTION
NORTHWEST CORNER
METHOD
VOGEL’S
APPROXIMATION
METHOD
FOR OPTIMAL SOLUTION
MODIFIED
DISTRIBUTION (MODI)
METHOD
STEPS IN MODIFIED DISTRIBUTION
(MODI) METHOD
Step 1: Under this method we construct penalties for rows and columns by
subtracting the least value of row / column from the next least value.
Step 2: We select the highest penalty constructed for both row and column. Enter
that row / column and select the minimum cost and allocate min (ai, bj)
Step 3: Delete the row or column or both if the rim availability / requirements is met.
Step 4:We repeat steps 1 to 2 to till all allocations are over.
Step 5: For allocation all form equation ui + vj = cj set one of the dual variable ui / vj
to zero and solve for others.
Step 6: Use this value to find Pij = ui+vj-cij of all pij , if all are negative then it is the
optimal solution.
EXAMPLE
COMPANIES DESTINATIONS
JPTrading Company(Ahmedabad, Gujrat) Tender Depot(Gurgram)
Rathore & Co.(Delhi) Mulund Depot(Mumbai)
Shrivinayak industries suppliers Palampur Depot(Indore)
and manufacturing Ltd.(Udaipur) Malanpur Depot(MP)
The stock held at each supplier and the demand from each depot is known.The
cost of transportation of one lorry load of grit from each supplier to each depot is
also known.The information is given in table.
Tender
Depot
Mulund
Depot
Palampur
Depot
Malan
Depot
SUPPLY
JPTrading
Co.
180 110 130 290 14
Rathore &
Co.
150 250 150 280 16
Shrivinayak
Ltd.
240 270 190 120 20
DEMAND 11 15 14 10 50
NORTH-WEST CORNER METHOD
Tender
Depot
Mulund
Depot
Palampur
Depot
Malan
Depot
SUPPLY
JPTrading
Co.
180 110 130 290 14
Rathore &
Co.
150 250 150 280 16
Shrivinayak
Ltd.
240 270 190 120 20
DEMAND 11 15 14 10 50
11 3
12 4
10 10
3
12
4
10
CALCULATION
Transportation cost is computed by evaluating the objective function
So,
Minimum Cost= C11X11 + C12X12 + C22X22 + C23X23 + C33X33 + C34X34
= 11 × 180 + 3 × 110 + 12 × 250 + 4 × 150 + 10 × 190 + 10 × 120
= Rs. 9010
VOGEL’S APPROXIMATION METHOD
Tender
Depot
Mulund
Depot
Palampur
Depot
Malan
Depot
SUPPLY ROW PENALTY
JPTrading
Co.
180 110 130 290 14 20 20 - -
Rathore &
Co.
150 250 150 280 16 0 0 0 100
Shrivinaya
k Ltd.
240 270 190 120 20 70 50 50 80
DEMAND 11 15 14 10 50
COLUMN
PENALTY
30 140 20 160
30 140 20 -
90 20 40 -
- 20 40 -
11
14
1091
5
CALCULATION
Transportation cost is computed by evaluating the objective function
Minimum Cost= C12X12 + C21X21 + C23X23 + C32X32 + C33X33 + C34X34
= 14 × 110 + 11 × 150 + 5 × 150 + 1 × 270 + 9 × 190 + 10 × 120
= Rs. 7120
So,
Vogel’s Method < North west corner method
MODI METHOD
Tender
Depot
Mulund
Depot
Palampur
Depot
Malan
Depot
SUPPLY
JP
Trading
Co.
180 110 130 220 14 U1=0
Rathore
& Co.
150 250 150 280 16 U2= 120
Shrivinay
ak Ltd.
240 270 190 120 20 U3=160
DEMAND 11 15 14 10 50
V1=30 V2=110 V3=30 V4=-40
11
10
14
5
91
CALCULATION
Cij = ui+vj
Pij = ui+vj-cij
C11 = 0+30-180 = -50
C13 = 0+30-130 = -100
C14 = 0-40-180 = -330
C22 = 120+110-250 = -20
C24 = 120-40-280 = -200
C31= 160+30-240 = -50
All the pij (which is non basic cell values) are negative.Therefore it is an optimal solution.
So, Minimum transportation cost is same as that ofVogel’s approximation method i.e. Rs.
7120
THANKYOU

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Operation Research

  • 2. TRANSPORTATION PROBLEM This is a type of linear programming problem that may be solved using a simplified version of the simplex technique called transportation method. Because of its major application in solving problems involving several product sources and several destinations of products, this type of problem is frequently called the transportation problem.
  • 3. MODELLINGTHETRANSPORTATION PROBLEM The transportation problem is concerned with finding the minimum cost of transporting a single commodity from a given number of sources (e.g. factories) to a given number of destinations (e.g. warehouses) here we use a specific transportation algorithm. The data of the model include 1.The level of supply at each source and the amount of demand at each destination. 2.The unit transportation cost of the commodity from each source to each destination.
  • 4. Since there is only one commodity, a destination can receive its demand from more than one source.The objective is to determine how much should be shipped from each source to each destination so as to minimize the total transportation cost.
  • 5. BALANCEDV/S UNBALANCED When the total supply is equal to the total demand m ∑i=1 ai = n ∑j=1 bj then the transportation model is said to be balanced. A transportation model in which the total supply and total demand are unequal m ∑i=1 ai = n ∑j=1 bj then the transportation model is called unbalanced. It is always possible to balance an unbalanced transportation problem. If the total supply exceeds the total demand, then an additional dummy column is added and if total demand exceeds the total supply, then an additional dummy row is added.
  • 7. TWO METHODS OF INITIAL FEASIBLE SOLUTION NORTHWEST CORNER METHOD VOGEL’S APPROXIMATION METHOD FOR OPTIMAL SOLUTION MODIFIED DISTRIBUTION (MODI) METHOD
  • 8. STEPS IN MODIFIED DISTRIBUTION (MODI) METHOD Step 1: Under this method we construct penalties for rows and columns by subtracting the least value of row / column from the next least value. Step 2: We select the highest penalty constructed for both row and column. Enter that row / column and select the minimum cost and allocate min (ai, bj) Step 3: Delete the row or column or both if the rim availability / requirements is met. Step 4:We repeat steps 1 to 2 to till all allocations are over. Step 5: For allocation all form equation ui + vj = cj set one of the dual variable ui / vj to zero and solve for others. Step 6: Use this value to find Pij = ui+vj-cij of all pij , if all are negative then it is the optimal solution.
  • 9. EXAMPLE COMPANIES DESTINATIONS JPTrading Company(Ahmedabad, Gujrat) Tender Depot(Gurgram) Rathore & Co.(Delhi) Mulund Depot(Mumbai) Shrivinayak industries suppliers Palampur Depot(Indore) and manufacturing Ltd.(Udaipur) Malanpur Depot(MP) The stock held at each supplier and the demand from each depot is known.The cost of transportation of one lorry load of grit from each supplier to each depot is also known.The information is given in table.
  • 10. Tender Depot Mulund Depot Palampur Depot Malan Depot SUPPLY JPTrading Co. 180 110 130 290 14 Rathore & Co. 150 250 150 280 16 Shrivinayak Ltd. 240 270 190 120 20 DEMAND 11 15 14 10 50
  • 11. NORTH-WEST CORNER METHOD Tender Depot Mulund Depot Palampur Depot Malan Depot SUPPLY JPTrading Co. 180 110 130 290 14 Rathore & Co. 150 250 150 280 16 Shrivinayak Ltd. 240 270 190 120 20 DEMAND 11 15 14 10 50 11 3 12 4 10 10 3 12 4 10
  • 12. CALCULATION Transportation cost is computed by evaluating the objective function So, Minimum Cost= C11X11 + C12X12 + C22X22 + C23X23 + C33X33 + C34X34 = 11 × 180 + 3 × 110 + 12 × 250 + 4 × 150 + 10 × 190 + 10 × 120 = Rs. 9010
  • 13. VOGEL’S APPROXIMATION METHOD Tender Depot Mulund Depot Palampur Depot Malan Depot SUPPLY ROW PENALTY JPTrading Co. 180 110 130 290 14 20 20 - - Rathore & Co. 150 250 150 280 16 0 0 0 100 Shrivinaya k Ltd. 240 270 190 120 20 70 50 50 80 DEMAND 11 15 14 10 50 COLUMN PENALTY 30 140 20 160 30 140 20 - 90 20 40 - - 20 40 - 11 14 1091 5
  • 14. CALCULATION Transportation cost is computed by evaluating the objective function Minimum Cost= C12X12 + C21X21 + C23X23 + C32X32 + C33X33 + C34X34 = 14 × 110 + 11 × 150 + 5 × 150 + 1 × 270 + 9 × 190 + 10 × 120 = Rs. 7120 So, Vogel’s Method < North west corner method
  • 15. MODI METHOD Tender Depot Mulund Depot Palampur Depot Malan Depot SUPPLY JP Trading Co. 180 110 130 220 14 U1=0 Rathore & Co. 150 250 150 280 16 U2= 120 Shrivinay ak Ltd. 240 270 190 120 20 U3=160 DEMAND 11 15 14 10 50 V1=30 V2=110 V3=30 V4=-40 11 10 14 5 91
  • 16. CALCULATION Cij = ui+vj Pij = ui+vj-cij C11 = 0+30-180 = -50 C13 = 0+30-130 = -100 C14 = 0-40-180 = -330 C22 = 120+110-250 = -20 C24 = 120-40-280 = -200 C31= 160+30-240 = -50 All the pij (which is non basic cell values) are negative.Therefore it is an optimal solution. So, Minimum transportation cost is same as that ofVogel’s approximation method i.e. Rs. 7120