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Dr. S.H. Burungale
Department of Chemistry
Yashwantrao Chavan College of Science
,Karad
Analysis of Pesticides
Introduction, classification of pesticides, sampling,
sample pretreatment and processin
analysis of DDT, gammexane, endosulphan, zinab,
ziram, malathion, thiram, thiometon, simazine and
chloridane.
SAMPLE COLLECTION
 Area selection and random collection
Packaging and Transmission of laboratory
samples a) packing b) sealing
Compositing
 grinding and mixing
Homogenization
Sample storage
Pesticide: Pesticide is a substance which kills a
pest.
Any substance or mixture of substances intended
for preventing, destroying, repelling, or
mitigating any pest.
(insect, rodent, nematode, fungus, weed, other
forms of terrestrial or aquatic plant or animal life
or viruses, bacteria, or other microorganisms.
Gammaxeneor Lindane
DDT
Endosulphon C9H6Cl6O3S Chloridane
C10H6Cl8 - 409.76
406.90 g·mol−1
C14H9Cl5
: 354.49 g/mol
290.814 g/mo
Ziram
Thiram
Thiomenton
insecticide
Simazine is herbicide
Zineb
Classification of pesticides
OrganicInorganic
Natural Synthetic
Organophosphates
Organochlorines
Carbamates
Synthetic Pyrethroids
Classification of pesticides
Synthesis : chemically synthesized
Microbial : Microbial agents stem from bacteria, fungi, algae,
naturally occurring viruses or protozoan
Botanical : Botanical pesticides come from plants eg neem,
pyrithrins
Mineral: Mineral based controls include sulfur and lime-sulfur.
Synthetic pesticides
Inorganic : Inorganic insecticides are of
mineral origin, mainly compounds of
antimony arsenic ,barium, boron, copper,
fluorine, mercury, selenium, sulfur,
thallium, and zinc, and elemental
phosphorus and sulfur. Antimonyl
potassium tartrate, tartar emetic, their
Oxides
Organic Pesticides
Organochlorines :DDT, methoxychlor, dieldrin, chlordane,
toxaphene, mirex, kepone, lindane, and benzene hexachloride.
DDT : C14H9Cl5
Organophosphate : parathion. Malathion.methyl
parathion.chlorpyrifos.diazinon.
Dichlorvos.phosmet.fenitrothion.
Phenoxy Herbicides
Carbamates :
Phenoxy Herbicides : 2 4 - D
2,4-dichlorophenoxyacetic acidUreas:
I.Analysis of Chlorinated Pesticides
Principle:
DDT is hydrolysed with Sodium hydroxide in a medium
of 1:1 mixture of methanol and
acetone under reflux when 3 equivalence of ionic
chloride are liberated per mole of DDT The ionic
chloride is estimated by Volhard’s method. A.I content is
calculated by multiplying per cent chloride (corrected
free chloride), with a suitable convernsion factor.
NaCl + AgNO3 ---AgCl + NaNO3
1 g DDT is taken in 250 ml
volumetric flask and 125ml
acetone is added.
Shaken well to dissolve the
DDT and make up to the
mark with Methanol.
To the 50ml aliquot, 50ml of
0.3N solution of aqueous
Sodium hydroxide is added
and refluxed for 1 hr
Analysis of DDT
After cooling add 5ml Hydrogen peroxide (30%)
and boil gently for 10 min
If it’s still coloured, repeat the above exercise.
Destroy the excess alkalinity by using 1:1 Nitric
acid and phenolphthalein
Add 10ml of Nitric acid in excess, 25ml standard
solution of Silver nitrate and 5ml Nitro-benzene
and 1 ml Ferric alum indicator and titrated against
standard Potassium thiocyanate solution to a faint
brick red colour (y ml).
Carry out a blank titration with 50ml aliquot of
stock solution without hydrolysis (x ml)
Calculate % value by deducting y ml from x ml.
and use dilution factor.
Calculations:
1000ml of 1 N normal Silver nitrate =354.49 g of
DDT
‘Z ’ ml of normal solution = 354.49 x Z x N
1000
% DDT = 354.49 x Z x N x 100 = 35.449 x Zx N
1000 x W W
II.ANALYSIS OF DITHIOCARBAMATES
Name Molecular formula Molecular
weight
Structure
A. Alkyl dithiocarbamates S
i. Thiram
( CH3 )2-N-C-S
C6H12N2S4 240.4 2
S
ii. Ziram ( CH3 )2-N-C-S Zn
iii. Ferbam
C6H12N2S4Zn 305.8
2
S
C9H18FeN3S6 418.9
( CH3 )2-N-C-S Fe2
B. Alkylene
dithiocarbamates
SII
CH2-NH-C-SI Zn
CH2-NH-C-SIISSII
CH2-NH-C-SI Mn(ZnCl2)y
CH2-NH-C-S
II xS
S CH3
S NH NH
S
S Zni. Zineb
C4H6N2S4Zn 275.74
ii. Mancozeb
C4H6N2S4Mn Zn
iii. Propineb
C5H8N2S4Zn 290
Principle:
One mole of dithiocarbamate on decomposition with hot
boiling dilute acid liberates two moles of carbondisulphide.
Absorption Hydrogen sulphide in Cadmium sulphate/Lead
acetate solution.
quantitatively in methanolic KOH to Potassium xanthate
. This Potassium xanthate is quantitatively estimated in acetic
acid medium by titration against standard Iodine solution using
starch solution as indicator.
In the case of alkyl
bisdithiocarbamates,
Ziram, Thiram,
Ferbam. A.I content
can also be estimated
on the basis of
dimethylamine content
Take 100 to 150 ml of 1 N
Sulphuric acid in reaction kettle.
Take 25ml Lead acetate in first
absorber and keep it hot
(approximately 70 deg.C). Take
25ml 2 N methanolic KOH in the
second absorber keep it chilled
below 10 deg.C.
Heat the acid in the kettle and
keep it boiling. Transfer sufficient
quantity of sample accurately by
weighing 0.2 to 0.3 gms of a.i into
the reaction flask
Analysis of
Thiocarbamates
Digest for one hour and forty- five minutes. After
the digestion is complete, quickly disconnect the
KOH trap
Transfer quantitatively with distilled water the
contents of the trap in to a 50ml iodine flask.
Neutralise it with 30% acetic acid using
phenolphthalein indicator, add 1ml excess acid
and titrate immediately with 0.1N Iodine solution
using starch solution as indicator. End point is
colourless to blue.
Calculations:
Thiram, Ziram, Mancozeb, Propineb and Zineb
2 equivalents of Iodine = 2 equivalents of CS2 = 1 mole of sample
1 equivalent of Iodine = ½ mole of sample
1000ml of 1 N Iodine solution = ½ mole of sample
Calculations:
1000ml of 1 N Iodine =Mol.wt. of sample
‘x ’ ml of normal solution = M.W x X x N
1000
% Sample = M.W x X x N x 100 = M.W x Zx N
1000 x W W
III.Analysis of organophosphorus
Principle: One mole of a.i on hydrolysis in
acidic medium yields one mole each of diethyl
dithio phosphoric acid and ethyl mercaptan,
which consume two equivalents of Silver nitrate.
From the quantity of Silver nitrate consumed by
a.i alone, obtained after correcting for impurity
interferences, a.i content is calculated.
Step I Preparation of sample stock solution
Sufficient quantity of the sample equivalent
to 2.5 g is extracted with acetone and made
up to 250ml in a volumetric flask.
Step II Estimation of samples –
To a flask containing 150 ml water acidified with
5 drops of Nitric acid, add by pipette 10ml of
standard Silver nitrate solution and maintain at
500C.
After attaining constant temperature, add by a
pipette 10ml of sample stock solution, and carry
out hydrolysis at 500C. for 15 minutes.
Titrate the excess silver nitrate against standard
thiocyanate solution using 1 ml 10% Ferric
nitrate solution as indicator (x ml).
Step III Estimation of impurities
 Transfer by pipette 50ml of sample stock solution in to a
500 ml separating funnel containing 50ml benzene.
 Extract this solution thrice, each time by 10ml of 0.1N
KOH in aqueous solution of 10% Potassium nitrate followed
by one washing with 50ml distilled water.
 Collect the aqueous layer and acidify with concentrated
Nitric acid till acidic to Congo red paper.
 Add 5 drops of acid in excess and keep it in
waer bath maintained at500C till contents of the
flask attained constant temperature.
 Then add by pipette 5 ml standard Silver
nitrate and keep it in the water bath at 500C for 15
minutes.
 Then cool to room temperature and titrate the
excess Silver nitrate against std. thiocyanate
solution using 1 ml of 10% Ferric nitrate as
indicator (y ml)
1gm equivalent of Silver nitrate = ½ mole of
sample
Calculations:
Gram equivalents of Silver nitrate = 1 gm mole
of sample
IV.Analysis of Fungicide :
Principle: Sulphur is converted to thiosulphate
by refluxing with Sodium sulfite. Excess Sodium
sulfite is destroyed by Formaldehyde and then the
thiosulphate is estimated by titration with
standard Iodine solution using starch solution
(1%) as indicator.
S + Na2SO3 2Na2S2O3
2Na2S2O3 + I2 2NaI + Na2S4O6
procedure:
Weigh accurately sufficient quantity of sample
to contain 0.1 g of Sulphur in a 250ml flat bottom
flask
add 30ml to 40ml distilled water. 2 g of sodium
sulfite and few drops of liquid paraffin.
Reflux for 40 minutes, cool the flask. add 10ml
formaldehyde, 10ml acetic acid solution .
 titrate immediately with standard Iodine using
freshly prepared Starch solution. (‘X’ ml).
Carry out a reagent blank without sample as per
above procedure.
Calculations:
2 gm equivalent of Iodine = 2 gm mole of Hypo
= 2 gm mole of Sulphur
1 gm equivalent of Iodine = 1 gm mole of sulphur = 32.06 gms of
Sulphur
1000ml of 1 N Iodine solution= 32.06 gms of Sulphur
‘X’ ml of N normal Iodine solution = 32.06 xXx N
1000
If dilution is made the, Sulphur content % by mass
= 32 .06 x Xx N x d
1000x W
d= dilution factor
Analysis of Phenolic Group in insecticide
Methyl parathion
Molecular formula:C8H10O5NPS
Molecular weight: 263.21
Principle:
The phenolic impurities mainly para nitrophenol are
separated from a.i by washing the ethereal sample
solution with dilute chilled sodium carbonate A.I is
reduced to amino derivative which is estimated by
diazotization titration.
Procedure:
 1 g sample equivalent of sample is dissolved in
100ml ether contained in a separating funnel.
 Wash very carefully using each time 10 to 20 ml of
chilled 1% Sodium carbonate solution till the aqueous
solution is free from yellow colour.
 Then ether layer is taken in to a beaker and mixed
with acid mixture (9:1 Acetic acid and HCl),
add about 2 g of Zinc dust or granules and heat
it on water bath for about 1 hr. and the solution
in the beaker is colourless.
Destroy the excess Zinc by adding conc. HCl
and heating.
Cool and chill it to about O0C, add 5 gms of
Sodium bromide or Potassium bromide .
titrate it slowly and carefully aganst standard
Sodium nitrite solution using starch iodide paper
as external indicator.
Calculations:
1 gm equivalent of Sodium nitrite = 1 gm mole of sample
= 263.21 g of sample
1000 ml of 1N Sodium nitrite = 263.21 gms of a.i
‘X’ml of n normal Sod. Nitrite = 263.21 x X x N g of
1000 sample
% sample = 26.321 x X x N
W
Where ‘X’ = ml of standard solution of Sodium nitrite
consumed by the sample N = normality of sodium nitrite
W = weight of the sample
Analysis of pesticides

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Analysis of pesticides

  • 1. Dr. S.H. Burungale Department of Chemistry Yashwantrao Chavan College of Science ,Karad
  • 2. Analysis of Pesticides Introduction, classification of pesticides, sampling, sample pretreatment and processin analysis of DDT, gammexane, endosulphan, zinab, ziram, malathion, thiram, thiometon, simazine and chloridane.
  • 3. SAMPLE COLLECTION  Area selection and random collection Packaging and Transmission of laboratory samples a) packing b) sealing Compositing  grinding and mixing Homogenization Sample storage
  • 4. Pesticide: Pesticide is a substance which kills a pest. Any substance or mixture of substances intended for preventing, destroying, repelling, or mitigating any pest. (insect, rodent, nematode, fungus, weed, other forms of terrestrial or aquatic plant or animal life or viruses, bacteria, or other microorganisms.
  • 5. Gammaxeneor Lindane DDT Endosulphon C9H6Cl6O3S Chloridane C10H6Cl8 - 409.76 406.90 g·mol−1 C14H9Cl5 : 354.49 g/mol 290.814 g/mo
  • 8. Classification of pesticides OrganicInorganic Natural Synthetic Organophosphates Organochlorines Carbamates Synthetic Pyrethroids
  • 9. Classification of pesticides Synthesis : chemically synthesized Microbial : Microbial agents stem from bacteria, fungi, algae, naturally occurring viruses or protozoan Botanical : Botanical pesticides come from plants eg neem, pyrithrins Mineral: Mineral based controls include sulfur and lime-sulfur.
  • 10. Synthetic pesticides Inorganic : Inorganic insecticides are of mineral origin, mainly compounds of antimony arsenic ,barium, boron, copper, fluorine, mercury, selenium, sulfur, thallium, and zinc, and elemental phosphorus and sulfur. Antimonyl potassium tartrate, tartar emetic, their Oxides
  • 11. Organic Pesticides Organochlorines :DDT, methoxychlor, dieldrin, chlordane, toxaphene, mirex, kepone, lindane, and benzene hexachloride. DDT : C14H9Cl5 Organophosphate : parathion. Malathion.methyl parathion.chlorpyrifos.diazinon. Dichlorvos.phosmet.fenitrothion. Phenoxy Herbicides Carbamates :
  • 12. Phenoxy Herbicides : 2 4 - D 2,4-dichlorophenoxyacetic acidUreas:
  • 13. I.Analysis of Chlorinated Pesticides Principle: DDT is hydrolysed with Sodium hydroxide in a medium of 1:1 mixture of methanol and acetone under reflux when 3 equivalence of ionic chloride are liberated per mole of DDT The ionic chloride is estimated by Volhard’s method. A.I content is calculated by multiplying per cent chloride (corrected free chloride), with a suitable convernsion factor. NaCl + AgNO3 ---AgCl + NaNO3
  • 14. 1 g DDT is taken in 250 ml volumetric flask and 125ml acetone is added. Shaken well to dissolve the DDT and make up to the mark with Methanol. To the 50ml aliquot, 50ml of 0.3N solution of aqueous Sodium hydroxide is added and refluxed for 1 hr Analysis of DDT
  • 15. After cooling add 5ml Hydrogen peroxide (30%) and boil gently for 10 min If it’s still coloured, repeat the above exercise. Destroy the excess alkalinity by using 1:1 Nitric acid and phenolphthalein Add 10ml of Nitric acid in excess, 25ml standard solution of Silver nitrate and 5ml Nitro-benzene and 1 ml Ferric alum indicator and titrated against standard Potassium thiocyanate solution to a faint brick red colour (y ml).
  • 16. Carry out a blank titration with 50ml aliquot of stock solution without hydrolysis (x ml) Calculate % value by deducting y ml from x ml. and use dilution factor. Calculations: 1000ml of 1 N normal Silver nitrate =354.49 g of DDT ‘Z ’ ml of normal solution = 354.49 x Z x N 1000 % DDT = 354.49 x Z x N x 100 = 35.449 x Zx N 1000 x W W
  • 17. II.ANALYSIS OF DITHIOCARBAMATES Name Molecular formula Molecular weight Structure A. Alkyl dithiocarbamates S i. Thiram ( CH3 )2-N-C-S C6H12N2S4 240.4 2 S ii. Ziram ( CH3 )2-N-C-S Zn iii. Ferbam C6H12N2S4Zn 305.8 2 S C9H18FeN3S6 418.9 ( CH3 )2-N-C-S Fe2 B. Alkylene dithiocarbamates SII CH2-NH-C-SI Zn CH2-NH-C-SIISSII CH2-NH-C-SI Mn(ZnCl2)y CH2-NH-C-S II xS S CH3 S NH NH S S Zni. Zineb C4H6N2S4Zn 275.74 ii. Mancozeb C4H6N2S4Mn Zn iii. Propineb C5H8N2S4Zn 290
  • 18. Principle: One mole of dithiocarbamate on decomposition with hot boiling dilute acid liberates two moles of carbondisulphide. Absorption Hydrogen sulphide in Cadmium sulphate/Lead acetate solution. quantitatively in methanolic KOH to Potassium xanthate . This Potassium xanthate is quantitatively estimated in acetic acid medium by titration against standard Iodine solution using starch solution as indicator.
  • 19. In the case of alkyl bisdithiocarbamates, Ziram, Thiram, Ferbam. A.I content can also be estimated on the basis of dimethylamine content
  • 20. Take 100 to 150 ml of 1 N Sulphuric acid in reaction kettle. Take 25ml Lead acetate in first absorber and keep it hot (approximately 70 deg.C). Take 25ml 2 N methanolic KOH in the second absorber keep it chilled below 10 deg.C. Heat the acid in the kettle and keep it boiling. Transfer sufficient quantity of sample accurately by weighing 0.2 to 0.3 gms of a.i into the reaction flask Analysis of Thiocarbamates
  • 21. Digest for one hour and forty- five minutes. After the digestion is complete, quickly disconnect the KOH trap Transfer quantitatively with distilled water the contents of the trap in to a 50ml iodine flask. Neutralise it with 30% acetic acid using phenolphthalein indicator, add 1ml excess acid and titrate immediately with 0.1N Iodine solution using starch solution as indicator. End point is colourless to blue.
  • 22. Calculations: Thiram, Ziram, Mancozeb, Propineb and Zineb 2 equivalents of Iodine = 2 equivalents of CS2 = 1 mole of sample 1 equivalent of Iodine = ½ mole of sample 1000ml of 1 N Iodine solution = ½ mole of sample Calculations: 1000ml of 1 N Iodine =Mol.wt. of sample ‘x ’ ml of normal solution = M.W x X x N 1000 % Sample = M.W x X x N x 100 = M.W x Zx N 1000 x W W
  • 23. III.Analysis of organophosphorus Principle: One mole of a.i on hydrolysis in acidic medium yields one mole each of diethyl dithio phosphoric acid and ethyl mercaptan, which consume two equivalents of Silver nitrate. From the quantity of Silver nitrate consumed by a.i alone, obtained after correcting for impurity interferences, a.i content is calculated.
  • 24. Step I Preparation of sample stock solution Sufficient quantity of the sample equivalent to 2.5 g is extracted with acetone and made up to 250ml in a volumetric flask. Step II Estimation of samples – To a flask containing 150 ml water acidified with 5 drops of Nitric acid, add by pipette 10ml of standard Silver nitrate solution and maintain at 500C.
  • 25. After attaining constant temperature, add by a pipette 10ml of sample stock solution, and carry out hydrolysis at 500C. for 15 minutes. Titrate the excess silver nitrate against standard thiocyanate solution using 1 ml 10% Ferric nitrate solution as indicator (x ml).
  • 26. Step III Estimation of impurities  Transfer by pipette 50ml of sample stock solution in to a 500 ml separating funnel containing 50ml benzene.  Extract this solution thrice, each time by 10ml of 0.1N KOH in aqueous solution of 10% Potassium nitrate followed by one washing with 50ml distilled water.  Collect the aqueous layer and acidify with concentrated Nitric acid till acidic to Congo red paper.
  • 27.  Add 5 drops of acid in excess and keep it in waer bath maintained at500C till contents of the flask attained constant temperature.  Then add by pipette 5 ml standard Silver nitrate and keep it in the water bath at 500C for 15 minutes.  Then cool to room temperature and titrate the excess Silver nitrate against std. thiocyanate solution using 1 ml of 10% Ferric nitrate as indicator (y ml)
  • 28. 1gm equivalent of Silver nitrate = ½ mole of sample Calculations: Gram equivalents of Silver nitrate = 1 gm mole of sample
  • 29. IV.Analysis of Fungicide : Principle: Sulphur is converted to thiosulphate by refluxing with Sodium sulfite. Excess Sodium sulfite is destroyed by Formaldehyde and then the thiosulphate is estimated by titration with standard Iodine solution using starch solution (1%) as indicator. S + Na2SO3 2Na2S2O3 2Na2S2O3 + I2 2NaI + Na2S4O6
  • 30. procedure: Weigh accurately sufficient quantity of sample to contain 0.1 g of Sulphur in a 250ml flat bottom flask add 30ml to 40ml distilled water. 2 g of sodium sulfite and few drops of liquid paraffin.
  • 31. Reflux for 40 minutes, cool the flask. add 10ml formaldehyde, 10ml acetic acid solution .  titrate immediately with standard Iodine using freshly prepared Starch solution. (‘X’ ml). Carry out a reagent blank without sample as per above procedure.
  • 32. Calculations: 2 gm equivalent of Iodine = 2 gm mole of Hypo = 2 gm mole of Sulphur 1 gm equivalent of Iodine = 1 gm mole of sulphur = 32.06 gms of Sulphur 1000ml of 1 N Iodine solution= 32.06 gms of Sulphur ‘X’ ml of N normal Iodine solution = 32.06 xXx N 1000 If dilution is made the, Sulphur content % by mass = 32 .06 x Xx N x d 1000x W d= dilution factor
  • 33. Analysis of Phenolic Group in insecticide Methyl parathion Molecular formula:C8H10O5NPS Molecular weight: 263.21
  • 34. Principle: The phenolic impurities mainly para nitrophenol are separated from a.i by washing the ethereal sample solution with dilute chilled sodium carbonate A.I is reduced to amino derivative which is estimated by diazotization titration.
  • 35. Procedure:  1 g sample equivalent of sample is dissolved in 100ml ether contained in a separating funnel.  Wash very carefully using each time 10 to 20 ml of chilled 1% Sodium carbonate solution till the aqueous solution is free from yellow colour.  Then ether layer is taken in to a beaker and mixed with acid mixture (9:1 Acetic acid and HCl),
  • 36. add about 2 g of Zinc dust or granules and heat it on water bath for about 1 hr. and the solution in the beaker is colourless. Destroy the excess Zinc by adding conc. HCl and heating. Cool and chill it to about O0C, add 5 gms of Sodium bromide or Potassium bromide . titrate it slowly and carefully aganst standard Sodium nitrite solution using starch iodide paper as external indicator.
  • 37. Calculations: 1 gm equivalent of Sodium nitrite = 1 gm mole of sample = 263.21 g of sample 1000 ml of 1N Sodium nitrite = 263.21 gms of a.i ‘X’ml of n normal Sod. Nitrite = 263.21 x X x N g of 1000 sample % sample = 26.321 x X x N W Where ‘X’ = ml of standard solution of Sodium nitrite consumed by the sample N = normality of sodium nitrite W = weight of the sample