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TUGASAN:
PISAH
RAGAMAN
NAMA: MUHAMMAD AZEEMSHAH BIN
AMIRUDDIN
NO MATRIK: A169571
PROF DATO’ IR .RIZA ATIQ ABDULLAH
BIN O.K RAHMAT
ASAS-ASAS SAINS DATA DALAM PENGANGKUTAN (SEMESTER
2 SESI 2020/2021)
1.(a) Tuliskan Fungsi Logistik
Yang Sesuai
•𝑃 =
1
1+𝑒𝛼𝑋+𝐶
•
1−𝑃
𝑃
= 𝑒𝛼𝑋+𝐶
•𝐿𝑛
1−𝑃
𝑃
= 𝛼𝑋 + 𝐶
(b) Plotkan Graf Bagi Data
Dibawah
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
0 1 2 3 4 5 6 7
KEBARANGKALIAN
PERALIH
KEPADA
PENGANGKUTAN
AWAM
KADAR PARKIR SATU JAM
KADAR PARKIR SATU JAM VS KEBARANGKALIAN PERALIH KEPADA
PENGANGKUTAN AWAM
(c) Tukarkan data dalam bentuk ln(log(e))
KADAR PARKIR
SATU JAM
KEBARANGKALIAN PERALIH
KEPADA PENGANGKUTAN AWAM (P) (1-P)/P Ln((1-P)/P)
0.5 0.04 24 3.178054
1 0.06 15.66667 2.751535
1.5 0.1 9 2.197225
2 0.17 4.882353 1.585627
2.5 0.28 2.571429 0.944462
3 0.39 1.564103 0.447312
3.5 0.5 1 0
4 0.65 0.538462 -0.61904
4.5 0.75 0.333333 -1.09861
5 0.8 0.25 -1.38629
5.5 0.83 0.204819 -1.58563
6 0.86 0.162791 -1.81529
(d) Plotkan graf dan dapatkan persamaan
garisan regresi
-3
-2
-1
0
1
2
3
4
0 1 2 3 4 5 6 7
(e) Masukkan Angka-Angka
Parameter Fungsi Logistic
Anda
•𝑷 =
𝟏
𝟏+𝒆𝜶𝑿+𝑪 =
𝟏
𝟏+𝒆−𝟎.𝟗𝟔𝟐𝟑𝒙+𝟑.𝟓𝟏𝟎𝟕
•𝐿𝑛
1−𝑃
𝑃
= 𝛼𝑋 + 𝐶
•𝑌 = 𝑚𝑋 + 𝐶
•𝑚 = −0.9623 = α
•𝑌 = 0.9834
•𝐶 = 3.5107
(f) Dengan Menggunakan Model yang Dibina,
Kirakan Kebarangkalian Pengguna Kereta Beralih
Kepada
KADAR
PARKIR
SATU JAM
KEBARANGKALIAN PERALIH KEPADA
PENGANGKUTAN AWAM (P) (1-P)/P Ln((1-P)/P) P
0.5 0.04 24 3.178054 0.046109
1 0.06 15.66667 2.751535 0.072534
1.5 0.1 9 2.197225 0.112321
2 0.17 4.882353 1.585627 0.169933
2.5 0.28 2.571429 0.944462 0.248814
3 0.39 1.564103 0.447312 0.348918
3.5 0.5 1 0 0.464398
4 0.65 0.538462 -0.61904 0.583826
4.5 0.75 0.333333 -1.09861 0.694162
5 0.8 0.25 -1.38629 0.78597
5.5 0.83 0.204819 -1.58563 0.855937
6 0.86 0.162791 -1.81529 0.905775
2. (a) Tuliskan Fungsi Logistik
yang Sesuai
•𝑃 =
1
1+𝑒𝛼𝑋+𝛽𝑍+𝐶
•
1−𝑃
𝑃
= 𝑒𝛼𝑋+𝛽𝑍+𝐶
•𝐿𝑛
1−𝑃
𝑃
= 𝛼𝑋 + 𝛽𝑍 + 𝐶
(b) Tukarkan Dalam Bentuk ln(log e)
TAMBANG BAS JIMAT MASA
KEBARANGKALIAN PENGGUNA
KERETA BERALIH KEPADA BUS (1-P)/P Ln((1-P)/P)
2.9 0 0.1 9 2.197225
2.9 5 0.14 6.142857 1.81529
2.9 10 0.19 4.263158 1.45001
2.9 15 0.25 3 1.098612
2.9 20 0.32 2.125 0.753772
2.9 25 0.4 1.5 0.405465
2.9 30 0.48 1.083333 0.080043
2 20 0.35 1.857143 0.619039
2.25 20 0.34 1.941176 0.663294
2.5 20 0.33 2.030303 0.708185
2.75 20 0.32 2.125 0.753772
3 20 0.31 2.225806 0.800119
3.25 20 0.31 2.225806 0.800119
3.5 20 0.3 2.333333 0.847298
3.75 20 0.29 2.448276 0.895384
(c) Lakukan Analisis Regresi (Tambang
Bas)
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
2 2.25 2.5 2.75 3 3.25 3.5 3.75
Tambang Bas
(c) Lakukan Analisis Regresi (Jimat Masa)
0
0.5
1
1.5
2
2.5
0 5 10 15 20 25 30 35
Jimat Masa
(d)Tuliskan Model Logistic
dengan Parameter dari Analisis
Regresi
• 𝑃 =
1
1+𝑒𝛼𝑋+𝛽𝑍+𝐶
•
1−𝑃
𝑃
= 𝑒𝛼𝑋+𝛽𝑍+𝐶
• 𝐿𝑛
1−𝑃
𝑃
= 𝛼𝑋 + 𝛽𝑍 + 𝐶
• 𝛼 = −0.0705
• 𝛽 = 0.982
• 𝐶 = 2.1716 + 0.326 = 2.4976
• 𝑃 =
1
1+𝑒𝛼𝑋+𝛽𝑍+𝐶 =
1
1+𝑒−0.0705𝑋+0.982𝑍+2.4976

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A169571 tugasan pisah ragaman

  • 1. TUGASAN: PISAH RAGAMAN NAMA: MUHAMMAD AZEEMSHAH BIN AMIRUDDIN NO MATRIK: A169571 PROF DATO’ IR .RIZA ATIQ ABDULLAH BIN O.K RAHMAT ASAS-ASAS SAINS DATA DALAM PENGANGKUTAN (SEMESTER 2 SESI 2020/2021)
  • 2.
  • 3. 1.(a) Tuliskan Fungsi Logistik Yang Sesuai •𝑃 = 1 1+𝑒𝛼𝑋+𝐶 • 1−𝑃 𝑃 = 𝑒𝛼𝑋+𝐶 •𝐿𝑛 1−𝑃 𝑃 = 𝛼𝑋 + 𝐶
  • 4. (b) Plotkan Graf Bagi Data Dibawah 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0 1 2 3 4 5 6 7 KEBARANGKALIAN PERALIH KEPADA PENGANGKUTAN AWAM KADAR PARKIR SATU JAM KADAR PARKIR SATU JAM VS KEBARANGKALIAN PERALIH KEPADA PENGANGKUTAN AWAM
  • 5. (c) Tukarkan data dalam bentuk ln(log(e)) KADAR PARKIR SATU JAM KEBARANGKALIAN PERALIH KEPADA PENGANGKUTAN AWAM (P) (1-P)/P Ln((1-P)/P) 0.5 0.04 24 3.178054 1 0.06 15.66667 2.751535 1.5 0.1 9 2.197225 2 0.17 4.882353 1.585627 2.5 0.28 2.571429 0.944462 3 0.39 1.564103 0.447312 3.5 0.5 1 0 4 0.65 0.538462 -0.61904 4.5 0.75 0.333333 -1.09861 5 0.8 0.25 -1.38629 5.5 0.83 0.204819 -1.58563 6 0.86 0.162791 -1.81529
  • 6. (d) Plotkan graf dan dapatkan persamaan garisan regresi -3 -2 -1 0 1 2 3 4 0 1 2 3 4 5 6 7
  • 7. (e) Masukkan Angka-Angka Parameter Fungsi Logistic Anda •𝑷 = 𝟏 𝟏+𝒆𝜶𝑿+𝑪 = 𝟏 𝟏+𝒆−𝟎.𝟗𝟔𝟐𝟑𝒙+𝟑.𝟓𝟏𝟎𝟕 •𝐿𝑛 1−𝑃 𝑃 = 𝛼𝑋 + 𝐶 •𝑌 = 𝑚𝑋 + 𝐶 •𝑚 = −0.9623 = α •𝑌 = 0.9834 •𝐶 = 3.5107
  • 8. (f) Dengan Menggunakan Model yang Dibina, Kirakan Kebarangkalian Pengguna Kereta Beralih Kepada KADAR PARKIR SATU JAM KEBARANGKALIAN PERALIH KEPADA PENGANGKUTAN AWAM (P) (1-P)/P Ln((1-P)/P) P 0.5 0.04 24 3.178054 0.046109 1 0.06 15.66667 2.751535 0.072534 1.5 0.1 9 2.197225 0.112321 2 0.17 4.882353 1.585627 0.169933 2.5 0.28 2.571429 0.944462 0.248814 3 0.39 1.564103 0.447312 0.348918 3.5 0.5 1 0 0.464398 4 0.65 0.538462 -0.61904 0.583826 4.5 0.75 0.333333 -1.09861 0.694162 5 0.8 0.25 -1.38629 0.78597 5.5 0.83 0.204819 -1.58563 0.855937 6 0.86 0.162791 -1.81529 0.905775
  • 9. 2. (a) Tuliskan Fungsi Logistik yang Sesuai •𝑃 = 1 1+𝑒𝛼𝑋+𝛽𝑍+𝐶 • 1−𝑃 𝑃 = 𝑒𝛼𝑋+𝛽𝑍+𝐶 •𝐿𝑛 1−𝑃 𝑃 = 𝛼𝑋 + 𝛽𝑍 + 𝐶
  • 10. (b) Tukarkan Dalam Bentuk ln(log e) TAMBANG BAS JIMAT MASA KEBARANGKALIAN PENGGUNA KERETA BERALIH KEPADA BUS (1-P)/P Ln((1-P)/P) 2.9 0 0.1 9 2.197225 2.9 5 0.14 6.142857 1.81529 2.9 10 0.19 4.263158 1.45001 2.9 15 0.25 3 1.098612 2.9 20 0.32 2.125 0.753772 2.9 25 0.4 1.5 0.405465 2.9 30 0.48 1.083333 0.080043 2 20 0.35 1.857143 0.619039 2.25 20 0.34 1.941176 0.663294 2.5 20 0.33 2.030303 0.708185 2.75 20 0.32 2.125 0.753772 3 20 0.31 2.225806 0.800119 3.25 20 0.31 2.225806 0.800119 3.5 20 0.3 2.333333 0.847298 3.75 20 0.29 2.448276 0.895384
  • 11. (c) Lakukan Analisis Regresi (Tambang Bas) 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 2 2.25 2.5 2.75 3 3.25 3.5 3.75 Tambang Bas
  • 12. (c) Lakukan Analisis Regresi (Jimat Masa) 0 0.5 1 1.5 2 2.5 0 5 10 15 20 25 30 35 Jimat Masa
  • 13. (d)Tuliskan Model Logistic dengan Parameter dari Analisis Regresi • 𝑃 = 1 1+𝑒𝛼𝑋+𝛽𝑍+𝐶 • 1−𝑃 𝑃 = 𝑒𝛼𝑋+𝛽𝑍+𝐶 • 𝐿𝑛 1−𝑃 𝑃 = 𝛼𝑋 + 𝛽𝑍 + 𝐶 • 𝛼 = −0.0705 • 𝛽 = 0.982 • 𝐶 = 2.1716 + 0.326 = 2.4976 • 𝑃 = 1 1+𝑒𝛼𝑋+𝛽𝑍+𝐶 = 1 1+𝑒−0.0705𝑋+0.982𝑍+2.4976