Which one is not primitive data type: Boolean, String, double, char List two relational operators and two logical operators Are the following expressions True or False(assume x = 10) (x > 10 || (x-5) !=5) (x - 2) 0 Write loop in Java syntax to repeat reading input if user input x is not between 0 and 25. What will be the value of x and sum after the following code is executed? Int x = 0, sum = 0; while (x 2) angel +=10; else angle +=15;
Solution
1) String is a class
2)
Relational Operator : equal to operator (=) and greater than equal to (>=)
Logical Operator : && (AND) operator, || (OR operator)
3) x=10
a) (x>10 || (x-5)!=5)
here first check x>10 i.e. 10>10 which is false
then check (x-5)!=5 i.e (10-5)!=5 => 5!=5 which is false
now combine the complete equation false || false which is false
b)
(x-2) <=8 && x>0
(x-2) <=8 i.e. (10-2)<=8 which is 8<=8 which results in true
x>0 i.e. 10>0 which is true
now combine the complete true && true which is true
4)
do
{
System.out.println(\"Enter the value of x\");
}
while(0<x<25);
5) x=0, sum=0
while loop will iterate till x<5 i.e x=0,1,2,3,4
and the expression will add the values of x (sum=sum+x)
and x++ increases the value by 1
hence
1) x=0 : sum=sum+x i.e. sum = 0+0; sum=0
2) x=1 : sum =sum +x i.e sum = 0+1; sum= 1
3) x=2 : sum =sum +x i.e sum = 1+2; sum= 3
2) x=3 : sum =sum +x i.e sum = 3+3; sum = 6
2) x=4 : sum =sum +x i.e sum = 6+4; sum = 10
At the end value of x will be 5 and sum will be 10
6) for(x=0;x<5;x++)
{
sum=sum+x;
}
7) here int len = str.length() will calculate the length of str which is 18
so System.out.println(len) will print 18.
System.out.println(str.charAt(3)); this will check character at index 3 which is l.
System.out.println(str.subString(len-4)); this function will fetch substring from str so it will return 1201
O/P 18
l
1201
8)
here str = str+\"E\" , this will append E to the str whcih is starting with H
and the loop iterate for count = 0, 1
count = 0 i.e str= str+\"E\" i.e HE
count = 1i.e. str = str = \"E\" i..e HEE
now it exits the loop
now str = str+ \"LP\" hence str becomes HEELP
O/P : HEELP
9)
user enters the value angle = 5
now check conditions one by one
if(angle>5) i.e. 5>5 which is false
else if (angle>2) angle= angle+10 i.e. 5>2 whcih is true hence angle becomes 5+10
hence after the code execution angle becomes 15
.
social pharmacy d-pharm 1st year by Pragati K. Mahajan
Which one is not primitive data type- Boolean- String- double- char.docx
1. Which one is not primitive data type: Boolean, String, double, char List two relational operators
and two logical operators Are the following expressions True or False(assume x = 10) (x > 10 ||
(x-5) !=5) (x - 2) 0 Write loop in Java syntax to repeat reading input if user input x is not
between 0 and 25. What will be the value of x and sum after the following code is executed? Int
x = 0, sum = 0; while (x 2) angel +=10; else angle +=15;
Solution
1) String is a class
2)
Relational Operator : equal to operator (=) and greater than equal to (>=)
Logical Operator : && (AND) operator, || (OR operator)
3) x=10
a) (x>10 || (x-5)!=5)
here first check x>10 i.e. 10>10 which is false
then check (x-5)!=5 i.e (10-5)!=5 => 5!=5 which is false
now combine the complete equation false || false which is false
b)
(x-2) <=8 && x>0
(x-2) <=8 i.e. (10-2)<=8 which is 8<=8 which results in true
x>0 i.e. 10>0 which is true
now combine the complete true && true which is true
4)
do
{
System.out.println("Enter the value of x");
}
while(0<x<25);
5) x=0, sum=0
2. while loop will iterate till x<5 i.e x=0,1,2,3,4
and the expression will add the values of x (sum=sum+x)
and x++ increases the value by 1
hence
1) x=0 : sum=sum+x i.e. sum = 0+0; sum=0
2) x=1 : sum =sum +x i.e sum = 0+1; sum= 1
3) x=2 : sum =sum +x i.e sum = 1+2; sum= 3
2) x=3 : sum =sum +x i.e sum = 3+3; sum = 6
2) x=4 : sum =sum +x i.e sum = 6+4; sum = 10
At the end value of x will be 5 and sum will be 10
6) for(x=0;x<5;x++)
{
sum=sum+x;
}
7) here int len = str.length() will calculate the length of str which is 18
so System.out.println(len) will print 18.
System.out.println(str.charAt(3)); this will check character at index 3 which is l.
System.out.println(str.subString(len-4)); this function will fetch substring from str so it will
return 1201
O/P 18
l
1201
8)
here str = str+"E" , this will append E to the str whcih is starting with H
and the loop iterate for count = 0, 1
count = 0 i.e str= str+"E" i.e HE
count = 1i.e. str = str = "E" i..e HEE
now it exits the loop
now str = str+ "LP" hence str becomes HEELP
O/P : HEELP
9)
user enters the value angle = 5
3. now check conditions one by one
if(angle>5) i.e. 5>5 which is false
else if (angle>2) angle= angle+10 i.e. 5>2 whcih is true hence angle becomes 5+10
hence after the code execution angle becomes 15
