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Heat Transfer
By
D. Mwakipesile
Fundamental Concepts and Principles
What and How?
Heat Transfer (or Heat) is energy in transit due to a
temperature difference.
How? Three types of heat transfer process-Three
modes.
Conduction:
Molecular diffusion of heat (by direct contact) heat
transfer occurs across the medium.
Convection:
Random molecular motion (diffusion)
Moving fluid (i.e. or macroscopic motion of the fluid)

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





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
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
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z
C
k
y
C
j
x
C
iC
z
P
k
y
P
j
x
P
iP
z
T
k
y
T
j
x
T
iT
Gradient

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

00:
00:
qTmediatwoBetween
qTmediumaIn
△
Radiation:
Electromagnetic wave or photons (without working
medium), All surfaces of finite temperature will emit
energy in the form of electromagnetic wave
Basic Laws
Tk
y
T
kq
w
w 





k
1. Fourier Law of Conduction
Where :Conductivity of media a material property
Nonmetallic liquid 0.08 ~ 0.7
Alloys 14 ~ 20
Pure metals 50 ~400
k  mkw/Typical Values of
2. Newton’s Law of Cooing
)(  TThq ww
)/( 2
kmwhWhere
It depends on condition in the boundary layer, which are
influenced by surface geometry, the nature of the fluid motion,
and an assortment of fluid thermodynamics and transport
properties.
, called the convection heat transfer coefficient,
the film conduction is not a property.
Typical values of the convection heat transfer coefficient
process  )/( 2
kmwh
Gases Liquids
Boiling or
condensation
Free Convection 2~25 50~1000
Forced Convection
25~250
50~20,00
0
Convection with Phase
Change
2500~100,000
Note:The fluid flow results from either an imposed pressure drop or
an induced buoyancy respectively called-forced and free convection.
3. Nu and Bi
 
 
Conduction
w
f
Convection
ww
y
T
kTThq 




  )(

))(/(
)(
)(
/
 

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
TTly
TT
l
k
TT
yT
kh
w
wf
W
w
f
*
*
y
T
k
hl
Nu
f 


l
y
y *



TT
TT
T
W
W*
Where, Nusselt Number is the dimensionless fluid temperature gradient
at the surface (or wall)
But, the Biot Number
resistencethermallayerBoundary
solidaofceresisthermalInternal
k
hl
Bi
s
tan
)(

Transport Phenomena
Due to non-uniform distributed field
(1) Transport of momentum velocity gradient→momentum transfer
y
u
w


  viscous stress
(2) Transport of Heat
y
T
kqw


  Tkor 
y
c
DN


  cDor 
Temperature gradient→heat transfer
(3) Transport of mass
Concentration gradient→mass flux
Focal Point in Conduction Heat Transfer
What drives heat transfer is temperature difference
and not temperature;
Conduction heat transfer problems involve the
determination of temperature distribution in a
region;
How is the rate of heat transfer related to
temperature distribution?
What governs temperature distribution in a region?
Fourier’s law of conduction provides the answer to
the first question while the principle of conservation
of energy gives the answer to the second.
Conservation of Energy
What determines temperature distribution in a
region is that the temperature at each point is
adjusted such that the principle of conservation of
energy is satisfied everywhere;
 By so doing, volumetric energy generation;
Examples of volumetric energy generation include,
among others, heat conduction in nuclear elements,
metabolic heat production in tissue, electrical
energy loss in transmission lines etc
Boundary Conditions
Since boundary conditions involve thermal interaction
with the surroundings, it is necessary to first describe
two common modes of surface heat transfer:
convection and radiation.
Surface Convection: Newton's Law of Cooling.
In this mode of heat transfer, energy is exchanged
between a surface and a fluid moving over it. The flux
in convection is directly proportional to the difference
in temperature between the surface and the streaming
Fluid. i.e
This result is known as Newton's law of cooling. The constant of
proportionality h is called heat transfer coefficient. This coefficient
depends on geometry, fluid properties, motion, and in some cases
temperature difference (Ts, T). Thus, unlike thermal conductivity, h is not
a property of material.
Surface Radiation: Stefan-Boltzmann Law
radiation energy is transmitted by electromagnetic waves, which travel
best in a vacuum.
The maximum possible radiation is described by the Stefan-Boltzmann
law, which gives surface radiation flux for an ideal body called
blackbody as
Radiation flux qr
To determine the radiation flux qr emitted from a real
surface, a radiation property called emissivity, ε, is
defined as
Thus
Radiation energy exchange between two surfaces
depends on the geometry, shape, area, orientation and
emissivity of the two surfaces.
Classification of conduction heat
transfer problems
Steady versus transient heat transfer,
multidimensional heat transfer,
heat generation.
Steady versus Transient Heat Transfer
Classification of conduction heat transfer cont.
The Heat Conduction Equation in Cylindrical and
Spherical Coordinates
Heat Generation
During steady one-dimensional heat conduction in a
spherical (or cylindrical) container, the total rate of
heat transfer remains constant, but the heat flux
decreases with increasing radius.
Under steady conditions,
The entire heat generated within the medium is
conducted through the outer surface of the cylinder,
The heat generated within this inner cylinder must
be equal to the heat conducted through the outer
surface of this inner cylinder
Thermal Resistance Concept
Convection Resistance
Radiation Resistance
Heat transfer in Composite materials
Consider sketch below, in which heat will tend to flow
between materials B and C, and this heat flow will be
normal to the primary direction of heat transfer.
In general, when thermal resistances occur in
parallel, heat will flow in more than one direction;
In this case, the one-dimensional calculation of q
represents an approximation, that is generally quite
acceptable for process engineering purposes.
The resistance to heat transfer is termed the thermal resistance,
and is denoted by Rth. Thus, the general rate equation may
be written as:
In this equation, all quantities take on positive values only, so that q
and T represent the absolute values of the heat-transfer rate and
temperature difference, respectively.
The thermal resistance concept permits some relatively complex heat-
transfer problems to be solved in a very simple manner. The reason is
that thermal resistances can be combined in the same way as electrical
resistances. Thus, for resistances in series, the total resistance is the sum
of the individual resistances:
Likewise, for resistances in parallel:
The effect of the additional resistance is to decrease the rate of
heat transfer.
Since the contact resistance is difficult to determine, it is often
neglected or a rough approximation is used. For example, a value
equivalent to an additional 5 mm of material thickness is
sometimes used for the contact resistance between two pieces
of the same material.
A slightly modified form of the thermal resistance, the R-value, is
commonly used for insulations and other building materials. The R-value
is defined as:
where B is the thickness of the material and k is its
thermal conductivity. The R-value is the thermal
resistance, in English units, of a slab of material
having a cross-sectional area of 1 ft2. Since the R-
value is always given for a specified thickness, the
thermal conductivity of a material can be obtained
from its R-value.
Also, since R-values are essentially thermal
resistances, they are additive for materials arranged in
series.
The summary of procedures
Write down the conduction equation in the appropriate
coordinate system;
Impose any restrictions dictated by the physical situation to
eliminate terms that are zero or negligible;
Integrate the resulting differential equation to obtain the
temperature profile;
Use the boundary conditions to evaluate the constants of
integration;
Use the appropriate form of Fourier’s law to obtain the heat
flux;
Multiply the heat flux by the cross-sectional area to obtain
the rate of heat transfer.
Questions
Q1. What drives heat transfer?
Q2. How is the rate of heat transfer related to temperature distribution?
Q3. What governs temperature distribution in a region?
Q4. In order to size the compressor of a new refrigerator, it is desired to
determine the rate of heat transfer from the kitchen air into the
refrigerated space through the walls, doors and the top and bottom
section of the refrigerator. In your analysis, would you treat this as a
transient or steady-state heat transfer problem? Also would you consider
the heat transfer to be one-dimensional or multidimensional? Explain.
Questions Cont.
Q5. Determine the heat transfer through a copper tube
5m long with inner diameter 80mm and outer
diameter 100mm. The inside temperature is 2000C
and the outside temperature is 700C. (The thermal
conductivity of copper is 385W/m. K)
Q6. A spherical steel reaction vessel has an outer
radius of 1.5m and is covered in lagging 200mm
thick. The thermal conductivity of the lagging is
0.1W/m. K. the temperature at the surface of the
steel is 3400C and the surface temperature of the
lagging is 450C. Taking thermal conductivity of
steel as 60W/m. K, calculate the heat loss.
Q7. A wall of an area of 25m2 is made up of four
layers. On the inside is plaster 15mm thick, then
there is brick 100mm thick, then insulation 60mm
thick and finally brick 100mm thick. The thermal
conductivities are : of plaster is 0.1W/m. K, brick is
0.6W/m. K and insulation is 0.08W/m. K. The inner
surface temperature of the wall is 180C and the outer
surface temperature is -20C. Calculate:
(a)The heat loss
(b) Temperature at the interface between the plaster
and the brick.
Q8. A steel pipe 120mm inside diameter has a wall
10mm thick. It is covered with insulation 20mm
thick. The thermal conductivity of steel is 60W/m. K
and for the insulation is 0.09W/m. K. The pipe
carries steam at 1500C and the outer surface
temperature of the insulation is 00C. Determine:
(i) The heat loss per meter length
(ii) The temperature at the pipe’s outer surface

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Heat Transfer Fundamentals and Principles Explained

  • 2. Fundamental Concepts and Principles What and How? Heat Transfer (or Heat) is energy in transit due to a temperature difference. How? Three types of heat transfer process-Three modes. Conduction: Molecular diffusion of heat (by direct contact) heat transfer occurs across the medium. Convection: Random molecular motion (diffusion) Moving fluid (i.e. or macroscopic motion of the fluid)
  • 4. Radiation: Electromagnetic wave or photons (without working medium), All surfaces of finite temperature will emit energy in the form of electromagnetic wave Basic Laws Tk y T kq w w       k 1. Fourier Law of Conduction Where :Conductivity of media a material property
  • 5. Nonmetallic liquid 0.08 ~ 0.7 Alloys 14 ~ 20 Pure metals 50 ~400 k  mkw/Typical Values of 2. Newton’s Law of Cooing )(  TThq ww )/( 2 kmwhWhere It depends on condition in the boundary layer, which are influenced by surface geometry, the nature of the fluid motion, and an assortment of fluid thermodynamics and transport properties. , called the convection heat transfer coefficient, the film conduction is not a property.
  • 6. Typical values of the convection heat transfer coefficient process  )/( 2 kmwh Gases Liquids Boiling or condensation Free Convection 2~25 50~1000 Forced Convection 25~250 50~20,00 0 Convection with Phase Change 2500~100,000 Note:The fluid flow results from either an imposed pressure drop or an induced buoyancy respectively called-forced and free convection. 3. Nu and Bi     Conduction w f Convection ww y T kTThq        )(
  • 7.  ))(/( )( )( /              TTly TT l k TT yT kh w wf W w f * * y T k hl Nu f    l y y *    TT TT T W W* Where, Nusselt Number is the dimensionless fluid temperature gradient at the surface (or wall) But, the Biot Number resistencethermallayerBoundary solidaofceresisthermalInternal k hl Bi s tan )( 
  • 8. Transport Phenomena Due to non-uniform distributed field (1) Transport of momentum velocity gradient→momentum transfer y u w     viscous stress (2) Transport of Heat
  • 9. y T kqw     Tkor  y c DN     cDor  Temperature gradient→heat transfer (3) Transport of mass Concentration gradient→mass flux
  • 10. Focal Point in Conduction Heat Transfer What drives heat transfer is temperature difference and not temperature; Conduction heat transfer problems involve the determination of temperature distribution in a region; How is the rate of heat transfer related to temperature distribution? What governs temperature distribution in a region? Fourier’s law of conduction provides the answer to the first question while the principle of conservation of energy gives the answer to the second.
  • 11. Conservation of Energy What determines temperature distribution in a region is that the temperature at each point is adjusted such that the principle of conservation of energy is satisfied everywhere;  By so doing, volumetric energy generation; Examples of volumetric energy generation include, among others, heat conduction in nuclear elements, metabolic heat production in tissue, electrical energy loss in transmission lines etc
  • 12. Boundary Conditions Since boundary conditions involve thermal interaction with the surroundings, it is necessary to first describe two common modes of surface heat transfer: convection and radiation. Surface Convection: Newton's Law of Cooling. In this mode of heat transfer, energy is exchanged between a surface and a fluid moving over it. The flux in convection is directly proportional to the difference in temperature between the surface and the streaming Fluid. i.e
  • 13. This result is known as Newton's law of cooling. The constant of proportionality h is called heat transfer coefficient. This coefficient depends on geometry, fluid properties, motion, and in some cases temperature difference (Ts, T). Thus, unlike thermal conductivity, h is not a property of material. Surface Radiation: Stefan-Boltzmann Law radiation energy is transmitted by electromagnetic waves, which travel best in a vacuum. The maximum possible radiation is described by the Stefan-Boltzmann law, which gives surface radiation flux for an ideal body called blackbody as
  • 14. Radiation flux qr To determine the radiation flux qr emitted from a real surface, a radiation property called emissivity, ε, is defined as Thus Radiation energy exchange between two surfaces depends on the geometry, shape, area, orientation and emissivity of the two surfaces.
  • 15. Classification of conduction heat transfer problems Steady versus transient heat transfer, multidimensional heat transfer, heat generation.
  • 16. Steady versus Transient Heat Transfer
  • 17. Classification of conduction heat transfer cont.
  • 18. The Heat Conduction Equation in Cylindrical and Spherical Coordinates
  • 19.
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  • 26. During steady one-dimensional heat conduction in a spherical (or cylindrical) container, the total rate of heat transfer remains constant, but the heat flux decreases with increasing radius. Under steady conditions, The entire heat generated within the medium is conducted through the outer surface of the cylinder, The heat generated within this inner cylinder must be equal to the heat conducted through the outer surface of this inner cylinder
  • 30. Heat transfer in Composite materials Consider sketch below, in which heat will tend to flow between materials B and C, and this heat flow will be normal to the primary direction of heat transfer. In general, when thermal resistances occur in parallel, heat will flow in more than one direction; In this case, the one-dimensional calculation of q represents an approximation, that is generally quite acceptable for process engineering purposes.
  • 31.
  • 32. The resistance to heat transfer is termed the thermal resistance, and is denoted by Rth. Thus, the general rate equation may be written as: In this equation, all quantities take on positive values only, so that q and T represent the absolute values of the heat-transfer rate and temperature difference, respectively. The thermal resistance concept permits some relatively complex heat- transfer problems to be solved in a very simple manner. The reason is that thermal resistances can be combined in the same way as electrical resistances. Thus, for resistances in series, the total resistance is the sum of the individual resistances: Likewise, for resistances in parallel:
  • 33. The effect of the additional resistance is to decrease the rate of heat transfer. Since the contact resistance is difficult to determine, it is often neglected or a rough approximation is used. For example, a value equivalent to an additional 5 mm of material thickness is sometimes used for the contact resistance between two pieces of the same material. A slightly modified form of the thermal resistance, the R-value, is commonly used for insulations and other building materials. The R-value is defined as:
  • 34. where B is the thickness of the material and k is its thermal conductivity. The R-value is the thermal resistance, in English units, of a slab of material having a cross-sectional area of 1 ft2. Since the R- value is always given for a specified thickness, the thermal conductivity of a material can be obtained from its R-value. Also, since R-values are essentially thermal resistances, they are additive for materials arranged in series.
  • 35. The summary of procedures Write down the conduction equation in the appropriate coordinate system; Impose any restrictions dictated by the physical situation to eliminate terms that are zero or negligible; Integrate the resulting differential equation to obtain the temperature profile; Use the boundary conditions to evaluate the constants of integration; Use the appropriate form of Fourier’s law to obtain the heat flux; Multiply the heat flux by the cross-sectional area to obtain the rate of heat transfer.
  • 36. Questions Q1. What drives heat transfer? Q2. How is the rate of heat transfer related to temperature distribution? Q3. What governs temperature distribution in a region? Q4. In order to size the compressor of a new refrigerator, it is desired to determine the rate of heat transfer from the kitchen air into the refrigerated space through the walls, doors and the top and bottom section of the refrigerator. In your analysis, would you treat this as a transient or steady-state heat transfer problem? Also would you consider the heat transfer to be one-dimensional or multidimensional? Explain.
  • 37. Questions Cont. Q5. Determine the heat transfer through a copper tube 5m long with inner diameter 80mm and outer diameter 100mm. The inside temperature is 2000C and the outside temperature is 700C. (The thermal conductivity of copper is 385W/m. K) Q6. A spherical steel reaction vessel has an outer radius of 1.5m and is covered in lagging 200mm thick. The thermal conductivity of the lagging is 0.1W/m. K. the temperature at the surface of the steel is 3400C and the surface temperature of the lagging is 450C. Taking thermal conductivity of steel as 60W/m. K, calculate the heat loss.
  • 38. Q7. A wall of an area of 25m2 is made up of four layers. On the inside is plaster 15mm thick, then there is brick 100mm thick, then insulation 60mm thick and finally brick 100mm thick. The thermal conductivities are : of plaster is 0.1W/m. K, brick is 0.6W/m. K and insulation is 0.08W/m. K. The inner surface temperature of the wall is 180C and the outer surface temperature is -20C. Calculate: (a)The heat loss (b) Temperature at the interface between the plaster and the brick.
  • 39. Q8. A steel pipe 120mm inside diameter has a wall 10mm thick. It is covered with insulation 20mm thick. The thermal conductivity of steel is 60W/m. K and for the insulation is 0.09W/m. K. The pipe carries steam at 1500C and the outer surface temperature of the insulation is 00C. Determine: (i) The heat loss per meter length (ii) The temperature at the pipe’s outer surface