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Erbil Polytechnic University
Koya Technical Institute
Petroleum Technology
Operation and Control
Report
Fluid Mechanic Lab.
Test no: (9)
Test name:
(Flow meter Demonstration)
Supervised by:
Karwan A. Ali
Date of Test: 1/02/2018
Date of Submit:08/02/2018
Prepared by: Muhammed Shwan Ali
Title Page number
Aim 3
Introduction 3
Apparatus 4 - 6
Procedure 6 - 7
Calculation 8-11
Discussion 12-15
Reference 15
Aim of the experiment:-
. Compression between different flow meter types.
. Determining the discharge coefficient.
Introduction:-
Fluid mechanics has developed an analytical discipline from the
application of the classical laws of static, dynamics and
thermodynamics, to situation in which fluids can be treated as
continuous media. The particular laws involved are those of
conservation of mass; these laws may be
simplified in an attempt to describe
quantitatively the behavior of the fluids.
The hydraulic bench service module, F1-
10, provides the necessary facilities to
support a comprehensive range of
hydraulic models each of which is
designed to demonstrate a particular
aspect of hydraulic theory. The specific
hydraulic model that is concerned for this
experiment is the flow meter test rig (F1-
21). This consists of venture meter,
variable area meter, and orifice plate installed in a series of
configurations to allow for direct comparisons.
OrificeNozzleVenturi
Apparatus:-
The apparatus is discharged to demonstrate three basics
types of flow meter.
-Rota meter
Rota meter:-
A Rota meter with the following characteristics is used to measure
flow rate:
- Plastic measuring tub
- Interchangeable stainless steel float
- Max. Flow rate 26 lit/min
The flow rate can be read from the upper edge of the conical
attachment.
Air particles on dirt particles on the float may affect measurement
precision.
To flush the out. Operate the test stand a maximum flow rate first.
To do so, open all cocks fully.
Nozzle and Orifice plate:
The orifice plate housing is made of transparent plastic allowing
visible functioning of the orifice plate. The flow causes a pressure
loss between inlet and outlet. Two tapings allow measurement of
inlet and outlet pressure. This differential pressure (p1-p2) is
proportional to the volume flow rate:
Q=Cd A2
√
2𝑔 (β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2
Venturi meter:
The venturi housing is made of transparent plastic allowing visible
functioning of the venturi.
The pressure in the venturi inversely propositional to the velocity
in the venturi according to Bernoulli’s law.
Two tapings allow measurement of the inlet pressure and the
pressure at the smallest area.
This differential pressure (p1-p2) is proportional to the volume flow
rate:
Q=Cd A2
√
2𝑔 (β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2
Procedure:-
- Arrange the experimentation set-up on the Hydraulic Bench
such that the discharge routs the water into the channel.
- Makes hose connection between Hydraulic Bench and unit
- Connect measurement lines
- Open all valves at pipe section and 6-tube manometer, let the
water flow for 1 minute
- Close flow control valve
- Clos drain valve of the 6-tube manometer to vent the
measurement lines
- Clos flow valve of the 6-tube manometer
- Close water inlet
- Disconnect measurement lines
- Open vent and drain valves to discharge level tubes of the 6-tube
manometer
- Close vent and drain valves
- Open flow control valve slowly
- Connect measurement lines again
- Open water inlet slowly
- Adjust the heights of the water in the manometer tubes with the
help of flow control valve until water becomes visible
-Set the flow rate and measurement scale with the inlet and outlet
control valves
-Determine volumetric flow rate. To do so. Use stopwatch to
establish time t required for raising the level in the volumetric tank
of the Hydraulic Bench.
Calculation:-
1/ Volume=25L β†’25000cm3
g=9.81m/s2
β†’981cm/s2
Time=110.69s
Qact=
π‘‰π‘œπ‘™π‘’π‘šπ‘’
π‘‡π‘–π‘šπ‘’
β†’
25000
110.69
=225.855 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
β†’981cm/s2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu=A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu=2.011
√
2(981)(32.4βˆ’28.1)
(1βˆ’
2.0112
5.3092 )
=199.58484
Cd Venturi =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
225.855
199.58484
= 1.1316
Orifice:-
A1=21.16cm2
A2=3.142cm2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu=A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu=3.142
√
2(981)(32βˆ’27)
(1βˆ’
3.1422
21.162 )
=311.5cm3
/s
Cd Orifice =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
225.855
311.5
= 0.725056
2/ Volume=25L β†’25000 cm3
,g=9.81m/s2
β†’981cm/s2
Time=73.45s
Qact=
π‘‰π‘œπ‘™π‘’π‘šπ‘’
π‘‡π‘–π‘šπ‘’
β†’
25000
73.45
= 340.3675 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
β†’981cm/s2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu=A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu=2.011
√
2(981)(34.2βˆ’24.9)
(1βˆ’
2.0112
5.3092 )
=293.5181
Cd Venturi =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
340.3675
293.5181
= 1.1584
Orifice:-
A1=21.16cm2
A2=3.142cm2
Time=73.45s
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu=A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu= 3.142
√
2(981)(33.7βˆ’22.2)
(1βˆ’
3.1422
21.162 )
=476.959cm3
/s
Cd Orifice =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
340.3675
476.959
= 0.71362
No.3/ Volume=25L β†’25000 cm3
,g=9.81m/s2
β†’981cm/s2
Time=51.61s
Qact=
π‘‰π‘œπ‘™π‘’π‘šπ‘’
π‘‡π‘–π‘šπ‘’
β†’
25000
51.61
= 484.4022 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
β†’981cm/s2
P= hy h=
𝑝
𝑦
Qmesu= A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu = A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu=2.011 √
2(981)(38βˆ’19.8)
(1βˆ’
2.0112
5.3092)
= 410.6096
Cd Venturi =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
484.4022
410.6096
= 1.17971
Orifice:-
A1=21.16cm2
A2=3.142cm2
Time=51.61s
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1βˆ’π‘2
𝑦
)
(1βˆ’
𝐴2
2
𝐴1
2)
β†’ Qmesu=A2
√
2𝑔(β„Ž1βˆ’β„Ž2)
(1βˆ’
𝐴2
2
𝐴1
2)
Qmesu=3.142 √
2(981)(37.2βˆ’14.2)
(1βˆ’
3.1422
21.162)
=675.26cm3
Cd Orifice =
𝑄 π‘Žπ‘π‘‘
𝑄 π‘šπ‘’π‘ π‘’
β†’
484.4022
675.26
= 0.71735
Table of calculation:-
Discussion:-
1/ is the ratio of the actual discharge to the ideal
discharge, assuming unit coefficients of contraction
and velocity, equal to the product of these coefficients.
--Coefficient of discharge is stated as the ratio between the actual
flow discharge and theoretical flow discharge. It is also referred to
as the ratio of mass flow rate at nozzle's discharge edge to the
No.
Qact
)/s3
(cm
Rotameter Venture meter Orifice meter
Qrot
(liter/min)
Qact
)/s3
(cm
Qi
)/s3
(cm Cd
Qi
)/s3
(cm Cd
1 225.855 9.9 165 199.58484 1.1316 311.5 0.725056
2 340.3675 16 266.6667 293.5181 1.1584 476.959 0.71362
3 484.4022 22.2 370 410.6096 1.17971 675.2 0.71735
standard nozzle which enlarges an exact working fluid maintained
at the similar initial conditions and pressures.
It has no dimensions and depends directly on the rate of flow and
velocity of working fluid. It is symbolized by Cd and its value is
different for each fluid depending on the kind of measurement of
flow. In nozzle flow measurement, the efficiency of Cd is higher
when compared to the flow measurement at the orifice. The
discharge coefficient is raised by increasing the overall pressure
ratio and reducing the convergence semi angle. Also, the range of
Cd is commonly superior in supercritical series.
Express the relation of discharge coefficient.
2/
0
50
100
150
200
250
300
350
400
450
500
5 7 9 11 13 15 17 19 21 23 25
Qrot
Qact
3/ Venturi
0
50
100
150
200
250
300
350
400
450
500
550
600
1.11 1.115 1.12 1.125 1.13 1.135 1.14 1.145 1.15 1.155 1.16 1.165 1.17 1.175 1.18 1.185 1.19 1.195 1.2
Qact
Cd
Orifice
Reference:-
www.piratesbay.com
www.scribd.com
www.merriam-webster.com
0.708
0.71
0.712
0.714
0.716
0.718
0.72
0.722
0.724
0.726
0.728
0.73
225.855 275.855 325.855 375.855 425.855 475.855
Cd
Qact

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exp.9 flow meter demonstration

  • 1. Erbil Polytechnic University Koya Technical Institute Petroleum Technology Operation and Control Report Fluid Mechanic Lab. Test no: (9) Test name: (Flow meter Demonstration) Supervised by: Karwan A. Ali Date of Test: 1/02/2018 Date of Submit:08/02/2018 Prepared by: Muhammed Shwan Ali
  • 2. Title Page number Aim 3 Introduction 3 Apparatus 4 - 6 Procedure 6 - 7 Calculation 8-11 Discussion 12-15 Reference 15
  • 3. Aim of the experiment:- . Compression between different flow meter types. . Determining the discharge coefficient. Introduction:- Fluid mechanics has developed an analytical discipline from the application of the classical laws of static, dynamics and thermodynamics, to situation in which fluids can be treated as continuous media. The particular laws involved are those of conservation of mass; these laws may be simplified in an attempt to describe quantitatively the behavior of the fluids. The hydraulic bench service module, F1- 10, provides the necessary facilities to support a comprehensive range of hydraulic models each of which is designed to demonstrate a particular aspect of hydraulic theory. The specific hydraulic model that is concerned for this experiment is the flow meter test rig (F1- 21). This consists of venture meter, variable area meter, and orifice plate installed in a series of configurations to allow for direct comparisons. OrificeNozzleVenturi
  • 4. Apparatus:- The apparatus is discharged to demonstrate three basics types of flow meter. -Rota meter Rota meter:- A Rota meter with the following characteristics is used to measure flow rate: - Plastic measuring tub
  • 5. - Interchangeable stainless steel float - Max. Flow rate 26 lit/min The flow rate can be read from the upper edge of the conical attachment. Air particles on dirt particles on the float may affect measurement precision. To flush the out. Operate the test stand a maximum flow rate first. To do so, open all cocks fully. Nozzle and Orifice plate: The orifice plate housing is made of transparent plastic allowing visible functioning of the orifice plate. The flow causes a pressure loss between inlet and outlet. Two tapings allow measurement of inlet and outlet pressure. This differential pressure (p1-p2) is proportional to the volume flow rate: Q=Cd A2 √ 2𝑔 (β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2 Venturi meter: The venturi housing is made of transparent plastic allowing visible functioning of the venturi.
  • 6. The pressure in the venturi inversely propositional to the velocity in the venturi according to Bernoulli’s law. Two tapings allow measurement of the inlet pressure and the pressure at the smallest area. This differential pressure (p1-p2) is proportional to the volume flow rate: Q=Cd A2 √ 2𝑔 (β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2 Procedure:- - Arrange the experimentation set-up on the Hydraulic Bench such that the discharge routs the water into the channel. - Makes hose connection between Hydraulic Bench and unit - Connect measurement lines - Open all valves at pipe section and 6-tube manometer, let the water flow for 1 minute - Close flow control valve
  • 7. - Clos drain valve of the 6-tube manometer to vent the measurement lines - Clos flow valve of the 6-tube manometer - Close water inlet - Disconnect measurement lines - Open vent and drain valves to discharge level tubes of the 6-tube manometer - Close vent and drain valves - Open flow control valve slowly - Connect measurement lines again - Open water inlet slowly - Adjust the heights of the water in the manometer tubes with the help of flow control valve until water becomes visible -Set the flow rate and measurement scale with the inlet and outlet control valves -Determine volumetric flow rate. To do so. Use stopwatch to establish time t required for raising the level in the volumetric tank of the Hydraulic Bench.
  • 8. Calculation:- 1/ Volume=25L β†’25000cm3 g=9.81m/s2 β†’981cm/s2 Time=110.69s Qact= π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘‡π‘–π‘šπ‘’ β†’ 25000 110.69 =225.855 cm3 /s *Venturi meter:- A1=5.309cm3 A2=2.011 cm3 g=9.81m/s2 β†’981cm/s2 P= hy h= 𝑝 𝑦 Qmesu=A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu=A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2) Qmesu=2.011 √ 2(981)(32.4βˆ’28.1) (1βˆ’ 2.0112 5.3092 ) =199.58484 Cd Venturi = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 225.855 199.58484 = 1.1316 Orifice:- A1=21.16cm2 A2=3.142cm2 P= hy h= 𝑝 𝑦 Qmesu=A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu=A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2)
  • 9. Qmesu=3.142 √ 2(981)(32βˆ’27) (1βˆ’ 3.1422 21.162 ) =311.5cm3 /s Cd Orifice = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 225.855 311.5 = 0.725056 2/ Volume=25L β†’25000 cm3 ,g=9.81m/s2 β†’981cm/s2 Time=73.45s Qact= π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘‡π‘–π‘šπ‘’ β†’ 25000 73.45 = 340.3675 cm3 /s *Venturi meter:- A1=5.309cm3 A2=2.011 cm3 g=9.81m/s2 β†’981cm/s2 P= hy h= 𝑝 𝑦 Qmesu=A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu=A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2) Qmesu=2.011 √ 2(981)(34.2βˆ’24.9) (1βˆ’ 2.0112 5.3092 ) =293.5181 Cd Venturi = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 340.3675 293.5181 = 1.1584
  • 10. Orifice:- A1=21.16cm2 A2=3.142cm2 Time=73.45s P= hy h= 𝑝 𝑦 Qmesu=A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu=A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2) Qmesu= 3.142 √ 2(981)(33.7βˆ’22.2) (1βˆ’ 3.1422 21.162 ) =476.959cm3 /s Cd Orifice = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 340.3675 476.959 = 0.71362 No.3/ Volume=25L β†’25000 cm3 ,g=9.81m/s2 β†’981cm/s2 Time=51.61s Qact= π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘‡π‘–π‘šπ‘’ β†’ 25000 51.61 = 484.4022 cm3 /s *Venturi meter:- A1=5.309cm3 A2=2.011 cm3 g=9.81m/s2 β†’981cm/s2 P= hy h= 𝑝 𝑦 Qmesu= A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu = A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2)
  • 11. Qmesu=2.011 √ 2(981)(38βˆ’19.8) (1βˆ’ 2.0112 5.3092) = 410.6096 Cd Venturi = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 484.4022 410.6096 = 1.17971 Orifice:- A1=21.16cm2 A2=3.142cm2 Time=51.61s P= hy h= 𝑝 𝑦 Qmesu=A2√ 2𝑔( 𝑝1βˆ’π‘2 𝑦 ) (1βˆ’ 𝐴2 2 𝐴1 2) β†’ Qmesu=A2 √ 2𝑔(β„Ž1βˆ’β„Ž2) (1βˆ’ 𝐴2 2 𝐴1 2) Qmesu=3.142 √ 2(981)(37.2βˆ’14.2) (1βˆ’ 3.1422 21.162) =675.26cm3 Cd Orifice = 𝑄 π‘Žπ‘π‘‘ 𝑄 π‘šπ‘’π‘ π‘’ β†’ 484.4022 675.26 = 0.71735
  • 12. Table of calculation:- Discussion:- 1/ is the ratio of the actual discharge to the ideal discharge, assuming unit coefficients of contraction and velocity, equal to the product of these coefficients. --Coefficient of discharge is stated as the ratio between the actual flow discharge and theoretical flow discharge. It is also referred to as the ratio of mass flow rate at nozzle's discharge edge to the No. Qact )/s3 (cm Rotameter Venture meter Orifice meter Qrot (liter/min) Qact )/s3 (cm Qi )/s3 (cm Cd Qi )/s3 (cm Cd 1 225.855 9.9 165 199.58484 1.1316 311.5 0.725056 2 340.3675 16 266.6667 293.5181 1.1584 476.959 0.71362 3 484.4022 22.2 370 410.6096 1.17971 675.2 0.71735
  • 13. standard nozzle which enlarges an exact working fluid maintained at the similar initial conditions and pressures. It has no dimensions and depends directly on the rate of flow and velocity of working fluid. It is symbolized by Cd and its value is different for each fluid depending on the kind of measurement of flow. In nozzle flow measurement, the efficiency of Cd is higher when compared to the flow measurement at the orifice. The discharge coefficient is raised by increasing the overall pressure ratio and reducing the convergence semi angle. Also, the range of Cd is commonly superior in supercritical series. Express the relation of discharge coefficient. 2/ 0 50 100 150 200 250 300 350 400 450 500 5 7 9 11 13 15 17 19 21 23 25 Qrot Qact
  • 14. 3/ Venturi 0 50 100 150 200 250 300 350 400 450 500 550 600 1.11 1.115 1.12 1.125 1.13 1.135 1.14 1.145 1.15 1.155 1.16 1.165 1.17 1.175 1.18 1.185 1.19 1.195 1.2 Qact Cd