Muhammed Fuad Rashid Petroleum Engineering Department at Koya Universiy Oil and Gas Property Laboratory 2020

1. Aim of the experiment:-
. Compression between different flow meter types.
. Determining the discharge coefficient.
Apparatus:-
The apparatus is discharged to demonstrate three basics
types of flow meter.
-Rota meter
Rota meter
A Rota meter with the following characteristics is used to
measure flow rate:
- Plastic measuring tub
- Interchangeable stainless steel float
- Max. Flow rate 26 lit/min
The flow rate can be read from the upper edge of the conical
attachment.
Air particles on dirt particles on the float may affect
measurement precision.
To flush the out. Operate the test stand a maximum flow rate
first.
To do so, open all cocks fully.

2. Nozzle and Orifice plate:
The orifice plate housing is made of transparent plastic allowing
visible functioning of the orifice plate. The flow causes a
pressure loss between inlet and outlet. Two tapings allow
measurement of inlet and outlet pressure. This differential
pressure (p1-p2) is proportional to the volume flow rate:
Q=Cd A2
√
2𝑔 (ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2
Venturi meter:
The venturi housing is made of transparent plastic allowing
visible functioning of the venturi.
The pressure in the venturi inversely propositional to the
velocity in the venturi according to Bernoulli’s law.
Two tapings allow measurement of the inlet pressure and the
pressure at the smallest area.
This differential pressure (p1-p2) is proportional to the volume
flow rate:
Q=Cd A2
√
2𝑔 (ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2

3. Procedure:-
- Arrange the experimentation set-up on the Hydraulic Bench
such that the discharge routs the water into the channel.
- Makes hose connection between Hydraulic Bench and unit
- Connect measurement lines
- Open all valves at pipe section and 6-tube manometer, let the
water flow for 1 minute
- Close flow control valve
- Clos drain valve of the 6-tube manometer to vent the
measurement lines
- Clos flow valve of the 6-tube manometer
- Close water inlet
- Disconnect measurement lines
- Open vent and drain valves to discharge level tubes of the 6-
tube manometer
- Close vent and drain valves
- Open flow control valve slowly
- Connect measurement lines again
- Open water inlet slowly
- Adjust the heights of the water in the manometer tubes with the
help of flow control valve until water becomes visible
-Set the flow rate and measurement scale with the inlet and
outlet control valves

4. -Determine volumetric flow rate. To do so. Use stopwatch to
establish time t required for raising the level in the volumetric
tank of the Hydraulic Bench.
Calculation:-
Volume=25L →25000 cm3
,g=9.81m/s2
→981cm/s2
Time=110.69s
1/
Qact=
𝑉𝑜𝑙𝑢𝑚𝑒
𝑇𝑖𝑚𝑒
Qact=
25000
110.69
→ Qact = 225.855 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
→981cm/s2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)

5. Qmesu=2.011
√
2(981)(32.4−28.1)
(1−
2.0112
5.3092 )
Qmesu=199.58484
Cd Venturi =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢
Cd Venturi =
225.855
199.58484
→ Cd Venturi = 1.1316
Orifice:-
A1=21.16cm2
A2=3.142mm2
→ 0.03142cm2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)
Qmesu=0.03142
√
2(981)(32−27)
(1−
0.031422
21.162 )
Qmesu=3.112

6. Cd Orifice =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢
Cd Orifice =
225.855
3.112
→ Cd Orifice = 72.5455
2/
Volume=25L →25000 cm3
,g=9.81m/s2
→981cm/s2
Time=73.45s
Qact=
𝑉𝑜𝑙𝑢𝑚𝑒
𝑇𝑖𝑚𝑒
Qact=
25000
73.45
→ Qact = 340.3675 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
→981cm/s2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)
Qmesu=2.011
√
2(981)(34.2−24.9)
(1−
2.0112
5.3092 )

7. Qmesu=293.5181
Cd Venturi =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢
Cd Venturi =
340.3675
293.5181
→ Cd Venturi = 1.1584
Orifice:-
A1=21.16cm2
A2=3.142mm2
→ 0.03142cm2
Time=73.45s
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)
Qmesu=0.03142
√
2(981)(33.7−22.2)
(1−
0.031422
21.162 )
Qmesu=4.71959
Cd Orifice =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢

8. Cd Orifice =
340.3675
4.71959
→ Cd Orifice = 72.11804
3/
Volume=25L →25000 cm3
,g=9.81m/s2
→981cm/s2
Time=51.61s
Qact=
𝑉𝑜𝑙𝑢𝑚𝑒
𝑇𝑖𝑚𝑒
Qact=
25000
51.61
→ Qact = 484.4022 cm3
/s
*Venturi meter:-
A1=5.309cm3
A2=2.011 cm3
g=9.81m/s2
→981cm/s2
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)
Qmesu=2.011
√
2(981)(38−19.8)
(1−
2.0112
5.3092 )
Qmesu=410.6096

9. Cd Venturi =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢
Cd Venturi =
484.4022
410.6096
→ Cd Venturi = 1.17971
Orifice:-
A1=21.16cm2
A2=3.142mm2
→ 0.03142cm2
Time=51.61s
P= hy h=
𝑝
𝑦
Qmesu=A2√
2𝑔(
𝑝1−𝑝2
𝑦
)
(1−
𝐴2
2
𝐴1
2)
→ Qmesu=A2
√
2𝑔(ℎ1−ℎ2)
(1−
𝐴2
2
𝐴1
2)
Qmesu=0.03142
√
2(981)(37.2−14.2)
(1−
0.031422
21.162 )
Qmesu=6.67452
Cd Orifice =
𝑄 𝑎𝑐𝑡
𝑄 𝑚𝑒𝑠𝑢
Cd Orifice =
484.4022
6.67452
→ Cd Orifice = 72.57483