5. 1. Rational numbers should be in the form
π
π
β
π
π
.
β Change whole numbers to rational numbers;
β Change mixed fractions to improper fractions
2. Multiply. If possible use cancellations.
β Multiply with ;
β Multiply with
3. Simplify. Reduce answers to if possible.
6. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 1:
1
3
β
2
3
=
2
9
1(2)
3(3)
Rational numbers
should be in the
form
π
π
β
π
π
.
Multiply.
If possible use
cancellations.
Simplify.
Reduce answers to
if
possible.
7. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 1:
1
3
β
2
3
=
2
9
1(2)
3(3)
Rational numbers
should be in the
form
π
π
β
π
π
.
Multiply.
If possible use
cancellations.
Simplify.
Reduce answers to
if
possible.
8. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 2:
4
5
β
11
7
=
44
35
4(11)
5(7)
Rational numbers
should be in the
form
π
π
β
π
π
.
Multiply.
If possible use
cancellations.
Simplify.
Reduce answers to
if
possible.
9. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 2:
4
5
β
11
7
=
44
35
= 1
9
35
Since the end
result is an
.
For a best answer.
Change to
.
10. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
Rational numbers
should be in the
form
π
π
β
π
π
.
11. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
Rational numbers
should be in the
form
π
π
β
π
π
.
5 β
6
5
=
5
1
β
6
5
Multiply.
If possible use
cancellations.
12. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
Multiply.
If possible use
cancellations.
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
13. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
Multiply.
If possible use
cancellations.
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
1(6)
14. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
Multiply.
If possible use
cancellations.
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
1(1)
15. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
Simplify.
Reduce answers to
if
possible.
= β6
16. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
What if we did
not use
cancellations?
17. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
5 β
6
5
=
5
1
β
6
5
Rational numbers
should be in the
form
π
π
β
π
π
.
18. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
5 β
6
5
=
5
1
β
6
5
Multiply.
If possible use
cancellations.
5(6)
= β
30
5
19. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
5 β
6
5
=
5
1
β
6
5
Multiply.
If possible use
cancellations.
1(5)
= β
30
5
20. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
5 β
6
5
=
5
1
β
6
5
= β
30
5
Simplify.
Reduce answers to
if
possible.
= β6
21. 1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 3:
5 β
6
5
=
5
1
β
6
5
=
1
1
β
6
1
1
1
= β
6
1
= β6
5 β
6
5
=
5
1
β
6
5
= β
30
5
= β6
22. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
23. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
24. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
Changing mixed fraction to
improper fraction.
Multiply the denominator
and whole number
1
2
3
=
5
3
3
3 1
25. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
Changing mixed fraction to
improper fraction.
Add up the product to the
numerator. The result will be the
new numerator.
1
2
3
=
5
3
3
3 + 2
26. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
Changing mixed fraction to
improper fraction.
Copy the denominator
1
2
3
=
5
3
27. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Rational numbers should
be in the form
π
π
β
π
π
.
-change whole numbers to
rational numbers;
-change mixed fractions to
improper fractions
Changing mixed fraction to
improper fraction.
Copy the denominator
1
2
3
=
5
3
28. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Multiply.
If possible use
cancellations.
29. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Multiply.
If possible use
cancellations.
4
1
30. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Multiply.
If possible use
cancellations.
4
1
=
4
1
5
1
31. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Multiply.
If possible use
cancellations.
4
1
=
4
1
5
1
= 20
4(5)
32. =
12
1
5
3
1. Rational numbers should be in the form
π
π
β
π
π
. 2. Multiply. If possible use cancellations.
- Change whole numbers to rational numbers; - Multiply with ;
- Change mixed fractions to improper fractions - Multiply with
3. Simplify. Reduce answers to if possible.
Example 4:
12 1
2
3
Multiply.
If possible use
cancellations.
4
1
=
4
1
5
1
= 20
4(5)
50. 1. 2 Γ· β
7
9
2. β
17
2
Γ· β
21
35
3.
26
36
Γ· 1
2
3
4. 4
2
5
Γ· β
2
3
5.
3
14
Γ· 12
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
52. 1. 2 Γ· β
7
9
2. β
17
2
Γ· β
21
35
3.
26
36
Γ· 3
2
5
4. 4
2
5
Γ· β
2
3
5.
3
14
Γ· 12
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
Reciprocal of the divisor:
β
9
7
β
35
21
5
17
β
3
2
1
12
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
54. Then proceed just like your
.
π
π
Γ·
π
π
π
π
β
π
π
When dividing rational numbers, multiply the by the
.
55. πβππππ π‘π ππ’ππ‘πππππππ‘πππ
When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 1:
1
5
Γ·
2
3
Change to
.
Get the
=
1
5
β
3
2
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
πΊππ‘ π‘βπ ππππππππππ ππ π‘βπ πππ£ππ ππ.
πππ£ππ πππππ£πππππ
56. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 1:
1
5
Γ·
2
3
Multiply.
If possible use
cancellations.
=
1
5
β
3
2
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
3
10
1(3)
5(3)
57. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 1:
1
5
Γ·
2
3
=
1
5
β
3
2
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
Simplify.
Reduce answers to
if
possible.
=
3
10
58. πβππππ π‘π ππ’ππ‘πππππππ‘πππ
When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
Change to
.
Get the
=
3
1
β
7
3
πππ£ππ πππππ£πππππ
πΊππ‘ π‘βπ ππππππππππ ππ π‘βπ πππ£ππ ππ.
59. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
Multiply.
If possible use
cancellations.
60. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
Multiply.
If possible use
cancellations.
1
1
=
1
1
β
7
1
61. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
Multiply.
If possible use
cancellations.
1
1
=
1
1
β
7
1
= β
7
1
1(7)
62. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
Multiply.
If possible use
cancellations.
1
1
=
1
1
β
7
1
= β
7
1
1(1)
63. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
Multiply.
If possible use
cancellations.
1
1
=
1
1
β
7
1
= β
7
1
64. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
1
1
=
1
1
β
7
1
= β
7
1
Simplify.
Reduce answers to
if
possible.
= β7
65. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 2:
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
3 Γ· β
3
7
=
3
1
β
7
3
1
1
=
1
1
β
7
1
= β
7
1
Simplify.
Reduce answers to
if
possible.
= β7
66. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Since we have
, changed
first to
.
67. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Since we have
, changed
first to
.
68. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Since we have
, changed
first to
.
69. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Change to
.
Get the
=
35
16
β
4
5
70. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Change to
.
Get the
=
35
16
β
4
5
πβππππ π‘π ππ’ππ‘πππππππ‘πππ
71. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Change to
.
Get the
=
35
16
β
4
5
πΊππ‘ π‘βπ ππππππππππ ππ π‘βπ πππ£ππ ππ.
72. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
73. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
7
1
74. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
7
1
75. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
7
14
1
76. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
7
14
1
=
7
4
7(1)
77. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
Multiply.
If possible use
cancellations.
=
35
16
β
4
5
7
14
1
=
7
4
4(1)
78. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
=
35
16
β
4
5
7
14
1
=
7
4
Simplify.
Reduce answers to
if
possible.
= 1
3
4
Since we got an
,
change it to
for a
.
79. When , multiply the by the
.
π
π
Γ·
π
π
π
π
β
π
π
Then proceed just like your .
Example 3:
2
3
16
Γ· 1
1
4
by which a given
number must be to get
a result of .
11
2
β
2
11
= 1
=
35
16
Γ·
5
4
=
35
16
β
4
5
7
14
1
=
7
4
= 1
3
4