3. Range:
• The Range is the difference between the highest and smallest values
in a set of observations.
Range: Large value in the series of data − Smallest value in the series data.
R= L −S
• Example:
141, 112, 125, 100, 115, 122, 150,
Arrange the data in ascending order: 100,112, 115,122,125,141,150.
Highest value: 150
Smallest value: 100
Range: 150-100= 50
4. Example: Calculate range for the following ungrouped data:
• 100, 112, 125, 135, 150, 152, 150, 155, 160, 130,128, 138,
133, 143, 147, 151, 154, 156, 112, 116.
5. Range of Grouped data in continuous series:
• Range= H −L
• H= Upper limit of the highest class.
• L= Lower limit of the lowest class.
Class interval Frequency
10-20 48
21-30 62
31-40 4
41-50 58
51- 60 69
Range= 60-10= 50
RANGE= 50
6. Calculate Range for following data:?
• Range= H −L
• H= Upper limit of the highest class.
• L= Lower limit of the lowest class.
Class interval Frequency
40-50 52
51-60 2
61-70 2
71-80 2
81-90 2
8. Coefficient of Range:
• The measure of the distribution based on range is the
coefficient of range also known as range coefficient of
dispersion.
• Coefficient of range is the relative measure corresponding to
range.
• Coefficient range=
• H= Highest value,
• L= Lowest value,
9. Coefficient of Range for the following data:
• 100,50,30,20,70,40,10,70
• Coefficient of Range:
= 100-10/100+10
= 90/110
= 0.81
= 81%
10. Calculate Range and coefficient range for the following data:
Example:
48, 60, 50, 36, 69, 51, 51, 38, 40, 41, 46, 45, 53, 41, 46, 45, 60.
11. Uses of Range
• Range observations is important in analysing the variations in
the quality of products, like medicines, antibiotics, tonics etc.
• Range is useful measure in the study of fluctuations in
maximum and minimum temperature and humidity are used
for weather forecast.
13. Mean deviation:
• Mean deviation: can be defined as the mean of all the
deviations in a given set of data obtained from an average.
• Formula for ungrouped data:
Mean deviation (MD):
Σ|X −X̅|
𝑵
X= Variable or Value of the observation
X̅: Arithmetic mean or mean or Average
N: Total number of observations
X-X̅ (d): Deviation
16. Mean deviation for grouped data (Continuous series)
• Mean Deviation (MD )= ∑fd / ∑f
• ∑fd = Sum of multiplication of each frequency and deviation
form mean.
• ∑f= Sum of all the frequency.
19. Example:1
Class
interval
Mid value
(m) or X
Frequency (f) ∑f.m Deviation (d)=
m-X
̅ or X-X
̅
Frequency
deviation fX-X
̅
(fd)
10-20 15 20 300 15-33.7= -18.7 18.7×20= 374
20-30 25 10 250 25-33.7=-8.7 8.7×10=87.8
30-40 35 6 210 35-33.7=1.3 1.3×6=7.8
40-50 45 12 540 45-33.7=11.3 11.3×12=135.6
50-60 55 15 825 55-33.7=21.3 21.3×15=319.5
∑f= 63 ∑f.m= 2125 ∑f.d= 924.7
Mean Deviation (MD )= ∑fd / ∑f
= 924.7/63
= 14.6
20. Example:2: Find mean deviation for the following data:
Age HBV patients
0-5 8
5-10 5
10-15 6
15-20 2
20-25 10
21. Uses of mean deviation:
• Mean deviation used in medicine, microbiology,
pharmacology, social sciences and in business etc.
• Mean deviation is good for sample studies where
detailed study is not required.
23. • A relative measure of dispersion based on the mean
deviation is called the coefficient of the mean deviation or the
coefficient of dispersion.
• The coefficient of mean deviation is calculated by dividing
mean deviation by the average (Mean).
Coefficient of M.D =
Mean Deviation
Mean
Coefficient of the mean deviation:
24. Calculate coefficient of mean deviation for the following grouped
data:
Age 3-4 4-5 5-6 6-7 7-8 8-9 9-10
Diabetes
PATIENTS
3 7 22 60 85 32 8
Mean Deviation (MD )= ∑fd / ∑f
Mean (X
̅ )= ∑fm / ∑f
Coefficient of M.D =
Mean Deviation
Mean
25. Class
interv
al
Middle
value
(m or
X)
Freque
ncy (f)
fm Deviation (d)=
m-X
̅
(Step: 2)
Frequency
deviation (fd)
(Step: 3)
3-4 3.5 3 10.5 3.5-7.09= 3.59 3×3.59=10.77
4-5 4.5 7 31.5 4.5-7.09=2.59 4.5×2.59=18.13
5-6 5.5 22 121. 1.59 34.98
6-7 6.5 60 390 0.59 35.40
7-8 7.5 85 637.5 0.41 34.85
8-9 8.5 32 272. 1.41 45.12
9-10 9.5 8 76 2.41 19.28
∑f=217 ∑fm=1538.5 ∑fd=198.53
Step:1
Mean (X
̅ )= ∑fm / ∑f
= 1538.5/217
Mean X
̅ = 7.09
Step:4
Mean Deviation (MD )= ∑fd / ∑f
= 198.53/217
= 0.915
Step:5
C.E of M.D =
Mean Deviation
Mean
= 0.915/7.09
= 0.129
26. Exercise: 1 Calculate coefficient of mean deviation for the
following data:
Age 1-10 10-20 20-30 30-40 40-50 50-60 60-70
Cancer
patients
4 10 6 15 20 50 5
Mean Deviation (MD )= ∑fd / ∑f
Mean (X
̅ )= ∑fx / ∑f
Coefficient of M.D =
Mean Deviation
Mean