Discuss and define Isotropy. Anisotropy and Orthotropy with regards t.pdf

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Discuss and define Isotropy. Anisotropy and Orthotropy with regards to engineering materials. Regarding Finite Element Analysis: List the three main types of elements and explain how to choose elements? Common sources of errors in FEA? After conducting a photoelastic investigation of a sample, you remove the load and notice that a fringe pattern still exists. What could this mean? Solution (i) Isotropy is the property of the material in which the physical properties of a substance are independent of the direction of measurement. Glass and metals are examples of isotropic materials. Anisotropy is the property of the material in which the physical properties of a substance varies with the change in direction. Wood and Composites are examples of anisotropic materials. Orthotropy is the property of the material in which the physical properties of a substance change when measured from different directions. The properties differ along three mutually orthogonal twofold axes of rotational symmetry. Wood is an example of orthotropic materials. (ii) (a )The three main elements in FEA are -.

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please send edited code of RCBug.java RCBUG.java import java.util.Random; public class RCBug { private EZImage bugPicture; // Member variable to store bug picture private int x, y, startx, starty; // Member variables to store x, y, startx, starty private int destx, desty; // Member variables to store destination values private long starttime; // Member variable to store the start time private long duration; // Member variable to store the duration private boolean interpolation; // Member variable that is set to true if it is in the interpolation state //1) add the private static final variables here // Constructor for RCBug takes 3 parameters public RCBug(String filename,int posx, int posy){ // Set the current position of the bug x=posx;y=posy; // Create the image of the bug bugPicture = EZ.addImage(filename, posx, posy); // Move it to the starting position. This is actually redundant. bugPicture.translateTo(x,y); // Set interpolation mode to false initially interpolation = false; } // Set the destination by giving it 3 variables // Dur means duration and is measured in seconds public void setDestination(int posx, int posy, long dur){ // Set destination position and duration // Convert seconds to miliseconds destx = posx; desty = posy; duration = dur*1000; // Get the startting time (i.e. time according to your computer) starttime = System.currentTimeMillis(); // Set the starting position of your bug startx=x; starty=y; // Set interolation mode to true interpolation = true; } // If you?re in interpolation state then return true, else false. public boolean moving() { return interpolation; } // This moves the bug based on the current time and elapsed time according to the interpolation equation public void go(){ // If interpolation mode is true then do interpolation if (interpolation == true) { // Normalize the time (i.e. make it a number from 0 to 1) float normTime = (float) (System.currentTimeMillis() - starttime)/ (float) duration; // Calculate the interpolated position of the bug x = (int) (startx + ((float) (destx - startx) * normTime)); y = (int) (starty + ((float) (desty - starty) * normTime)); // If the difference between current time and start time has exceeded the duration // then the animation/interpolation is over. if ((System.currentTimeMillis() - starttime) >= duration) { // Set interpolation to false interpolation = false; // Move the bug all the way to the destination x = destx; y = desty; } //2)add a random amount to the x and y coordinates // Don?t forget to move the image itself. bugPicture.translateTo(x,y); } } } RCBugMain.java import java.awt.Color; import java.io.InputStreamReader; import java.util.Scanner; public class RCBugMain { public static void main(String[] args) { // Setup EZ graphics system. EZ.initialize(512, 512); // Set background color to dark green EZ.setBackgroundColor(new Color(0, 100, 0)); // Make an InputStreamReader object which reads from the keyboard. // Make a Scanner object that uses the InputStreamRe.

please send edited code of RCBug.javaRCBUG.javaimport java.util..pdf

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On January 1, 2002, Germany officially adopted the euro as its currency, and deutsche mark stopped being legal tender. According to the Article in the Wall Street Journal, even 10 years later many stores in Germany continued to accept it. Briefly explain how possible for people to continue to use a currency when government replaced it with another currency. Source: Who needs the euro When You Can Pay with Deutsche Marks? Wall Street Journal July, 2012 Solution The most important function of money is that it is used as medium of exchange. In other words, it can be used for payment of goods and services. Money is able to act as medium of exchange because it possesses the quality of general acceptability. Anything that is generally acceptable can act as money and thus can be used as medium of exchange. Quality of general acceptability is the key and not the government undertaking. Many people across Germany are still accepting deutsche mark as medium of exchange and due to this general acceptability it is still being used as medium of exchange even though German government has discontinued deutsche mark and adopted the Euro. Adoption of a currency by government makes it legal tender in the country concerned but it does not guarantee that it will be used as medium of exchange unless and until it is generally acceptable. Thus, it is possible for people to continue using a currency when government replaced it with another currency if the currency being used by the people is still generally acceptable as medium of exchange. This quality of currency keeps it in circulation and prolongs its usage even though government has dumped it..

On January 1, 2002, Germany officially adopted the euro as its curre.pdf

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Networking problem help Consider the following TCP session between hosts A and host B on a perfect channel: A has a file of size 2.5MSS to send to B. A desires to send segments of alternating sizes MSS and MSS/2 (sequence number = 0 for the first segment of size MSS). B also has a file of size 2.5MSS to send to A. B desires to send segments of alternating sizes MSS/2 and MSS (sequence number = 0 for the first segment of size MSS/2). A sends first.Note, A and B don’t have to fully fill up their “desired” segment size if there is no sufficient bytes to send, especially at the end of their conversation, where it is even possible for them to send a segment whose data size is equal to 0. Draw all the segment exchanges until the Both A and B think they don’t have any more bytes to send and there is no byte to acknowledge. For each segment, clearly mark the sequence number, the ACK number, and the size of data it carries. If the data size is equal to 0 in a segment, the sequence number field is irrelevant. You may just mark N/A. Solution Source port: 16 Bit number which identifies the Source Port number (Sending Computer\'s TCP Port). Destination port: 16 Bit number which identifies the Destination Port number (Receiving Port). Sequence number: 32 Bit number used for byte level numbering of TCP segments. If you are using TCP, each byte of data is assigned a sequence number. If SYN flag is set (during the initial three way handshake connection initiation), then this is the initial sequence number. The sequence number of the actual first data byte will then be this sequence number plus 1. For example, let the first byte of data by a device in a particular TCP header will have its sequence number in this field 50000. If this packet has 500 bytes of data in it, then the next packet sent by this device will have the sequence number of 50000 + 500 + 1 = 50501. Acknowledgment Number: 32 Bit number field which indicates the next sequence number that the sending device is expecting from the other device. Header Length: 4 Bit field which shows the number of 32 Bit words in the header. Also known as the Data Offset field. The minimum size header is 5 words (binary pattern is 0101). Reserved: Always set to 0 (Size 6 bits). Control Bit Flags: We have seen before that TCP is a Connection Oriented Protocol. The meaning of Connection Oriented Protocol is that, before any data can be transmitted, a reliable connection must be obtained and acknowledged. Control Bits govern the entire process of connection establishment, data transmissions and connection termination. The control bits are listed as follows: They are: URG: Urgent Pointer. ACK: Acknowledgement. PSH: This flag means Push function. Using this flag, TCP allows a sending application to specify that the data must be pushed immediately. When an application requests the TCP to push data, the TCP should send the data that has accumulated without waiting to fill the segment. RST: Reset the connection. The RST bit.

Networking problem help Consider the following TCP session between h.pdf

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Lipid bilayers can only be synthesized by biological organisms. This is supported by the rise of internal compartmentalization seen in eukaryotic organisms. It is thought that the formation of internal organelles in eukaryotic cells resulted from the invagination of the external cell membrane in prokaryotic cells True False Abiogenesis is the hypothesis that life exists throughout the universe, distributed by meteorites, planetoids and asteroids. The theory of abiogenesis proposes that life in this planet arouse from extremophile bacteria that came from outer space trapped in interstellar debris. True False The basic elements that are the building blocks of life in this planet are only found in living organisms; hence, these are only of biological origin. This contradicts the theory of abiogenesis. True False Solution 30) False. In abiogensis, life arose from non living matter like organic compounds. It didnot arise from extremophile bacteria. The panspermia hypothesis is an alternatively theory which suggests life on earth arose from the microscopic life from meteoroids, asteroids and other small Solar System bodies entered the earth. 31) False. Lipid bilayers are liposomes can be made in vitro.

Lipid bilayers can only be synthesized by biological organisms. This .pdf

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Is a neutral trait (meaning it is neither deleterious nor advantageous to the survival and reproduction of the organism) likely to be eliminated from a population by adaptive evolution? (such as the presence of pelvic bones in snakes, which are legless) Why or why not? Solution There are four major methods by which evolution happens: mutation, migration, drift, and selection Mutation brings about changes or variations in the populaton. Migration increases or decreases the number of the population. Drift: when the individuals do not reproduce or they die, there could be disappearance of genes which changes the frequency of occurrence of some genotypes in a population. Selection occurs when the superior, better traits are selected to move forward in the generations. When we consider evolution of neutral traits, we cover all the first three : Mutation, migration and drift. These neutral traits generally stay in the population for a long time. They may disappear eventually but its longevity is uncertain. It also could be that the genes responsible for the neutral trait do not come under direct selection or it could also be the result of plieotropy where one gene is responsible for many traits..

Is a neutral trait (meaning it is neither deleterious nor advantageo.pdf

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Let T : R^n rightarrow R^m be a linear transformation. Given a subspace Z of R^m, let 5 {v elementof R^n | T(v) elementof Z). Show that S is a subspace of R^n. Solution Let v,w in S Then T(v) and T(w) belongs to Z Consider av+bw , a,b are scalars We need to see if av+bw are in S For this consider T(av+bw) = aT(v)+bT(w) (because T is linear transformtaion) Now T(v) and T(w) are in Z And so aT(v) and bT(w) are in Z This => aT(v)+bT(w) are in Z Hence we get that T(av+bw) is in Z So we get av+bw is in S Hence S is subspace of Rn.

Let T R^n rightarrow R^m be a linear transformation. Given a subspa.pdf

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Just a general question on some vocab words I cannot piece together myself. Can you provide me with some relevance to some terms used in my biology class literature that I do not understand. Oxidized/oxidation. I understand what these are, but I do not understand their relevance... When you oxidize a compound like ammonia NH3 to NO3...what is the point? does it make energy... is it like an enzyme.. like what does that mean? electron donor/acceptor....why does this matter which is which....? what is the purpose of this besides donating and excepting electrons....? NAD, NADPH... okay I know what these are composed of but what are they exactly and what is their purpose...? some of my definitions say things like \"use CO2\" as main carbon source\" ???? okay.. but what does carbon have to do with anything... how is that energy or food or whatever? Solution 1. ANS: Oxidation: Oxidation is defined as the loss of electrons, hydrogen’s or gain of oxygen atom. If the oxidation taken placed in a cell, then it is called as oxidized. Both the Oxidized/oxidation are same, but the using situation is different. Reduction: Reduction is defined as gain of electrons, hydrogen’s or loss of oxygen atom. Depends upon reaction the redox (oxidation or reduction) will change, sometimes it explains about electrons or in another time it states about oxygen but the sole of the meaning will never change. Ex: Oxidation and Reduction in terms of oxygen transfer Oxidation and Reduction in terms of electrons transfer Oxidation and Reduction in terms of hydrogen transfer 2. ANS: Nitrogen oxidation: It is a process of biological oxidation, in which the anaerobic ammonia (NH4+) and nitrite (NO2-) converts into nitrogen gas (N2). Ammonia is converted into nitrite (NO2-) due to the effect of nitrosomonas bacteria. Nitrite (NO2-) then is converted into nitrate (NO3-) by the influence of nitrobacter bacteria. In this reaction ATP is not released, so the energy is not produced. 3. ANS: Electron donor/acceptor: Electron acceptor: It accept ions that act as oxidizing agents in chemical reactions. Electron donor: It donates electrons, these are reducing agents. The main purpose of this donating and accepting electrons to stabilizes chemical reactions. In biological point of view a series of electron transfer can produce ATP molecules. ATP act like a universal currency. ATP is produced by photon gradient, which is created by ETC in mitochondria. 4. ANS: NAD and NADPH: NAD is a primary oxidizing agents of cell and the NADPH is a primary reducing agents of cell. NAD in oxidation reactions, it accepts two electrons and one photon from the substrate. In reduced form NADPH acts as the primary reducing agent of cell, it donates two electrons and one photon to the medium. 5. ANS: In the photosynthesis reactions plants make glucose by incorporating CO2 and water. The glucose molecule later oxidized in organisms and produced energy in the form of ATP. Foods are mostly composed with carbohydrates.

Just a general question on some vocab words I cannot piece together .pdf

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In order to be useful to managers, management accounting reports should possess all of the following cs EXCEPT a, be prepared to report information for any unit of the business to support decision making. b. be ed at any time management needs information d. provide objective measures of past operations and subjective estimates about future decisions Solution The correct choice is b Explanation : - Management accounting is not required to adhere to generally accepted accounting principle because it provides managerial information for internal purposes i.e. it is used by the members within the organization and not used by members outside the organizations such as regulators, creditors etc..

In order to be useful to managers, management accounting reports shou.pdf

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Im also confused on question 9 and 10 On which point(s) would Charles Darwin and Georges Button have likely agreed Select one: the idea that all of life shared a common ancestor the idea that species change over time both are correct neither is correct On which point(s) would Charles Darwin and Georges Button have likely disagreed: Select one: the idea that the earth was formed according to the laws of physics the idea that all life shares a common ancestor the idea that species change over time they would have agreed on all of these points Which of the following ideas was NOT accepted by Jean-Batiste Lamarck? Select one: bacteria represent some of the youngest species on earth life arises spontaneously organisms go extinct none of the above Solution Answer c : Both are correct Answer d: Earth is quite old both agree, common ancestor in species tree Answer c:Lamarck did not believe that species could become extinct.

Im also confused on question 9 and 10 On which point(s) would Charle.pdf

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In about six billion years, our sun\'s luminosity (a.k.a. power output) will be 2000 times more than it is now. At this stage, our sun will be considered a \"red giant\" star. The surface temperature of a red giant is only about two thirds of our sun\'s current temperature. Between what two famous celestials objects will be the location of our sun\'s surface in six billion years? Solution Luminosity,L = k*R^2 * T^4 so, L2/L1 = [R2/R1]^2 * [T2/T1]^4 2000 = [R2/R1]^2 * 0.1975 R2 = 100.62 * R1 = 100.62 * 6.96*10^8 = 7.003 * 10 ^10m Radius of orbit of mercury = 4.6*10^10 m - 7 * 10 ^ 7m Radius of orbit of venus = 1.08*10^11 m Hence sun\'s surface will be between venus amd mercury.

In about six billion years, our suns luminosity (a.k.a. power outpu.pdf

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I have to write a java program . So basically I have to take my input in only cms. Inches is also accepted but the inches should be converted into the cms before the program take in the input . So when the program takes the input , the input must be in cm . I have to write a java program . So basically I have to take my input in only cms. Inches is also accepted but the inches should be converted into the cms before the program take in the input . So when the program takes the input , the input must be in cm . Solution import java.io.*; import java.util.*; class InchesToCms{ public static void main (String[] args)throws Exception{ //1 Inches = 2.54 Centimeters; BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));//to get input creating bf is an object. System.out.print(\"Enter the inches: \");//asking the input is inches float inches = Float.parseFloat(bf.readLine());//geting input first in string,so convert into float using parseFloat function. float cms = inches * 2.54f;//multiplying given input inches and 2.54. System.out.println(inches + \" inches is \" + cms + \" centimeter(s).\");//display the inches and centimeters. System.out.print(\"Enter the Centimeters: \");//asking the input is Centimeters. float CMS = Float.parseFloat(bf.readLine()); System.out.println(\"You entered \" +CMS+ \" centimeter(s).\");//display out put in Centimeters only. } } /* Output: 1) Enter the inches: 11.0 11.0 inches is 27.939999 centimeter(s). Enter the Centimeters: 2.0 You entered 2.0 centimeter(s). Explanatin: This program 1) It takes input in inches and convert into centimeters 2) and Next It takes input in centimters and display the out in the same centimeters. */.

I have to write a java program . So basically I have to take my in.pdf

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Fill in the blanks. Intensity of orange/brown/red color of reduced DNS is ____________ related to the amount of _______________ in solution. Solution Intensity of orange/brown/red color of reduced DNS is proportionally related to the amount of maltose in solution. DNS is used to study the enzymatic activity of amylase, which breaks starch into maltose. Higher amylase activity produces more amount of maltose, which reduces 3, 5-dinitrosalicylic acid (DNS), which is yellow in color, to 3-amino, 5-nitrosalicylic acid (commonly termed \"reduced DNS\"), which may be orange, brown or red depending on the concentration of maltose..

Fill in the blanks.Intensity of orangebrownred color of reduced .pdf

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Explain how cellular respiration (O2 consumption and CO2 production) is linked to ATP production. Is the coupling of these two processes perfect? Why or why not? Solution The primary function of cellular respiration is to generate ATP, which traps some of the chemical energy of food molecules in its high- energy bonds (adenosine triphosphate). The process of generation of ATP is via glycolysis and Krebs’s cycle finally through oxidative phosphorylation. The overall balanced reaction of cellular respiration is: CHO + 6O 6CO + 6HO + ATP Glucose + oxygen carbon dioxide + water + energy In this reaction, glucose oxidized and oxygen reduced. Cellular respiration (O2 consumption and CO2 production) is linked to ATP production because it is different from cellular respiration as it involves metabolic activities using molecular oxygen such as Citric acid cycle and electron transport to synthesize energy in the form of ATP to perform respiration. CO2 is the output of the cellular respiration from mitochondria and expelled out of the body by carrying through hemoglobin in the form of carboxy- hemoglobin to the alveoli of lungs. The coupling of these two processes such as O2 consumption and CO2 production inked to ATP production is perfect. Mitochondrial chemiosmosis –cellular respiration (through Fernadez Moran inner mitochondrial oxysomes particles) during cellular respiration obtain energy from chemical enzymatic breakdown of the organic food molecules (glucose, pyruvate, acetylcoA) to produce ATP in the presence of O2 consumption. During electron transport, the final electron acceptor is oxygen for oxidative phosphorylation via energy producing molecules such as NADH (3 ATP), FADH2 (2ATP) and ATP. Therefore, it is going to \"oxygen\" that accepting electrons at the end of the electron transport chain to generate ATP via mitochondrial respiratory complex- I to V. Every 3 protons used to produce one ATP molecule. Inner membrane possess small protein channels known as porins in mitochondria & these channels promote the movement of any small molecules such as ATP through them However, the coupling is perfect between the O2 consumption and CO2 production for ATP production but whole-organism oxygen consumption is mainly related to rate of substrate oxidation & it cannot be accurate measurement for ATP production due to variable P/O ratio occurs..

Explain how cellular respiration (O2 consumption and CO2 production).pdf

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Entrepreneurship is A. one of the basic rights of the private enterprise system. B. the willingness to take risks. C. required for capital expansion. D. not found in the private enterprise system. Solution B. the willingness to take risks. entrepenuership is the willingness to take risk. even if u have money and idea of business, but u don\'t have willpower to invest in that idea and take risk than u can\'t be entrepreneure. so risk taker can only become entrepenure than only he can set up a business by using his own or borrowed capital..

Entrepreneurship isA. one of the basic rights of the private enter.pdf

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Discrete Random Variables we are working with commonly used discrete and continuous distribution In a hospital there are 16 patients, 4 of whom have AIDS. A doctor is assigned to 6 of these patients at random. What is the probability that he gets 2 of the AIDS patients? Solution There are 16C6 ways to choose any 6 patients. There are 4C2 ways to get 2 with AIDS, and 12C4 to choose 4 without. Thus, P = [(12C4)(4C2)]/(16C6) = 0.370879121 [ANSWER].

Discrete Random Variables we are working with commonly used discre.pdf

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Determine the open intervals over which the function is increasing an.pdf

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Consider the circuits in figure 2.32. If we assume the transistors are well described by the Schockley model and their respective S and B terminals are tied together, the two circuits are equivalent (i.e. I_dsi=I_ds2). If the body effect is considered, will I_Ds2 be equal to, greater than, or less than I_dsi? Consider only body effect: assume velocity saturation and mobility degradation effects are negligible. Explain. Solution As source(S) and Substrate terminals are tied together, hence VSB= potential difference between S and B=0. Hence is no body effect. Hence Id1= Id2..

Consider the circuits in figure 2.32. If we assume the transistors ar.pdf

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Can you please debug this? Thank you in advance! This program is supposed to use stacks and find the paths of an airplane. It should tell you whether or not the plane goes from the requested city to the requested destination. requestFile.txt contains the requests, flightFile.txt contains the flights and cityFile.txt contains the city\'s that the airline serves. My errors: my output is simply \"Hpair does not serve Los Angeles.\" Thats it and it stops. It should look something like (these are not real values of the file just an example): \"Request is to fly from cityA to CityB. Hpair flight from cityA to CityB. Request is to fly from cityC to cityD. Sorry, HPAir does not serve City D Request is to fly from cityE to CityF Sorry, HPAir does not fly from cityE to CityF\" **It said to use ispath.cpp but I got confused on how to implement it completely.\" isPath.cpp //***I did not include ispath.cpp in my program. Parts of it are in the map.h portion. main.cpp #include #include #include \"Map.h\" using namespace std; int main() { Map aMap; aMap.readFlights(); aMap.verifyRequestedFile(); } StackInterface.h #ifndef StackInterface_h #define StackInterface_h template class StackInterface { /** Checks if the stack is empty. @return True if the stack is empty or false if the stack is not.*/ virtual bool isEmpty() const = 0; /** Adds a new item to the stack @post newEntry is at the top of the stack @param newEntry is the object to be added to the stack @return True if successfully added, otherwise false. */ virtual bool push(const ItemType& newEntry) = 0; /** Removes item from stack @post The top item in the stack is removed @return True if the item was removed, false if it was not. */ virtual bool pop() = 0; /** Returns the top item in the stack @pre The stack is not empty @post The top item in the stack is returned @return The top of the stack */ virtual ItemType peek() const = 0; }; #endif /* StackInterface_h */ Node.h #ifndef node_h #define node_h template class Node { public: Node(); Node (const ItemType &anItem); Node(const ItemType &anItem, Node * nextNodePtr); void setItem(const ItemType &anItem); void setNext(Node * nextNodePtr); ItemType getItem() const; Node* getNext() const; private: ItemType item; Node* next; }; template Node::Node():next(nullptr){} template Node::Node(const ItemType &anItem):item(anItem), next(nullptr){} template Node::Node(const ItemType &anItem, Node * nextNodePtr):item(anItem), next(nextNodePtr) { } template void Node::setItem(const ItemType &anItem){ item = anItem; } template void Node::setNext(Node * nextNodePtr) { next = nextNodePtr; } template ItemType Node::getItem() const { return item; } template Node* Node::getNext()const{ return next; } #endif /* node_h */ LinkedStack.h #include #ifndef LinkedStack_h #define LinkedStack_h #include \"Node.h\" #include \"StackInterface.h\" template class LinkedStack:public StackInterface{ public: LinkedStack(); LinkedStack(const LinkedStack &aStack); //space matter?*********** virt.

Can you please debug this Thank you in advance! This program is sup.pdf

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Circulating blood cells that differentiate into macrophages in the tissue M cells Monocytes Common myeloid progenitors Eosinophils Solution Answer: b. Monocytes Monocytes are the circulating blood cells which after production from the bone marrow, circulate in the bloodstream for about 8 h, during which they enlarge; and then migrate into the tissues and differentiate into specific tissue macrophages. The differentiation of a monocyte into a tissue macrophage involves a number of changes such as :.

Circulating blood cells that differentiate into macrophages in the ti.pdf

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Between January 2005 and May 2007, the CDC had identified 138 cases of Acanthomelobe Keratitis infections (a rare but potentially blinding infection of the cornea of the eye) in 35 states and Puerto Rico. Although only 46 interviews of infected individuals have been acquired, the results indicate a linkage to the use of Complete MoisturePlus Multipurpose contact lens solution. How might public health officials have handled this outbreak? Official letters to all registered healthcare practitioners announcing methods of treatment and follow-up Provide the option to health care providers to report the disease Public health announcement All of the abovea. Official letters to all registered healthcare practitioners announcing methods of treatment and follow-upb. Provide the option to health care providers to report the diseasec. Public health announcementd. All of the above Solution D.All of above Public health officials work in outbreak very precociously. Too often an initial suspicious outbreak is just lots of different illnesses that are being confused for the same thing or an error from the lab or other monitoring systems. So it’s important to study sign/symptoms and study the number of cases. The case definition will create a standardized method for identifying past, present and future cases. It should include clinical information, characteristics of those with the disease, and geographic and timing information about the cluster of cases. A good case definition starts out very inclusive so as not to miss any potential cases that do not have the typically identified symptoms. As the investigation continues for an unknown disease, this definition may become more restricted to ensure we focus on persons who truly have the illness of concern. After confirmation, they take appropriate action.As in above cases in only 46 interviews have been developed infection still part of their procedure they have to follow all three steps which mention above..

Between January 2005 and May 2007, the CDC had identified 138 cases .pdf

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