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ACTUAL ORGANIC
CHEMISTRY
Finally!
What will nucleophilic substitutions work with
• Need a leaving group that is connected to sp^3 carbon
• Or a leaving group that is allylic
Nomenclature
• Same steps as last time
• Take your halogen
• Take off suffix –ine
• Add suffix –o
• This will give you the name of the substituent
Practice
Alkyl halide properties
• Very polar C-X bond
• Takes electrons away from Carbon
• Due to polar C-X bond: molecule has dipole-dipole IMFs
General substitution reaction
• What you need
• Nucleophile
• C-X bond
• General feature: nucleophile replaces leaving group
Leaving groups
• Bigger is better
• The bigger it is, the better it can
accept a negative charge
• The better the leaving group, the
faster the reaction
• Trend opposes that of basicity and
follows acidity
• Think in terms of its conjugate acid
Electronegativity increase
Increase in
size
Bad leaving groups
practice
Bases and nucleophiles
• Bases attack protons : symbol is B:
• Nucleophiles attack carbons : symbol is Nu:
• In general nucleophilicity increases with basicity: opposite if solvent is
protic (if I DO NOT FIX THIS; IT IS WRONG. WRONG. WRONG. WrOnG
• Does charge matter? Yes, negative means stronger
• Nucleophiles are Dependent on sterics
practice
Solvents
• Right now we are really only worried about polar solvents
• Two types: protic and aprotic
• Protic solvents Hydrogen bond
• Aprotic solvents: have no hydrogen bonds but do have dipole-dipoles
• Acetone, DMSO, acetonitrile, DMF all are aprotic solvents
• Protic favors Sn1
• Aprotic favors Sn2
practice
Relationship between Nu: and solvents
Sn2
• Bimolecular
• Concerted
• Stereochemistry is inversion always
• Mechanism
• Rate= k[substrate][Nu:]
• Favors lower substitution due to steric hinderance
practice
practice
Sn1
• Unimolecular
• Stepwise reaction
• Carbocation intermediate
• Racemization
• Rate= k[substrate]
• Favors higher substitution due to hyperconjugation and induction
• Mechanism
practice
Stability of carbocations
• In order of increasing stability
• Methyl, primary, secondary, tertiary
practice
Hammond postulate
• Tells us what the intermediate looks like
• If closer in energy to products, it will look like the products
• If it is closer in energy to the reactants it will look like the reactants
practice
Did we do synthesis today?
• Yuppy Puppy? Lets yabba dabba do this thing
• No? I cant wait til we do
In summary
Sn1 Sn2
Stepwise Concerted
Carbocation intermediate Only has a transition state
Racemic products Always inverted
Favored by polar protic Favored by polar aprotic
Weak nucleophile Strong nucleophile
Rate=k[substrate] Rate=k[substrate][Nu:]
Favored by tertiary and secondary halides Favored by methyl, primary, secondary halides
Unimolecular Bimolecular
Are you SN1 or SN2
• Step 1: How many R groups
• Methyl, 1= Sn2
• 3= Sn1
• 2= next step
• Step 2: strength of nucleophile: strong or weak?
• Step 3: Is solvent protic or aprotic?
practice
practice
Exam 4 review: Ch.8
GO TO SLIDESHARE POWERED BY LINKEDIN AND SEARCH
“DANIELEISENSTEIN1”
Alkene Fun Facts
 C=C bond
 Sp2 hybridized = trigonal planar
 Pi and sigma bond
 Don’t conform = What a rebel
Alkene Stability
Practice
Leaving Group Ability
Beta carbons
 Beta carbons are secondarily adjacent to the
functional group
 Immediately adjacent to the alpha carbon
 Finding beta carbons is the first step in
predicting products for eliminations
 Find Beta carbons and draw all Elimination
products
 This is 8.1 in solution manual
Its all about that base!
 Basicity increases as the formal charge gets more negative
 Basicity is not as dependent on steric hinderance as nucleophiles
 A sterically hindered base is called a nonnucleophilic base
 B: is the symbol for a base
Trend for basicity
Elimination reaction
 Forms alkene
 We need a base
 We need a Leaving Group
 As number of R groups increase, rate of
reaction increases
This Photo by Unknown Author is licensed under CC BY-SA-NC
E2 reaction
 Rate= k[substrate][base]
 Bimolecular
 Concerted
 Strong base
 Requires anti periplanar geometry
 Trans-diaxial on a ring
This Photo by Unknown Author is licensed under
CC BY-SA-NC
E2 Mechanism
Practice
practice
practice
Major vs. Minor products
 We want the most stable product
 Follows Zaitsev’s rule
 The less stable product can be favored
 Hoffmann product
 Due to steric effects
This Photo by Unknown Author is licensed under CC BY-SA-NC
Practice (8.12)
What alkenes are
formed?
Follow zaittsev rule
E1 reaction
 Weak base
 Unimolecular
 Involves carbocation intermediate
 Two-step reaction
 Rate= k[substrate]
This Photo by Unknown Author is licensed under CC BY-NC
E1 vs. E2
E1 vs. E2 vs. Sn1 vs. Sn2
 BIG DADDY FLOW CHART
 This is not mine
 This is the work of clutchprep
 If you are having trouble in this
course or in organic chemistry 2, I
highly recommend them
This Photo by Unknown Author is licensed under CC BY-NC-ND
Practice (8.16)
Questions I like
 8.1, 8.3, 8.5, 8.6, 8.7, 8.8, 8.9, 8.10, 8.11, 8.12, 8.13, 8.14, 8.15, 8.18, 8.19
 You know what, I Iike all of them

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Chapter 7 wiley version

  • 2. What will nucleophilic substitutions work with • Need a leaving group that is connected to sp^3 carbon • Or a leaving group that is allylic
  • 3. Nomenclature • Same steps as last time • Take your halogen • Take off suffix –ine • Add suffix –o • This will give you the name of the substituent
  • 5. Alkyl halide properties • Very polar C-X bond • Takes electrons away from Carbon • Due to polar C-X bond: molecule has dipole-dipole IMFs
  • 6. General substitution reaction • What you need • Nucleophile • C-X bond • General feature: nucleophile replaces leaving group
  • 7. Leaving groups • Bigger is better • The bigger it is, the better it can accept a negative charge • The better the leaving group, the faster the reaction • Trend opposes that of basicity and follows acidity • Think in terms of its conjugate acid Electronegativity increase Increase in size
  • 10. Bases and nucleophiles • Bases attack protons : symbol is B: • Nucleophiles attack carbons : symbol is Nu: • In general nucleophilicity increases with basicity: opposite if solvent is protic (if I DO NOT FIX THIS; IT IS WRONG. WRONG. WRONG. WrOnG • Does charge matter? Yes, negative means stronger • Nucleophiles are Dependent on sterics
  • 12. Solvents • Right now we are really only worried about polar solvents • Two types: protic and aprotic • Protic solvents Hydrogen bond • Aprotic solvents: have no hydrogen bonds but do have dipole-dipoles • Acetone, DMSO, acetonitrile, DMF all are aprotic solvents • Protic favors Sn1 • Aprotic favors Sn2
  • 14. Relationship between Nu: and solvents
  • 15. Sn2 • Bimolecular • Concerted • Stereochemistry is inversion always • Mechanism • Rate= k[substrate][Nu:] • Favors lower substitution due to steric hinderance
  • 18. Sn1 • Unimolecular • Stepwise reaction • Carbocation intermediate • Racemization • Rate= k[substrate] • Favors higher substitution due to hyperconjugation and induction • Mechanism
  • 20. Stability of carbocations • In order of increasing stability • Methyl, primary, secondary, tertiary
  • 22. Hammond postulate • Tells us what the intermediate looks like • If closer in energy to products, it will look like the products • If it is closer in energy to the reactants it will look like the reactants
  • 24. Did we do synthesis today? • Yuppy Puppy? Lets yabba dabba do this thing • No? I cant wait til we do
  • 25. In summary Sn1 Sn2 Stepwise Concerted Carbocation intermediate Only has a transition state Racemic products Always inverted Favored by polar protic Favored by polar aprotic Weak nucleophile Strong nucleophile Rate=k[substrate] Rate=k[substrate][Nu:] Favored by tertiary and secondary halides Favored by methyl, primary, secondary halides Unimolecular Bimolecular
  • 26. Are you SN1 or SN2 • Step 1: How many R groups • Methyl, 1= Sn2 • 3= Sn1 • 2= next step • Step 2: strength of nucleophile: strong or weak? • Step 3: Is solvent protic or aprotic?
  • 29. Exam 4 review: Ch.8 GO TO SLIDESHARE POWERED BY LINKEDIN AND SEARCH “DANIELEISENSTEIN1”
  • 30. Alkene Fun Facts  C=C bond  Sp2 hybridized = trigonal planar  Pi and sigma bond  Don’t conform = What a rebel
  • 34. Beta carbons  Beta carbons are secondarily adjacent to the functional group  Immediately adjacent to the alpha carbon  Finding beta carbons is the first step in predicting products for eliminations  Find Beta carbons and draw all Elimination products  This is 8.1 in solution manual
  • 35. Its all about that base!  Basicity increases as the formal charge gets more negative  Basicity is not as dependent on steric hinderance as nucleophiles  A sterically hindered base is called a nonnucleophilic base  B: is the symbol for a base
  • 37. Elimination reaction  Forms alkene  We need a base  We need a Leaving Group  As number of R groups increase, rate of reaction increases This Photo by Unknown Author is licensed under CC BY-SA-NC
  • 38. E2 reaction  Rate= k[substrate][base]  Bimolecular  Concerted  Strong base  Requires anti periplanar geometry  Trans-diaxial on a ring This Photo by Unknown Author is licensed under CC BY-SA-NC
  • 43. Major vs. Minor products  We want the most stable product  Follows Zaitsev’s rule  The less stable product can be favored  Hoffmann product  Due to steric effects This Photo by Unknown Author is licensed under CC BY-SA-NC
  • 44. Practice (8.12) What alkenes are formed? Follow zaittsev rule
  • 45. E1 reaction  Weak base  Unimolecular  Involves carbocation intermediate  Two-step reaction  Rate= k[substrate] This Photo by Unknown Author is licensed under CC BY-NC
  • 46.
  • 48. E1 vs. E2 vs. Sn1 vs. Sn2  BIG DADDY FLOW CHART  This is not mine  This is the work of clutchprep  If you are having trouble in this course or in organic chemistry 2, I highly recommend them This Photo by Unknown Author is licensed under CC BY-NC-ND
  • 50. Questions I like  8.1, 8.3, 8.5, 8.6, 8.7, 8.8, 8.9, 8.10, 8.11, 8.12, 8.13, 8.14, 8.15, 8.18, 8.19  You know what, I Iike all of them

Editor's Notes

  1. Experimentally from hydrogenation So carbocation is formed in hydrogenation reaction, so stability of carbocation decides amount of energy released in hydrogenation and therefore alkene stability Alkene stability increases= hydrogenation energy decreases = carbocation stability increases= increased Rs
  2. Leaving group= college student More stable = the easier they leave Across because: increasing electronegativity Down because of increasing size Increased electronegativity means that they are more likely to “Steal” the e- in their bond and more able to keep those e- once they are taken. The increased size means that the atom has more space to spread out the increased number of e-
  3. In powerpoint there is DBN and DBU. Do we need to teach this? Check second line
  4. Across: electronegativity; more likely to share electrons to form a bond with hydrogen Up: less real estate
  5. Find this