AMANI JAMES as the electronic circuit designer , I have designed the dual power supply with +/-12V output voltage. if you are interested with this , contact me with amanirah@gmail.com. also I can design the PCB for the same circuit
1. DAR ES SALAAM INSTITUTE OF TECHNOLOGY
DEPARTMENT OF ELECTRONICS AND TELECOMMUNICATION
ETT 05213: ELECTRONIC SYSTEM COMPUTER AIDED DESIGN
PILI JAMES 140627193619.
TELECOM 1.
2. AIM
To design a Dual DC power supply of DC output power Po=290 mV, DC output
voltage Vo(avg) =+12V and -12V, with AC mains Vs=240V/60Hz with the following
functionality;
I. On/Off switch
II. Current flow direction
III. Output results displayed on Oscilloscope
IV. Output results displayed on Graph
V. Voltmeter/Ammeter measurement.
THEORY.
Bellow is the block diagram for the Regulated DC Power Supply.
3. The operation of power supply circuits is built using AC power source , step down
transformer, rectifiers, filters and then voltage regulators.
4. An Ac voltage from Ac source is stepped down by transformer .Then the bridge rectifier
circuit convert the Ac voltage into pulsating DC voltage. The capacitor filter circuit filter
out the ripple voltage from rectified voltage to get non-pulsating voltage. In order to get
the steady DC voltage regardless the variation in AC power source ,the Voltage regulator
is required for the same purpose. LM7812 LM7912 regulators are used to get the fixed
+12V and -12V output voltage respectively.
MATHEMATICAL ANALYSIS
The following data were used during designing
1.AC Power Source.
The AC source should be 240V/60Hz.
Editing the AC source properties:
Amplitude=maximum voltage(vm)
Vm=1.414Vrms
5. Vm=1.414×240V=339.36V
2. Centre tapped transformer.
Transformer output = 30V.
Transformer ratio = Vp/Vs =240/30 =8:1
Editing transformer properties in proteus.
Parameters to consider are ;
1.Primary inductance Lp
2. Secondary inductance Ls
3. Primary voltage VP
4. Secondary voltage Vs
Then;
Lp =( Vp/Vs)2
×Ls let Ls =1, Lp =(240/15)2
×1 = 256.
NOTE. Vs is taken as 15V since it is the centre tapped transformer and Ls is
edited as 2 due to the same reason. The results is as shown in the diagram
bellow
7. 3. Bridge Rectifier.
The output from bridge rectifier is the pulsating DC voltage and is calculated
as follows;
Vdc = 0.9Vrms
= 0.9×15v
= 13.5V
NOTE; Vrms is taken as 15V since is from the half part of the centre tapped
transformer.
Therefore the calculated output value is 13.5V but the measured value is
14.4V as shown bellow.
9. Given that; Output power Po = 290mW.
And Po = Vo2
/RL, where ,RL is the load resistance. Then,
RL = Vo2
/po
RL = 13.52
/290mW = 628.45Ω or 0.628kΩ.
R1
0.68k
C2
14.0uF
10. From, Vdc = Vm÷[1+(5/RLC)] for filtration.then,
C = 5Vdc ÷ [RL(Vm-Vdc)] where ,
C is the capacitance in microfarads and
RL is the load resistance in kilohms.
Also ,Vm = 1.414Vrms.
Vm = 1.414×15V
= 21.21V . then,
C =( 5×13.5)÷[0.628(21.21-13.5)]
= 67.5÷4.842
= 13.94uF.
From the calculated value of resistor and capacitor, then the selected standard
value for RL is 0.68kΩ and for capacitor is 14.0uF.
11. 5. Selecting DC voltage regulator.
The DC voltage regulators are LM7812 and LM7912 for +12V and -12V fixed
voltage respectively. C2 and C4 are for noise isolation.
C1
14.0uF
R1
0.68k
VI
1
VO
3
GND
2
U1
7812
C2
14.0uF
VI
2
VO
3
GND
1
U2
7912
Volts
+12.0
12. Calculating DC output current.
From , current I = V/R,
= 12/0.68k = 0.02A.
C3
14.0uF
C4
14.0uF
R2
0.68k
VI
2
VO
3
GND
1
U2
7912
Volts
-12.0
15. List of components used are as follows
S/N Components Quantity Values
1 AC power source 1
2 Centre tapped transformer 1
3 Bridge Rectifier 1
4 Capacitors 4 14.0uF
5 Voltage Regulators 2 LM7812, LM7912
6 Resistors 2 0.680k
7 Switch(SPST) 1
8 DC Voltmeter 1
9 AC Voltmeter 1
20. The table for comparison between measured and calculated values
Quantity Calculated value Measured value
Pulsating Vdc 13.5V 14.4V
Output filtered Vdc 13.5V 13.4V
Regulated output Vdc - +12V ,-12V
Output dc current 0.02A 0.01A