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INSTITUTO TECNOLOGICO SAN IGNACIO DE LOYOLA (ITESIL)
Facilitadora: Altagracia Belliard
Realizaloque se te pide a continuaciΓ³n:
a) Calcula los siguientesdeterminantes de segundoorden.
1. ⌈
𝟐 𝟏
𝟏 πŸ‘πŸŽ
βŒ‰
2. ⌈
πŸ‘ 𝟐
𝟐 𝟎
βŒ‰
3. ⌈
πŸ— πŸπŸ”
𝟏 𝟏
βŒ‰
4. ⌈
𝟐 𝟏
πŸ‘ βˆ’πŸ
βŒ‰
5. ⌈
βˆ’πŸ’ βˆ’πŸ“
πŸ‘ 𝟐
βŒ‰
b) Calcular los siguientes determinantesde tercer ordenaplicandoel
mΓ©todode sarrus.
1. ⌈
𝟐 βˆ’πŸ 𝟐
𝟏 πŸ‘ 𝟏
πŸ’ βˆ’πŸ πŸ“
βŒ‰
2. ⌈
𝟏 𝟐 βˆ’πŸ
βˆ’πŸ πŸ“ 𝟎
πŸ’ βˆ’πŸ‘ βˆ’πŸ“
βŒ‰
3. ⌈
𝟏𝟎 βˆ’πŸ‘ πŸ“
βˆ’πŸ 𝟐 πŸ‘
βˆ’πŸ” πŸ’ βˆ’πŸ
βŒ‰
4. ⌈
𝟏 βˆ’πŸ‘ 𝟐
𝟐 βˆ’πŸ βˆ’πŸ
𝟏 𝟏 βˆ’πŸ‘
βŒ‰
5. ⌈
𝟏 𝟐 πŸ‘
πŸ‘ 𝟐 𝟏
𝟏 𝟏 𝟏
βŒ‰
c) Resuelve los siguientes sistemas de ecuaciones linealesaplicando
la reglade Cramer
1. {
πŸ“π’™ + πŸπ’š = πŸ”
πŸ‘π’™ + πŸ—π’š = βˆ’πŸπŸ
}
2. {
πŸ‘π’™ + πŸπ’š = πŸ•
πŸπ’™ βˆ’ π’š = 𝟎
}
3. {
βˆ’π’™ + πŸπ’š βˆ’ πŸ“π’› = βˆ’πŸπŸ“
βˆ’πŸ‘π’™ + πŸπ’š βˆ’ πŸ‘π’› = βˆ’πŸπŸ“
πŸ‘π’™ βˆ’ πŸπ’š βˆ’ πŸ”π’› = βˆ’πŸπŸ
}
4. {
πŸ‘π’™ + πŸ“π’š = 𝟏
βˆ’π’™ + πŸπ’š = πŸ•
}
5. {
πŸ‘π’™ βˆ’ πŸπ’š + πŸ“π’› = πŸπŸ’
π’š βˆ’ πŸ’π’› = βˆ’πŸπŸŽ
πŸπ’š + 𝒛 = πŸ•
}
6. {
πŸπ’™ + πŸ’π’› βˆ’ πŸ“π’š = βˆ’πŸ
πŸ’π’™ βˆ’ πŸ“π’š + πŸ’π’› = πŸ‘
πŸ“π’™ βˆ’ πŸ‘π’› = πŸπŸ‘
}

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5 f y 5 g

  • 1. INSTITUTO TECNOLOGICO SAN IGNACIO DE LOYOLA (ITESIL) Facilitadora: Altagracia Belliard
  • 2. Realizaloque se te pide a continuaciΓ³n: a) Calcula los siguientesdeterminantes de segundoorden. 1. ⌈ 𝟐 𝟏 𝟏 πŸ‘πŸŽ βŒ‰ 2. ⌈ πŸ‘ 𝟐 𝟐 𝟎 βŒ‰ 3. ⌈ πŸ— πŸπŸ” 𝟏 𝟏 βŒ‰ 4. ⌈ 𝟐 𝟏 πŸ‘ βˆ’πŸ βŒ‰ 5. ⌈ βˆ’πŸ’ βˆ’πŸ“ πŸ‘ 𝟐 βŒ‰ b) Calcular los siguientes determinantesde tercer ordenaplicandoel mΓ©todode sarrus. 1. ⌈ 𝟐 βˆ’πŸ 𝟐 𝟏 πŸ‘ 𝟏 πŸ’ βˆ’πŸ πŸ“ βŒ‰ 2. ⌈ 𝟏 𝟐 βˆ’πŸ βˆ’πŸ πŸ“ 𝟎 πŸ’ βˆ’πŸ‘ βˆ’πŸ“ βŒ‰ 3. ⌈ 𝟏𝟎 βˆ’πŸ‘ πŸ“ βˆ’πŸ 𝟐 πŸ‘ βˆ’πŸ” πŸ’ βˆ’πŸ βŒ‰ 4. ⌈ 𝟏 βˆ’πŸ‘ 𝟐 𝟐 βˆ’πŸ βˆ’πŸ 𝟏 𝟏 βˆ’πŸ‘ βŒ‰ 5. ⌈ 𝟏 𝟐 πŸ‘ πŸ‘ 𝟐 𝟏 𝟏 𝟏 𝟏 βŒ‰
  • 3. c) Resuelve los siguientes sistemas de ecuaciones linealesaplicando la reglade Cramer 1. { πŸ“π’™ + πŸπ’š = πŸ” πŸ‘π’™ + πŸ—π’š = βˆ’πŸπŸ } 2. { πŸ‘π’™ + πŸπ’š = πŸ• πŸπ’™ βˆ’ π’š = 𝟎 } 3. { βˆ’π’™ + πŸπ’š βˆ’ πŸ“π’› = βˆ’πŸπŸ“ βˆ’πŸ‘π’™ + πŸπ’š βˆ’ πŸ‘π’› = βˆ’πŸπŸ“ πŸ‘π’™ βˆ’ πŸπ’š βˆ’ πŸ”π’› = βˆ’πŸπŸ } 4. { πŸ‘π’™ + πŸ“π’š = 𝟏 βˆ’π’™ + πŸπ’š = πŸ• } 5. { πŸ‘π’™ βˆ’ πŸπ’š + πŸ“π’› = πŸπŸ’ π’š βˆ’ πŸ’π’› = βˆ’πŸπŸŽ πŸπ’š + 𝒛 = πŸ• } 6. { πŸπ’™ + πŸ’π’› βˆ’ πŸ“π’š = βˆ’πŸ πŸ’π’™ βˆ’ πŸ“π’š + πŸ’π’› = πŸ‘ πŸ“π’™ βˆ’ πŸ‘π’› = πŸπŸ‘ }