Arrhenius concept of acids and bases, bronsted-lowry theory of acids and bases,amphoteric nature of water , characteristics of strong acids , characteristics of weak acids , characteristics of strong bases, characteristics of weak bases, conjugate acids, conjugate base,introduction on buffers , preparation of buffers, types of buffer, acidic buffer, basic buffer, how do buffers act, why doesn't the ph of buffers doesn't change , Handerson-Hasselbach equation, buffer capacity, pharmaceutical buffers, why maintainance of body ph is important, osmolarity of blood, isotonic, hypertonic and hypotonic solution, pharmaceutical buffer system,phosphate-buffered saline, methods to measure tonicity, hemolytic method, methods to adjust tonicity, cryoscopic method, NaCl equivalent method
2. ARRHENIUS CONCEPT OF ACIDS AND BASES
â˘
⢠Accordingly, HCl is a strong acid because it dissociates completely into H+ ions in aqueous solution
⢠And NaOH is a strong base because it dissociates completely into OH- ions in aqueous solution
LIMITATIONS OFARRHENIUS DEFINTION
The theory does not help to identify acids and bases in non-aqueous enviornment such as the solid or
gas phase
ACIDS
BASES
HCl + H2O H30+ + Cl-
NaOH + H20 Na+ + H2O + OH-
3.
4. BRONSTED-LOWRY CONCEPT OF ACIDS AND BASES
WHAT WOULD BE THE RESULT OF SUCH INTERACTION..?
PREREQUISITES FOR BEING AN ACID OR BASE
After donation of electron the acid will become the conjugate base
and the base would become conjugate acid.
H-A + B: A: + B-H
(Acid) (Base) (Conjugate Base) (Conjugate Acid)
5. ⢠Let us study Bronsted-Lowry concept with the aid of an exampleâŚ.
HERE, BRONSTED LOWRY ACID = HCl (IT CONTAINS PROTON)
AND, BRONSTED-LOWRY BASE = NH3 (IT CONTAINS A PAIR OF ELECTRONS)
NH3(g) + HCl (g) NH4Cl(s)
NOTE: ACCORDING TO ARRHENIUS, THE ABOVE REACTION IS NOT
EVEN AN ACID-BASE REACTIONâŚ.
6. WATER
⢠CASE I: WATER ACTS AS A BRONSTED-LOWRY BASE
Reaction between HNO3 and water
⢠CASE II: WATER ACTS AS A BRONSTED-LOWRY ACID
Reaction between NH3 and water
That whether water would react as an acid or a base depends upon what it is reacting with.
HNO3 + H20 H3O+ + NO3
-
(B-L BASE)
7. STRONG ACIDS AND WEAK ACIDS
STRONG ACIDS
⢠A STRONG ACID COMPLETELY DISSOCIATES INTO ITâS CONSTITUENT IONS IN AQUEOUS SOLUTION.
HCl + H20 H3O+ + Cl-
Note the single arrow which indicates
complete dissociation of HCl into
constituent ions
8. ⢠WEAK ACIDS
WEAK ACIDS PARTIALLY DISSOCIATES INTO ITS CONSTITUENT IONS AND DISSOCIATION IS IN A STATE OF
DYNAMIC EQUILIBRIUM
Eg: Acids like HF and CH3COOH dissociate partially
into its constituent ions.
The arrows are pointed in both direction which indicates that the reaction is in a state of
dynamic equilibrium.
That is, at a particular time there will be a significant concentration of acetic acid
molecules and a smaller fraction of acetate ions in the reaction system which would
remain constant.
9. STRONG BASE
⢠A STRONG BASE COMPLETELY DISSOCIATES INTO ITS CONSTITUENT IONSâŚ.
NaOH + H2O Na+ + OH- + H20
THE ARROW IS SINGLE DIRECTIONAL ARROW WHICH MEANS THAT THERE WILL
BE NO NaOH LEFT AFTER WE DISSOLVE IT IN WATER.
Only Na+ and OH- will be present in final solution
10. WEAK BASE
⢠A WEAK BASE DOES NOT COMPLETELY DISSOCIATE INTO ITS CONSTITUENT IONS.
⢠Eg: AMMONIA IN WATER
11. CONJUGATE ACID AND CONJUGATE BASE
⢠Consider the reaction of HNO3 with H20
⢠2 CONJUGATE PAIR:
1. CONJUGATE PAIR I: HNO3 AND NO3
-
2. CONJUGATE PAIR II: H2O AND OH-
⢠Consider the reaction of NH3 and H2O
⢠Conjugate pair I : NH3 and NH4
+
⢠Conjugate pair II: H20 and OH-
HNO3 + H20 H3O+ + NO3
-
(Acid) (Base) (Conjugate acid) (Conjugate Base)
IRREVERSIBLE REACTION
REVERSIBLE REACTION
12. BUFFER
⢠LET US ASSUME THAT WE CONDUCT A SIMPLE EXPIREMENT IN LABâŚâŚ
ďź SOLUTION A
In solution A (pH = 7), we put HCl pH of Solution A decreases
In solution A(pH = 7), we put NaOH pH increases
PH OF SOLUTION A CHANGES ON ADDITION OF ALKALI OR ACID.
ďź SOLUTION B
⢠In solution B (pH = 7) , we put HCl No Change in pH
⢠In solution B(pH = 7), we put NaOH No Change in Ph
PH OF SOLUTION B RESISTS THE CHANGE IN PH.
WHAT IS THE DIFFERENCE�
WHILE SOLUTION A IS JUST WATER, SOLUTION B IS A BUFFERâŚâŚâŚâŚâŚâŚ..
13. Q.1 WHAT IS BUFFERâŚ..???
⢠A BUFFER IS AN AQUEOUS SOLUTION THAT RESISTS CHANGE IN pH ON ADDITION OF SMALL AMOUNTS OF ALKALI
OR ACIDS.
Q.2. HOW IS BUFFER PREPAREDâŚâŚ???
pH wonât change on boiling of solution
pH wonât change on addition of water
ACIDIC BUFFER = WEAK ACID + CONJUGATE
BASE.
Eg: CH3COOH + CH3COO-
BASIC BUFFER = WEAK BASE + CONJUGATE
ACID
Eg: NH3 + NH4
+
14. ⢠Q.3. HOW DO BUFFERS ACTâŚ..????
⢠WHAT HAPPENS WHEN YOU DISSOLVE ACETIC ACID IN WATERâŚ.??
⢠ACETIC ACID BUFFER CONSISTS OF ACETIC ACID AND ITS CONJUGATE BASE, ACETATE ION..
LET US STUDY THIS USING THE EXAMPLE OF ACETIC ACID
BUFFERâŚâŚ
To prepare it, you have to dissolve Acetic acid in waterâŚ..
15. ⢠CASE I: WHAT HAPPENS WHEN AN ACID IS ADDED INTO THIS BUFFERâŚ.?
⢠ACETATE ION REACTS WITH HYDRONIUM ION TO FORM ACETIC ACID WHICH IS ALREADY A
COMPONENT OF THE BUFFER.
⢠CASE II: WHAT HAPPENS WHEN A BASE IS ADDED INTO THIS BUFFERâŚ.?
⢠ACETIC ACID REACTS WITH HYDROXYL ION TO FORM ACETATE ION WHICH IS ALREADY A COMPONENT
OF THE BUFFER.
H+
OH-
16. Let us study buffers by taking an example of Basic BuffersâŚ
Let us take the case of NH3- NH4
+ BufferâŚ.
For this, we have to dissolve NH3 in H20âŚ..
17. ⢠CASE I: WHAT HAPPENS WHEN AN ACID IS ADDED INTO THIS BUFFER SYSTEMâŚâŚ
⢠IN THIS CASE, THE HYDRONIUM ION REAACTS WITH AMMONIA TO FORM AMMONIUM ION WHICH IS
ALREADY A COMPONENT OF THE BUFFER SYSTEMâŚ
⢠CASE II: WHAT HAPPENS WHEN A BASE IS ADDED INTO THIS BUFFER SYSTEMâŚ.
⢠THE HYDROXYL ION REACTS WITH AMMONIUM ION TO GIVE AMMONIA WHICH IS ALREADY A
COMPONENT OF THE BUFFER SYSTEMâŚâŚ
H+
OH-
18. ⢠IN THIS CASE, THERE IS NO CHANGE IN CONCENTRATION OF OH- IONS
⢠THE DYNAMIC EQILIBRIUM FOLLOWS LE-CHATELIERâS PRINCIPLEâŚâŚâŚ.
H+
OH-
THE BUFFER SYSTEM NUETRALIZES THE HYDRONIUM OR HYDROXYL ION ADDED SO AS
TO RESIST A CHANGE IN pH.
https://byjus.com/jee/le-chateliers-principle-on-equilibrium/
19. Handerson-Hasselbalch equation.
⢠Therefore, it is used to calculate the pH of buffers when other parameters are knownâŚâŚ
⢠At equilibrium, [Base] = [Acid]
⢠Equation becomesâŚ..
pH = pKa at equilibriumâŚâŚ
Similarly, for a basic buffer, the pOH is given as followsâŚ.
⢠At equilibrium, [Acid] = [Base]
⢠Equation becomesâŚ..
pOH = pKb at equilibriumâŚâŚ
⢠LIMITATIONS OF HANDERSON-HASSELBACH EQUATION
KNOWN
KNOWN
KNOWN
KNOWN
KNOWN
KNOWN
20. 2. NOT APPLICABLE TO ACIDS THAT CAN DONATE MORE THAN ONE H+ SUCH AS H2SO4,
H3PO4
3. THE SALT (CONJUGATE BASE OR CONJUGATE ACID) COMPLETELY DISSOCIATES IN
SOLUTION. IN ACTUAL PRACTICE, IT IS NOT SOâŚâŚ
Eg: CH3COONa DOES NOT COMPLETELY DISSOCIATE IN WATER
1. Self-ionization of water affect pH , specially when the buffer solution is of less
strength.
Therefore, HH equation is only applicable to buffers of substantial strength
It cannot be used to calculate the pH of strong acid or a strong base
DERIVATION OF HENDERSON-HASSELBACH EQUATION
https://chem.libretexts.org/Bookshelves/Ancillary_Materials/Reference/Organic_Chemistry_Glo
ssary/Henderson-Hasselbach_Equation
21. BUFFER CAPACITY
⢠NO. OF MOLES OF ACID OR BASE REQUIRED TO CHANGE THE pH OF A BUFFER SOLUTION BY 1.
⢠IT IS GIVEN AS NUMBER OF MOLES OF ACID AND BASE ADDED, DIVIDED BY THE CHANGE IN pH AND
THE VOLUME OF BUFFER IN LITRESâŚ..
PHARMACEUTICAL BUFFERS
DRUGS ARE EITHER ACIDIC OR BASIC. THEREFORE, DISSOLVING THEM IN A SOLUTION OF CONSTANT pH
BECOMES NECESSARY.
⢠WHY MAINTAINING pH IS SO IMPORTANTâŚ..????
22. PLASMA PROTIENS AND MEMBRANE
PROTIENS ARE VERY SENSITIVE TO pH
ION CHANNELS CAN
MALFUNCTIONS ON CHANGE
IN pH
ACID-BASE HOMEOSTASIS
Stringent measures are taken up by the body to maintain pH.
Our blood is a buffer system. It is called the bicarbonate buffer system.
Lungs can breathe out CO2
and maintain pH
Kidneys can excrete H+
And HCO3
-
23. Lacrimal fluid has a pH of 6.5 to 7.6
OUR BODY DOES NOT CHANGE pH, NO MATTER WHAT WE EATâŚ..
Therefore, there is a need to maintain a pH of drugsâŚ
2. PH ALSO LEADS TO CHANGES IN OSMALARITY OF BODY FLUIDSâŚâŚ
H+
WHAT HAPPENS WHEN OSMALARITY OF THE BLOOD CHANGESâŚ.???
24. Therefore, it is very important to maintain pH of medicinal preperations
25. ⢠PHARMACEUTICAL BUFFER SYSTEM
Drugs are dissolved in buffers of suitable pH before being administered into the bodyâŚ
Some commonly used pharmaceutical buffer systems are given below:
1. PHOSPHATE BUFFERED SALINE
2. ACETATE BUFFER: CONTAINS CH3COOH AND CH3COONa
3. CITRATE BUFFER: CITRIC ACID AND SODIUM CITRATE (C6H8O7 and C6H707Na)
BUFFER SYSTEM OF PBS
26. Isotonic with cells; non-toxic
APPLICATION OF PBS
Used in microbiology to dilute cells and to wash containers
containing cells
Storage of microorganisms and viruses
Used in all kinds of eye dropsâŚ.
Used in Vaginal washes
27. HOW TO PREPARE BUFFER SOLUTIONâŚ.???
GENERAL METHOD OF PREPARATION
28. TONICITY
It is the difference in osmotic pressure of the two solutions that is separated by semi-
permeable membrane.
It decides the direction and extent of the diffusion of water
29. HOW TO MEASURE TONICITYâŚ..???
TWO METHODS
HAEMOLYTIC METHOD CRYOSCOPIC METHOD
HAEMOLYTIC METHOD: BASED ON CHANGES IN THE SIZE AND SHAPE OF RBC AND THE
RESULTING EFFECT ON THE VOLUME THEY OCCUPY WHEN PLACED IN SOLUTIONS OF
DIFFERENT TONICITY
OR, IT IS BASED ON CHANGE IN VOLUME OCCUPIED BY RBCâS WITH
CHANGE IN SHAPE AND SIZE
30. TAKE TWO CENTRIFUGAL TUBES.
TUBE A IS FILLED WITH BLOOD AND IS DILUTED WITH 5ML
OF 0.9% W/V OF NaCl SOLUTION (ISOTONIC SOLUTION)
TUBE B IS FILLED WITH BLOOD AND IS DILUTED WITH 5ML OF
TEST SOLUTION
THE TUBES ARE ROTATED AT VERY HIGH SPEEDSâŚâŚ
31. AFTER CENTRIFUGATION, THE BLOOD CELLS ARE CONCENTRATED
AT ONE END OF CENTRIFUGATION TUBE
PACKED CELL VOLUME (PCV) IS MEASURED FOR BOTH SOLUTIONS AND THE VOLUME ARE
COMPARED WITH EACH OTHER
Tube 1:Isotonic
Tube 2: Test solution
CASE I: NO CHANGE IN VOLUME
IF PACKED CELL VOLUME OF TEST SOLUTION (TUBE B) IS EQUAL TO THAT OF TUBE A, THE
SOLUTION IN TUBE B IS SAID TO BE ISOTONIC
CASE II: VOLUME OF TEST TUBE B IS MORE
IF PACKED CELL VOLUME (PCV) OF TUBE B (TEST SOLUTION) IS MORE THAN THAT OF TUBE
A, THE SOLUTION IS SAID TO BE HYPOTONIC
32. CRYOSCOPIC METHOD
⢠THE FREEZING POINT OF WATER = 0°C
⢠THE FREEZING POINT OF BLOOD = -0.52 °C
⢠THE FREEZING POINT OF 0.9 % NaCl = -0.52 °C
CASE III: VOLUME OF TUBE B IS LESS
THE VOLUME OF TUBE B (TEST SOLUTION) IS LESS THAN THAT OF TUBE A. IN SUCH CASE,
THE SOLUTION IS SAID TO BE HYPERTONICâŚ
ADDITION OF SOLUTES TO
WATER DECREASES ITS
FREEZING POINT
PROCEDURE
THE TEST SOLUTION (DRUG) IS FROZEN TO RECORD ITS
FREEZING POINT
RESULTS
1. TAKE TWO TEST TUBES. TUBE A CONTAINS 0.9% NaCl
solution or blood while TUBE B contains drug solution.
2. Record the freezing point of both solutions and compare the values.
33. CASE III: THE FREEZING POINT IS MORE THAN THAT OF TUBE A
IN SUCH CASE, SOLUTION IN TUBE B IS SAID TO BE HYPOTONIC
METHODS TO ADJUST TONICITY
NaCl or some other substances are added till the freezing point of the solution becomes -
0.52°C and thus the solution becomes isotonic.
It is very important to know the exact tonicity of the drug solution so that exact amount of
NaCl is added such that tonicity is equal to that of blood.
TWO METHODS
Cryoscopic Method NaCl Equivalent Method
I. CRYOSCOPIC METHOD
Not possible to adjust tonicity by altering drug concentration as it can lead to dose
related adverse effects in humans.
The only way to adjust tonicity is to add adjusting agents for tonicity such as NaCl.
34. Drug solution
Measure ÎTf
ÎTf = a X x
Where, a = Concentration of the drug solution
x = one unit of concentration
x = ÎTf/a
x= ÎTf
If w = grams of adjusting substance that is to be added
Then, ÎTf = w x ÎTf of 1 % solution of adjusting substance
ÎTf = w X b = wb
The drug solutionâs tonicity = x; and the adjusting substanceâs tonicity = wb.
Adjusting substance is added to drug solution but the sum of the tonicity of them should
not exceed 0.52
i.e., x + wb = 0.52
35. w = 0.52 â x/b
Remember, b = ÎTf of 1% concentration of adjusting substance
If adjusting substance added is NaCl ,
âŚ.then b or ÎTf for 1% solution of NaCl = 0.58
Therefore, w = 0.52-x/0.58
Where, x = ÎTf of 1% drug solution (which is already measured)
Where, P.S.M. = Parent strength of medicament
It is only valid for 100 ml of solutionâŚ.