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LAPLACE TRANSFORM
WHY USE LAPLACE
TRANSFORMS?
• Find solution to differential equation using
algebra
• Relationship to Fourier Transform allows
easy way to characterize systems
• No need for convolution of input and
differential equation solution
• Useful with multiple processes in system
HOW TO USE LAPLACE
• Find differential equations that describe
system
• Obtain Laplace transform
• Perform algebra to solve for output or
variable of interest
• Apply inverse transform to find solution
WHAT ARE LAPLACE
TRANSFORMS?
















j
j
st
1
0
st
ds
e
)
s
(
F
j
2
1
)}
s
(
F
{
L
)
t
(
f
dt
e
)
t
(
f
)}
t
(
f
{
L
)
s
(
F
• t is real, s is complex!
• Inverse requires complex analysis to solve
• Note “transform”: f(t)  F(s), where t is
integrated and s is variable
• Conversely F(s)  f(t), t is variable and s is
integrated
EVALUATING F(S) = L{F(T)}
• Hard Way – do the integral

 



 




















0
st
0 0
t
)
a
s
(
st
at
at
0
st
dt
)
t
sin(
e
)
s
(
F
t
sin
)
t
(
f
a
s
1
dt
e
dt
e
e
)
s
(
F
e
)
t
(
f
s
1
)
1
0
(
s
1
dt
e
)
s
(
F
1
)
t
(
f
let
let
let
Integrate by parts
EVALUATING F(S)=L{F(T)}- HARD
WAY
remember
 

 vdu
uv
udv
)
t
cos(
v
,
dt
)
t
sin(
dv
dt
se
du
,
e
u st
st





 


 



 











0
0 0
0
)
cos(
)
1
(
)
cos(
)
cos(
[
)
sin( ]
dt
t
e
s
e
dt
t
e
s
t
e
dt
t
e
st
st
st
st
st
)
t
sin(
v
,
dt
)
t
cos(
dv
dt
se
du
,
e
u st
st




 




















0
st
st
0
st
0
st
0
st
dt
)
t
sin(
e
s
)
0
(
e
dt
)
t
sin(
e
s
)
t
sin(
e
[
dt
)
t
cos(
e
]
2
0
st
0
st
2
0 0
st
2
st
s
1
1
dt
)
t
sin(
e
1
dt
)
t
sin(
e
)
s
1
(
dt
)
t
sin(
e
s
1
dt
)
t
sin(
se









 




 


let
let
Substituting, we get:
EVALUATING F(S) = L{F(T)}
• This is the easy way ...
• Recognize a few different transforms
• Learn a few different properties
• Do a little math
TABLE OF SELECTED LAPLACE
TRANSFORMS
1
1
)
(
)
sin(
)
(
1
)
(
)
cos(
)
(
1
)
(
)
(
1
)
(
1
)
(
2
2
















s
s
F
t
t
f
s
s
s
F
t
t
f
a
s
s
F
e
t
f
s
s
F
t
f
at
MORE TRANSFORMS
1
!
)
(
)
( 


 n
n
s
n
s
F
t
t
f
6
6
5
2
1
s
120
s
!
5
)
s
(
F
)
t
(
u
t
)
t
(
f
,
5
n
s
!
1
)
s
(
F
)
t
(
tu
)
t
(
f
,
1
n
s
1
s
!
0
)
s
(
F
)
t
(
u
)
t
(
f
,
0
n














PROPERTIES OF LAPLACE
TRANSFORMS
• Linearity
• Change of scale
• Time Shift
• “frequency” or s-plane shift
• Multiplication by tn
• Integration
• Differentiation
PROPERTIES: LINEARITY
)
s
(
F
c
)
s
(
F
c
)}
t
(
f
c
)
t
(
f
c
{
L 2
2
1
1
2
2
1
1 


Example :
Proof :
)
s
(
F
c
)
s
(
F
c
dt
e
)
t
(
f
c
dt
e
)
t
(
f
c
dt
e
)]
t
(
f
c
)
t
(
f
c
[
)}
t
(
f
c
)
t
(
f
c
{
L
2
2
1
1
0
st
2
2
0
st
1
1
st
2
2
0
1
1
2
2
1
1
















1
1
)
1
)
1
(
)
1
(
(
2
1
)
1
1
1
1
(
2
1
}
{
2
1
}
{
2
1
}
2
1
2
1
{
)}
{sinh(
2
2

















s
s
s
s
s
s
e
L
e
L
e
e
L
t
L
t
t
t
t
)
a
s
(
F
a
1
)}
at
(
f
{
L 
Example :
2
2
2
2
2
2
s
)
s
(
1
)
1
)
s
(
1
(
1
)}
t
{sin(
L













Proof :
)
a
s
(
F
a
1
du
e
)
u
(
f
a
1
du
a
1
dt
,
a
u
t
,
at
u
dt
e
)
at
(
f
)}
at
(
f
{
L
a
0
u
)
a
s
(
0
st












let
PROPERTIES: CHANGE OF SCALE
PROPERTIES: TIME SHIFT
)
s
(
F
e
)}
t
t
(
u
)
t
t
(
f
{
L 0
st
0
0




Example :
a
s
e
t
u
e
L
s
t
a






10
)
10
(
)}
10
(
{
Proof :
)
s
(
F
e
du
e
)
u
(
f
e
du
e
)
u
(
f
t
u
t
,
t
t
u
dt
e
)
t
t
(
f
dt
e
)
t
t
(
u
)
t
t
(
f
)}
t
t
(
u
)
t
t
(
f
{
L
0
0
0
0
0
st
0
su
st
t
0
)
t
u
(
s
0
0
t
st
0
0
st
0
0
0
0






























let
PROPERTIES: S-PLANE
(FREQUENCY) SHIFT
)
a
s
(
F
)}
t
(
f
e
{
L at



Example :
2
2
at
)
a
s
(
)}
t
sin(
e
{
L







Proof :
)
a
s
(
F
dt
e
)
t
(
f
dt
e
)
t
(
f
e
)}
t
(
f
e
{
L
0
t
)
a
s
(
0
st
at
at













PROPERTIES:
MULTIPLICATION BY tn
)
s
(
F
ds
d
)
1
(
)}
t
(
f
t
{
L n
n
n
n


Example :
1
n
n
n
n
n
s
!
n
)
s
1
(
ds
d
)
1
(
)}
t
(
u
t
{
L




Proof :
)
s
(
F
s
)
1
(
dt
e
)
t
(
f
s
)
1
(
dt
e
s
)
t
(
f
)
1
(
dt
e
t
)
t
(
f
dt
e
)
t
(
f
t
)}
t
(
f
t
{
L
n
n
n
0
st
n
n
n
0
st
n
n
n
0
st
n
0
st
n
n


























THE “D” OPERATOR
1. Differentiation shorthand
2. Integration shorthand
)
t
(
f
dt
d
)
t
(
f
D
dt
)
t
(
df
)
t
(
Df
2
2
2


)
t
(
f
)
t
(
Dg
dt
)
t
(
f
)
t
(
g
t

 

)
t
(
f
D
)
t
(
g
dt
)
t
(
f
)
t
(
g
1
a
t
a


 
if
then then
if
PROPERTIES: INTEGRALS
s
s
F
t
f
D
L
)
(
)}
(
{ 1
0 

Example :
)}
t
{sin(
L
1
s
1
)
1
s
s
)(
s
1
(
)}
t
cos(
D
{
L
2
2
1
0





Proof :
let
st
st
0
st
1
0
e
s
1
v
,
dt
e
dv
dt
)
t
(
f
du
),
t
(
g
u
dt
e
)
t
(
g
)}
t
{sin(
L
)
t
(
f
D
)
t
(
g



















 


t
0
st
0
st
dt
)
t
(
f
)
t
(
g
s
)
s
(
F
dt
e
)
t
(
f
s
1
]
e
)
t
(
g
s
1
[








0
)
(
)
( dt
e
t
f
t st
If t=0, g(t)=0
for so
slower than





0
)
(
)
( t
g
dt
t
f 0

st
e
PROPERTIES: DERIVATIVES
(THIS IS THE BIG ONE)
)
0
(
f
)
s
(
sF
)}
t
(
Df
{
L 


Example :
)}
t
sin(
{
L
1
s
1
1
s
)
1
s
(
s
1
1
s
s
)
0
(
f
1
s
s
)}
t
cos(
D
{
L
2
2
2
2
2
2
2
2















Proof :
)
s
(
sF
)
0
(
f
dt
e
)
t
(
f
s
)]
t
(
f
e
[
)
t
(
f
v
,
dt
)
t
(
f
dt
d
dv
se
du
,
e
u
dt
e
)
t
(
f
dt
d
)}
t
(
Df
{
L
0
st
0
st
st
st
0
st





















let
DIFFERENCE IN
• The values are only different if f(t) is not
continuous at t=0
• Example of discontinuous function: u(t)
)
0
(
f
&
)
0
(
f
),
0
(
f 

1
)
0
(
u
)
0
(
f
1
)
t
(
u
lim
)
0
(
f
0
)
t
(
u
lim
)
0
(
f
0
t
0
t












?
)}
t
(
f
D
{
L 2

)
0
(
'
f
)
0
(
sF
)
s
(
F
s
)
0
(
'
f
))
0
(
f
)
s
(
sF
(
s
)
0
(
'
f
)}
t
(
Df
{
sL
)
0
(
g
)
s
(
sG
)}
t
(
g
D
{
L
)
0
(
'
f
)
0
(
Df
)
0
(
g
),
t
(
Df
)
t
(
g
2
2














let
)
0
(
f
)
0
(
sf
)
0
(
'
f
s
)
0
(
f
s
)
s
(
F
s
)}
t
(
f
D
{
L )'
1
n
(
)'
2
n
(
)
2
n
(
)
1
n
(
n
n 








 
NOTE: to take
you need the value of t=0 for
called initial conditions!
We will use this to solve differential equations!



)
t
(
f
),
t
(
Df
),...
t
(
f
D
),
t
(
f
D 2
n
1
n
)}
t
(
f
D
{
L n
PROPERTIES: NTH ORDER
DERIVATIVES
PROPERTIES: NTH ORDER
DERIVATIVES
)
0
(
f
)
s
(
sF
)}
t
(
Df
{
L 

)}
t
(
f
D
{
L 2
)
0
(
f
)
s
(
sF
)}
t
(
Df
{
L
)}
t
(
g
{
L
)
s
(
G
)
0
(
'
f
)
0
(
g
)
t
(
Df
)
t
(
g
)
0
(
g
)
s
(
sG
)}
t
(
Dg
{
L
)
t
(
f
D
)
t
(
Dg
and
)
t
(
Df
)
t
(
g 2











)
0
(
'
f
)
0
(
sf
)
s
(
F
s
)
0
(
'
f
)]
0
(
f
)
s
(
sF
[
s
)
0
(
g
)
s
(
sG
)}
t
(
Dg
{
L 2









.
etc
),
t
(
f
D
),
t
(
f
D 4
3
Start with
Now apply again
let
then
remember
Can repeat for
)
0
(
f
)
0
(
sf
)
0
(
'
f
s
)
0
(
f
s
)
s
(
F
s
)}
t
(
f
D
{
L )'
1
n
(
)'
2
n
(
)
2
n
(
)
1
n
(
n
n 








 
REAL WORLD APPLICATIONS OF
LAPLACE TRANSFORM
• A simple Laplace Transform is conducted while sending
signals over any two-way communication medium
(FM/AM stereo, 2-way radio sets, cellular phones).
When information is sent over medium such as cellular
phones, they are first converted into time-varying wave,
and then it is super-imposed on the medium. In this
way, the information propagates. Now, at the receiving
end, to decipher the information being sent, medium
wave’s time functions are converted to frequency
functions.
MORE EXAMPLE
• Laplace transform is crucial for the study of
control systems, hence they are used for the
analysis of HVAC (Heating, Ventilation and Air
Conditioning) control systems, which are used in
all modern buildings and constructions
ENGINEERING APPLICATIONS OF
LAPLACE TRANSFORM
• System Modeling
• Analysis of Electrical Circuits
• Analysis of Electronic Circuits
• Digital Signal Processing
• Nuclear Physics
THANKS TO ALL


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Laplace Transform Guide

  • 2. WHY USE LAPLACE TRANSFORMS? • Find solution to differential equation using algebra • Relationship to Fourier Transform allows easy way to characterize systems • No need for convolution of input and differential equation solution • Useful with multiple processes in system
  • 3. HOW TO USE LAPLACE • Find differential equations that describe system • Obtain Laplace transform • Perform algebra to solve for output or variable of interest • Apply inverse transform to find solution
  • 4. WHAT ARE LAPLACE TRANSFORMS?                 j j st 1 0 st ds e ) s ( F j 2 1 )} s ( F { L ) t ( f dt e ) t ( f )} t ( f { L ) s ( F • t is real, s is complex! • Inverse requires complex analysis to solve • Note “transform”: f(t)  F(s), where t is integrated and s is variable • Conversely F(s)  f(t), t is variable and s is integrated
  • 5. EVALUATING F(S) = L{F(T)} • Hard Way – do the integral                             0 st 0 0 t ) a s ( st at at 0 st dt ) t sin( e ) s ( F t sin ) t ( f a s 1 dt e dt e e ) s ( F e ) t ( f s 1 ) 1 0 ( s 1 dt e ) s ( F 1 ) t ( f let let let Integrate by parts
  • 6. EVALUATING F(S)=L{F(T)}- HARD WAY remember     vdu uv udv ) t cos( v , dt ) t sin( dv dt se du , e u st st                            0 0 0 0 ) cos( ) 1 ( ) cos( ) cos( [ ) sin( ] dt t e s e dt t e s t e dt t e st st st st st ) t sin( v , dt ) t cos( dv dt se du , e u st st                           0 st st 0 st 0 st 0 st dt ) t sin( e s ) 0 ( e dt ) t sin( e s ) t sin( e [ dt ) t cos( e ] 2 0 st 0 st 2 0 0 st 2 st s 1 1 dt ) t sin( e 1 dt ) t sin( e ) s 1 ( dt ) t sin( e s 1 dt ) t sin( se                    let let Substituting, we get:
  • 7. EVALUATING F(S) = L{F(T)} • This is the easy way ... • Recognize a few different transforms • Learn a few different properties • Do a little math
  • 8. TABLE OF SELECTED LAPLACE TRANSFORMS 1 1 ) ( ) sin( ) ( 1 ) ( ) cos( ) ( 1 ) ( ) ( 1 ) ( 1 ) ( 2 2                 s s F t t f s s s F t t f a s s F e t f s s F t f at
  • 9. MORE TRANSFORMS 1 ! ) ( ) (     n n s n s F t t f 6 6 5 2 1 s 120 s ! 5 ) s ( F ) t ( u t ) t ( f , 5 n s ! 1 ) s ( F ) t ( tu ) t ( f , 1 n s 1 s ! 0 ) s ( F ) t ( u ) t ( f , 0 n              
  • 10. PROPERTIES OF LAPLACE TRANSFORMS • Linearity • Change of scale • Time Shift • “frequency” or s-plane shift • Multiplication by tn • Integration • Differentiation
  • 11. PROPERTIES: LINEARITY ) s ( F c ) s ( F c )} t ( f c ) t ( f c { L 2 2 1 1 2 2 1 1    Example : Proof : ) s ( F c ) s ( F c dt e ) t ( f c dt e ) t ( f c dt e )] t ( f c ) t ( f c [ )} t ( f c ) t ( f c { L 2 2 1 1 0 st 2 2 0 st 1 1 st 2 2 0 1 1 2 2 1 1                 1 1 ) 1 ) 1 ( ) 1 ( ( 2 1 ) 1 1 1 1 ( 2 1 } { 2 1 } { 2 1 } 2 1 2 1 { )} {sinh( 2 2                  s s s s s s e L e L e e L t L t t t t
  • 12. ) a s ( F a 1 )} at ( f { L  Example : 2 2 2 2 2 2 s ) s ( 1 ) 1 ) s ( 1 ( 1 )} t {sin( L              Proof : ) a s ( F a 1 du e ) u ( f a 1 du a 1 dt , a u t , at u dt e ) at ( f )} at ( f { L a 0 u ) a s ( 0 st             let PROPERTIES: CHANGE OF SCALE
  • 13. PROPERTIES: TIME SHIFT ) s ( F e )} t t ( u ) t t ( f { L 0 st 0 0     Example : a s e t u e L s t a       10 ) 10 ( )} 10 ( { Proof : ) s ( F e du e ) u ( f e du e ) u ( f t u t , t t u dt e ) t t ( f dt e ) t t ( u ) t t ( f )} t t ( u ) t t ( f { L 0 0 0 0 0 st 0 su st t 0 ) t u ( s 0 0 t st 0 0 st 0 0 0 0                               let
  • 14. PROPERTIES: S-PLANE (FREQUENCY) SHIFT ) a s ( F )} t ( f e { L at    Example : 2 2 at ) a s ( )} t sin( e { L        Proof : ) a s ( F dt e ) t ( f dt e ) t ( f e )} t ( f e { L 0 t ) a s ( 0 st at at             
  • 15. PROPERTIES: MULTIPLICATION BY tn ) s ( F ds d ) 1 ( )} t ( f t { L n n n n   Example : 1 n n n n n s ! n ) s 1 ( ds d ) 1 ( )} t ( u t { L     Proof : ) s ( F s ) 1 ( dt e ) t ( f s ) 1 ( dt e s ) t ( f ) 1 ( dt e t ) t ( f dt e ) t ( f t )} t ( f t { L n n n 0 st n n n 0 st n n n 0 st n 0 st n n                          
  • 16. THE “D” OPERATOR 1. Differentiation shorthand 2. Integration shorthand ) t ( f dt d ) t ( f D dt ) t ( df ) t ( Df 2 2 2   ) t ( f ) t ( Dg dt ) t ( f ) t ( g t     ) t ( f D ) t ( g dt ) t ( f ) t ( g 1 a t a     if then then if
  • 17. PROPERTIES: INTEGRALS s s F t f D L ) ( )} ( { 1 0   Example : )} t {sin( L 1 s 1 ) 1 s s )( s 1 ( )} t cos( D { L 2 2 1 0      Proof : let st st 0 st 1 0 e s 1 v , dt e dv dt ) t ( f du ), t ( g u dt e ) t ( g )} t {sin( L ) t ( f D ) t ( g                        t 0 st 0 st dt ) t ( f ) t ( g s ) s ( F dt e ) t ( f s 1 ] e ) t ( g s 1 [         0 ) ( ) ( dt e t f t st If t=0, g(t)=0 for so slower than      0 ) ( ) ( t g dt t f 0  st e
  • 18. PROPERTIES: DERIVATIVES (THIS IS THE BIG ONE) ) 0 ( f ) s ( sF )} t ( Df { L    Example : )} t sin( { L 1 s 1 1 s ) 1 s ( s 1 1 s s ) 0 ( f 1 s s )} t cos( D { L 2 2 2 2 2 2 2 2                Proof : ) s ( sF ) 0 ( f dt e ) t ( f s )] t ( f e [ ) t ( f v , dt ) t ( f dt d dv se du , e u dt e ) t ( f dt d )} t ( Df { L 0 st 0 st st st 0 st                      let
  • 19. DIFFERENCE IN • The values are only different if f(t) is not continuous at t=0 • Example of discontinuous function: u(t) ) 0 ( f & ) 0 ( f ), 0 ( f   1 ) 0 ( u ) 0 ( f 1 ) t ( u lim ) 0 ( f 0 ) t ( u lim ) 0 ( f 0 t 0 t            
  • 20. ? )} t ( f D { L 2  ) 0 ( ' f ) 0 ( sF ) s ( F s ) 0 ( ' f )) 0 ( f ) s ( sF ( s ) 0 ( ' f )} t ( Df { sL ) 0 ( g ) s ( sG )} t ( g D { L ) 0 ( ' f ) 0 ( Df ) 0 ( g ), t ( Df ) t ( g 2 2               let ) 0 ( f ) 0 ( sf ) 0 ( ' f s ) 0 ( f s ) s ( F s )} t ( f D { L )' 1 n ( )' 2 n ( ) 2 n ( ) 1 n ( n n            NOTE: to take you need the value of t=0 for called initial conditions! We will use this to solve differential equations!    ) t ( f ), t ( Df ),... t ( f D ), t ( f D 2 n 1 n )} t ( f D { L n PROPERTIES: NTH ORDER DERIVATIVES
  • 21. PROPERTIES: NTH ORDER DERIVATIVES ) 0 ( f ) s ( sF )} t ( Df { L   )} t ( f D { L 2 ) 0 ( f ) s ( sF )} t ( Df { L )} t ( g { L ) s ( G ) 0 ( ' f ) 0 ( g ) t ( Df ) t ( g ) 0 ( g ) s ( sG )} t ( Dg { L ) t ( f D ) t ( Dg and ) t ( Df ) t ( g 2            ) 0 ( ' f ) 0 ( sf ) s ( F s ) 0 ( ' f )] 0 ( f ) s ( sF [ s ) 0 ( g ) s ( sG )} t ( Dg { L 2          . etc ), t ( f D ), t ( f D 4 3 Start with Now apply again let then remember Can repeat for ) 0 ( f ) 0 ( sf ) 0 ( ' f s ) 0 ( f s ) s ( F s )} t ( f D { L )' 1 n ( )' 2 n ( ) 2 n ( ) 1 n ( n n           
  • 22. REAL WORLD APPLICATIONS OF LAPLACE TRANSFORM • A simple Laplace Transform is conducted while sending signals over any two-way communication medium (FM/AM stereo, 2-way radio sets, cellular phones). When information is sent over medium such as cellular phones, they are first converted into time-varying wave, and then it is super-imposed on the medium. In this way, the information propagates. Now, at the receiving end, to decipher the information being sent, medium wave’s time functions are converted to frequency functions.
  • 23. MORE EXAMPLE • Laplace transform is crucial for the study of control systems, hence they are used for the analysis of HVAC (Heating, Ventilation and Air Conditioning) control systems, which are used in all modern buildings and constructions
  • 24. ENGINEERING APPLICATIONS OF LAPLACE TRANSFORM • System Modeling • Analysis of Electrical Circuits • Analysis of Electronic Circuits • Digital Signal Processing • Nuclear Physics