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ELECTROCHEMISTRY
By
Mr. Abdulwakil Daudi
(MSc. BSc)
MNARA HIGH SCHOOL
INTRODUCTION
• Electrochemistry is a branch of Chemistry, which deals with
the interaction of electricity and chemical reactions. The
chemical reactions involved are called Redox reactions.
• Either:-
 Redox reactions occur to generate electric current as in
Electrochemical/ Voltaic/Galvanic cell. Galvanic cells
convert chemical energy into electrical energy
 Electric current causes redox reactions to occur as in
Elelectrolytic cells. Electrolytic cells convert electrical
energy into chemical
energy.
Galvanic Cell
Electrolytic cell
REDUCTION AND OXIDATION (REDOX)
REACTIONS
Redox reactions are reactions in which both oxidation
and reduction reactions occurs simultaneously. Redox
reactions can be defined in terms of
• Oxygen transfer
• Hydrogen transfer, or
• electron transfer.
In this unit, electron transfer will be considered.
In teams of oxygen transfer:
• Reduction is removal of oxygen; Oxidation is
addition of oxygen; Redox is simultaneous
addition and removal of oxygen.
• e.g. Hydrogen reduces hot copper(II)oxide to
copper metal, when passed over it and itself
oxidised to water as in the equation below:
• CuO (s) + H2 (g) Cu (s) + H2O (l)
In terms of hydrogen transfer:
• Oxidation is the removal of hydrogen;
Reduction is the addition of hydrogen; Redox
is simultaneous addition and removal of
hydrogen.
• e.g. Hydrogen sulphide gas is oxidized (loose
the hydrogen) to sulphur when mixed with
chlorine gas The chlorine is reduced (gain
hydrogen) to hydrogen chlorine gas.
• Cl2 (g) + H2S (g) S(S) + 2HCl (g)
In terms of electron transfer
• Oxidation is loss/ removal of electrons.
Recall: OIL for Oxidation Is Loss of electrons.
O - Oxidation
I - Is
L - Loss of electrons
• Metals ionizes by loss of electrons to form
positively charged ions.
Na(s) → Na+(aq) + e-
• Non-metallic ions also lose electrons to form
neutral elements as shown below.
2O2-(aq) → O2 (g) + 4e-
In terms of electron transfer
• Reduction is gain/ addition of electrons.
Recall: RIG for Reduction Is Gain of electrons
R - Reduction
I - Is
G - Gain of electrons
• Non-metals gain electrons to form anions
Non-metals: I2 (g) + 2e- → 2I- (aq)
• Metallic cations will gain electrons to form metals
Cations: Ca2+(aq) + 2e- → Ca(s)
In terms of electron transfer
• Redox is the simultaneous gaining and losing of
electrons in a chemical process. Example
CuO (s) + H2 (g) → Cu (s) + H2O (l)
• CuO is undergoing reduction. Cu in CuO occurs as
Cu2+ and will gain electrons (RIG) hence undergo
reduction.
Cu2+(s) + 2e- → Cu (s)
• Hydrogen gas is undergoing oxidation. H2 is losing
electrons to form H+ ions hence oxidation.
H2 (g) → 2H+(l) + 2e-
• Therefore, in redox reactions, both reduction and
oxidation reactions occur simultaneously.
Reducing and Oxidising Agents
• Reducing agent is the species that undergoes
oxidation and therefore it loses electrons. e.g.
as in above H2.
• Oxidizing agent is the species that undergoes
reduction and therefore it gains electrons. e.g.
CuO.
CuO (s) + H2 (g) → Cu (s) + H2O (l)
Oxidizing agent Reducing agent
Results and Discussions
DEISPLACEMENT REACTIONS
• A displacement reaction is a type of reaction in
which part of one reactant is replaced by another
reactant. They are sometimes referred to as
replacement reaction and include:
• Metal- Acid reaction- Displacement of hydrogen
with metal above it in reactivity series.
• Metal- Metal ion Reaction- Displacement of a
cation with a metal above it in reactivity series.
• Halogen-Halogen ion Displacement-
Displacement of anionic halogen with a halogen
above it in reactivity series.
Reactivity Series of Metals
Displacement of Hydrogen from Acid
• Magnesium metal reacts with hydrochloric acid to
produce hydrogen gas. Magnesium replaces
hydrogen ions in acid to form a salt of that acid.
 Chemical Equation:
Mg(s)+2HCl (aq) MgCl2 (aq) + H2 (g)
 Ionic equation:
Mg(s) + 2H+ (aq) Mg2+ (aq) + H2 (g)
• Redox reaction: Mg is oxidized from Mg (0) to
Mg2+(+2) by loss of electrons. Hydrogen is reduced
from H+(+) to H2(0) by gain of electrons.
• Metals like Cu, Hg, Ag, and Au are below hydrogen
on reactivity series hence cannot displace it.
Displacement of Hydrogen from Acid
Mg + H+Cl- Mg2+2Cl- + H2
H+ gains e- (Reduction)
Mg losses e- ( Oxidation)
Displacement of Metals from Solution
• Experiment
• When about 1g copper, zinc and magnesium
powders are added into three separate test
tubes each containing Iron (II) sulphate
displacement reactions occur in some.
Metal added to Iron (II)
sulphate solution
Colour changes
Copper Solution remains green
Zinc Green colour fades
Magnesium Green colour fades
Results of Displacenment
• A less reactive metal does not displace a more
reactive metal from its solution.
• Thus Cu cannot displace Fe2+ ions from its
solution.
• A more reactive metal displaces a less reactive
metal from its solution.
• Zn and Mg are more reactive than Fe hence
displace Fe2+ from its solution.
 FeSO4 (aq) + Zn(s) ZnSO4 (aq) + Fe(s)
 FeSO4 (aq) + Mg(s) MgSO4 (aq) + Fe(s)
Displacement in terms of electron transfer
• The more reactive metal undergoes oxidation by loss of
electrons to form ions. It is a reducing agent or reductant.
• The less reactive metal ions undergoes reduction by gain of
electrons to form the metal. It is an oxidizing agent or
oxidant.
• Displacement of metals involves electron transfer from a
more reactive metal to ions of another less reactive metal.
 Zn(s) Zn2+(aq) + 2e (oxidation)
Fe2+(aq) + 2e- Fe(s) (reduction)
Fe2+(aq) + Zn(s) Zn2+(aq) + Fe(s) (redox reaction)
 Mg(s) Mg2+(aq) + 2e (oxidation)
Fe2+(aq) + 2e Fe(s) (reduction)
Fe2+(aq) + Mg(s) Mg2+(aq) + Fe(s) (redox reaction)
Summary of Displacement of Metals
M Mn+ + ne-
• The forward reaction is oxidation
• The backward reaction is reduction
Mn+ gains e- (Reduction)
M losses e- ( Oxidation)
Displacement of Halides by Halogens
• Halogen solutions are prepared by dissolving them in
water to form halogen water (eg chlorine water).
X2(aq) + H2O(l) → HX(aq) + HOX(aq)
Halogen water
• Chlorine water is added to KCl, KBr and KI solutions,
but there will be no reaction with KCl. However, Cl2
displaces Br- and I- in KBr and KI respectively, because
it is higher on reactivity series hence more reactive.
• Bromine water is added to KCl, KBr and KI solutions,
but there will be no reaction with KCl and KBr.
However, Br2 displaces I- in KI, because it is higher on
reactivity series than it hence more reactive.
• iodine water is added to KCl, KBr and KI solutions, but
there will be no reaction. Iodine is least reactive, hence
cannot displace halides above it from their solutions.
Displacement of Halides by Halogens
Halogen Colour after shaking
with CCl4
Reactio
n with
KCl
solution
Reaction with
KBr solution
Reaction with
KI solution
Chlorine
water
Aqueous layer: pale
yellow-green
Hydrocarbon layer:
pale yellow-green
No
reaction
The yellow-
orange colour
of bromine
appears
The brown
colour of iodine
appears
Bromine
water
Aqueous layer:
yellow-orange
Hydrocarbon layer:
pale yellow-orange
No
reaction
No reaction Colour darkens
from yellow-
orange to
brown
Iodine
solution
Aqueous layer: brown
Hydrocarbon layer:
Purple
No
reaction
No reaction No reaction
Displacement of Halides by Halogens
• Iodine colour change is clear, from brown in water to
purple in the hydrocarbon layer.
• Iodine is the least soluble in water but more soluble in KI
solution, so the ‘iodine solution’ here is actually iodine in
KI solution.
• Chlorine displaces both bromine and iodine from their
halides and bromine displaces iodine from iodide:
• Cl2(aq) + 2KI(aq) → I2(aq) + 2KCl(aq)
Cl2(aq) + 2I- (aq) → I2(aq) + 2Cl- (aq) (Redox)
Cl2(aq) + 2e- (aq) → 2Cl- (aq) (Reduction)
2I- (aq) → I2(aq) + 2e- (aq) (Oxidation)
• Cl2(aq) + 2Br- (aq) → Br2(aq) + 2Cl- (aq)
• Br2(aq) + 2I- (aq) → I2(aq) + 2Br- (aq)
Displacement of Halides by Halogens
Displacement of Halides by Halogens
• The order of reactivity is
therefore
Cl2 > Br2 > I2.
• Therefore, Cl2 is an oxidizing
agent with both KI and KBr
while Br2 is an oxidizing agent
for KI. The respective halides
are reducing agents.
• Cl2(aq) + 2e- → + 2Cl- (aq)
• 2I- (aq) → I2(aq) + 2e- (aq)
Summary of Displacement Reactions

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Electrochemistry presentation 1

  • 2. INTRODUCTION • Electrochemistry is a branch of Chemistry, which deals with the interaction of electricity and chemical reactions. The chemical reactions involved are called Redox reactions. • Either:-  Redox reactions occur to generate electric current as in Electrochemical/ Voltaic/Galvanic cell. Galvanic cells convert chemical energy into electrical energy  Electric current causes redox reactions to occur as in Elelectrolytic cells. Electrolytic cells convert electrical energy into chemical energy.
  • 5. REDUCTION AND OXIDATION (REDOX) REACTIONS Redox reactions are reactions in which both oxidation and reduction reactions occurs simultaneously. Redox reactions can be defined in terms of • Oxygen transfer • Hydrogen transfer, or • electron transfer. In this unit, electron transfer will be considered.
  • 6. In teams of oxygen transfer: • Reduction is removal of oxygen; Oxidation is addition of oxygen; Redox is simultaneous addition and removal of oxygen. • e.g. Hydrogen reduces hot copper(II)oxide to copper metal, when passed over it and itself oxidised to water as in the equation below: • CuO (s) + H2 (g) Cu (s) + H2O (l)
  • 7. In terms of hydrogen transfer: • Oxidation is the removal of hydrogen; Reduction is the addition of hydrogen; Redox is simultaneous addition and removal of hydrogen. • e.g. Hydrogen sulphide gas is oxidized (loose the hydrogen) to sulphur when mixed with chlorine gas The chlorine is reduced (gain hydrogen) to hydrogen chlorine gas. • Cl2 (g) + H2S (g) S(S) + 2HCl (g)
  • 8. In terms of electron transfer • Oxidation is loss/ removal of electrons. Recall: OIL for Oxidation Is Loss of electrons. O - Oxidation I - Is L - Loss of electrons • Metals ionizes by loss of electrons to form positively charged ions. Na(s) → Na+(aq) + e- • Non-metallic ions also lose electrons to form neutral elements as shown below. 2O2-(aq) → O2 (g) + 4e-
  • 9. In terms of electron transfer • Reduction is gain/ addition of electrons. Recall: RIG for Reduction Is Gain of electrons R - Reduction I - Is G - Gain of electrons • Non-metals gain electrons to form anions Non-metals: I2 (g) + 2e- → 2I- (aq) • Metallic cations will gain electrons to form metals Cations: Ca2+(aq) + 2e- → Ca(s)
  • 10. In terms of electron transfer • Redox is the simultaneous gaining and losing of electrons in a chemical process. Example CuO (s) + H2 (g) → Cu (s) + H2O (l) • CuO is undergoing reduction. Cu in CuO occurs as Cu2+ and will gain electrons (RIG) hence undergo reduction. Cu2+(s) + 2e- → Cu (s) • Hydrogen gas is undergoing oxidation. H2 is losing electrons to form H+ ions hence oxidation. H2 (g) → 2H+(l) + 2e- • Therefore, in redox reactions, both reduction and oxidation reactions occur simultaneously.
  • 11. Reducing and Oxidising Agents • Reducing agent is the species that undergoes oxidation and therefore it loses electrons. e.g. as in above H2. • Oxidizing agent is the species that undergoes reduction and therefore it gains electrons. e.g. CuO. CuO (s) + H2 (g) → Cu (s) + H2O (l) Oxidizing agent Reducing agent
  • 13. DEISPLACEMENT REACTIONS • A displacement reaction is a type of reaction in which part of one reactant is replaced by another reactant. They are sometimes referred to as replacement reaction and include: • Metal- Acid reaction- Displacement of hydrogen with metal above it in reactivity series. • Metal- Metal ion Reaction- Displacement of a cation with a metal above it in reactivity series. • Halogen-Halogen ion Displacement- Displacement of anionic halogen with a halogen above it in reactivity series.
  • 15. Displacement of Hydrogen from Acid • Magnesium metal reacts with hydrochloric acid to produce hydrogen gas. Magnesium replaces hydrogen ions in acid to form a salt of that acid.  Chemical Equation: Mg(s)+2HCl (aq) MgCl2 (aq) + H2 (g)  Ionic equation: Mg(s) + 2H+ (aq) Mg2+ (aq) + H2 (g) • Redox reaction: Mg is oxidized from Mg (0) to Mg2+(+2) by loss of electrons. Hydrogen is reduced from H+(+) to H2(0) by gain of electrons. • Metals like Cu, Hg, Ag, and Au are below hydrogen on reactivity series hence cannot displace it.
  • 16. Displacement of Hydrogen from Acid Mg + H+Cl- Mg2+2Cl- + H2 H+ gains e- (Reduction) Mg losses e- ( Oxidation)
  • 17. Displacement of Metals from Solution • Experiment • When about 1g copper, zinc and magnesium powders are added into three separate test tubes each containing Iron (II) sulphate displacement reactions occur in some. Metal added to Iron (II) sulphate solution Colour changes Copper Solution remains green Zinc Green colour fades Magnesium Green colour fades
  • 18. Results of Displacenment • A less reactive metal does not displace a more reactive metal from its solution. • Thus Cu cannot displace Fe2+ ions from its solution. • A more reactive metal displaces a less reactive metal from its solution. • Zn and Mg are more reactive than Fe hence displace Fe2+ from its solution.  FeSO4 (aq) + Zn(s) ZnSO4 (aq) + Fe(s)  FeSO4 (aq) + Mg(s) MgSO4 (aq) + Fe(s)
  • 19. Displacement in terms of electron transfer • The more reactive metal undergoes oxidation by loss of electrons to form ions. It is a reducing agent or reductant. • The less reactive metal ions undergoes reduction by gain of electrons to form the metal. It is an oxidizing agent or oxidant. • Displacement of metals involves electron transfer from a more reactive metal to ions of another less reactive metal.  Zn(s) Zn2+(aq) + 2e (oxidation) Fe2+(aq) + 2e- Fe(s) (reduction) Fe2+(aq) + Zn(s) Zn2+(aq) + Fe(s) (redox reaction)  Mg(s) Mg2+(aq) + 2e (oxidation) Fe2+(aq) + 2e Fe(s) (reduction) Fe2+(aq) + Mg(s) Mg2+(aq) + Fe(s) (redox reaction)
  • 20. Summary of Displacement of Metals M Mn+ + ne- • The forward reaction is oxidation • The backward reaction is reduction Mn+ gains e- (Reduction) M losses e- ( Oxidation)
  • 21. Displacement of Halides by Halogens • Halogen solutions are prepared by dissolving them in water to form halogen water (eg chlorine water). X2(aq) + H2O(l) → HX(aq) + HOX(aq) Halogen water • Chlorine water is added to KCl, KBr and KI solutions, but there will be no reaction with KCl. However, Cl2 displaces Br- and I- in KBr and KI respectively, because it is higher on reactivity series hence more reactive. • Bromine water is added to KCl, KBr and KI solutions, but there will be no reaction with KCl and KBr. However, Br2 displaces I- in KI, because it is higher on reactivity series than it hence more reactive. • iodine water is added to KCl, KBr and KI solutions, but there will be no reaction. Iodine is least reactive, hence cannot displace halides above it from their solutions.
  • 22. Displacement of Halides by Halogens Halogen Colour after shaking with CCl4 Reactio n with KCl solution Reaction with KBr solution Reaction with KI solution Chlorine water Aqueous layer: pale yellow-green Hydrocarbon layer: pale yellow-green No reaction The yellow- orange colour of bromine appears The brown colour of iodine appears Bromine water Aqueous layer: yellow-orange Hydrocarbon layer: pale yellow-orange No reaction No reaction Colour darkens from yellow- orange to brown Iodine solution Aqueous layer: brown Hydrocarbon layer: Purple No reaction No reaction No reaction
  • 23. Displacement of Halides by Halogens • Iodine colour change is clear, from brown in water to purple in the hydrocarbon layer. • Iodine is the least soluble in water but more soluble in KI solution, so the ‘iodine solution’ here is actually iodine in KI solution. • Chlorine displaces both bromine and iodine from their halides and bromine displaces iodine from iodide: • Cl2(aq) + 2KI(aq) → I2(aq) + 2KCl(aq) Cl2(aq) + 2I- (aq) → I2(aq) + 2Cl- (aq) (Redox) Cl2(aq) + 2e- (aq) → 2Cl- (aq) (Reduction) 2I- (aq) → I2(aq) + 2e- (aq) (Oxidation) • Cl2(aq) + 2Br- (aq) → Br2(aq) + 2Cl- (aq) • Br2(aq) + 2I- (aq) → I2(aq) + 2Br- (aq)
  • 24. Displacement of Halides by Halogens
  • 25. Displacement of Halides by Halogens • The order of reactivity is therefore Cl2 > Br2 > I2. • Therefore, Cl2 is an oxidizing agent with both KI and KBr while Br2 is an oxidizing agent for KI. The respective halides are reducing agents. • Cl2(aq) + 2e- → + 2Cl- (aq) • 2I- (aq) → I2(aq) + 2e- (aq)