Motivasi maths tahun 5 2010 k2

2. MATEMATIK KERTAS 2

4. 2 436 ÷ 12 = 12 ) 2 436 - 2 THN 5 2009 2 4 0 0 3 0 0 - 3 6 3 36 00 - 2 1 4 2 6 3 8 4 0 6 +1 2 7 4 8 6 9 8 0 +1 1 x 1 2 1 2 3 4 5 6 7 8 9

5. 1 2 3 4 5 6 7 8 9 2 3 4 5 6 7 8 9 4 6 8 10 12 14 16 18 6 8 10 12 14 16 18 9 12 15 18 21 24 27 12 15 18 21 24 27 16 20 24 28 32 36 20 24 28 32 36 25 30 35 40 45 30 35 40 45 36 42 48 54 42 48 54 49 56 63 56 63 64 72 72 81 x 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9

6. 1 2 3 4 5 6 7 8 9 8 6 4 2 0 8 6 4 2 0 1 2 3 4 4 5 6 7 +1 +1 +1 +1 +1 +1 +1 9 7 0 +1 +1 8 5 1 +1 +1 7 3 2 +1 +1 6 1 3 +1 +1 5 9 3 +1 4 7 4 +1 +1 3 5 5 +1 +1 2 3 6 +1 +1 1 1 7 x 8 1 1 2 3 4 5 6 7 8 9 x 7 9 1 2 3 4 5 6 7 8 9

7. Diagram 1 shows two square of equal size. Each square is divided into 4 equal parts. Rajah 1 menunjukkan dua buah segi empat sama yang sama saiz. Setiap segi empat sama dibahagikan kepada 4 bahagian yang sama besar. THN 5 2009 Diagram 1 Rajah 1 State improper fraction of the shaded parts. Nyatakan pecahan tak wajar bagi kawasan berlorek. 4 4 3 4 + = 7 4

9. Diagram 2 shows a digital clock. Rajah 2 menunjukkan sebuah jam digital. THN 5 2009 Diagram 2 Rajah 2 State the time, in 12-hour system. Nyatakan waktu, dalam sistem 12 jam. 2 1 : 3 0 - 9 3 0 = 9 : 30 p.m. Jam Minit Jam Minit 1 2 0 0

10. Convert 5 km to m. 8 Tukarkan 5 km kepada m 8 THN 5 2009 = 625 m = 5 x 1 000 8 1 = 5 000 8 0 0 0 5 8 6 - 2 0 2 - 4 0 5 - 0 0 km 1 m 1 000 km 1 m 1 000 8 4 1 6 4 0

11. State 2 in percentage. 8 Nyatakan 2 dalam peratus. 8 THN 5 2009 = 25 = 2 x 100 8 1 = 200 8 0 0 2 8 2 - 4 0 5 - 0 0 1 6 4 0

12. 2 marks 405 x 24 ÷ 3 = 4 0 5 x 2 4 THN 5 2009 0 +2 2 1 6 0 1 8 +1 + 0 2 7 9 3 ) 9 720 - 3 9 0 2 4 7 6 - 1 2 12 - 00 0 0 - 0 0

13. Diagram 3 shows a combination of two squares. Rajah 3 menunjukkan satu gabungan dua buah segi empat sama. THN 5 2009 Diagram 3 Rajah 3 Calculate the perimeter of the whole diagram. Hitung perimeter bagi seluruh rajah itu. 12 cm 8 cm 8 cm 12 cm 12 cm 8 cm Perimeter = - 8 4 4 cm 4 8 8 8 + +3 4 6 = 64 cm 1 2 1 2 1 2 1 2

14. 320.31 - 17.156 = THN 5 2009 • • 0 2 3 3 1 • 7 1 1 5 6 - 0 0 +10 4 2 +10 5 1 1 +10 3 0 3 = 303.154 •

15. A box contain 12 pencils. How many pencils are there in 150 similar boxes? Sebuah kotak mengandungi 12 batang pensel. Berapa batangkah pensel yang Terdapat dalam 150 kotak yang sama? THN 5 2009 Cara penyelesaian : 12 12 12 + 24 1 2 0 5 1 x 0 +1 0 6 2 1 + 0 0 8 1 = 1 800

16. 3 of 232 = 8 3 daripada 232 = 8 THN 5 2009 = 87 = 3 x 232 8 1 = 696 8 6 9 6 8 8 - 5 6 7 - 0 0 2 3 2 x 3 6 9 6 6 4 5 6

17. 3 hours 20 minutes ÷ 2 = Give the answer, in minutes. 3 jam 20 minit ÷ 2 = Beri jawapan, dalam minit. THN 5 2009 0 2 3 2 2 1 - 1 0 4 - 8 0 0 0 - 0 0 + 8 1 4 0 6 0 + 0 1 0 = 100 minit jam 1 minit 60 jam 1 minit 60 6 0 jam 1 minit 60

18. 6 - 2 = 7 THN 5 2009 = 7 7 5 = - 2 7 5 7 5

19. Diagram 4 shows the mass of a kettle. Rajah 4 menunjukkan jisim sebuah cerek. THN 5 2009 Diagram 4 Rajah 4 State the mass, in kg. Nyatakan jisim, dalam kg. 2 • = 7 10 x 1 000 1 = 7 000 10 = 700 0 7 0 = 2.7 kg kg 1 gram 1 000 kg 1 gram 1 000

20. Diagram 5 shows the volume of orange juice in a jug. Rajah 5 menunjukkan isipadu jus oren dalam sebuah jag. THN 5 2009 Diagram 5 Rajah 5 Jenny drank 1 l of the orange juice. 5 Calculate the volume, in m l , the remaining orange juice in the jug. Jenny minum 1 l daripada jus oren itu. 5 Hitung isipadu, dalam m l , baki jus oren di dalam jag itu.

21. • 7 2 0 0 = 1 5 x 2.700 1 = 2.700 5 = 2 160 7 2 0 0 5 5 - 2 0 4 - 0 0 0 0 - 0 • m l - 1 6 0 6 +10 2 l 1 m l 1 000 l 1 m l 1 000 l 1 m l 1 000 5 2 0 2 l 1 m l 1 000 ` 7 2 0 0 5 4 0

22. Table 1 shows the price of two types of food at the school canteen. Jadual 1 menunjukkan harga bagi dua jenis makanan di kantin sekolah. THN 5 2009 A total of 7 pupils buy both types of food. How much money did they spend? Sejumlah 7 orang murid membeli kedua-dua jenis makanan tersebut. Berapakah jumlah wang yang telah mereka belanjakan? Table 1 Jadual 1 Type of Food Jenis makanan Price Harga Chicken burger Burger ayam RM1.50 Orange juice Jus oren 80 sen

23. 1 • 5 0 8 0 + +1 0 3 2 • x 7 0 1 +2 • = RM16.10 RM 1 sen 100 RM 1 sen 100 6 1

24. A factory produces 25 000 tins of milk every month continuously for 5 months. All the tins of milk are distributed equally to 8 supermarkets. How many tins of milk does each supermarket receive? Sebuah kilang menghasilkan 25 000 tin susu setiap bulan secara berterusan selama 5 bulan. Kesemua tin susu tersebut diedarkan secara sama rata kepada 8 buah pasaraya. Berapakah tin susu yang diterima oleh setiap pasaraya? THN 5 2009 1 bulan = 25 000 2 bulan = 25 000 + 25 000 = 50 000 5 bulan = x 5 5 0 0 0 +2 5 0 0 0 2 1 8 1 8 - 4 5 5 - 5 0 6 - 2 0 2 - 4 0 5 - 0 0 = 15 625 5 2 0 0 0 2 1 4 0 4 8 1 6 4 0

25. Puan Maria bought 30 m of cloth. She used 24 m of it to make curtains. What is the length of the cloth, in cm, is left? Puan Maria telah membeli 30 m kain. Dia menggunakan 24 m daripada kain itu untuk membuat langsir. Berapakah panjang kain yang tinggal, dalam cm? THN 5 2009 3 0 2 4 - 2 +10 6 0 0 = 600 cm m 1 cm 100 m 1 cm 100

26. Table 2 shows the number of doctors in two hospitals. Jadual 2 menunjukkan bilangan doktor bagi dua buah hospital. THN 5 2009 Calculate the average number of doctors in a hospital. Hitung purata doktor bagi sebuah hospital. Table 1 Jadual 1 Hospital Number of Doctors Bilangan Doktor R 53 S 4 less than R 4 kurang daripada R

27. Purata = Jumlah keseluruhan Bilangan 5 3 4 - 4 +10 9 4 + +1 2 2 5 - 2 1 2 - 0 = 51 R 5 3 S 9 4 0 1 2 0 1 0 1 0 0