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Finding the Vertex of a Parabola ,[object Object]
Example 1: ,[object Object],Completing the Square if the coefficient of x 2  is 1.
Example 1: ,[object Object],Completing the Square if the coefficient of x 2  is 1. f(x)=(x 2 -4x  )+3 Separate the x-terms
Example 1:  Continued ,[object Object],f(x)=(x 2 -4 x  )+3 Square half of the coefficient of x (  ) -4 2 2 =4 __
Example 1:  Continued ,[object Object],-4 2 f(x)=(x 2 -4x  )+3 (  ) 2 = 4 f(x)=(x 2 -4x  + 4 )+3 -4 Add this constant inside the parentheses, and subtract it on the outside
Example 1:  Continued ,[object Object],f(x)=(x 2 -4x + 4)+3-4
Example 1:  Continued ,[object Object],f(x)=( x 2 -4x + 4 )+3-4 The expression in the parentheses is a perfect square trinomial
Example 1:  Continued ,[object Object],f(x)=( x 2 -4x + 4 )+3-4 Factor it! f(x)=( x-2 )( x -2 )+3-4
Example 1:  Continued ,[object Object],f(x)=(x 2 -4x + 4)+3-4 Simplify the right side f(x)=(x-2)(x -2)+ 3-4 f(x)=(x-2) 2 -1
Example 1:  Continued ,[object Object],f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 -1
Example 1:  Continued ,[object Object],Subtraction is like  adding the opposite f(x)=(x-2) 2  + ( - 1) f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 - 1
Example 1:  Continued ,[object Object],f(x)=(x- 2 ) 2  +( -1 ) f(x)=(x- h ) 2 + k where (h,k) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1
Example 1:  Continued ,[object Object],f(x)=(x-2) 2  +(-1) f(x)=(x-h) 2 +k where ( h , k ) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1 Therefore, the vertex is ( 2 ,  -1 )
Example 1:  Completed Here is the graph of  f(x)=x 2 -4x+3 Vertex is (2, -1)
Example 2: ,[object Object],Completing the Square if the coefficient of x 2  is not 1.
Example 2:  Continued ,[object Object],f(x)=(-2x 2 -2 x  )+1 Separate the x-terms
Example 2:  Continued ,[object Object],f(x)=( -2 x 2 -2 x  )+1 Factor out the  coefficient of x 2 f(x)= -2 (x 2 + x  )+1
Example 2:  Continued ,[object Object],f(x)=(-2x 2 -2 x  )+1 f(x)= -2 (x 2 + 1 x  )+1 Square half of the coefficient of x (  ) 2 = __ 2 __ 4 1 1
Example 2:  Continued ,[object Object],__ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)= -2(x 2 +x+  )+1 Add this constant  inside the parentheses __ 4 1 __ 4 1
Example 2:  Continued ,[object Object],__ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)=   -2 (x 2 + x+  )+1 Notice we have really added  -2 (  ) to the  equation __ 4 1 __ 4 1 __ 4 1
Example 2:  Continued ,[object Object],__ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)=   -2 (x 2 + x+  )+1 -( -2 )(  ) Therefore, subtract  -2 (  )  to maintain the same equation __ 4 1 __ 4 1 __ 4 1 __ 4 1
Example 2:  Continued ,[object Object],__ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)= -2(x 2 +x+  )+ 1-(-2)(  ) Simplify f(x)= -2(x 2 +x+  )+ __ 4 1 __ 4 1 __ 4 1 __ 4 1 __ 2 3
Example 2:  Continued ,[object Object],3 f(x)= -2(x 2 +x+  )+ __ 4 1 __ 2
Example 2:  Continued ,[object Object],3 f(x)= -2( x 2 +x+  )+ __ 4 1 __ 2 The expression in the parentheses is a perfect square trinomial
Example 2:  Continued ,[object Object],3 f(x)= -2( x+  )( x +   )+ f(x)= -2( x 2 +x+   )+ __ 4 1 __ 2 Factor it! __ 2 1 __ 2 1 __ 2 3
Example 2:  Continued ,[object Object],3 Simplify the right side f(x)= -2( x+   )( x +   )+ f(x)=-2 ( x+   ) 2  + f(x)= -2(x 2 +x+  )+ __ 4 1 __ 2 __ 2 1 __ 2 1 __ 2 3 __ 2 3 __ 2 1
Example 2:  Continued ,[object Object],f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x+  ) 2   + __ 2 3 __ 2 1
Example 2:  Continued ,[object Object],f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x -   ) 2   + Change addition to  subtracting the opposite f(x)=-2 (x +   ) 2   + __ 2 3 __ 2 - 1  __ 2 3 __ 2 1
Example 2:  Continued ,[object Object],f(x)=a(x- h ) 2 + k where (h,k) is the vertex f(x)=-2 (x-  ) 2   + For our function, h=  and k= f(x)=-2 (x+  ) 2   + __ 2 3 __ 2 -1  __ 2 3 __ 2 -1  __ 2 3 __ 2 1
Example 2:  Continued ,[object Object],f(x)=a(x-h) 2 +k where ( h , k ) is the vertex f(x)=-2 (x-  ) 2   + For our function, h=  and k= f(x)=-2 (x+  ) 2   + Therefore, the vertex is (   ,  ) __ 2 3 __ 2 -1  __ 2 3 __ 2 -1  __ 2 3 __ 2 1 __ 2 -1  __ 2 3
Example 2:  Completed Here is the graph of  f(x)= -2x 2 -2x+1 Vertex is (   ,  ) __ 2 -1  __ 2 3

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Parabola

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  • 14. Example 1: Completed Here is the graph of f(x)=x 2 -4x+3 Vertex is (2, -1)
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  • 31. Example 2: Completed Here is the graph of f(x)= -2x 2 -2x+1 Vertex is ( , ) __ 2 -1 __ 2 3