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even though the answer is circle can you show they got those answer? thanks
4. The neutralization reaction between AI(OH)3 and HNO3 produces the salt with the formula
AJH20. B) A?NOg. C)A?H2. Al(NO3)3- E) NO3OH. 5. 25.0 mL of 0.212 M NaOH is
neutralized by 13.6 mL of an HCI solution. The molarity of the HC solution is A) 0.212 M. B)
0.115 M. C) 0.500 M. 0.390 M. E) 0.137 M. 6. What is the molarity of a KOH solution if 25.0
mL neutralizes 35.0 mL of a 0.200 M HCI solution? A) 0.267 M B)0.143 M C)0.200 M 280 M
E) 0.100 M 7. A 25.0 mL sample of H3PO4 requires 50.0 mL of 1.50 M NaOH for complete
neutralization. What is the molarity of the acid? H3PO4+3NaOH-Na3PO4+3H20 A) 0.333 M
B)3.00 M C)1.50 M D) 1.00 M E) 0.750 M How many milliliters of 0.400 M NaOH are required
to completely neutralize 20.0 mL of 0.200 M HCI? 8. A) 50.0 mL B) 40.0 mL ) 0.100 mL D)
20.0 mL ?ho.0 mL Answer: E Which of the following is a buffer system? A) NaCI and NaNO3
B) HCI and NaOH C) H2CO3 and KHCO3 9. D) NaCl and NaOH E) H20 and HCl C) the HF is
not necessary D) the F- neutralizes added H20. E) the F neutralizes added base. 10. In a buffer
system of HF and its salt, NaF A) the HF neutralizes added acid. B) the HF neutralizes added
base.
Solution
Ans 4 :
Ans : 4: D) Al(NO3)3
The reaction is given as :
Al(OH)3 + 3HNO3 = Al(NO3)3 + 3H2O
It is a neutralisation reaction , in which one mole of base reacts with 3 moles of acid , to give one
mole of salt and three moles of water.
even though the answer is circle can you show they got those answer- t.docx

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even though the answer is circle can you show they got those answer- t.docx

  • 1. even though the answer is circle can you show they got those answer? thanks 4. The neutralization reaction between AI(OH)3 and HNO3 produces the salt with the formula AJH20. B) A?NOg. C)A?H2. Al(NO3)3- E) NO3OH. 5. 25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCI solution. The molarity of the HC solution is A) 0.212 M. B) 0.115 M. C) 0.500 M. 0.390 M. E) 0.137 M. 6. What is the molarity of a KOH solution if 25.0 mL neutralizes 35.0 mL of a 0.200 M HCI solution? A) 0.267 M B)0.143 M C)0.200 M 280 M E) 0.100 M 7. A 25.0 mL sample of H3PO4 requires 50.0 mL of 1.50 M NaOH for complete neutralization. What is the molarity of the acid? H3PO4+3NaOH-Na3PO4+3H20 A) 0.333 M B)3.00 M C)1.50 M D) 1.00 M E) 0.750 M How many milliliters of 0.400 M NaOH are required to completely neutralize 20.0 mL of 0.200 M HCI? 8. A) 50.0 mL B) 40.0 mL ) 0.100 mL D) 20.0 mL ?ho.0 mL Answer: E Which of the following is a buffer system? A) NaCI and NaNO3 B) HCI and NaOH C) H2CO3 and KHCO3 9. D) NaCl and NaOH E) H20 and HCl C) the HF is not necessary D) the F- neutralizes added H20. E) the F neutralizes added base. 10. In a buffer system of HF and its salt, NaF A) the HF neutralizes added acid. B) the HF neutralizes added base. Solution Ans 4 : Ans : 4: D) Al(NO3)3 The reaction is given as : Al(OH)3 + 3HNO3 = Al(NO3)3 + 3H2O It is a neutralisation reaction , in which one mole of base reacts with 3 moles of acid , to give one mole of salt and three moles of water.