UNIAXIAL

1. UNIAXIAL (PERSEGI)
Grafik Kolom Uniaxial Bending (PERSEGI) Poly Ordo = 4
fc' = 27.58 Mpa 4 ksi
fy = 413.69 Mpa 60 ksi
b = 300 mm 12 in
h = 450 mm 18 in
N = 4 jumlah baris
Atot = 6080 mm² 9.42478 in
2
Pu = 738.4 kN 166 kip
Mux = 187.1 kNm 138 kipft
Muy = 74.57 kNm 55 kipft
Ø = 0.7
Result
Po = (0.85 fc') (Ag - Ast) + fy (Ast) =
(0.85*27.58)(135000 - 6080) + 413.69(6080) = 5537.5 kN
ex = Muy/Pu = 74570/738.4 = 101 mm 3.98 in
ey = Mux/Pu = 187100/738.4 = 253.4 mm 9.98 in
Py = 2499.85 kN 561.99 kip FindPx(fc, fy, h, b, N, At, ez)!! Fungsi Baru
Px = 1728.29 kN 388.54 kip FindPx(fc, fy, b, h, N,At, ez)!! Fungsi Baru
253.4
1728.29
101
2499.85
0
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Grafik : P - e
Toni Hartono Bagio 1

2. UNIAXIAL (PERSEGI)
Pn ≈ Pi = 1253.1 kN 281.71 kip
Mox = 464.49 kN-m 342.59 kipft
Moy = 309.66 kN-m 228.39 kipft
Pu = 0 kN → Mu =
Mu = 200 kN-m → Pu =
X C1 C2
X^0 0.397857 0.265421
X^1 0.130708 0.086528
X^2 -0.081135 -0.05357
X^3 0.013307 0.008723
X^4 -0.000955 -0.00062
1253.10
464.49309.66
4430
2880
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6000
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P - M
Toni Hartono Bagio 2

3. UNIAXIAL (PERSEGI)
Mnx = Pn * ey = 1253.1 * 0.2534 = 317.5 kN-m
Mny = Pn * ex = 1253.1 * 0.101 = 126.6 kN-m
BRESLER's
Penampang Persegi a = 1.5
(Mnx/Mox)
a
+ (Mny/Moy)
a
≤ 1
(317.5/464.49)^1.5 + (126.6/309.66)^1.5
0.826544 < 1
PARME
Mux = 187.1 kN-m (diketahui)
Mnx = Mux/Ø = 187.1/0.7 = 267.3 kN-m
Mox = 464.49 kN-m
Mnx/Mox = 267.3/464.49 = 0.5755
Muy = 74.57 kN-m (diketahui)
Mny = Muy/Ø = 74.57/0.7 = 106.5 kN-m
Moy = 309.66 kN-m
Mny/Moy = 106.5/309.66 = 0.3439
q = ρg. (fy/fc') = 6080/(300*450)*413.69/27.58
0.675539
Pn/Po = (738.4/0.7)/5537.5
0.190493
Mencari nilai β (dari grafik disamping)
β = 0.61
Pn/Po = 0.190493389
Check : q = 0.675539226
(Mnx/Mox) + (Mny/Moy)(1-β) / β ≤ 1
0.5755 + 0.3439*(1-0.61)/0.61 ≤ 1
0.79537 < 1 OK
0.19
0.61
Toni Hartono Bagio 3

4. UNIAXIAL (BULAT)
Grafik Kolom Uniaxial Bending (BULAT) Poly Ordo = 8
fc' = 28 Mpa 4 ksi
fy = 414 Mpa 60 ksi
h = 450 mm 18 in
N = 8 jumlah tulangan
Atot = 6000 mm² 9.42478 in
2
Pu = 750 kN 166 kip
Mux = 190 kNm 138 kipft
Muy = 75 kNm 55 kipft
Ø = 0.75
Result
Po = (0.85 fc') (Ag - Ast) + fy (Ast) =
(0.85*28)(159043 - 6000) + 414(6000) = 6126.4 kN
ex = Muy/Pu = 75000/750 = 100 mm 3.94 in
ey = Mux/Pu = 190000/750 = 253.3 mm 9.97 in
Py = 3211.14 kN 721.89 kip FindPx(fc, fy, h, b, N, At, ez)!! Fungsi Baru
Px = 1584.8 kN 356.28 kip FindPx(fc, fy, b, h, N,At, ez)!! Fungsi Baru
253.3
1584.8
100
3211.14
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Grafik : P - e
Toni Hartono Bagio 4

5. UNIAXIAL (BULAT)
Pn ≈ Pi = 1283.4 kN 288.52 kip
Mox = 400.67 kN-m 295.52 kipft
Moy = 400.67 kN-m 295.52 kipft
Pu = 0 kN → Mu =
Mu = 200 kN-m → Pu =
X C1 C2
X^0 0.335765 0.335765
X^1 0.062639 0.062639
X^2 0.012933 0.012933
X^3 -0.025691 -0.02569
X^4 0.004358 0.004358
X^5 0.000762 0.000762
X^6 -0.000227 -0.00023
X^7 2.08E-06 2.08E-06
X^8 1.67E-06 1.67E-06
1283.40
400.67400.67
4902
3187
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P - M
Toni Hartono Bagio 5

6. UNIAXIAL (BULAT)
Mnx = Pn * ey = 1283.4 * 0.2533 = 325.1 kN-m
Mny = Pn * ex = 1283.4 * 0.1 = 128.3 kN-m
BRESLER's
Penampang Persegi a = 1.5
(Mnx/Mox)
a
+ (Mny/Moy)
a
≤ 1
(325.1/400.67)^1.5 + (128.3/400.67)^1.5
0.912079 < 1
PARME
Mux = 190 kN-m (diketahui)
Mnx = Mux/Ø = 190/0.75 = 253.3 kN-m
Mox = 400.67 kN-m
Mnx/Mox = 253.3/400.67 = 0.6322
Muy = 75 kN-m (diketahui)
Mny = Muy/Ø = 75/0.75 = 100 kN-m
Moy = 400.67 kN-m
Mny/Moy = 100/400.67 = 0.2496
q = ρg. (fy/fc') = 6000/(0.25*3.14159*450^2)*414/28
0.5578
Pn/Po = (750/0.75)/6126.4
0.163228
Mencari nilai β (dari grafik disamping)
β = 0.62
Check :
(Mnx/Mox) + (Mny/Moy)(1-β) / β
0.6322 + 0.2496*(1-0.62)/0.62
0.785181 Pn/Po = 0.163227997
q = 0.557800182
0.16
0.62
Toni Hartono Bagio 6