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On July 17, 1940, F. Wheeler Loomis, Head of 
the Department of Physics at the University of 
Illinois, received a letter from Donald W. Kerst. 
“Monday afternoon the electron accelerator 
started to work. It was its first trial with the new 
glass doughnut and the new pole pieces. By 
evening the intensity of the X-rays produced 
when the electrons strike the target was up to 
about the effect of 10 mill curies of radium 
gamma rays (radium at target distance) 
according to the calibration on the electron-scope.”
Betatron is a device for speeding up electron to 
extremely high energies with the help of expending 
magnetic field. 
It was constructed in 1941 by D.W.Kerst.
K.W. Kerst with BETATRON
Betatron Differs 
from cyclotron 
The electrons are accelerated 
by expending magnetic field. 
 The circular orbit has a 
constant radius.
Different Betatrons 
According to their 
Generations
Construction 
Betatron consists of highly evacuated angular tube D known 
as doughnut chamber. 
The chamber is placed between the poles of an 
electromagnet excited by an alternating current (frequency of 
60 or 180 Hz) 
Electrons are produced by electron gun and are injected 
into doughnut at the beginning of each cycle of alternate 
current. 
The increasing magnetic flux gives rise to a voltage 
gradient(electric field) round the doughnut which accelerates 
the orbiting electrons
Constant Radius of Betatron
PRINCIPLE 
The principle of the betatron is the same as that of a transformer in which an 
Alternating current applied to the primary coil induces an alternating current 
In the secondary. 
In betatron secondary coil is replaced by a doughnut shaped vaccum 
chamber. 
When the electron is injected in doughnut, the alternating magnetic field has 
two effects : 
 An electromotive force is produced in the electron orbit by changing 
magnetic flux that gives an additional energy to the electrons. 
 A radial force is produced by the reaction of magnetic field whose direction 
is perpendicular to the electron velocity which keeps the electrons moving 
in the circular part.
OPERATION 
Electrons from the electron gun are injected into doughnut shaped 
vacuum chamber when the magnetic field is just rising from its zero 
value in the first quarter cycle. 
The electrons now make several thousand revolution and gain energy. 
When the magnetic field has reached its maximum value, the electrons 
are pulled out from their orbit. 
Either they strike a target and produce X-rays or emerge from the 
apparatus through a window
BETATRON CONDITION 
Consider an electron is moving in a circular orbit of radius ’r’ in the magnetic field. 
Let at any instant, B be the magnetic field at this orbit and the total magnetic flux through 
the orbit is ΦB. The flux ΦB increases at the rate of d/dt (ΦB) and the induced e.m.f. In 
the orbit is given by 
Induced e.m.f. = d /dt (ΦB) .....(i) 
work done on the electron in one revolution 
= induced e.m.f. X Charge 
= - d/dt (ΦB) x e 
Thus work done must be equal to the tangential force F acting on the electron 
multiplied by the length of the orbit path i.e., 
work done = Force x Distance 
= F x 2 π r 
Therefore, F x 2 π r = - d/dt (ΦB) x e 
F =- e/ 2 π r x {d/dt (ΦB)} ....(ii)
The force F will increase the electron energy and which in turn would tend to 
increase the orbit of large radius. In order to maintain the radius of the orbit, 
The force experienced by the electron must be counteracted. Suppose the velocity 
Of the electron is v and its mass is m. When the electron moves in an orbit of 
Radius r under the action of field of magnetic induction B, the inward radial 
force B e v is to be equal to the upwards centrifugal force mv2/r . 
Therefore, B e v = m v2 / r 
m v = B e r ....(iii) 
According to Newton’s law, the force is defined at the rate of change of 
momentum (p=m v) i.e., 
F = d/dt (B e r) 
= er dB/dt ....(iv)
To maintain the radius constant, the value of F given in equation (ii) and 
Equation (iv), should numerically, hence 
e/ 2 π r x {d/dt (ΦB)} = e r dB/dt 
d/dt (ΦB) = 2 π r2 dB/dt 
Integrating, we get 
ΦB = 2 π r2 B 
This is known as Betatron condition
sBetatron
sBetatron

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sBetatron

  • 1.
  • 2.
  • 3. On July 17, 1940, F. Wheeler Loomis, Head of the Department of Physics at the University of Illinois, received a letter from Donald W. Kerst. “Monday afternoon the electron accelerator started to work. It was its first trial with the new glass doughnut and the new pole pieces. By evening the intensity of the X-rays produced when the electrons strike the target was up to about the effect of 10 mill curies of radium gamma rays (radium at target distance) according to the calibration on the electron-scope.”
  • 4. Betatron is a device for speeding up electron to extremely high energies with the help of expending magnetic field. It was constructed in 1941 by D.W.Kerst.
  • 5. K.W. Kerst with BETATRON
  • 6. Betatron Differs from cyclotron The electrons are accelerated by expending magnetic field.  The circular orbit has a constant radius.
  • 7. Different Betatrons According to their Generations
  • 8.
  • 9.
  • 10. Construction Betatron consists of highly evacuated angular tube D known as doughnut chamber. The chamber is placed between the poles of an electromagnet excited by an alternating current (frequency of 60 or 180 Hz) Electrons are produced by electron gun and are injected into doughnut at the beginning of each cycle of alternate current. The increasing magnetic flux gives rise to a voltage gradient(electric field) round the doughnut which accelerates the orbiting electrons
  • 11. Constant Radius of Betatron
  • 12.
  • 13. PRINCIPLE The principle of the betatron is the same as that of a transformer in which an Alternating current applied to the primary coil induces an alternating current In the secondary. In betatron secondary coil is replaced by a doughnut shaped vaccum chamber. When the electron is injected in doughnut, the alternating magnetic field has two effects :  An electromotive force is produced in the electron orbit by changing magnetic flux that gives an additional energy to the electrons.  A radial force is produced by the reaction of magnetic field whose direction is perpendicular to the electron velocity which keeps the electrons moving in the circular part.
  • 14.
  • 15. OPERATION Electrons from the electron gun are injected into doughnut shaped vacuum chamber when the magnetic field is just rising from its zero value in the first quarter cycle. The electrons now make several thousand revolution and gain energy. When the magnetic field has reached its maximum value, the electrons are pulled out from their orbit. Either they strike a target and produce X-rays or emerge from the apparatus through a window
  • 16.
  • 17. BETATRON CONDITION Consider an electron is moving in a circular orbit of radius ’r’ in the magnetic field. Let at any instant, B be the magnetic field at this orbit and the total magnetic flux through the orbit is ΦB. The flux ΦB increases at the rate of d/dt (ΦB) and the induced e.m.f. In the orbit is given by Induced e.m.f. = d /dt (ΦB) .....(i) work done on the electron in one revolution = induced e.m.f. X Charge = - d/dt (ΦB) x e Thus work done must be equal to the tangential force F acting on the electron multiplied by the length of the orbit path i.e., work done = Force x Distance = F x 2 π r Therefore, F x 2 π r = - d/dt (ΦB) x e F =- e/ 2 π r x {d/dt (ΦB)} ....(ii)
  • 18. The force F will increase the electron energy and which in turn would tend to increase the orbit of large radius. In order to maintain the radius of the orbit, The force experienced by the electron must be counteracted. Suppose the velocity Of the electron is v and its mass is m. When the electron moves in an orbit of Radius r under the action of field of magnetic induction B, the inward radial force B e v is to be equal to the upwards centrifugal force mv2/r . Therefore, B e v = m v2 / r m v = B e r ....(iii) According to Newton’s law, the force is defined at the rate of change of momentum (p=m v) i.e., F = d/dt (B e r) = er dB/dt ....(iv)
  • 19. To maintain the radius constant, the value of F given in equation (ii) and Equation (iv), should numerically, hence e/ 2 π r x {d/dt (ΦB)} = e r dB/dt d/dt (ΦB) = 2 π r2 dB/dt Integrating, we get ΦB = 2 π r2 B This is known as Betatron condition