EPANDING THE CONTENT OF AN OUTLINE using notes.pptx
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1.4.3 Slopes and Equations of Lines
1. Slopes and Equations of Lines
The student is able to (I can):
β’ Find the slope of a line given
β Graph
β Two points
β Equation
β’ Write the equation of a line given
β Slope and y-intercept
β Slope and point on line
β Two points
β Graph
2. rise
run
The difference in the yyyy----valuesvaluesvaluesvalues of two points
on a line.
The difference in the xxxx----valuesvaluesvaluesvalues of two points
on a line.
2 4 6 8
-2
2
4
6
8
x
y
β’
β’(xxxx1111, yyyy1111)
(xxxx2222, yyyy2222)
run = 4run = 4run = 4run = 4
rise = 6rise = 6rise = 6rise = 6
3. slope The ratio of riseriseriserise to runrunrunrun. If (xxxx1111, yyyy1111) and
(xxxx2222, yyyy2222) are any two points on a line, the
slope of the line is
So, for the previous example, substitute
(1111, 1111) for (xxxx1111, yyyy1111) and (5555, 7777) for (xxxx2222, yyyy2222):
Note: Always reduce fractions to their
simplest forms. Also, itβs usually better to
leave improper fractions improper.
2 1
2 1x
y
m
y
x
β
β
=
1
2 1
2
x x
y y 7 6 3
m
41 2
1
5
β β
= = = =
β β
4. Summary: Slope of a Line
positive slope negative slope
zero slope undefined slope
5. Practice
Find the slopes between the following points:
1. (2, β1) and (8, β4) 2. (β3, 10) and (5, β6)
3. (1, 12) and (β10, β10) 4. (22, 4) and (0, 28)
( )β β β β
= = = β
β
4 1 3 1
m
8 2 6 2 ( )
β β β
= = = β
β β
6 10 16
m 2
5 3 8
β β β
= = =
β β β
10 12 22
m 2
10 1 11
β
= = = β
β β
28 4 24 12
m
0 22 22 11
6. Point-Slope
Form
Given the slope, mmmm, and a point on the line
(xxxx1111, yyyy1111), the equation of the line is
y β yyyy1111 = mmmm(x β xxxx1111)
Example: Write the equation of the line
whose slope is 2222, which goes through the
point (1111, 6666)
y β 6666 = 2222(x β 1111)
In point-slope form, you can leave it like this
β you donβt have to simplify it any
further.
7. Slope-
Intercept Form
Given the slope, mmmm, and bbbb, the y-intercept,
the equation of the line is
y = mmmmx + bbbb
Example: For mmmm = ββββ3333 and y-intercept 7777,
find the equation of the line.
y = ββββ3333x + 7777
8. Horizontal Line
Vertical Line
For a horizontal line (mmmm = 0000), the equation
of the line is
y = bbbb
For a vertical line (mmmm = undefinedundefinedundefinedundefined), the
equation of the line is
x = xxxx1111
Notice that this equation does not start
with βy=β
9. Practice
Write the equations in point-slope form
1. m = β2; (3, 5) 2. (1, 2)
y β 5 = β2(x β 3)
3. m = β4; (β1, 4) 4. (β2, β3)
y β 4= β4(x + 1)
Write the equations in slope-intercept form
5. m = 6, b = 2 6. m = β1, b = β4
y = 6x + 2 y = βx β 4
2
m ;
3
=
3
m ;
4
= β
2
y 2 (x 1)
3
β = β
3
y 3 (x 2)
4
+ = β +
10. Practice
7. Write the equation of the line through (ββββ1111, 0000) and (1, 2) in
slope-intercept form.
2 0 2
m
1 ( 1) 2
1
β
= = =
β β
Method #1
y β 0000 = 1111(x + 1111)
y = x + 1
Method #2
0000 = (1111)(ββββ1111) + b
0 = β1 + b
1 = b
y = x + 1