You recovered an animal virus particle from drain water. When tested in tissue culture, the virus
infected cells. The virus particle most likely has a _________ capsid. A. naked helical
B. naked icosahedral
C. enveloped icosahedral
D. enveloped helical
E. naked icosahedral or naked helical
Solution
Answer: E. naked icosahedral or naked helical
Reason:
Several families of animal viruses often contain either naked icosahedral or naked helical
symmetry because these are non-enveloped & have ability to infect cells in the tissue culture.
These can be examined by collecting water sample from drainage or sewage using tissue culture
procedure. Rotaviruses and picarnoviruses have ability to contaminate through feces and water
they do possess either non-enveloped icosahedral or naked helical that have ability to infect
animal cells
Norovirus, rotavirus is one of RNA dependant (molecular background) viruses with Non-
Enveloped capsid & Icosahedral structurae along with monopartite segmentation. These viruses
are going to cause gastroentiritis (disease) and these are transmitted via, fecal–oral route from
person to person by either food or water..
Virology is the scientific study of biological viruses. It is a subfield of microbiology that focuses on their detection, structure, classification and evolution, their methods of infection and exploitation of host cells for reproduction, their interaction with host organism physiology and immunity, the diseases they cause, the techniques to isolate and culture them, and their use in research and therapy
Virology is the scientific study of biological viruses. It is a subfield of microbiology that focuses on their detection, structure, classification and evolution, their methods of infection and exploitation of host cells for reproduction, their interaction with host organism physiology and immunity, the diseases they cause, the techniques to isolate and culture them, and their use in research and therapy
Study of parasites Hymenolepis nana, Taenia Echinococcus(), & Pneumocystis carinii
Treatment
Morphology
Life cycle
Pathogenesis
Laboratory diagnosis
Parasites
Hymenolepis nana – Cestode (Dwarf Tapeworm)
Taenia Echinococcus – Cestode (Dog Tapeworm)
Pneumocystis carinii - Sporozoan parasite
Hymenolepis nana
Geographical Distribution
Habitat
Morphology of Hymenolepis nana
Adult Worm
Eggs
Larva
Life cycle of Hymenolepis nana
Direct Cycle
Indirect Cycle
Hymenolepis nana - Life cycle
Life cycle of Hymenolepis nana
Pathogenesis of Hymenolepis nana
Laboratory diagnosis of Hymenolepis nana
Treatment of Hymenolepis nana
Prevention (Prophylaxis) of H. nana
Taenia Echinococcus
Echinococcus Genus: Tapeworm with carnivorous and herbivorous hosts.
Morphology of Taenia Echinococcus
Life Cycle of Taenia Echinococcus
1.T or F The dividend payout ratio includes both stock dividends an.pdfthorsendrouillardu93
1.T or F: The dividend payout ratio includes both stock dividends and cash dividends.
2.T or F: Firms with extra money should always repurchase their own stock, thus increasing the
value of the firm.
3.Stability of dividends is not important to stockholders, especially to those that rely on fixed
income.
4.T or F: The major drawback to an investor is that dividends are viewed as a passive variable,
so a fixed income is never guaranteed.
5.T or F: A reverse stock split is normally used by those firms whose stock price has been stable
for several years.
Solution
1. False only cash dividens
2 False can invest too
3 False
4 True
5 False reverse split is used to increase the price.
Describe the Sev signaling pathway.SolutionR7 cell plays an im.pdfthorsendrouillardu93
Describe the Sev signaling pathway.
Solution
R7 cell plays an important role in study of RTK signaling processes in cell fate determination.
Firstly, only two cells are involved, differentiated R8 cell as the signal sender and the
presumptive R7 cell as the recipient. Secondly, depending on the presence or absence of the
signal, the R7 precursor cell can only choose between the neuronal R7 and the non-neuronal
cone cell fate, respectively. Thirdly, the presence of the R7 cell can be easily noticed in living
animals. This allows extensive genetic screens for mutations that specifically interfere with the
formation of the R7 cell and, therefore, might disrupt reception, transduction, or interpretation of
the inductive signal in the R7 precursor cell. Two classes of mutations are anticipated. The first
class is homozygous viable mutations like SEV which specifically affect R7 cell development.
Few isolated mutations have met the criteria of specificity. The second class of mutations are
more difficult to isolate. If the SEV cascade shares components with other RTKs like DER with
multiple functions during development, animals homozygous for loss-of-function mutations in
the corresponding genes would presumably die prior to R7 cell commitment. Simon used a
temperature sensitive allele of sev (sevts) which provides barely sufficient activity to allow R7
cell development. The second approach involved expression of constitutively activated versions
of SEV in all sev-expressing cells [20] and [21]. This resulted in transformation of cone cells
into additional R7 cells resulting in a rough eye phenotype. The conclusion drawn from these
experiments is that cone cell precursors are competent to respond to the inductive signal.R7 cell
specification became sensitive to the gene dosage of rate-limiting components acting
downstream of SEV. Hence, for a recessive lethal mutation, reducing the gene dose by half is
sufficient to modify the sevts or the sevS11 phenotype, which can be scored in living animals.
Large-scale screens conducted with both systems unravelled the first steps in the SEV signaling
cascade..
More Related Content
Similar to You recovered an animal virus particle from drain water. When tested.pdf
Study of parasites Hymenolepis nana, Taenia Echinococcus(), & Pneumocystis carinii
Treatment
Morphology
Life cycle
Pathogenesis
Laboratory diagnosis
Parasites
Hymenolepis nana – Cestode (Dwarf Tapeworm)
Taenia Echinococcus – Cestode (Dog Tapeworm)
Pneumocystis carinii - Sporozoan parasite
Hymenolepis nana
Geographical Distribution
Habitat
Morphology of Hymenolepis nana
Adult Worm
Eggs
Larva
Life cycle of Hymenolepis nana
Direct Cycle
Indirect Cycle
Hymenolepis nana - Life cycle
Life cycle of Hymenolepis nana
Pathogenesis of Hymenolepis nana
Laboratory diagnosis of Hymenolepis nana
Treatment of Hymenolepis nana
Prevention (Prophylaxis) of H. nana
Taenia Echinococcus
Echinococcus Genus: Tapeworm with carnivorous and herbivorous hosts.
Morphology of Taenia Echinococcus
Life Cycle of Taenia Echinococcus
1.T or F The dividend payout ratio includes both stock dividends an.pdfthorsendrouillardu93
1.T or F: The dividend payout ratio includes both stock dividends and cash dividends.
2.T or F: Firms with extra money should always repurchase their own stock, thus increasing the
value of the firm.
3.Stability of dividends is not important to stockholders, especially to those that rely on fixed
income.
4.T or F: The major drawback to an investor is that dividends are viewed as a passive variable,
so a fixed income is never guaranteed.
5.T or F: A reverse stock split is normally used by those firms whose stock price has been stable
for several years.
Solution
1. False only cash dividens
2 False can invest too
3 False
4 True
5 False reverse split is used to increase the price.
Describe the Sev signaling pathway.SolutionR7 cell plays an im.pdfthorsendrouillardu93
Describe the Sev signaling pathway.
Solution
R7 cell plays an important role in study of RTK signaling processes in cell fate determination.
Firstly, only two cells are involved, differentiated R8 cell as the signal sender and the
presumptive R7 cell as the recipient. Secondly, depending on the presence or absence of the
signal, the R7 precursor cell can only choose between the neuronal R7 and the non-neuronal
cone cell fate, respectively. Thirdly, the presence of the R7 cell can be easily noticed in living
animals. This allows extensive genetic screens for mutations that specifically interfere with the
formation of the R7 cell and, therefore, might disrupt reception, transduction, or interpretation of
the inductive signal in the R7 precursor cell. Two classes of mutations are anticipated. The first
class is homozygous viable mutations like SEV which specifically affect R7 cell development.
Few isolated mutations have met the criteria of specificity. The second class of mutations are
more difficult to isolate. If the SEV cascade shares components with other RTKs like DER with
multiple functions during development, animals homozygous for loss-of-function mutations in
the corresponding genes would presumably die prior to R7 cell commitment. Simon used a
temperature sensitive allele of sev (sevts) which provides barely sufficient activity to allow R7
cell development. The second approach involved expression of constitutively activated versions
of SEV in all sev-expressing cells [20] and [21]. This resulted in transformation of cone cells
into additional R7 cells resulting in a rough eye phenotype. The conclusion drawn from these
experiments is that cone cell precursors are competent to respond to the inductive signal.R7 cell
specification became sensitive to the gene dosage of rate-limiting components acting
downstream of SEV. Hence, for a recessive lethal mutation, reducing the gene dose by half is
sufficient to modify the sevts or the sevS11 phenotype, which can be scored in living animals.
Large-scale screens conducted with both systems unravelled the first steps in the SEV signaling
cascade..
2. What is gender identity How is gender identity constructed Expl.pdfthorsendrouillardu93
2. What is gender identity? How is gender identity constructed? Explain this question using
gender socialization process.
Solution
2. Gender Identity:
A Humans perception of possess a specific gender, which may or may not comparable with their
birth sex.
Gender Identity Constructed:
The design that gender dissimilarity is socially constructed is a vision available in sociological
and philosophical hypothesis about gender. According to this vision, association and culture
produce gender character, and these character are authorize as design or appropriate etiquette for
a human of that particular gender.
Gender socialization process:.
Abiotic Factor
Too Little
Too Much
Just Right
The Consequences
Salinity
Temperature
Sunlight
Nutrients
symbiotic algae within coral can\'t grow
coral reef gets overgrown with algae
symbiotic microalgae grow and feed coral, but macroalgae does not take over the reef
Coral reefs grow best in areas with low nutrient concentrations in the water, but not too low.
Tides
Wind
Abiotic Factor
Too Little
Too Much
Just Right
The Consequences
Salinity
Temperature
Sunlight
Nutrients
symbiotic algae within coral can\'t grow
coral reef gets overgrown with algae
symbiotic microalgae grow and feed coral, but macroalgae does not take over the reef
Coral reefs grow best in areas with low nutrient concentrations in the water, but not too low.
Tides
Wind
Solution
iotic Factor
Too Little
Too Much
Just Right
The Consequences
Salinity
Corals cannot survive in low salinity.Leads to coral bleaching.
They cannot thrive.
25 to 42% salinity is the best for corals to exist.32-40 PSU(Practical saline units) is the best
salinity range for corals to occur.
Corals cannot grow in very low salinity.Best range of salinity i.e 32-40 PSU that is found near
the equator where corals are founf the most.
Temperature
Corals reefs do not grow well in lowered temperatures.
Prolonged higher temperatures can cause coral bleaching( as the zooxanthellae leave the tissues
of the coral) and occurence of infectious diseases.
Zooxanthellae can survive inside corals and so corals can grow.
High temperatures favour coral growth but too high temperatures for long time leads to coral
bleaching.
Sunlight
Too little sunlight does not favour photosynthesis by zooxanthellae and hence growth of coral is
lowered.
Too much of sunlight results in excess photosynthesis by zooxanthellae that in turn results in
high amounts of oxygen that can be toxic leading to mass bleaching.
Neither too high nor too less light is favourable for coral growth.
Corals require the right amount of light for growth,For this they grow in shallow water.
Nutrients
symbiotic algae within coral can\'t grow
coral reef gets overgrown with algae
symbiotic microalgae grow and feed coral, but macroalgae does not take over the reef
Coral reefs grow best in areas with low nutrient concentrations in the water, but not too low.
Tides
Corals cannot get their food (zooxanthellae) and disperse their larvae.
Corals become prone to tidal emersions that causes bleaching and death of corals.
The right tidal current brings food to the corals ,helps in spawing and larva dispersal.
Right tidal currents help in survival of the corals by getting them their food,Spring tides favour
spawing in corals.
Wind
Does not affect much.
Results in coral degradation.
The right wind velocity gives proper shape and position to the corals.
The right wind velocity orients the coral reefs inna proper direction giving it proper dhape and
position but higher wind velocities destruct the corals.
iotic Factor
Too Little
Too Much
Just Right
The Consequences
Salinity
Corals can.
amongst B. cereus, S. aureus, S. sp, and L. monocytogenes, which two.pdfthorsendrouillardu93
amongst B. cereus, S. aureus, S. sp, and L. monocytogenes, which two cannot be separated on
the basis of morphology or gram reaction? Why?
Solution
Among B. cereus, S. aureus and L. monocytogenes, B. cereus and L. monocytogenes are rod
shaped, while S. aureus is a round shaped bacterium. all the three are Gram positive.
therefore, B. cereus and L. monocytogenes can not be separated..
4 o o o o o o o o 4 Passage III recorded. The figure shows, for each .pdfthorsendrouillardu93
4 o o o o o o o o 4 Passage III recorded. The figure shows, for each group, the average number
of offspring (as eggs, as and as Scientists studied how perceived predation (hearing per clutch.
the calls and sounds of predators). in the absence of direct NPT group produce 2 clutches
(groups) of eggs in a breeding season. Study At the beginning of a breeding season, nests without
eggs were located in ow-growing shrubs. 3.6 Direct predation was eliminated by surrounding
each shrub with an electric fence to protect the nest from ground predators and by covering each
shrub with a net to protect the nest from aerial predators. The nests were evenly divided into 2
groups: a preda 2.4 tor treatment (PT) group and a nonpredator treatment 2.2 (NPT group. A
speaker that broadcast the calls and sounds of predators of M. melodia was set up near each nest
in the 2.0 first clutch PT group. A speaker that broadcast the calls and sounds of 1.8 nonpredators
of M. melodia was set up near each nest in second clutch 1.6 the NPT group 1.2 Throughout the
breeding season, each speaker broad- cast the appropriate calls and sounds every few minutes on
a 4-day-on, 4-day-off cycle. The parents and offspring associated with each nest did not hear
sounds emitted by from Liana Y. zanette et al., \"Perceived Predation speakers other than their
own speaker.) The number of eggs Figure adapted offspring Songbirds Produce and the number
of hatchlings produced in each nest were Risk Reduces the Number Advancement of recorded.
The number of hatchlings that successfully left Year.\" 02011 by American Association for the
each nest (such ings are called fledglings) was also Science
Solution
14.G. tagging the hatchlings in both groups with identifying markers before they fledged.
15.A
16.H
17.D
18.G
19.A
20.H.
blood agar plate importance scientific explanationSolutionImpo.pdfthorsendrouillardu93
blood agar plate importance scientific explanation
Solution
Importance of Blood Agar Plates:
· Blood agar(BA) is a solid growth medium that contains red blood cells. It is the enriched
medium used to culture those bacteria or microbes that do not grow easily. These types of
bacteria are called “fastidious” as they demand a special, enriched nutritional environment as
compared to the routine bacteria. They require a source of blood as a culture medium
supplement.
It is also required to detect and differentiate haemolytic bacteria, especially Streptococcus
species.
It is also a differential media in allowing the detection ofhemolysis(destroying the RBC) by
cytolytic toxins secreted by some bacteria, such as certain strains of Bacillus, Streptococcus,
Enterococcus, Staphylococcus, and Aerococcus.
· Blood agar can be made selective for certain pathogens by the addition of antibiotics,
chemicals or dyes. Examples include crystal violet blood agar to select Streptococcus pyogens
from throat swabs, and kanamycin or neomycin blood agar to select anaerobes from pus.
The main aim is :
ii) To differentiate bacteria based on their hemolytic properties (-hemolysis,.
Why is it scientifically inaccurate to portray the process of evoluti.pdfthorsendrouillardu93
Why is it scientifically inaccurate to portray the process of evolution like this picture below?
Solution
The depiction of evolution of Man from monkey is wrong. Humans did not evolve from
monkeys; humans and monkeys both evolved from an extinct common ancestor. We are all
modern species that have followed different evolutionary paths, though humans share a common
ancestor with some primates, such as the African ape..
What term is used to describe overwriting media to allow for its reu.pdfthorsendrouillardu93
What term is used to describe overwriting media to allow for its reuse in an environment
operating at the same sensitivity level?
Solution
clearing is answer
clearing
its preparing media for reuse.
when media is cleared, unclassified data is written over all addressable location on the media.
once that\'s completed the media can be reused.
Erasing
its used to delete files or media.
purging is more intensive form of clearing for reuse in lower security areas.
sanitization is a series of processes that removes data from a system or media while ensuring that
the data is unrecoverable by any means..
Unnithan, Houser, and Fernhall (2006) were interested in whether pla.pdfthorsendrouillardu93
Unnithan, Houser, and Fernhall (2006) were interested in whether playing the game Dance
Dance Revolution (DDR) affected the heart rate of overweight and nonoverweight adolescents
differently. A group of 22 adolescents, 10 classified as overweight and 12 as not overweight,
played DDR for 12 minutes, during which time the researchers measured each participant\'s heart
rate. Which statistical test should the researchers use to analyze their data?independent-samples t
test
Solution
The dependent-samples t test should be used by the researchers use to analyze their data..
The following statements are on the DAC pins and output. Only one is .pdfthorsendrouillardu93
The following statements are on the DAC pins and output. Only one is correct. Which one? The
reason that the DAC pins are first be configured to analogue inputs (AIN) is to avoid parasitic
consumption. The maximum output of a DAC is 2 times Vref The two DAC pins are PA14 and
PA15. To carry a DAC conversion, you have to load the digital data to output holding register
DORx in your program.
Solution
OPTION C IS CORRECT.
Ethics in the WorkplaceHome Publications & Resources Knowledge.pdfthorsendrouillardu93
Ethics in the Workplace
Home > Publications & Resources > Knowledge Center > Article Index
By: Joshua Joseph , Ethics Resource Center, Inc joshua@ethics.org
Source: Executive Update
Feature
Published: October 2000
Results of a recent national study provide solid data that leaders who want to establish a practice
of positive workplace ethics within their organizations should develop written ethics standards,
provide ethics training, and ensure resources are available for employees in need of ethics
advice.
Association executives typically want the answers to two key questions about ethics in their
association offices: “How do workplace ethics apply to the practical goals of my organization
and the work of my employees?” and “Can you show me reliable data that support your
assertions?” In this article, we address those questions as we present findings from the Ethics
Resource Center’s 2000 National Business Ethics Survey (2000 NBES) - a rigorous telephone
survey of 1,500 U.S. employees - and discuss what these findings mean for association
executives.
One caveat first - we focus on issues relevant to an association’s internal staff and to ethics
programs designed for them, not for association members whose relationships with their
organization are often very different from those of staff. In the 2000 NBES, we gathered
information on three key elements of an ethics program: written ethics standards, ethics training,
and means for employees to get ethics advice (e.g., a telephone help line or ethics office).
Ethics Trends
Studies show that formal ethics programs are becoming increasingly common in U.S.
organizations across the nonprofit, for-profit, and government sectors. Compared to the 1994
survey, the 2000 NBES finds dramatic increases in the percentage of employees who report that
their organizations have ethics programs. In the nonprofit sector specifically, the 2000
NBESfinds that nearly 90 percent of employees say their organizations have written standards of
ethical conduct. In addition, 65 percent say their organizations provide some form of training
about these standards, and more than 40 percent say a dedicated telephone line or office is
available for ethics advice. Not surprisingly, the percentages are consistently higher among
larger nonprofits - those with more than 500 employees - as compared to smaller ones.
These percentages suggest that many nonprofit executives are seeing value in actively promoting
ethics within their organizations. The list of potential benefits linked to an effective ethics
program includes the following:
Recruiting and retaining top-quality people;
Fostering a more satisfying and productive working environment;
Building and sustaining your association’s reputation within the communities in which you
operate;
Maintaining the trust of members to ensure continued self-regulation;
Legitimizing open discussion of ethical issues;
Providing ethical guidance and resources for employees prior to making difficult d.
System AdminThere has been a new surge of mergers and acquisitions.pdfthorsendrouillardu93
System Admin
There has been a new surge of mergers and acquisitions (M and A) in the last several years. Why
is this? In the past, why have so many not been successful? In your opinion, what are the most
important factors to be taken into account for a successful M and A? Provide an example to
support your position.
Solution.
Let A and B be two finite sets. Let f A --B be any map. Assume tha.pdfthorsendrouillardu93
Let A and B be two finite sets. Let f: A -->B be any map. Assume that |A|=|B|.
(i) Show that if f is surjective, then f is injective.
(ii) Show that if f is injective, then f is surjective.
Solution
i)
Let f be surjective.
Let f not be injective
Let, a and b be two distinct elemetns in A so that
f(a)=f(b)
IN a map one element can map to only one element
Hence, remaining |A|-2 elements other than a and b map to at most |A|-2=|B|-2 elements in B
a and b map to f(a)
Hence , f maps to at most |B|-2+1 =|B|-1 elements in B
But f is sujrective to |f(A)|=|B|
HEnce contradiction
So, f is injective
ii)
Let, f be injective
Let, |A|=|B|=n
Let, elemetns of A as
a1,..,an such ai is not equal to aj with i is not equal to j
and elements of B as
b1,b2,...bn so tha
f(ai)=bi
f is injective so
f(ai) is not equal to f(aj) for i not equal to j
Hence, b1,...bn are are mutually distinct
Hence, f(A) has n=|B| elements
Hence, f is surjective.
Q2 New radioactive particles are generated at rate Mu from a radioact.pdfthorsendrouillardu93
Q2 New radioactive particles are generated at rate Mu from a radioactive source. They have a
lifetime with distribution Exp(1) after which they decay. At time 0 there are no particles present,
calculate the distribution of the number present at time 1. For a particle present at time 1,
calculate the distribution of the time that it arrived.
Solution
P = p0e-t.
Presented below is selected information pertaining to Pineapple Ente.pdfthorsendrouillardu93
Presented below is selected information pertaining to Pineapple Enterprises Ltd. for last year:
Assets January 1
$240,000
Assets December 31
$320,000
Liabilities January 1
$120, 000
Common shares December 31
60,000
Retained earnings December 31
$20,000
Common shares issued during the year
2,000
Dividends declared during the year
32,000
Required
Calculate the net income for last year.
Assets January 1
$240,000
Assets December 31
$320,000
Liabilities January 1
$120, 000
Common shares December 31
60,000
Retained earnings December 31
$20,000
Common shares issued during the year
2,000
Dividends declared during the year
32,000
Solution
Assets January 1 240000 Less Liabilities January 1 120000 Common stockholders
equity January 1 120000 less Common stock January 1 ( 60000-2000) 58000 Retained
earnings January 1 62000 Retained earnings December 31 20000 Add Dividend declared
32000 52000 less Retained earnings January 1 62000 Net income -10000.
Please determine all the sixth squareroots of -64. Give your answer i.pdfthorsendrouillardu93
Please determine all the sixth squareroots of -64. Give your answer in rectangular form Please
express - 12i in polar form. Please express 4cis (5 pi/4) in rectangular form. Please determine
the principal value of (1 + i)^3 - 2i. You may leave your answer in polar form. Please evaluate
(10 + i) (8 - 2i) Please evaluate (3 + 2i) -(4 - 7i) Please evaluate i^217.
Solution.
Location aound Mo Function Reticular connective (Tissue Location Fu.pdfthorsendrouillardu93
Location: aound Mo Function Reticular connective (Tissue Location: Function: ou
Solution
Reticular Connective Tissue composed of Fibers like cells called Fibroblasts. It act as scafold for
several organs such as Lymphnodes and Monemarrow.
Reticular Connective Tissue is found in around the Kidney, spleen, lymph nodes and
Bonemarrow.
Soft skeleton formed by these RCT supports the Lymphoid organs and and Adipose tissue.
1 What can you conclude about the blood type of this individual (ABO.pdfthorsendrouillardu93
1 What can you conclude about the blood type of this individual (ABO and Rho)?
2. A woman who has A(+) blood type has a daughter who is A negative and a son who is B
positive. What is the mother\'s genotype for AB antigens?
3. A woman, who has Rh-positive blood type has two children, Rh-positive son and Rh-negative
daughter. is the genotype of the mother. Is she homozygous or heterozygous? Antiserum Anti-A
Anti-B Anti-Rh Reaction No clumping Clumping Clumping
Solution
Ans. 1. B positive ; or B(+)
No clumping in “Anti-A” indicates that antigen A is absent.
Clumping in “Anti-B” indicates that antigen B is present. So, blood group is B
Clumping in “Anti-Rh” indicates that Rh antigen is present. Presence of Rh antigen is indicated
by “positive” suffix.
So, the blood group is “B positive” meaning that the RBC has B antigen as well as Rh antigen.
For more clarification: If there was clumping only in Anti-B but NOT in Anti-Rh- the blood
group would be “B negative” meaning RBC has antigen B but lacks Rh antigen.
Ans. 2. Given,
Mother’s blood type = A(+); possible genotypes = IAIA or IAI0
Daughter’s blood type = A (-) ; possible genotypes = IAIA or IAI0
Son’s blood type = B (+) ; possible genotypes = IBIB or IBI0
(Note: Rh factor has not been shown because it’s not required here).
Coming to son’s genotype, it can be IBIB or IBI0. Each progeny receives one allele from mother
and another from father.
The son’s genotype IBIB is NOT possible in this case because it need to inherit one IB allele
from both parents whereas mother does not have an IB allele.
The true genotype of son is IBI0. Since mother can’t contribute IB allele, the son must have
inherited it from his father. Therefore, the allele contributed by mother is I0. The mother can
contribute I0 only when her genotype is IAI0 – so that she can produce gametes with allele I0 as
well as IA.
Thus, mother genotype = IAI0
Ans. 3. Given,
The son is Rh positive
Daughter is Rh negative.
Rh negative genotype is Rh- Rh- i.e. the individual must Rh- allele at both the loci. That is, the
daughter must have inherited one Rh- allele from mother and another Rh- allele from father.
To produce a gamete with Rh- allele, the must also has a Rh- allele. Moreover, the must also has
an Rh+ allele, so that a Rh+ son would be produced.
Therefore, mother’s genotype = Rh+ Rh- , she is heterozygous..
Identify the class for each of the following. acetylcholine (ACh) at.pdfthorsendrouillardu93
Identify the class for each of the following. acetylcholine (ACh) atrial nature tic peptide (ANP)
calcitonin chorion gonadotropin dopamine endorphins erythropoietin (EPO) gamma-amino
butyric acid (GABA) glutamate growth factors (GF) interferon (IF) interleukins (IL) leptin
leukotrienes melatonin nicotine nitric oxide (NO) oxytocin (OXY) pheromones progesterone
prostaglandins pyrogens serotonin tumor necrosis factor (TNF) vasopressin CYTOKINE
ECTOHORMONE EICOSANOID HORMONE NEUROHORMONE NEUROMODULATOR
NEUROTRANSMITTER
Solution
1) actylcholine is a neurotransmitter for cell signalling
7) erthrypoetein is a hormone responsible for RBC growth.
25) vasopressin is a hormone responsible for water reabsorption from kidney..
3) calcitonin is a hormone responsible for the maintaince of calcium level in the body..
14) leukotrines are cytokines..
23) serotonin are neuro hormone which acts on the brain for signalling..
19) pheromones are ectohormone in nature...
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Introduction to AI for Nonprofits with Tapp NetworkTechSoup
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Acetabularia Information For Class 9 .docxvaibhavrinwa19
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar Kanvaria
Chapter 3 - Islamic Banking Products and Services.pptx
You recovered an animal virus particle from drain water. When tested.pdf
1. You recovered an animal virus particle from drain water. When tested in tissue culture, the virus
infected cells. The virus particle most likely has a _________ capsid. A. naked helical
B. naked icosahedral
C. enveloped icosahedral
D. enveloped helical
E. naked icosahedral or naked helical
Solution
Answer: E. naked icosahedral or naked helical
Reason:
Several families of animal viruses often contain either naked icosahedral or naked helical
symmetry because these are non-enveloped & have ability to infect cells in the tissue culture.
These can be examined by collecting water sample from drainage or sewage using tissue culture
procedure. Rotaviruses and picarnoviruses have ability to contaminate through feces and water
they do possess either non-enveloped icosahedral or naked helical that have ability to infect
animal cells
Norovirus, rotavirus is one of RNA dependant (molecular background) viruses with Non-
Enveloped capsid & Icosahedral structurae along with monopartite segmentation. These viruses
are going to cause gastroentiritis (disease) and these are transmitted via, fecal–oral route from
person to person by either food or water.
