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You are asked with writing a program in C that manages contact information for a group of people. The program should save the first name, last name, and telephone number for up to 12 people. The program should have options to add a person, delete a person, update the information for a person, and display all information for all current entries. How could you go about breaking up the programming work into a set of subproblems that could be implemented separately? Solution Whenever we asked about these type of problems.we just go to data structures.i.e,Data structures that are suitable to our problem whether it may be linked lists,arrays,trees.Here we are taking about a person information that to it is not about a single person information. 1)Identify data structure.Here i think linked list data structure can be used because array cannot store all information about a person.and arrays cannot support delete operation like that. 2)1st sub problem:creating a structure to a single person 3)2nd sub problem:add a person:inserting data in linked list by creating a single node 3)updating information:modifying node information in single linked list 4)delete the information of a person:delete a single node information in single linked list 5)display all information for all current entries:traversing a single linked list. each step is considered to subproblem or function in \'C\' language..

You are asked with writing a program in C that manages contact information for a group of
people. The program should save the first name, last name, and telephone number for up to 12
people. The program should have options to add a person, delete a person, update the
information for a person, and display all information for all current entries. How could you go
about breaking up the programming work into a set of subproblems that could be implemented
separately?
Solution
Whenever we asked about these type of problems.we just go to data structures.i.e,Data structures
that are suitable to our problem whether it may be linked lists,arrays,trees.Here we are taking
about a person information that to it is not about a single person information.
1)Identify data structure.Here i think linked list data structure can be used because array cannot
store all information about a person.and arrays cannot support delete operation like that.
2)1st sub problem:creating a structure to a single person
3)2nd sub problem:add a person:inserting data in linked list by creating a single node
3)updating information:modifying node information in single linked list
4)delete the information of a person:delete a single node information in single linked list
5)display all information for all current entries:traversing a single linked list.
each step is considered to subproblem or function in 'C' language.

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FOREVERPRODUCTCHD

Know the different types of viruses which have a dsRNA genome A type of infection caused by bacteriophages which involves a transition from a lytic to a lysogenic stage. What is the defense mechanism employed by the T4 phage to prevent excision of its DNA by restriction enzymes? Know the viruses that use RNA/DNA genomes. Describe in general terms how bacteriophage lambda regulates the switch between the lytic and lysogenic cycles. Proteins involved? What factors may influence the transition from a lytic to lysogenic state in lambda phage? Describe in general terms how bacteriophage lambda regulates the switch between the lytic and lysogenic cycles. Other Proteins involved? Describe in general terms the strategy used by the ssDNA virus phiX174 to synthesize its nucleic acids and proteins. Function of the replicative form? Know the different viruses which have a ssDNA genome Outline the major events involved in plus-strand RNA viruses and the specific mechanisms used to accomplish each step. Type of template used? Describe in general terms the strategy used by minus and plus strand RNA viruses to synthesize their nucleic acids and proteins. Propose how a retrovirus with a single RNA molecule as its genome might generate multiple proteins from that molecule. Intermediate molecule? What are cytokines? Roles in immunity? What is the alternate complement pathway? Roles? What are the functions and locations (blood, tissue etc) of the different immune cells? Mechanisms employed by the lungs to help protect it from infection What are dendritic cells? Roles they play in the immune response? Specific vs non-specific Function of lysozyme? Know the different body areas which act as physical barriers to infection. Know the different physical and biological defense mechanisms? Examples? Solution As per the rule i have answered your first question: Reoviridae: Reoviridae are currently classified into nine genera. The genomes of these viruses consist of 10 to 12 segments of dsRNA, each generally encoding one protein. The mature virions are non-enveloped. Their capsids, formed by multiple proteins, have icosahedral symmetry and are arranged generally in concentric layers. A distinguishing feature of the dsRNA viruses, irrespective of their family association, is their ability to carry out transcription of the dsRNA segments, under appropriate conditions, within the capsid. In all these viruses, the enzymes required for endogenous transcription are thus part of the virion structure. Orthoreoviruses: The orthoreoviruses (reoviruses) are the prototypic members of the virus Reoviridae family and representative of the turreted members, which comprise about half the genera. Like other members of the family, the reoviruses are non-enveloped and characterized by concentric capsid shells that encapsidate a segmented dsRNA genome. In particular, reovirus has eight structural proteins and ten segments of dsRNA. A series of uncoating steps and conformational changes accom.

Know the different types of viruses which have a dsRNA genome A type.pdf

Know the different types of viruses which have a dsRNA genome A type.pdf

Know the different types of viruses which have a dsRNA genome A type.pdf

FOREVERPRODUCTCHD

In what ways do the experts foresee the use of both virtualization and cloud computing evolving in the future? Solution Use ofVirtualization and cloud computing security : • Self-defending VM security • Layered coordinated defenses • Security optimized for virtual and cloud environments • Visibility, reporting, and auditing • Encryption for virtual and cloud environments • Security that travels with data Security solutions should offer both agent-less and agent-based security options to provide flexible deployment alternatives and close security gaps unique to virtualized and cloud environments. Encryption addresses a range of security challenges related to virtualization and cloud computing. Standard 128-, 192-, or 256-bit encryption of storage volumes deters hackers from prying and thieving, and reduces the risk that the cloud storage devices could be sold or reused while they still contain confidential or private information. Encryption also greatly reduces the risk of malicious VM attacks; as long as the encryption key for the data stores have not been provided, even if rogue VMs reach data stores, volumes are unmountable and unreadable. Encryption with enterprise-controlled key management enables IT to comply with security best practices, internal governance, and external regulation. Data is kept secure, and the key management solution can provide monitoring, reporting, and auditing capabilities that provide visibility into data access. As a result, enterprises realize a significant reduction in the scope of compliance audits. Encryption for virtual and cloud environments: In summary, best practices for encryption for virtual and cloud data protection include: • Integration with leading cloud service providers and virtual environments. • Policy-based key management that determines where and when encrypted data can be accessed. • Identity-based and integrity-based server validation to determine which servers can access secure storage volumes and whether security is up-to-date on those servers prior to data access. • Business control of encryption keys, either on-site or through a separate SaaS service, to maintain a strict separation of duties between the business and cloud service provider..

In what ways do the experts foresee the use of both virtualization a.pdf

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In what ways do the experts foresee the use of both virtualization a.pdf

FOREVERPRODUCTCHD

In the Meselson Stahl experiment, E. coli was grown for many generations in a medium \"heavy\" nitrogen^15 N. Once the bacterial DNA was uniformly labeled, the bacteria were transferred to a medium containing the \"light\" nitrogen, ^14N. After ONE round of replication, DNA was extracted and subjected to density gradient centrifugation in cesium chloride. Upon inspection, there was only a single band of intermediate density DNA in the gradient. This proved that DNA replication CANNOT be conservative dispersive semiconservative conservative of dispersive continuous. Solution Answer is Dispersive replication. Dispersive replication would result in double-stranded DNA with both strands having mixtures of 15N and 14N DNA, either of which would have appeared as DNA of an intermediate density..

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FOREVERPRODUCTCHD

implement the ListLinked ADT (the declaration is given in ListLinked.h)(60 points) - implement the following operations: - constructor, assignment operator, destructor - insert, remove, replace, clear - isFull, isEmpty - gotoBeginning, gotoEnd, gotoNext, gotoPrior, getCursor implement the function moveToBeginning() that removes the data item marked by the cursor and reinserts it at the beginning of the list - implement the function insertBefore(..) that will insert the new data item before the cursor or if the list is empty as the first element of the list #include \"ListLinked.h\" // ListNode member functions template List::ListNode::ListNode(const DataType& nodeData, ListNode* nextPtr) { this->dataItem = nodeData; this->next = nextPtr; } // List member functions template List::List(int ignored = 0) { } template List::List(const List& other) { } template List& List::operator=(const List& other) { } template List::~List() { } template void List::insert(const DataType& newDataItem) throw (logic_error) { } template void List::remove() throw (logic_error) { } template void List::replace(const DataType& newDataItem) throw (logic_error) { } template void List::clear() { } template bool List::isEmpty() const { return false; } template bool List::isFull() const { return false; } template void List::gotoBeginning() throw (logic_error) { } template void List::gotoEnd() throw (logic_error) { } template bool List::gotoNext() throw (logic_error) { return false; } template bool List::gotoPrior() throw (logic_error) { return false; } template DataType List::getCursor() const throw (logic_error) { DataType t; return t; } template void List::moveToBeginning () throw (logic_error) { } template void List::insertBefore(const DataType& newDataItem) throw (logic_error) { } #include \"show5.cpp\" Solution #include #include #include using namespace std; struct Node { int data; Node *next; }; Node *tail=NULL; Node* Insert_atHead(Node *head, int data) { Node *temp=new Node; temp->data=data; temp->next=head; head=temp; return head; } Node* Insert_atTail(Node *head, int data) { Node *tail=head; if(tail==NULL) { Node *temp = new Node; temp->data=data; temp->next=NULL; head=temp; return head; } while(tail!= NULL) { if(tail->next==NULL) { Node *temp=new Node; temp->data=data; temp->next=NULL; tail->next=temp; return tail; } else { tail=tail->next; } } } Node *Insert_atPosition(Node *head, int data, int position) { int i=0; int j=position-1; if(position==0) { Node *temp = new Node; temp->data=data; temp->next=head; head=temp; return head; } else { Node *temp=head; while(inext; i++; } Node *temp1 = new Node; temp1->data=data; temp1->next=temp->next; temp->next=temp1; return head; } return head; } Node* Delete(Node *head, int position) { Node *temp=head; int i=1; int j=position; if(j==0) { head=head->next; return head; } Node *temp1 = new Node; while(j>0) { temp1=temp; temp=temp->next; j--; } temp1->next=temp->next; delete temp; return head; } int GetNode(Node *head,int posi.

implement the ListLinked ADT (the declaration is given in ListLinked.pdf

implement the ListLinked ADT (the declaration is given in ListLinked.pdf

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