1) The document provides instructions for making 52 cubes with dimensions of 3cm x 3cm x 3cm. It explains that the first layer needs 5 cubes, the second layer needs 11 cubes, and the third and fourth layers each need 12 cubes. This accounts for the total of 52 additional cubes needed. 2) There is a diagram showing the shaded and unshaded areas of two figures. It is explained that one part of the shaded area is 3 units and the total shaded area is 29 units. 3) A triangle problem is presented where the height of one triangle is three times the height of another triangle. It is determined that the length of the base AC is 17cm.

1. Prepared By Mr Seelan 3cm
Hp: 90691139
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3cm
3cm
15 cm
3cm
3cm
52 more cubes
3cm 3cm 3cm 3cm
12cm
Needed = 5 + 11 + 12 + 12 + 12 = 52 more cubes
Mark out theFirstrd layer needsaddcubescubes each
Similarly,Mark out th layersneeds 12first the height
2nd3 and 5 need to required for
remaining layerare needed
4thlayer needdimensionscubes
52 more the to 12 11cubes
layer cubes add 5

2. x 4 parts = 12 units
9
3 1 part = 3 units
x3 x y
1 x3
3 5 parts = 15 units
3 + 12
3 Shaded Area of Y : Total area of figure
z 3 : 3 + 12 + 9 +5
5 3 : 29
Prepared By Mr Seelan
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Divide 15 unitsArea 3 isYto 3 and29 units parts
Shaded is 3whole unshadedthe 5 parts
Make both shaded 29 is unshaded
Area ofinto of figure
1 part, = units is 3
shaded units same

3. 2
The height of triangle AEC is 3 times the height of triangle ADC. The shaded area is 34 cm
Find the length of the base AC. E
2cm
2
34cm
D 2cm6cm Divide this into 3 units
2cm 2cm
A C
B
17cm
Height of triangle ADC = 6cm ÷ 3 = 2cm
Area = 1 unit
Area of triangle ADC = 1 x Base x Height
2
17 = 1 x AC x 2 cm 2
2 2 units = 34 cm2
AC = 17 cm 1 unit = 34 cm ÷ 2
Area = 3units 2
= 17 cm
Prepared By Mr Seelan
Hp: 90691139
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DB ismanyAEC2cm the shadedof ADC. So area=of AEC is also 3 times that of ADC.
How equalunits is times that area?
Shaded of to is units
Height area is 2 3 AC 17 cm

4. 2
= 36cm
At first 5u : 2u
- Area R S - Area
3P
5u
3 : 1
p p
CUT 9cm 2 CUT
6cm
1P
2u
CUT18
u
u 18
6cm 2
3p u 18 Area of rectangle at first = 6cm x 6cm = 36cm
2p CUT 18
u 18 u 2 u = 36 cm 2 2
u 18 u 18 1p 1 u = 36 cm 2 ÷ 2 =18cm
2 p = 18 cm 2 X 3 36 cm 2
Rectangle Square
= 54cm 2 - 27 cm 2
Prepared By Mr Seelan
1 p = 54cm 2 ÷ 2 = 27cm 2 2 =9cm2
Hp: 90691139
Home use only AfterCut the Separate theRectanglethe3cm–squareandunits 1 part
shadedshaded cut, 5 = AreaisAreapartssquarethe end
Area ofareaAfter of for bothatand of squareSquare
Area of rectangle square , isfirstthe and 2 square
shaded partrectangle 36 rectangle in
is area units Area

5. X = 1 unit, rectangle A = 8 units Prepared By Mr Seelan
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X = 1 unit, rectangle B = 6 units
3 boxes = 9cm 2 boxes = 4cm
1 box = 9cm ÷ 3 1 box = 4cm ÷ 2
8 7 6 5 = 3cm = 2cm
2 2 2 2
6 cm 6 cm 6 cm 6 cm Area of small rectangle =3cm x 2cm
2
3cm = 6 cm
4 3 2 1 2 3 9cm
2 2 2
A
6 cm 6 cm 6 cm x 2 2
6 cm 1 6 cm 2 3
4 5
x6 2
6 cm 6 cm
2 2cm
2 2 2 4cm
6 cm 6 cm 4 6 cm 5 6
2 2 2
6 cm 6 B B cm 6 cm
2 B
Area of unshaded part = 12 boxes x 6 cm
2
= 72 cm
2
Raffles SA1 2010
5/23/2012 Mr Seelan Ans : Area of unshaded part is 72 cm
Hp: 90691139 5

6. Total boxes = 15 boxes
Make all boxes $540equal size
15 boxes = into
Henry Park SA1 2009 Extend the= $540boxes to make the same size as the big boxes
1 box small ÷ 15
= $36
Ans: a) The badminton racket cost $21
Ans: b) The tennis racket cost $342
$36 1 badminton racket cost = $36 -$15
Badminton $21 $15
? = $21
1 badminton racket
racket 1 1 Tennis racket cost = $57 x 6
= $342
2 soccer balls
1 soccer ball
Soccer Ball 2 3 1 tennis racket
$435+$15+$15+$15
$15 $15 $15 $15 $15 $15 +$15 +$15 +$15+$15
Tennis 4 5
$21 6
$21 $21 $15 $21
7 8 9
$21
= $540
racket
$36 $36 $36 $36 $36
10 11 12 13 14 15
5/23/2012 $57 $57Mr Seelan Hp: 90691139
$57 $57 $57 $57 6
1 time 2 times 3 times 4 times 5 times 6 times

7. June = 3 boxes
same Amy = 7 boxes
$60
$20 same
$60
Divide this into 3 boxes Divide this into 3 boxes 3 boxes = $180
1 box = $180 ÷ 3 boxes
= $60
3 small boxes = $60
$60 1 small box = $60 ÷ 3 boxes
= $20
$60 $180
$60
Amy and Susan each pay = $60 + $20
Susan = $80
June Amy
Prepared By Mr Seelan
Hp: 90691139 Home use only Ans: $80 each
Raffles SA2
5/23/2012 2010 Mr Seelan Hp: 90691139 7