Assume that a gold bar is hidden in a room where
you are standing. The following information is given
below.
a. It is underneath the sofa 2 meters away from you.
b. It is 2 meters away from where you are standing.
c. It is 2 meters north from where you are standing.
Which of the given information would be the most
useful? Which is the least useful?
Let us analyze each of the given.
a. You will have to search the whole area of the sofa
starting from you including those above and below
the sofa.
b. You will have to search all points 2 meters away
from you including those above and below the sofa.
c. Provided that you know about the direction of north,
you will be able to find the gold bar quickly.
Vector and Scalar
Vector is a physical quantity that has both magnitude
and direction.
Examples:
•Displacement of 2.0 m [North]
•Velocity of 60 km/hr [East]
•Force of 40 Newton [West]
Scalar is physical quantity that has the only magnitude.
Example:
•Speed of 60 km/hr
•Time of 3 hours
•Temperature of 28 ºC
Enumerate five examples of Vector and
Scalar quantities
Vector Scalar
1 1
2 2
3 3
4 4
5 5
Enumerate five examples of Vector and
Scalar quantities
Vector Scalar
1 Speed – e.g., 60 km/h 1 Velocity – e.g., 60 km/h north
2 Distance – e.g., 100 meters
2 Displacement – e.g., 100
meters east
3 Mass – e.g., 5 kilograms 3 Force – e.g., 10 N downward
4 Temperature – e.g., 37°C
4 Acceleration – e.g., 5 m/s²
upward
5 Time – e.g., 3 seconds
5 Momentum – e.g., 20 kg·m/s
west
Displacement
Vectors
Displacement
is a change in position, which has both magnitude
and direction. We will use letter d for position and the
symbol delta d (∆d) for displacement. The triangle sign,
∆, is the Greek letter delta and is used to represent
“change.”
We could represent the relationship between
displacement and position as:
Sample Problem (DISPLACEMENT
VECTORS)
A student walks 4 meters east from her
house to the nearby store. Then, she
continues walking 3 meters further east to
her friend’s house.
Where: d1 is the initial point
d2 is the final point
R Resultant displacement
Sample Problem (OPPOSITE
DISPLACEMENT VECTORS)
Marvin walks 14 meters east to a nearby bakery.
After buying bread, he walks 9 meters west toward
his house.
Question:
What is Marvin’s resultant displacement from his
house? In which direction?
Where: d1 is the initial point
d2 is the final point
R Resultant displacement
Sample Problem (OPPOSITE
DISPLACEMENT VECTORS)
A student walks 5 meters west to meet a friend.
Later, she walks 9 meters east to go to school.
Question:
What is her resultant displacement from her
house? In which direction?
Sample Problem (Perpendicular Vectors )
Jessa leaves her house and walks 9 meters east to
buy snacks at a nearby store. After that, she walks
12 meters north to visit a friend.
Question:
What is Jessa’s resultant displacement from her
house? How far and in what direction is she from
her starting point?
Use the Pythagorean theorem to find
the resultant displacement
Where: d1 is the initial point
d2 is the final point
R Resultant displacement
Use trigonometry to find the angle
θ= (y/x)
Sample Problem (Perpendicular Vectors )
An airplane flies at 100 km/h north, while
the wind blows 60 km/h west.
31 west of north
∘
​
1. Opposite Displacement Vectors
🔍 Clues/Characteristics:
Vectors point in exactly opposite directions
Example: East vs. West, North vs. South
•Movement is along the same straight line (1D motion)
•Often involves going forward and then backward, or to
and from the same path
•The angle between the vectors is 180°
🧠 How to identify:
•Check if both vectors are along the same axis (horizontal or vertical)
•See if one is described as going back, returning, or opposite in direction
•Use subtraction of magnitudes (larger minus smaller) to find the resultant
✅ Example:
10 m east, then 4 m west → opposite displacement vectors → Resultant: 6
m east​
2. Perpendicular Displacement Vectors
🔍 Clues/Characteristics:
•Vectors form a right angle (90°) between them
•Involves 2D motion — movement in two directions (e.g.,
north then east)
•Describes an L-shaped path or turn
•The vectors are on different axes (e.g., x-axis and y-axis)
🧠 How to identify:
•Look for direction changes like:
•From north to east
•From right to up
•From forward to sideways
Resultant forms the hypotenuse of a right triangle
Use the Pythagorean Theorem and trigonometric ratios (e.g., tan ¹)
⁻
✅ Example:
6 m north, then 8 m east → perpendicular vectors → Resultant: 10 m northeast
Distance
Distance
a scalar quantity in which direction is not
specified.
If the displacement from +2 m to +8 m is +6 m,
what is the distance covered?
The distance covered consists of the total distance
of the path taken and not the change in the initial and
final points.
PRACTICE PROBLEM
1. Anna walks 6 meters east to buy snacks, then
continues walking 4 meters east to visit a friend.What is
Anna’s total displacement from her starting point, and
in what direction?
2. Liza walks 15 meters east from her house to a
grocery store. After shopping, she walks 10 meters west
back toward home.
EXAMPLE PROBLEM
Carlos walks 5 meters north, then 3 meters
south to return toward his house.
d= d2 - d1
PRACTICE PROBLEM
1. Anna walks 6 meters east to buy snacks, then
continues walking 4 meters east to visit a friend.What is
Anna’s total displacement from her starting point, and
in what direction?
2. Liza walks 15 meters east from her house to a
grocery store. After shopping, she walks 10 meters west
back toward home. What is Liza’s resultant
displacement from her starting point?
PRACTICE PROBLEM
3. A student walks 6 m east, then turns and walks 8
m north.
Q: What is the resultant displacement?
4. A boat moves 100 m north across a river, while
the current pushes it 60 m east.
Q: What is its displacement?
PRACTICE PROBLEM
5. A delivery man rides 25 km north to drop
off a package. Then, he rides 30 km south to
another location.What is the resultant
displacement?
Given the following Number Points Distance Traveled
1. -6 m to +7m
2. -2 m to -8 m
3. +2 m to +6 m
4. +8 m to -9 m
5. +2 to -8 m
Solving Vector Component
Vector Components
•Component – part
•The components of a vector mean the parts of a
vector.
•A vector has an x-part and a y-part or an x component
and a y-component
Force Vector Example
Given a set of axes (x, y) where force vector of
316 N has a direction of 35º North of East
35º
F = 316 N
Checking the X-Part or X-Component
The force vector, F, has an x-part or x-component. Draw a vertical
line from the end of the force vector to the x-axis. Starting from the
origin, draw a vector along the x-axis up to the drawn line. This vector
is called the x-component of the force vector
X-component
Checking the Y-Part or Y-Component
Draw a horizontal line from the y-axis to the end of the force
vector. Then draw a vertical vector, which is parallel to the y-axis,
starting from the x-axis to the end of the first vector. This vector is
called the y-component of the force vector.
X-component
Y-component
Using Trigonometry, Solve the Sides of the
Right Triangle
SOH – CAH – TOA
Opposite side of
the angle
Adjacent side of
the angle
The Value of X-Component
If the hypotenuse is 316 N and the angle is 35º, the
length of the adjacent side can be calculated. The
trigonometric functions that forms a relationship between the
angle of the hypotenuse and the adjacent side in a right triangle
is called the cosine function.
cos 𝜃=
𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑠𝑖𝑑𝑒𝑙𝑒𝑛𝑔𝑡ℎ
ℎ𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒𝑙𝑒𝑛𝑔𝑡
cos 35 º=
𝑥 −𝑐𝑜𝑚𝑝𝑜𝑛𝑒𝑛𝑡
316 𝑁
The Value of Y-Component
Since the hypotenuse is 316 N and the angle is 35º, the
length of the opposite side can be solved. The trigonometric
function that relates the length of the hypotenuse, the angle of
the hypotenuse, and the length of its opposite side in a right
triangle is called the sine function.
sin 𝜃=
𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑠𝑖𝑑𝑒𝑙𝑒𝑛𝑔𝑡ℎ
ℎ𝑦𝑝𝑜𝑡ℎ𝑒𝑛𝑢𝑠𝑒𝑙𝑒𝑛𝑔𝑡ℎ
Exercise
The magnitude of a vector F is 10 N and the
direction of the vector is 60º horizontal. Find the
components of the vector.

VECTOR AND SCALAR PPT, FOR GRADE 12 STUDENTS

  • 2.
    Assume that agold bar is hidden in a room where you are standing. The following information is given below. a. It is underneath the sofa 2 meters away from you. b. It is 2 meters away from where you are standing. c. It is 2 meters north from where you are standing.
  • 3.
    Which of thegiven information would be the most useful? Which is the least useful?
  • 4.
    Let us analyzeeach of the given. a. You will have to search the whole area of the sofa starting from you including those above and below the sofa. b. You will have to search all points 2 meters away from you including those above and below the sofa. c. Provided that you know about the direction of north, you will be able to find the gold bar quickly.
  • 5.
  • 6.
    Vector is aphysical quantity that has both magnitude and direction. Examples: •Displacement of 2.0 m [North] •Velocity of 60 km/hr [East] •Force of 40 Newton [West]
  • 7.
    Scalar is physicalquantity that has the only magnitude. Example: •Speed of 60 km/hr •Time of 3 hours •Temperature of 28 ºC
  • 8.
    Enumerate five examplesof Vector and Scalar quantities Vector Scalar 1 1 2 2 3 3 4 4 5 5
  • 9.
    Enumerate five examplesof Vector and Scalar quantities Vector Scalar 1 Speed – e.g., 60 km/h 1 Velocity – e.g., 60 km/h north 2 Distance – e.g., 100 meters 2 Displacement – e.g., 100 meters east 3 Mass – e.g., 5 kilograms 3 Force – e.g., 10 N downward 4 Temperature – e.g., 37°C 4 Acceleration – e.g., 5 m/s² upward 5 Time – e.g., 3 seconds 5 Momentum – e.g., 20 kg·m/s west
  • 10.
  • 11.
    Displacement is a changein position, which has both magnitude and direction. We will use letter d for position and the symbol delta d (∆d) for displacement. The triangle sign, ∆, is the Greek letter delta and is used to represent “change.” We could represent the relationship between displacement and position as:
  • 12.
    Sample Problem (DISPLACEMENT VECTORS) Astudent walks 4 meters east from her house to the nearby store. Then, she continues walking 3 meters further east to her friend’s house.
  • 13.
    Where: d1 isthe initial point d2 is the final point R Resultant displacement
  • 14.
    Sample Problem (OPPOSITE DISPLACEMENTVECTORS) Marvin walks 14 meters east to a nearby bakery. After buying bread, he walks 9 meters west toward his house. Question: What is Marvin’s resultant displacement from his house? In which direction?
  • 15.
    Where: d1 isthe initial point d2 is the final point R Resultant displacement
  • 16.
    Sample Problem (OPPOSITE DISPLACEMENTVECTORS) A student walks 5 meters west to meet a friend. Later, she walks 9 meters east to go to school. Question: What is her resultant displacement from her house? In which direction?
  • 17.
    Sample Problem (PerpendicularVectors ) Jessa leaves her house and walks 9 meters east to buy snacks at a nearby store. After that, she walks 12 meters north to visit a friend. Question: What is Jessa’s resultant displacement from her house? How far and in what direction is she from her starting point?
  • 18.
    Use the Pythagoreantheorem to find the resultant displacement Where: d1 is the initial point d2 is the final point R Resultant displacement
  • 19.
    Use trigonometry tofind the angle θ= (y/x)
  • 20.
    Sample Problem (PerpendicularVectors ) An airplane flies at 100 km/h north, while the wind blows 60 km/h west. 31 west of north ∘ ​
  • 21.
    1. Opposite DisplacementVectors 🔍 Clues/Characteristics: Vectors point in exactly opposite directions Example: East vs. West, North vs. South •Movement is along the same straight line (1D motion) •Often involves going forward and then backward, or to and from the same path •The angle between the vectors is 180°
  • 22.
    🧠 How toidentify: •Check if both vectors are along the same axis (horizontal or vertical) •See if one is described as going back, returning, or opposite in direction •Use subtraction of magnitudes (larger minus smaller) to find the resultant ✅ Example: 10 m east, then 4 m west → opposite displacement vectors → Resultant: 6 m east​
  • 23.
    2. Perpendicular DisplacementVectors 🔍 Clues/Characteristics: •Vectors form a right angle (90°) between them •Involves 2D motion — movement in two directions (e.g., north then east) •Describes an L-shaped path or turn •The vectors are on different axes (e.g., x-axis and y-axis)
  • 24.
    🧠 How toidentify: •Look for direction changes like: •From north to east •From right to up •From forward to sideways Resultant forms the hypotenuse of a right triangle Use the Pythagorean Theorem and trigonometric ratios (e.g., tan ¹) ⁻ ✅ Example: 6 m north, then 8 m east → perpendicular vectors → Resultant: 10 m northeast
  • 26.
  • 27.
    Distance a scalar quantityin which direction is not specified. If the displacement from +2 m to +8 m is +6 m, what is the distance covered? The distance covered consists of the total distance of the path taken and not the change in the initial and final points.
  • 28.
    PRACTICE PROBLEM 1. Annawalks 6 meters east to buy snacks, then continues walking 4 meters east to visit a friend.What is Anna’s total displacement from her starting point, and in what direction? 2. Liza walks 15 meters east from her house to a grocery store. After shopping, she walks 10 meters west back toward home.
  • 29.
    EXAMPLE PROBLEM Carlos walks5 meters north, then 3 meters south to return toward his house. d= d2 - d1
  • 30.
    PRACTICE PROBLEM 1. Annawalks 6 meters east to buy snacks, then continues walking 4 meters east to visit a friend.What is Anna’s total displacement from her starting point, and in what direction? 2. Liza walks 15 meters east from her house to a grocery store. After shopping, she walks 10 meters west back toward home. What is Liza’s resultant displacement from her starting point?
  • 31.
    PRACTICE PROBLEM 3. Astudent walks 6 m east, then turns and walks 8 m north. Q: What is the resultant displacement? 4. A boat moves 100 m north across a river, while the current pushes it 60 m east. Q: What is its displacement?
  • 32.
    PRACTICE PROBLEM 5. Adelivery man rides 25 km north to drop off a package. Then, he rides 30 km south to another location.What is the resultant displacement?
  • 33.
    Given the followingNumber Points Distance Traveled 1. -6 m to +7m 2. -2 m to -8 m 3. +2 m to +6 m 4. +8 m to -9 m 5. +2 to -8 m
  • 34.
  • 35.
    Vector Components •Component –part •The components of a vector mean the parts of a vector. •A vector has an x-part and a y-part or an x component and a y-component
  • 36.
    Force Vector Example Givena set of axes (x, y) where force vector of 316 N has a direction of 35º North of East 35º F = 316 N
  • 37.
    Checking the X-Partor X-Component The force vector, F, has an x-part or x-component. Draw a vertical line from the end of the force vector to the x-axis. Starting from the origin, draw a vector along the x-axis up to the drawn line. This vector is called the x-component of the force vector X-component
  • 38.
    Checking the Y-Partor Y-Component Draw a horizontal line from the y-axis to the end of the force vector. Then draw a vertical vector, which is parallel to the y-axis, starting from the x-axis to the end of the first vector. This vector is called the y-component of the force vector. X-component Y-component
  • 39.
    Using Trigonometry, Solvethe Sides of the Right Triangle SOH – CAH – TOA Opposite side of the angle Adjacent side of the angle
  • 40.
    The Value ofX-Component If the hypotenuse is 316 N and the angle is 35º, the length of the adjacent side can be calculated. The trigonometric functions that forms a relationship between the angle of the hypotenuse and the adjacent side in a right triangle is called the cosine function. cos 𝜃= 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑠𝑖𝑑𝑒𝑙𝑒𝑛𝑔𝑡ℎ ℎ𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒𝑙𝑒𝑛𝑔𝑡 cos 35 º= 𝑥 −𝑐𝑜𝑚𝑝𝑜𝑛𝑒𝑛𝑡 316 𝑁
  • 41.
    The Value ofY-Component Since the hypotenuse is 316 N and the angle is 35º, the length of the opposite side can be solved. The trigonometric function that relates the length of the hypotenuse, the angle of the hypotenuse, and the length of its opposite side in a right triangle is called the sine function. sin 𝜃= 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑠𝑖𝑑𝑒𝑙𝑒𝑛𝑔𝑡ℎ ℎ𝑦𝑝𝑜𝑡ℎ𝑒𝑛𝑢𝑠𝑒𝑙𝑒𝑛𝑔𝑡ℎ
  • 42.
    Exercise The magnitude ofa vector F is 10 N and the direction of the vector is 60º horizontal. Find the components of the vector.