The document summarizes the analysis of a credit card default dataset to predict customer default status. A logistic regression model was created using income, balance, and student status as predictors. The model had good performance with an AUC of 0.9503, correctly classifying 86.24% of customers and reducing the default rate from 3.36% to 0.32% using a probability threshold of 0.03197311. Balance was the most significant predictor of default. The model provides a useful tool for credit card companies to identify high-risk customers.
This document discusses a fraud data set used to build a logistic regression model to predict whether an individual committed fraud (the binary target variable). The training data contains over 3,500 observations with 20% fraud events, and validation data contains over 2,300 observations with 19% fraud events. The logistic regression model found several predictor variables to be statistically significant in predicting fraud, including member duration, number of optometry prescriptions, total spend, and number of no claims. The model provides odds ratio estimates for each predictor variable.
This document provides an overview of chi-square and analysis of variance (ANOVA) statistical tests. It defines chi-square as a test of independence using contingency tables and as a test of goodness of fit. It also defines ANOVA as a test used to compare three or more population means and determine if they are equal or different. Examples are provided to demonstrate how to perform chi-square and one-way ANOVA calculations and analyses.
Experience Mazda Zoom Zoom Lifestyle and Culture by Visiting and joining the Official Mazda Community at http://www.MazdaCommunity.org for additional insight into the Zoom Zoom Lifestyle and special offers for Mazda Community Members. If you live in Arizona, check out CardinaleWay Mazda's eCommerce website at http://www.Cardinale-Way-Mazda.com
Course Project, Part IIntroduction(REMOVE THIS LINE PRIOR CruzIbarra161
Course Project, Part I
Introduction
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: Summarize what you have learned about confidence intervals. Discuss why it would be important to know the population mean of the data used for this term. Is this an important health measure?)
Sample Data
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: List ALL of the sample data in the table below.)
Directions:
1. Use the table above to create an 80%, 95%, and 99% confidence interval.
2. Choose another confidence level (besides 80%, 95% or 99%) to create another confidence interval.
3. Provide a sentence for each confidence interval created above which explains what the confidence interval means in context of topic of your project.
Computations
(Round all values to TWO decimal places)
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: Calculate each of the following.)
Sample Mean =
Sample Standard Deviation =
80% Confidence Interval:
80% Confidence Interval Margin of Error:
Sentence:
95% Confidence Interval:
95% Confidence Interval Margin of Error:
Sentence:
99% Confidence Interval:
99% Confidence Interval Margin of Error:
Sentence:
______% Confidence Interval:
______% Confidence Interval Margin of Error:
Sentence
Problem Analysis
(REMOVE THESE LINES PRIOR TO SUBMITTING REPORT: Write a half-page reflection. What trend do you see takes place to the confidence interval as the confidence level rises? Explain mathematically why that takes place. Explain how Part I of the project has helped you understand confidence intervals better? How did this project help you understand statistics better?)
Course Project, Part II
Preliminary Calculations
Round Preliminary Values to the nearest whole number.
Summary Table for:
Live Births
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Deaths
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Divorces
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Marriages
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Hypothesis Testing
With the information that you gather from the Summary Tables above, test the following (you can use excel when appropriate):
Hypothesis Test #1:
Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance.
Step 1: Clearly state a null and alternative hypothesis, identify the claim, and the type of test.
Ho: μ ≥ ≤ =
Ha: μ < > ≠
Circle One: Left Tailed Test Right Tailed Test Two-Tailed Test
Step 2: Determine the Rejection Region
Pick ONE multiple choice answer below and fill in the critical value. Round Critical Value to two decimal places.
a) ...
Part 1 of 16 -Question 1 of 231.0 PointsThe data presented i.docxodiliagilby
Part 1 of 16 -
Question 1 of 23
1.0 Points
The data presented in the table below resulted from an experiment in which seeds of 5 different types were planted and the number of seeds that germinated within 5 weeks after planting was recorded for each seed type. At the .01 level of significance, is the proportion of seeds that germinate dependent on the seed type?
Seed Type
Observed Frequencies
Germinated
Failed to Germinate
1
31
7
2
57
33
3
87
60
4
52
44
5
10
19
Reset Selection
Question 2 of 23
1.0 Points
A company operates four machines during three shifts each day. From production records, the data in the table below were collected. At the .05 level of significance test to determine if the number of breakdowns is independent of the shift.
Machine
Shift
A
B
C
D
1
41
20
12
16
2
31
11
9
14
3
15
17
16
10
Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
In choosing the “best-fitting” line through a set of points in linear regression, we choose the one with the:
Reset Selection
Question 4 of 23
1.0 Points
A single variable X can explain a large percentage of the variation in some other variable Y when the two variables are:
Reset Selection
Question 5 of 23
1.0 Points
A correlation value of zero indicates.
Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
An investor wants to compare the risks associated with two different stocks. One way to measure the risk of a given stock is to measure the variation in the stock’s daily price changes.
In an effort to test the claim that the variance in the daily stock price changes for stock 1 is different from the variance in the daily stock price changes for stock 2, the investor obtains a random sample of 21 daily price changes for stock 1 and 21 daily price changes for stock 2.
The summary statistics associated with these samples are: n
1
= 21, s
1
= .725, n
2
= 21, s
2
= .529.
If you compute the test value by placing the larger variance in the numerator, at the .05 level of significance, would you conclude that the risks associated with these two stocks are different?
Reset Selection
Question 7 of 23
1.0 Points
Two independent samples of sizes n
1
= 50 and n
2
= 50 are randomly selected from two populations to test the difference between the population means,
. The sampling distribution of the sample mean difference,
is:
Reset Selection
Part 4 of 16 -
Question 8 of 23
1.0 Points
Suppose that the mean time for a certain car to go from 0 to 60 miles per hour was 7.7 seconds. Suppose that you want to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer than 7.7 seconds. What would you use for the alternative hypothesis?
Reset Selection
Question 9 of 23
1.0 Points
A two-tailed test is one where:
Reset Selection
Question 10 of 23
1.0 Points
Which of the following values is not typically used for
?
Reset Selection
Part 5 of 16 -
Question 11 of 23
1.0 Points
From a sample of 500 items, 30 wer.
Question 4 of 400.0 2.5 PointsJoe dealt 20 cards from a stand.docxwraythallchan
Question 4 of 40
0.0/ 2.5 Points
Joe dealt 20 cards from a standard 52-card deck, and the number of red cards exceeded the number of black cards by 8. He reshuffled the cards and dealt 30 cards. This time, the number of red cards exceeded the number of black cards by 10. Determine which deal is closer to the 50/50 ratio of red/black expected of fairly dealt hands from a fair deck and why.
A. The first series is closer because 1/10 is farther from 1/2 than is 1/8.
B. The series closer to the theoretical 50/50 cannot be determined unless the number of red and black cards for each deal is given.
C. The second series is closer because 20/30 is closer to 1/2 than is 14/20.
D. The first series is closer because the difference between red and black is smaller than the difference in the second series.
Question 5 of 40
0.0/ 2.5 Points
A study of 600 college students taking Statistics 101 revealed that 54 students received the grade of A. Typically 10% of the class gets an A. The difference between this group of students and the expected value is not significant at the 0.05 level. What does this mean in this case?
A. The probability that the difference occurred due to chance is less than 0.05.
B. The probability of getting an A is 10% and only 9% got an A in this study. The difference is less than 5% so it is not significant.
C. There is not enough information to make any conclusion.
D. The probability that the difference occurred due to chance is more than 0.05.
Question 6 of 40
0.0/ 2.5 Points
Jody checked the temperature 12 times on Monday, and the last digit of the temperature was odd six times more than it was even. On Tuesday, she checked it 18 times and the last digit was odd eight times more than it was even. Determine which series is closer to the 50/50 ratio of odd/even expected of such a series of temperature checks.
A. The Monday series is closer because 1/6 is closer to 1/2 than is 1/8.
B. The Monday series is closer because 6/12 is closer to 0.5 than is 8/18.
C. The Tuesday series is closer because the 13/18 is closer to 0.5 than is 9/12.
D. The series closest to the theoretical 50/50 cannot be determined without knowing the number of odds and evens in each series.
Question 10 of 40
0.0/ 2.5 Points
If you flip a coin three times, the possible outcomes are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the probability of getting at most one head?
A. 4/9
B. 5/6
C. 7/8
D. 5/8
Question 11 of 40
0.0/ 2.5 Points
A study of two types of weed killers was done on two identical weed plots. One weed killer killed 15% more weeds than the other. This difference was significant at the 0.05 level. What does this mean?
A. The improvement was due to the fact that there were more weeds in one study.
B. The probability that the difference was due to chance alone is greater than 0.05.
C. The probability that one weed killer performed better by chance alone is less than 0.05.
D. There is not enough inform ...
The document summarizes the analysis of a credit card default dataset to predict customer default status. A logistic regression model was created using income, balance, and student status as predictors. The model had good performance with an AUC of 0.9503, correctly classifying 86.24% of customers and reducing the default rate from 3.36% to 0.32% using a probability threshold of 0.03197311. Balance was the most significant predictor of default. The model provides a useful tool for credit card companies to identify high-risk customers.
This document discusses a fraud data set used to build a logistic regression model to predict whether an individual committed fraud (the binary target variable). The training data contains over 3,500 observations with 20% fraud events, and validation data contains over 2,300 observations with 19% fraud events. The logistic regression model found several predictor variables to be statistically significant in predicting fraud, including member duration, number of optometry prescriptions, total spend, and number of no claims. The model provides odds ratio estimates for each predictor variable.
This document provides an overview of chi-square and analysis of variance (ANOVA) statistical tests. It defines chi-square as a test of independence using contingency tables and as a test of goodness of fit. It also defines ANOVA as a test used to compare three or more population means and determine if they are equal or different. Examples are provided to demonstrate how to perform chi-square and one-way ANOVA calculations and analyses.
Experience Mazda Zoom Zoom Lifestyle and Culture by Visiting and joining the Official Mazda Community at http://www.MazdaCommunity.org for additional insight into the Zoom Zoom Lifestyle and special offers for Mazda Community Members. If you live in Arizona, check out CardinaleWay Mazda's eCommerce website at http://www.Cardinale-Way-Mazda.com
Course Project, Part IIntroduction(REMOVE THIS LINE PRIOR CruzIbarra161
Course Project, Part I
Introduction
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: Summarize what you have learned about confidence intervals. Discuss why it would be important to know the population mean of the data used for this term. Is this an important health measure?)
Sample Data
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: List ALL of the sample data in the table below.)
Directions:
1. Use the table above to create an 80%, 95%, and 99% confidence interval.
2. Choose another confidence level (besides 80%, 95% or 99%) to create another confidence interval.
3. Provide a sentence for each confidence interval created above which explains what the confidence interval means in context of topic of your project.
Computations
(Round all values to TWO decimal places)
(REMOVE THIS LINE PRIOR TO SUBMITTING REPORT: Calculate each of the following.)
Sample Mean =
Sample Standard Deviation =
80% Confidence Interval:
80% Confidence Interval Margin of Error:
Sentence:
95% Confidence Interval:
95% Confidence Interval Margin of Error:
Sentence:
99% Confidence Interval:
99% Confidence Interval Margin of Error:
Sentence:
______% Confidence Interval:
______% Confidence Interval Margin of Error:
Sentence
Problem Analysis
(REMOVE THESE LINES PRIOR TO SUBMITTING REPORT: Write a half-page reflection. What trend do you see takes place to the confidence interval as the confidence level rises? Explain mathematically why that takes place. Explain how Part I of the project has helped you understand confidence intervals better? How did this project help you understand statistics better?)
Course Project, Part II
Preliminary Calculations
Round Preliminary Values to the nearest whole number.
Summary Table for:
Live Births
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Deaths
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Divorces
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Summary Table for:
Marriages
Mean
Median
Sample Standard Deviation
Minimum
Maximum
Sample Size
Hypothesis Testing
With the information that you gather from the Summary Tables above, test the following (you can use excel when appropriate):
Hypothesis Test #1:
Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance.
Step 1: Clearly state a null and alternative hypothesis, identify the claim, and the type of test.
Ho: μ ≥ ≤ =
Ha: μ < > ≠
Circle One: Left Tailed Test Right Tailed Test Two-Tailed Test
Step 2: Determine the Rejection Region
Pick ONE multiple choice answer below and fill in the critical value. Round Critical Value to two decimal places.
a) ...
Part 1 of 16 -Question 1 of 231.0 PointsThe data presented i.docxodiliagilby
Part 1 of 16 -
Question 1 of 23
1.0 Points
The data presented in the table below resulted from an experiment in which seeds of 5 different types were planted and the number of seeds that germinated within 5 weeks after planting was recorded for each seed type. At the .01 level of significance, is the proportion of seeds that germinate dependent on the seed type?
Seed Type
Observed Frequencies
Germinated
Failed to Germinate
1
31
7
2
57
33
3
87
60
4
52
44
5
10
19
Reset Selection
Question 2 of 23
1.0 Points
A company operates four machines during three shifts each day. From production records, the data in the table below were collected. At the .05 level of significance test to determine if the number of breakdowns is independent of the shift.
Machine
Shift
A
B
C
D
1
41
20
12
16
2
31
11
9
14
3
15
17
16
10
Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
In choosing the “best-fitting” line through a set of points in linear regression, we choose the one with the:
Reset Selection
Question 4 of 23
1.0 Points
A single variable X can explain a large percentage of the variation in some other variable Y when the two variables are:
Reset Selection
Question 5 of 23
1.0 Points
A correlation value of zero indicates.
Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
An investor wants to compare the risks associated with two different stocks. One way to measure the risk of a given stock is to measure the variation in the stock’s daily price changes.
In an effort to test the claim that the variance in the daily stock price changes for stock 1 is different from the variance in the daily stock price changes for stock 2, the investor obtains a random sample of 21 daily price changes for stock 1 and 21 daily price changes for stock 2.
The summary statistics associated with these samples are: n
1
= 21, s
1
= .725, n
2
= 21, s
2
= .529.
If you compute the test value by placing the larger variance in the numerator, at the .05 level of significance, would you conclude that the risks associated with these two stocks are different?
Reset Selection
Question 7 of 23
1.0 Points
Two independent samples of sizes n
1
= 50 and n
2
= 50 are randomly selected from two populations to test the difference between the population means,
. The sampling distribution of the sample mean difference,
is:
Reset Selection
Part 4 of 16 -
Question 8 of 23
1.0 Points
Suppose that the mean time for a certain car to go from 0 to 60 miles per hour was 7.7 seconds. Suppose that you want to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer than 7.7 seconds. What would you use for the alternative hypothesis?
Reset Selection
Question 9 of 23
1.0 Points
A two-tailed test is one where:
Reset Selection
Question 10 of 23
1.0 Points
Which of the following values is not typically used for
?
Reset Selection
Part 5 of 16 -
Question 11 of 23
1.0 Points
From a sample of 500 items, 30 wer.
Question 4 of 400.0 2.5 PointsJoe dealt 20 cards from a stand.docxwraythallchan
Question 4 of 40
0.0/ 2.5 Points
Joe dealt 20 cards from a standard 52-card deck, and the number of red cards exceeded the number of black cards by 8. He reshuffled the cards and dealt 30 cards. This time, the number of red cards exceeded the number of black cards by 10. Determine which deal is closer to the 50/50 ratio of red/black expected of fairly dealt hands from a fair deck and why.
A. The first series is closer because 1/10 is farther from 1/2 than is 1/8.
B. The series closer to the theoretical 50/50 cannot be determined unless the number of red and black cards for each deal is given.
C. The second series is closer because 20/30 is closer to 1/2 than is 14/20.
D. The first series is closer because the difference between red and black is smaller than the difference in the second series.
Question 5 of 40
0.0/ 2.5 Points
A study of 600 college students taking Statistics 101 revealed that 54 students received the grade of A. Typically 10% of the class gets an A. The difference between this group of students and the expected value is not significant at the 0.05 level. What does this mean in this case?
A. The probability that the difference occurred due to chance is less than 0.05.
B. The probability of getting an A is 10% and only 9% got an A in this study. The difference is less than 5% so it is not significant.
C. There is not enough information to make any conclusion.
D. The probability that the difference occurred due to chance is more than 0.05.
Question 6 of 40
0.0/ 2.5 Points
Jody checked the temperature 12 times on Monday, and the last digit of the temperature was odd six times more than it was even. On Tuesday, she checked it 18 times and the last digit was odd eight times more than it was even. Determine which series is closer to the 50/50 ratio of odd/even expected of such a series of temperature checks.
A. The Monday series is closer because 1/6 is closer to 1/2 than is 1/8.
B. The Monday series is closer because 6/12 is closer to 0.5 than is 8/18.
C. The Tuesday series is closer because the 13/18 is closer to 0.5 than is 9/12.
D. The series closest to the theoretical 50/50 cannot be determined without knowing the number of odds and evens in each series.
Question 10 of 40
0.0/ 2.5 Points
If you flip a coin three times, the possible outcomes are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the probability of getting at most one head?
A. 4/9
B. 5/6
C. 7/8
D. 5/8
Question 11 of 40
0.0/ 2.5 Points
A study of two types of weed killers was done on two identical weed plots. One weed killer killed 15% more weeds than the other. This difference was significant at the 0.05 level. What does this mean?
A. The improvement was due to the fact that there were more weeds in one study.
B. The probability that the difference was due to chance alone is greater than 0.05.
C. The probability that one weed killer performed better by chance alone is less than 0.05.
D. There is not enough inform ...
ELEMENTS OF STATISTICS / TUTORIALOUTLET DOT COMalbert0076
Unit 3 Problem Set NAME: Elements of Statistics--FHSU Virtual College--Spring 2017
REMEMBER, these are assessed preparatory problems related to the content of Unit 3. The Unit 3 Exam will consist of similar types of
1. Consider the following partially completed computer printout fo.docxjackiewalcutt
1. Consider the following partially completed computer printout for a regression analysis where the dependent variable is the price of a personal computer and the independent variable is the size of the hard drive.
Based on the information provided, what is the F statistic?
About 8 .33
Just over 2.35
About 4.76
About 69.5
4 points
QUESTION 2
1. The standard error of the estimate is a measure of
total variation of the Y variable.
the variation around the sample regression line.
explained variation.
the variation of the X variable.
4 points
QUESTION 3
3.Nintendo Sony would like to test the hypothesis that a difference exists in the average age of users of a Wii, a PlayStation, or an Xbox console game. The following data represent the age of a random sample of Wii, PlayStation, and Xbox users.
Wii
PlayStation
Xbox
37
26
31
31
21
20
47
24
38
29
24
31
36
25
30
Using α = 0.05, the conclusion for this hypothesis test would be that because the test statistic is
more than the critical value, we cannot conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
less than the critical value, we cannot conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
more than the critical value, we can conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
less than the critical value, we can conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
4 points
QUESTION 4
1. The relationship of Y to four other variables was established as Y = 12 + 3X1 - 5X2 + 7X3 + 2X4. When X1 increases 5 units and X2 In a sample of n = 23, the Student's t test statistic for a correlation of r = .500 would be:
2.559
2.819
2.646
can’t say without knowing α (alpha)
4 points
QUESTION 5
1. Given the following ANOVA table (some information is missing), find the F statistic.
3.71
0.99
0.497
4.02
4 points
QUESTION 6
1. Examine the following two-factor analysis of variance table:
Complete the analysis of variance table.
MSA = 40.928, F Factor A =3.35, SSB = 85.35, Factor B df = 3, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 1.8, SSE = 789.29, SSE df = 66, MSE = 12.143
MSA = 40.928, F Factor A = 3.35, SSB = 85.35, Factor B df = 4, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 2.1 SSE = 789.29, SSE df = 66, MSE = 12.143
MSA = 40.698, F Factor A = 3.35, SSB = 84.35, Factor B df = 5, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 2.1, SSE = 789.29, SSE df = 65, MSE = 12.143
MSA = 40.698, F Factor A = 3.35, SSB = 84.35, Factor B df = 3, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 1.8, SSE = 789.29, SSE df = 65, MSE = 12.143
4 points
QUESTION 7
1. The critical value for a two-tailed test of H0: ß1 = 0 at a (alpha) = .05 in a simple regression with 22 observations is:
+ or - 1.725 ...
Part 1 of 16 - Question 1 of 231.0 PointsThe data pres.docxherbertwilson5999
Part 1 of 16 -
Question 1 of 23
1.0 Points
The data presented in the table below resulted from an experiment in which seeds of 5 different types were planted and the number of seeds that germinated within 5 weeks after planting was recorded for each seed type. At the .01 level of significance, is the proportion of seeds that germinate dependent on the seed type?
Seed Type
Observed Frequencies
Germinated
Failed to Germinate
1
31
7
2
57
33
3
87
60
4
52
44
5
10
19
A.Yes, because the test value 16.86 is greater than the critical value of 13.28
B.Yes, because the test value 16.86 is less than the critical value of 14.86
C.No, because the test value 16.86 is greater than the critical value of 13.28
D.No, because the test value 13.28 is less than the critical value of 16.86
Reset Selection
Question 2 of 23
1.0 Points
The chi-square goodness-of-fit test can be used to test for:
A.significance of sample statistics
B.normality
C.difference between population variances
D.difference between population means
Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
The marketing manager of a large supermarket chain would like to use shelf space to predict the sales of pet food. For a random sample of 12 similar stores, she gathered the following information regarding the shelf space, in feet, devoted to pet food and the weekly sales in hundreds of dollars.
Store
1
2
3
4
5
6
Shelf Space
5
5
5
10
10
10
Weekly Sales
1.6
2.2
1.4
1.9
2.4
2.6
Store
7
8
9
10
11
12
Shelf Space
15
15
15
20
20
20
Weekly Sales
2.3
2.7
2.8
2.6
2.9
3.1
What is the estimated regression equation?
A. = 1.45 + 0.074x
B. = 2.63 - 0.174x
C. = 2.63 + 0.724x
D. = 1.45 + 0.724x
Reset Selection
Question 4 of 23
1.0 Points
A single variable X can explain a large percentage of the variation in some other variable Y when the two variables are:
A.highly correlated
B.directly related
C.inversely related
D.mutually exclusive
Reset Selection
Question 5 of 23
1.0 Points
Data for a sample of 25 apartments in a particular neighborhood are provided in the worksheet Apartments in the Excel workbook Apartments.xlsx. Using that data, find the estimated regression equation which can be used to estimate the monthly rent for apartments in this neighborhood using size as the predictor variable.
Apartments.xlsx
A. 177.12 + 1.065(size)
B.177.12 + 0.8500(size)
C.1.065 + 177.12(size)
D.197.12 + 2.065(size)
Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
A pharmaceutical company is testing the effectiveness of a new drug for lowering cholesterol. As part of this trial, they wish to determine whether there is a difference between the effectiveness for women and for men. Assume α = 0.05. What is the test value?
Women
Men
Sample size
50
80
Mean effect
7
6.95
Sample variance
3
4
A.t = 3.252
B.t = 0.151
C.z = 0.081
D.z = 0.455
Reset Selection
Question 7 of 23
.
26 Ch. 3 Organizing and Graphing DataAssignment 2ME.docxeugeniadean34240
26 Ch. 3: Organizing and Graphing Data
Assignment 2
MEASURES OF CENTRAL TENDENCY
Fill in the blanks:
4.1. The score that repeats the most often in a distribution is called the ______.
4.2. The descriptive statistic used the most in inferential statistics as a measure of central tendency is the _________.
4.3. The measure of central tendency used with nominal scale data is the _______.
4.4. To find the mean of a sample, thethe sum of the scoresas is divided by ______.
Circle the correct answer:
4.5. In a positively skewed distribution, the majority of the scores cluster above/below the ________.
4.6. The mode and the mean have the same values in distributions that are normal/negatively skewed.
4.7. Distributions with few scores are more/less likely to have a mode than distributions with many scores.
Answer the following questions:
4.8. Which measure of central tendency would be the most appropriate for summarizing the following test scores? Explain your choice.
13, 14, 10, 38, 11, 12, 16, 15
4.9. What is the difference between and ? How are they related to each other?
4.10. A distribution of 10 scores has a mean of 6. Following are 9 scores of this distribution. Which score is missing (remember that the mean should be 6)?
4, 8, 10, 5, 9, 3, 6, 7, 3
4.11. When the sum of a group of scores is 280 and the mean of the scores is 7, how many scores are in the distribution?
4.12. Find the mode, median, and mean of the distribution depicted in the following histogram:
Frequency
Scores
MEASURES OF VARIABILITY
Circle the correct answer:
5.1. The distance between the highest and the lowest scores is called the range/variance.
5.2. The SD is equal to the square root of the mean/variance.
5.3. A test with 30 items is likely to have a higher/lower standard deviation that a test with 80 items.
5.4. The mean of the squared deviation scores is called the variance/standard deviation.
5.5. The SD of the number of errors found by an auditor in a sample of accounts of one company is likely to be higher/lower than the SD of the number of errors found in samples taken from a number of different companies.
5.6. The SD is/is not sensitive to extreme scores.
5.7. The variance of the population is represented by S2/2.
5.8. In most cases, the variance is larger/smaller than the SD.
5.9. The measure of variability that takes into consideration every score in the distribution is the range/standard deviation.
Answer/compute the following questions:
5.10. Study the following three distributions. What are the similarities and differences between the three distributions in terms of their means, ranges, and standard deviations? (Note: Assume the three distributions to be samples if you decide to compute their standard deviations.)
Distribution A: 8, 9, 6, 12, 5
Distribution B: 7, 10, 11, 8, 4
Distribution C: 7, 9, 8, 9, 7
5.11. Three statistics classes (Sections A, B and C), each with 26 students, took the same test. The SD o.
QNT Weekly learning assessments - Questions and Answers | UOP E AssignmentsUOP E Assignments
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InstructionDue Date 6 pm on October 28 (Wed)Part IProbability a.docxdirkrplav
This document discusses implementing a social, environmental, and economic impact measurement system within a company. It explains that measuring sustainability performance is critical for evaluating projects, the company, and its members. A proper measurement system allows companies to develop a sustainability strategy, allocate resources to support it, and evaluate trade-offs between sustainability projects. The document provides examples from Nike and P&G of measuring impacts to demonstrate the business case for sustainability. It stresses that measurement is important for linking performance to sustainability principles and facilitating continuous improvement.
1T1 Conduct one-way ANOVA analysis on the height using the .docxeugeniadean34240
1
T1: Conduct one-way ANOVA analysis on the height using the "Weight and Height.xlsx" sample data under the Data Sets (See Attachment) folder (Note that you will need to change the format of the data set to conduct the analysis). Based on your results, what conclusion would you draw regarding the average height of students in the three states?
Solution
:
Null Hypothesis: All the states have the same mean height of the students.
Alternate Hypothesis: Not all the states have the same mean height of the students.
The One-Way Analysis of Variance was performed in SPSS. The SPSS output is given as follows:
Descriptives
Height
N
Mean
Std. Deviation
Std. Error
95% Confidence Interval for Mean
Minimum
Maximum
Lower Bound
Upper Bound
KS
28
67.5714
3.30184
.62399
66.2911
68.8517
62.00
75.00
MO
41
69.9756
3.24220
.50635
68.9522
70.9990
61.00
75.00
NE
23
67.8696
4.18593
.87283
66.0594
69.6797
61.75
74.00
Total
92
68.7174
3.65929
.38151
67.9596
69.4752
61.00
75.00
Test of Homogeneity of Variances
Height
Levene Statistic
df1
df2
Sig.
1.697
2
89
.189
Levene Statistic (2, 89) = 1.697, p-value = 0.189Comment by Bo Yan: I don’t have SPSS installed on my computer. But the your results are slightly different from the numbers I got from using Excel and another statistical package.
The p-value is significant at α=0.05. From this test we conclude that we do not have the homogeneity of variance. Comment by Bo Yan: Does the evidence support your conclusion here when p > 0.05?
ANOVA
Height
Sum of Squares
df
Mean Square
F
Sig.
Between Groups
118.211
2
59.105
4.781
.011
Within Groups
1100.316
89
12.363
Total
1218.527
91
F (2, 89) = 4.781, p-value = 0.011
The p-value is significant at α=0.05. We reject the null hypothesis. From our analysis there is sufficient evidence to conclude that not all the states have the same mean height of the students, at a significance level of 0.05. This can be further emphasized from the results of the post-hoc tests. The following table shows the results of the Turkey’s HSD post hoc tests:Comment by Bo Yan: Good.
Multiple Comparisons
Dependent Variable: Height
Tukey HSD
(I) State
(J) State
Mean Difference (I-J)
Std. Error
Sig.
95% Confidence Interval
Lower Bound
Upper Bound
KS
MO
-2.40418*
.86202
.018
-4.4588
-.3495
NE
-.29814
.98948
.951
-2.6566
2.0603
MO
KS
2.40418*
.86202
.018
.3495
4.4588
NE
2.10604
.91601
.061
-.0773
4.2894
NE
KS
.29814
.98948
.951
-2.0603
2.6566
MO
-2.10604
.91601
.061
-4.2894
.0773
*. The mean difference is significant at the 0.05 level.
KS & MO:
The 95% confidence interval for the difference of means is given as (-4.4588, -.3495).
As the confidence interval does not contain 0, we can conclude that there is statistically significant difference between the mean height of students belonging to the states KS and MO.Comment by Bo Yan: Now you should understand the difference between statistically significant and practically significant difference. So I expect you to be mor.
Question 1 (25 points)Question 1 optionsEnter the answer to.docxIRESH3
Question 1 (25 points)
Question 1 options:
Enter the answer to each of the of the questions with:
T for True
F for False
a. If the variance from a data set is zero, then all the observations in this data set must be identical.
b. P(A and Ac) = 1 where Ac is the compliment of A.
c. The mean is always equal to the median for a normal distribution.
d. A 99% confidence interval is wider than a 95% confidence interval of the same parameter.
e. It is easier to reject the null hypothesis if we use a smaller significance level (alpha).
Question 2 (4 points)
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
A
2.0 - 2.9
B
.4
3.0 - 3.9
C
D
4.0 - 5.9
5
E
Total
25
F
Complete the Frequency Table with the missing frequency and relative frequency numbers.
Enter answer for "A" with 2 decimal place acueacy.
Enter answer for "B" as an integer.
Enter answer for "C" as an integer.
Enter answer for "D" as an integer.
Enter answer for "E" with 2 decimal place acueacy.
Enter answer for "F" as an integer.
Question 3 (5 points)
Question 3 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question.
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
2.0 - 2.9
0.4
3.0 - 3.9
4.0 - 5.9
5
Total
25
What percentage of the checkout times was at least 3 minutes?
Enter answer as a percent without the percent sign to 0 decimal places.
Question 4 (5 points)
Question 4 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question with the Interval column added.
Interval
Checkout Time (in minutes)
Frequency
Relative Frequency
1
1.0 - 1.9
4
2
2.0 - 2.9
0.4
3
3.0 - 3.9
4
4.0 - 5.9
5
5
Total
25
In what class interval must the median lie?
Enter answer with the appropriate Interval number.
Question 5 (5 points)
Question 5 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question.
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
2.0 - 2.9
0.4
3.0 - 3.9
4.0 - 5.9
5
Total
25
Assume that the largest observation in this dataset is 4.8. Suppose this observation were incorrectly recorded as 8.4 instead of 4.8.
Will the ...
Question 2 of 231.0 PointsA company operates four machines dur.docxwraythallchan
Question 2 of 23
1.0 Points
A company operates four machines during three shifts each day. From production records, the data in the table below were collected. At the .05 level of significance test to determine if the number of breakdowns is independent of the shift.
Machine
1
2
3
Shift
A
41
31
15
B
20
11
17
C
12
9
16
D
16
14
10
A.The number of breakdowns is dependent on the shift, because the test value 11.649 is less than the critical value of 12.592.
B.The claim that the number of breakdowns is independent of the shift cannot be rejected, because the test value 11.649 is less than the critical value of 12.592.
C.The number of breakdowns is dependent on the shift, because the p-value is .07.
D.The number of breakdowns is independent of the shift, because the test value 12.592 is greater than the critical value of 11.649. Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
If an estimated regression line has a Y-intercept of –7.5 and a slope of 2.5, then when X = 3, the actual value of Y is:
A.10
B.5
C.unknown
D.0 Reset Selection
Question 4 of 23
1.0 Points
The city of Oakdale wishes to see if there is a linear relationship between the temperature and the amount of electricity used (in kilowatts). Based on the data in the table below, is there a significant linear relationship between temperature and the amount of electricity used? These data are also available in the worksheet temperature in the Excel workbook Temperature.xlsx.
Temperature.xlsx
Temperature (x)
Kilowatts (y)
73
680
78
760
85
910
98
1510
93
1170
81
837
76
600
105
1800
A.No, the sample correlation coefficient is equal to 0.098, which does not provide evidence of a significant linear relationship.
B.No, the sample correlation coefficient is equal to 0.981, which does not provide evidence of a significant linear relationship.
C.Yes, the sample correlation coefficient is equal to 0.878, which provides evidence of a significant linear relationship.
D.Yes, the sample correlation coefficient is equal to 0.981, which provides evidence of a significant linear relationship. Reset Selection
Question 5 of 23
1.0 Points
____________ is/are especially helpful in identifying outliers.
A.Scatterplots
B.Normal curves
C.Linear regression
D.Regression analysis Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
Serum ferritin is used in diagnosing iron deficiency. In a study conducted recently researchers discovered that in a sample of 28 elderly men the sample standard deviation of serum ferritin was 52.6 mg/L. For 26 younger men the sample standard deviation was 84.2 mg/L. At the .01 level of significance, do these data support the conclusion that the ferritin distribution in elderly men has a smaller variance than in younger men?
A.No, because the test value 1.60 is less than the critical value of 2.54
B.Yes, because the test value 0.390 is less than the critical value 2.54
C.Yes, because the test value 2.56 is greater than the critical value ...
[The following information applies to the questions displayed belo.docxdanielfoster65629
[The following information applies to the questions displayed below.]
A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.01 significance level.
H0: μ ≤ 10
H1: μ > 10
1.
Value:
10.00 points
Required information
a.
Is this a one- or two-tailed test?
One-tailed test
Two-tailed test
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
2.
Value:
10.00 points
Required information
b.
What is the decision rule?
Reject H0 when z ≤ 2.326
Reject H0 when z > 2.326
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
3.
Value:
10.00 points
Required information
c.
What is the value of the test statistic?
Value of the test statistic
References
EBook & Resources
Worksheet Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
4.
Value:
10.00 points
Required information
d.
What is your decision regarding H0?
Fail to reject H0
Reject H0
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
5.
Value:
10.00 points
Required information
e.
What is the p-value?
p-value
References
Given the following hypotheses:
H0 : μ = 400
H1 : μ ≠ 400
A random sample of 12 observations is selected from a normal population. The sample mean was 407 and the sample standard deviation 6. Using the .01 significance level:
a.
State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.)
Reject H0 when the test statistic is the interval (,).
b.
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
Value of the test statistic
c.
What is your decision regarding the null hypothesis?
Do not reject
Reject
The management of White Industries is considering a new method of assembling its golf cart. The present method requires 42.3 minutes, on the average, to assemble a cart. The mean assembly time for a random sample of 24 carts, using the new method, was 40.6 minutes, and the standard deviation of the sample was 2.7 minutes. Using the .10 level of significance, can we conclude that the assembly time using the new method is faster?
a.
What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Rej.
- The document provides information about statisticshomeworkhelper.com, a service that offers probability and statistics assignment help. It lists their website, email, and phone number for contacting them.
- It then provides an example of a multi-part statistics problem involving hypothesis testing on coin flips and dice data. It asks the reader to conduct various statistical tests and interpret the results.
- Finally, it lists some additional practice problems involving chi-square tests, ANOVA, and other statistical analyses for the reader to work through.
This document contains exercises related to probability and expected value concepts. It includes 3 practice problems:
1) Calculating the expected payment of an inverse floater security based on the probability distribution of short-term interest rates.
2) Finding the expected profit for a mining company with two potential reserves that each have a 30% chance of success.
3) Determining the joint probability distribution and expected total demand for a salmon dish served at a cafe based on the independent lunch and dinner demand distributions.
The document presents a case study where Lisa wants to open a beauty store and needs data to support her belief that women in her local area spend more than the national average of $59 every 3 months on fragrance products. Lisa takes a random sample of 25 women in her area and finds the sample mean is $68.10 with a standard deviation of $14.46. She conducts a one-sample t-test to test if the population mean is greater than $59. The test statistic is 3.1484 with a p-value of 0.0021, which is less than the significance level of 0.05. Therefore, there is sufficient evidence to conclude that the population mean is indeed greater than $
Probability Distributions for Discrete Variablesgetyourcheaton
This document discusses probability distributions for discrete variables. It begins by defining a probability distribution as a relative frequency distribution of all possible outcomes of an experiment. It provides examples of probability distributions for discrete variables like the binomial distribution. It discusses key aspects of probability distributions like the mean, standard deviation, and different types of distributions like binomial. It provides examples of calculating probabilities, means, and standard deviations for binomial distributions. It discusses the basic characteristics of the binomial distribution and provides an example of constructing a binomial distribution and calculating related probabilities.
Assessment 3 – Hypothesis, Effect Size, Power, and t Tests.docxcargillfilberto
Assessment 3 – Hypothesis, Effect Size, Power, and
t
Tests
Complete the following problems within this Word document. Do not submit other files. Show your work for problem sets that require calculations. Ensure that your answer to each problem is clearly visible. You may want to highlight your answer or use a different type color to set it apart.
Hypothesis, Effect Size, and Power
Problem Set 3.1: Sampling Distribution of the Mean Exercise
Criterion:
Interpret population mean and variance.
Instructions:
Read the information below and answer the questions.
Suppose a researcher wants to learn more about the mean attention span of individuals in some hypothetical population. The researcher cites that the attention span (the time in minutes attending to some task) in this population is normally distributed with the following characteristics: 20
36
. Based on the parameters given in this example, answer the following questions:
1. What is the population mean (μ)? __________________________
2. What is the population variance
? __________________________
3. Sketch the distribution of this population. Make sure you draw the shape of the distribution and label the mean plus and minus three standard deviations.
Problem Set 3.2: Effect Size and Power
Criterion:
Explain effect size and power.
Instructions:
Read each of the following three scenarios and answer the questions.
Two researchers make a test concerning the effectiveness of a drug use treatment. Researcher A determines that the effect size in the population of males is
d
= 0.36; Researcher B determines that the effect size in the population of females is
d
= 0.20. All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Two researchers make a test concerning the levels of marital satisfaction among military families. Researcher A collects a sample of 22 married couples (
n
= 22); Researcher B collects a sample of 40 married couples (
n
= 40). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Two researchers make a test concerning standardized exam performance among senior high school students in one of two local communities. Researcher A tests performance from the population in the northern community, where the standard deviation of test scores is 110 (
); Researcher B tests performance from the population in the southern community, where the standard deviation of test scores is 60 (
). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Problem Set 3.3: Hypothesis, Direction, and Population Mean
Criterion:
Explain the relationship between hypothesis, tests, and population mean.
Instructions:
Read the following and answer the questions.
STAT 200 Final ExaminationFall 2016 OL1US1Page 9 of 9STAT 200.docxwhitneyleman54422
STAT 200 Final ExaminationFall 2016 OL1/US1Page 9 of 9
STAT 200 Introduction to Statistics Name______________________________
Final Examination: Fall 2016 OL1/US1 Instructor __________________________
Answer Sheet
Instructions:
This is an open-book exam. You may refer to your text and other course materials as you work on the exam, and you may use a calculator.
Record your answers and work in this document.
Answer all 20 questions. Make sure your answers are as complete as possible. Show all of your work and reasoning. In particular, when there are calculations involved, you must show how you come up with your answers with critical work and/or necessary tables. Answers that come straight from calculators, programs or software packages without explanation will not be accepted. If you need to use technology to aid in your calculation, you have to cite the source and explain how you get the results. For example, state the Excel function along with the required parameters when using Excel; describe the detailed steps when using a hand-held calculator; or provide the URL and detailed steps when using an online calculator, and so on.
Show all supporting work and write all answers in the spaces allotted on the following pages. You may type your work using plain-text formatting or an equation editor, or you may hand-write your work and scan it. In either case, show work neatly and correctly, following standard mathematical conventions. Each step should follow clearly and completely from the previous step. If necessary, you may attach extra pages.
You must complete the exam individually. Neither collaboration nor consultation with others is allowed. It is a violation of the UMUC Academic Dishonesty and Plagiarism policy to use unauthorized materials or work from others. Your exam will receive a zero grade unless you complete the following honor statement.
Please sign (or type) your name below the following honor statement:
I understand that it is a violation of the UMUC Academic Dishonesty and Plagiarism policy to use unauthorized materials or work from others. I promise that I did not discuss any aspect of this exam with anyone other than my instructor. I further promise that I neither gave nor received any unauthorized assistance on this exam, and that the work presented herein is entirely my own.
Name _____________________Date___________________
Record your answers and work.
Problem Number
Solution
1
Answer:
(a)
(b)
(c)
(d)
(e)
Justification:
2
Answer:
(a)
(b)
(c)
Justification:
3
Answer:
(a)
(b)
Justification:
4
Answer:
(a)
IQ Scores
Frequency
Relative Frequency
50 - 69
23
70 - 89
249
90 -109
0.450
110 - 129
130 - 149
25
Total
1000
(b)
(c)
Work for (a) and (b):
5
Answer:
(a)
(b)
(c)
Justification:
6
Answer:
(a)
(b)
Work for (a) and (b):
7
Answer:
(a)
(b)
Work for (b):
8
Answer:
(.
Question 1 of 201.0 PointsA sample of 20 observations has a st.docxhildredzr1di
Question 1 of 20
1.0 Points
A sample of 20 observations has a standard deviation of 4. The sum of the squared deviations from the sample mean is:
A.
320
B.
304
C.
288
D.
400
Reset Selection
Question 2 of 20
1.0 Points
Suppose that a histogram of a data set is approximately symmetric and "bell shaped". Approximately, what percent of the observations are within three standard deviations of the mean?
A.
50%
B.
99.7%
C.
95%
D.
68%
Reset Selection
Question 3 of 20
1.0 Points
Which of the following correctly describes the relationship between a sample and a population?
A.
A sample is a group of populations that are subject to observation.
B.
A population and a sample are not related.
C.
A population is a group of samples that may or may not be included in a study
D.
A sample is a group of subjects selected from a population to be studied.
Reset Selection
Question 4 of 20
1.0 Points
A histogram that has a single peak and looks approximately the same to the left and right of the peak is called:
A.
bimodal
B.
symmetric
C.
proportional
D.
balanced
Reset Selection
Question 5 of 20
1.0 Points
Which of the following statements is true for the following data values: 7, 5, 6, 4, 7, 8, and 12?
A.
Only the mean and median are equal
B.
The mean, median and mode are all equal
C.
Only the median and mode are equal
D.
Only the mean and mode are equal
Reset Selection
Question 6 of 20
1.0 Points
If a variable has possible values –2, 6, and 17, then this variable is
A.
both a continuous and a discrete variable
B.
a discrete variable
C.
neither a continuous nor a discrete variable
D.
a continuous variable
Reset Selection
Question 7 of 20
1.0 Points
Which of the following statements is true regarding the data set 10, 10, 10, 10, and 10?
A.
The range is zero
B.
The standard deviation equals zero
C.
The interquartile range equals zero
D.
all of the above
Reset Selection
Question 8 of 20
1.0 Points
Gender and State are examples of which type of data?
A.
Discrete data
B.
Continuous data
C.
Categorical data
D.
Ordinal data
Reset Selection
Question 9 of 20
1.0 Points
If a value represents the 95th percentile, this means that
A.
95% of the time you will observe this value
B.
95% of all values are below this value
C.
95% of all values are above this value
D.
there is a 5% chance that this value is incorrect
Reset Selection
Question 10 of 20
1.0 Points
A scatter plot would be useful for
A.
Showing the trend of sales, over time, of five different brands of blank DVDs
B.
Showing the relationship between the sales of blank CDs and blank DVDs
C.
Showing the top selling brands of blank DVDs
D.
Showing the relative number of sales of four different brands of blank DVDs
Reset Selection
Question 11 of 20
1.0 Points
Which of the following indicates how many observations fall into various categories?
A.
The frequency table
B.
The tabulation scale
C.
The Likert scale
D.
The sample table
Reset .
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ELEMENTS OF STATISTICS / TUTORIALOUTLET DOT COMalbert0076
Unit 3 Problem Set NAME: Elements of Statistics--FHSU Virtual College--Spring 2017
REMEMBER, these are assessed preparatory problems related to the content of Unit 3. The Unit 3 Exam will consist of similar types of
1. Consider the following partially completed computer printout fo.docxjackiewalcutt
1. Consider the following partially completed computer printout for a regression analysis where the dependent variable is the price of a personal computer and the independent variable is the size of the hard drive.
Based on the information provided, what is the F statistic?
About 8 .33
Just over 2.35
About 4.76
About 69.5
4 points
QUESTION 2
1. The standard error of the estimate is a measure of
total variation of the Y variable.
the variation around the sample regression line.
explained variation.
the variation of the X variable.
4 points
QUESTION 3
3.Nintendo Sony would like to test the hypothesis that a difference exists in the average age of users of a Wii, a PlayStation, or an Xbox console game. The following data represent the age of a random sample of Wii, PlayStation, and Xbox users.
Wii
PlayStation
Xbox
37
26
31
31
21
20
47
24
38
29
24
31
36
25
30
Using α = 0.05, the conclusion for this hypothesis test would be that because the test statistic is
more than the critical value, we cannot conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
less than the critical value, we cannot conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
more than the critical value, we can conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
less than the critical value, we can conclude that there is a difference in the average age of users of a Wii, a PlayStation, or an Xbox console game.
4 points
QUESTION 4
1. The relationship of Y to four other variables was established as Y = 12 + 3X1 - 5X2 + 7X3 + 2X4. When X1 increases 5 units and X2 In a sample of n = 23, the Student's t test statistic for a correlation of r = .500 would be:
2.559
2.819
2.646
can’t say without knowing α (alpha)
4 points
QUESTION 5
1. Given the following ANOVA table (some information is missing), find the F statistic.
3.71
0.99
0.497
4.02
4 points
QUESTION 6
1. Examine the following two-factor analysis of variance table:
Complete the analysis of variance table.
MSA = 40.928, F Factor A =3.35, SSB = 85.35, Factor B df = 3, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 1.8, SSE = 789.29, SSE df = 66, MSE = 12.143
MSA = 40.928, F Factor A = 3.35, SSB = 85.35, Factor B df = 4, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 2.1 SSE = 789.29, SSE df = 66, MSE = 12.143
MSA = 40.698, F Factor A = 3.35, SSB = 84.35, Factor B df = 5, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 2.1, SSE = 789.29, SSE df = 65, MSE = 12.143
MSA = 40.698, F Factor A = 3.35, SSB = 84.35, Factor B df = 3, F Factor B = 2.316, MSAB = 21.859, F Factor AB = 1.8, SSE = 789.29, SSE df = 65, MSE = 12.143
4 points
QUESTION 7
1. The critical value for a two-tailed test of H0: ß1 = 0 at a (alpha) = .05 in a simple regression with 22 observations is:
+ or - 1.725 ...
Part 1 of 16 - Question 1 of 231.0 PointsThe data pres.docxherbertwilson5999
Part 1 of 16 -
Question 1 of 23
1.0 Points
The data presented in the table below resulted from an experiment in which seeds of 5 different types were planted and the number of seeds that germinated within 5 weeks after planting was recorded for each seed type. At the .01 level of significance, is the proportion of seeds that germinate dependent on the seed type?
Seed Type
Observed Frequencies
Germinated
Failed to Germinate
1
31
7
2
57
33
3
87
60
4
52
44
5
10
19
A.Yes, because the test value 16.86 is greater than the critical value of 13.28
B.Yes, because the test value 16.86 is less than the critical value of 14.86
C.No, because the test value 16.86 is greater than the critical value of 13.28
D.No, because the test value 13.28 is less than the critical value of 16.86
Reset Selection
Question 2 of 23
1.0 Points
The chi-square goodness-of-fit test can be used to test for:
A.significance of sample statistics
B.normality
C.difference between population variances
D.difference between population means
Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
The marketing manager of a large supermarket chain would like to use shelf space to predict the sales of pet food. For a random sample of 12 similar stores, she gathered the following information regarding the shelf space, in feet, devoted to pet food and the weekly sales in hundreds of dollars.
Store
1
2
3
4
5
6
Shelf Space
5
5
5
10
10
10
Weekly Sales
1.6
2.2
1.4
1.9
2.4
2.6
Store
7
8
9
10
11
12
Shelf Space
15
15
15
20
20
20
Weekly Sales
2.3
2.7
2.8
2.6
2.9
3.1
What is the estimated regression equation?
A. = 1.45 + 0.074x
B. = 2.63 - 0.174x
C. = 2.63 + 0.724x
D. = 1.45 + 0.724x
Reset Selection
Question 4 of 23
1.0 Points
A single variable X can explain a large percentage of the variation in some other variable Y when the two variables are:
A.highly correlated
B.directly related
C.inversely related
D.mutually exclusive
Reset Selection
Question 5 of 23
1.0 Points
Data for a sample of 25 apartments in a particular neighborhood are provided in the worksheet Apartments in the Excel workbook Apartments.xlsx. Using that data, find the estimated regression equation which can be used to estimate the monthly rent for apartments in this neighborhood using size as the predictor variable.
Apartments.xlsx
A. 177.12 + 1.065(size)
B.177.12 + 0.8500(size)
C.1.065 + 177.12(size)
D.197.12 + 2.065(size)
Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
A pharmaceutical company is testing the effectiveness of a new drug for lowering cholesterol. As part of this trial, they wish to determine whether there is a difference between the effectiveness for women and for men. Assume α = 0.05. What is the test value?
Women
Men
Sample size
50
80
Mean effect
7
6.95
Sample variance
3
4
A.t = 3.252
B.t = 0.151
C.z = 0.081
D.z = 0.455
Reset Selection
Question 7 of 23
.
26 Ch. 3 Organizing and Graphing DataAssignment 2ME.docxeugeniadean34240
26 Ch. 3: Organizing and Graphing Data
Assignment 2
MEASURES OF CENTRAL TENDENCY
Fill in the blanks:
4.1. The score that repeats the most often in a distribution is called the ______.
4.2. The descriptive statistic used the most in inferential statistics as a measure of central tendency is the _________.
4.3. The measure of central tendency used with nominal scale data is the _______.
4.4. To find the mean of a sample, thethe sum of the scoresas is divided by ______.
Circle the correct answer:
4.5. In a positively skewed distribution, the majority of the scores cluster above/below the ________.
4.6. The mode and the mean have the same values in distributions that are normal/negatively skewed.
4.7. Distributions with few scores are more/less likely to have a mode than distributions with many scores.
Answer the following questions:
4.8. Which measure of central tendency would be the most appropriate for summarizing the following test scores? Explain your choice.
13, 14, 10, 38, 11, 12, 16, 15
4.9. What is the difference between and ? How are they related to each other?
4.10. A distribution of 10 scores has a mean of 6. Following are 9 scores of this distribution. Which score is missing (remember that the mean should be 6)?
4, 8, 10, 5, 9, 3, 6, 7, 3
4.11. When the sum of a group of scores is 280 and the mean of the scores is 7, how many scores are in the distribution?
4.12. Find the mode, median, and mean of the distribution depicted in the following histogram:
Frequency
Scores
MEASURES OF VARIABILITY
Circle the correct answer:
5.1. The distance between the highest and the lowest scores is called the range/variance.
5.2. The SD is equal to the square root of the mean/variance.
5.3. A test with 30 items is likely to have a higher/lower standard deviation that a test with 80 items.
5.4. The mean of the squared deviation scores is called the variance/standard deviation.
5.5. The SD of the number of errors found by an auditor in a sample of accounts of one company is likely to be higher/lower than the SD of the number of errors found in samples taken from a number of different companies.
5.6. The SD is/is not sensitive to extreme scores.
5.7. The variance of the population is represented by S2/2.
5.8. In most cases, the variance is larger/smaller than the SD.
5.9. The measure of variability that takes into consideration every score in the distribution is the range/standard deviation.
Answer/compute the following questions:
5.10. Study the following three distributions. What are the similarities and differences between the three distributions in terms of their means, ranges, and standard deviations? (Note: Assume the three distributions to be samples if you decide to compute their standard deviations.)
Distribution A: 8, 9, 6, 12, 5
Distribution B: 7, 10, 11, 8, 4
Distribution C: 7, 9, 8, 9, 7
5.11. Three statistics classes (Sections A, B and C), each with 26 students, took the same test. The SD o.
QNT Weekly learning assessments - Questions and Answers | UOP E AssignmentsUOP E Assignments
What the benefits of learning QNT 561 Weekly Learning Assessments ? Know from UOP E Assignments which is the largest going online educational portal whose motive is to provide best knowledge to UOP students for final exam. You get QNT 561 weekly learning assessments question and answers, QNT 561 weekly learning assessments 30 questions, QNT 561 weekly learning assessments quiz 1 answers etc in USA.
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InstructionDue Date 6 pm on October 28 (Wed)Part IProbability a.docxdirkrplav
This document discusses implementing a social, environmental, and economic impact measurement system within a company. It explains that measuring sustainability performance is critical for evaluating projects, the company, and its members. A proper measurement system allows companies to develop a sustainability strategy, allocate resources to support it, and evaluate trade-offs between sustainability projects. The document provides examples from Nike and P&G of measuring impacts to demonstrate the business case for sustainability. It stresses that measurement is important for linking performance to sustainability principles and facilitating continuous improvement.
1T1 Conduct one-way ANOVA analysis on the height using the .docxeugeniadean34240
1
T1: Conduct one-way ANOVA analysis on the height using the "Weight and Height.xlsx" sample data under the Data Sets (See Attachment) folder (Note that you will need to change the format of the data set to conduct the analysis). Based on your results, what conclusion would you draw regarding the average height of students in the three states?
Solution
:
Null Hypothesis: All the states have the same mean height of the students.
Alternate Hypothesis: Not all the states have the same mean height of the students.
The One-Way Analysis of Variance was performed in SPSS. The SPSS output is given as follows:
Descriptives
Height
N
Mean
Std. Deviation
Std. Error
95% Confidence Interval for Mean
Minimum
Maximum
Lower Bound
Upper Bound
KS
28
67.5714
3.30184
.62399
66.2911
68.8517
62.00
75.00
MO
41
69.9756
3.24220
.50635
68.9522
70.9990
61.00
75.00
NE
23
67.8696
4.18593
.87283
66.0594
69.6797
61.75
74.00
Total
92
68.7174
3.65929
.38151
67.9596
69.4752
61.00
75.00
Test of Homogeneity of Variances
Height
Levene Statistic
df1
df2
Sig.
1.697
2
89
.189
Levene Statistic (2, 89) = 1.697, p-value = 0.189Comment by Bo Yan: I don’t have SPSS installed on my computer. But the your results are slightly different from the numbers I got from using Excel and another statistical package.
The p-value is significant at α=0.05. From this test we conclude that we do not have the homogeneity of variance. Comment by Bo Yan: Does the evidence support your conclusion here when p > 0.05?
ANOVA
Height
Sum of Squares
df
Mean Square
F
Sig.
Between Groups
118.211
2
59.105
4.781
.011
Within Groups
1100.316
89
12.363
Total
1218.527
91
F (2, 89) = 4.781, p-value = 0.011
The p-value is significant at α=0.05. We reject the null hypothesis. From our analysis there is sufficient evidence to conclude that not all the states have the same mean height of the students, at a significance level of 0.05. This can be further emphasized from the results of the post-hoc tests. The following table shows the results of the Turkey’s HSD post hoc tests:Comment by Bo Yan: Good.
Multiple Comparisons
Dependent Variable: Height
Tukey HSD
(I) State
(J) State
Mean Difference (I-J)
Std. Error
Sig.
95% Confidence Interval
Lower Bound
Upper Bound
KS
MO
-2.40418*
.86202
.018
-4.4588
-.3495
NE
-.29814
.98948
.951
-2.6566
2.0603
MO
KS
2.40418*
.86202
.018
.3495
4.4588
NE
2.10604
.91601
.061
-.0773
4.2894
NE
KS
.29814
.98948
.951
-2.0603
2.6566
MO
-2.10604
.91601
.061
-4.2894
.0773
*. The mean difference is significant at the 0.05 level.
KS & MO:
The 95% confidence interval for the difference of means is given as (-4.4588, -.3495).
As the confidence interval does not contain 0, we can conclude that there is statistically significant difference between the mean height of students belonging to the states KS and MO.Comment by Bo Yan: Now you should understand the difference between statistically significant and practically significant difference. So I expect you to be mor.
Question 1 (25 points)Question 1 optionsEnter the answer to.docxIRESH3
Question 1 (25 points)
Question 1 options:
Enter the answer to each of the of the questions with:
T for True
F for False
a. If the variance from a data set is zero, then all the observations in this data set must be identical.
b. P(A and Ac) = 1 where Ac is the compliment of A.
c. The mean is always equal to the median for a normal distribution.
d. A 99% confidence interval is wider than a 95% confidence interval of the same parameter.
e. It is easier to reject the null hypothesis if we use a smaller significance level (alpha).
Question 2 (4 points)
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
A
2.0 - 2.9
B
.4
3.0 - 3.9
C
D
4.0 - 5.9
5
E
Total
25
F
Complete the Frequency Table with the missing frequency and relative frequency numbers.
Enter answer for "A" with 2 decimal place acueacy.
Enter answer for "B" as an integer.
Enter answer for "C" as an integer.
Enter answer for "D" as an integer.
Enter answer for "E" with 2 decimal place acueacy.
Enter answer for "F" as an integer.
Question 3 (5 points)
Question 3 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question.
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
2.0 - 2.9
0.4
3.0 - 3.9
4.0 - 5.9
5
Total
25
What percentage of the checkout times was at least 3 minutes?
Enter answer as a percent without the percent sign to 0 decimal places.
Question 4 (5 points)
Question 4 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question with the Interval column added.
Interval
Checkout Time (in minutes)
Frequency
Relative Frequency
1
1.0 - 1.9
4
2
2.0 - 2.9
0.4
3
3.0 - 3.9
4
4.0 - 5.9
5
5
Total
25
In what class interval must the median lie?
Enter answer with the appropriate Interval number.
Question 5 (5 points)
Question 5 options:
A random sample of 25 customers was chosen in UMUC MiniMart between 3:00 and 4:00 PM on a Friday afternoon. The frequency distribution below shows the distribution for checkout time (in minutes).
This is the same table from the previous question.
Checkout Time (in minutes)
Frequency
Relative Frequency
1.0 - 1.9
4
2.0 - 2.9
0.4
3.0 - 3.9
4.0 - 5.9
5
Total
25
Assume that the largest observation in this dataset is 4.8. Suppose this observation were incorrectly recorded as 8.4 instead of 4.8.
Will the ...
Question 2 of 231.0 PointsA company operates four machines dur.docxwraythallchan
Question 2 of 23
1.0 Points
A company operates four machines during three shifts each day. From production records, the data in the table below were collected. At the .05 level of significance test to determine if the number of breakdowns is independent of the shift.
Machine
1
2
3
Shift
A
41
31
15
B
20
11
17
C
12
9
16
D
16
14
10
A.The number of breakdowns is dependent on the shift, because the test value 11.649 is less than the critical value of 12.592.
B.The claim that the number of breakdowns is independent of the shift cannot be rejected, because the test value 11.649 is less than the critical value of 12.592.
C.The number of breakdowns is dependent on the shift, because the p-value is .07.
D.The number of breakdowns is independent of the shift, because the test value 12.592 is greater than the critical value of 11.649. Reset Selection
Part 2 of 16 -
Question 3 of 23
1.0 Points
If an estimated regression line has a Y-intercept of –7.5 and a slope of 2.5, then when X = 3, the actual value of Y is:
A.10
B.5
C.unknown
D.0 Reset Selection
Question 4 of 23
1.0 Points
The city of Oakdale wishes to see if there is a linear relationship between the temperature and the amount of electricity used (in kilowatts). Based on the data in the table below, is there a significant linear relationship between temperature and the amount of electricity used? These data are also available in the worksheet temperature in the Excel workbook Temperature.xlsx.
Temperature.xlsx
Temperature (x)
Kilowatts (y)
73
680
78
760
85
910
98
1510
93
1170
81
837
76
600
105
1800
A.No, the sample correlation coefficient is equal to 0.098, which does not provide evidence of a significant linear relationship.
B.No, the sample correlation coefficient is equal to 0.981, which does not provide evidence of a significant linear relationship.
C.Yes, the sample correlation coefficient is equal to 0.878, which provides evidence of a significant linear relationship.
D.Yes, the sample correlation coefficient is equal to 0.981, which provides evidence of a significant linear relationship. Reset Selection
Question 5 of 23
1.0 Points
____________ is/are especially helpful in identifying outliers.
A.Scatterplots
B.Normal curves
C.Linear regression
D.Regression analysis Reset Selection
Part 3 of 16 -
Question 6 of 23
1.0 Points
Serum ferritin is used in diagnosing iron deficiency. In a study conducted recently researchers discovered that in a sample of 28 elderly men the sample standard deviation of serum ferritin was 52.6 mg/L. For 26 younger men the sample standard deviation was 84.2 mg/L. At the .01 level of significance, do these data support the conclusion that the ferritin distribution in elderly men has a smaller variance than in younger men?
A.No, because the test value 1.60 is less than the critical value of 2.54
B.Yes, because the test value 0.390 is less than the critical value 2.54
C.Yes, because the test value 2.56 is greater than the critical value ...
[The following information applies to the questions displayed belo.docxdanielfoster65629
[The following information applies to the questions displayed below.]
A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.01 significance level.
H0: μ ≤ 10
H1: μ > 10
1.
Value:
10.00 points
Required information
a.
Is this a one- or two-tailed test?
One-tailed test
Two-tailed test
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
2.
Value:
10.00 points
Required information
b.
What is the decision rule?
Reject H0 when z ≤ 2.326
Reject H0 when z > 2.326
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
3.
Value:
10.00 points
Required information
c.
What is the value of the test statistic?
Value of the test statistic
References
EBook & Resources
Worksheet Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
4.
Value:
10.00 points
Required information
d.
What is your decision regarding H0?
Fail to reject H0
Reject H0
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
5.
Value:
10.00 points
Required information
e.
What is the p-value?
p-value
References
Given the following hypotheses:
H0 : μ = 400
H1 : μ ≠ 400
A random sample of 12 observations is selected from a normal population. The sample mean was 407 and the sample standard deviation 6. Using the .01 significance level:
a.
State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.)
Reject H0 when the test statistic is the interval (,).
b.
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
Value of the test statistic
c.
What is your decision regarding the null hypothesis?
Do not reject
Reject
The management of White Industries is considering a new method of assembling its golf cart. The present method requires 42.3 minutes, on the average, to assemble a cart. The mean assembly time for a random sample of 24 carts, using the new method, was 40.6 minutes, and the standard deviation of the sample was 2.7 minutes. Using the .10 level of significance, can we conclude that the assembly time using the new method is faster?
a.
What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Rej.
- The document provides information about statisticshomeworkhelper.com, a service that offers probability and statistics assignment help. It lists their website, email, and phone number for contacting them.
- It then provides an example of a multi-part statistics problem involving hypothesis testing on coin flips and dice data. It asks the reader to conduct various statistical tests and interpret the results.
- Finally, it lists some additional practice problems involving chi-square tests, ANOVA, and other statistical analyses for the reader to work through.
This document contains exercises related to probability and expected value concepts. It includes 3 practice problems:
1) Calculating the expected payment of an inverse floater security based on the probability distribution of short-term interest rates.
2) Finding the expected profit for a mining company with two potential reserves that each have a 30% chance of success.
3) Determining the joint probability distribution and expected total demand for a salmon dish served at a cafe based on the independent lunch and dinner demand distributions.
The document presents a case study where Lisa wants to open a beauty store and needs data to support her belief that women in her local area spend more than the national average of $59 every 3 months on fragrance products. Lisa takes a random sample of 25 women in her area and finds the sample mean is $68.10 with a standard deviation of $14.46. She conducts a one-sample t-test to test if the population mean is greater than $59. The test statistic is 3.1484 with a p-value of 0.0021, which is less than the significance level of 0.05. Therefore, there is sufficient evidence to conclude that the population mean is indeed greater than $
Probability Distributions for Discrete Variablesgetyourcheaton
This document discusses probability distributions for discrete variables. It begins by defining a probability distribution as a relative frequency distribution of all possible outcomes of an experiment. It provides examples of probability distributions for discrete variables like the binomial distribution. It discusses key aspects of probability distributions like the mean, standard deviation, and different types of distributions like binomial. It provides examples of calculating probabilities, means, and standard deviations for binomial distributions. It discusses the basic characteristics of the binomial distribution and provides an example of constructing a binomial distribution and calculating related probabilities.
Assessment 3 – Hypothesis, Effect Size, Power, and t Tests.docxcargillfilberto
Assessment 3 – Hypothesis, Effect Size, Power, and
t
Tests
Complete the following problems within this Word document. Do not submit other files. Show your work for problem sets that require calculations. Ensure that your answer to each problem is clearly visible. You may want to highlight your answer or use a different type color to set it apart.
Hypothesis, Effect Size, and Power
Problem Set 3.1: Sampling Distribution of the Mean Exercise
Criterion:
Interpret population mean and variance.
Instructions:
Read the information below and answer the questions.
Suppose a researcher wants to learn more about the mean attention span of individuals in some hypothetical population. The researcher cites that the attention span (the time in minutes attending to some task) in this population is normally distributed with the following characteristics: 20
36
. Based on the parameters given in this example, answer the following questions:
1. What is the population mean (μ)? __________________________
2. What is the population variance
? __________________________
3. Sketch the distribution of this population. Make sure you draw the shape of the distribution and label the mean plus and minus three standard deviations.
Problem Set 3.2: Effect Size and Power
Criterion:
Explain effect size and power.
Instructions:
Read each of the following three scenarios and answer the questions.
Two researchers make a test concerning the effectiveness of a drug use treatment. Researcher A determines that the effect size in the population of males is
d
= 0.36; Researcher B determines that the effect size in the population of females is
d
= 0.20. All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Two researchers make a test concerning the levels of marital satisfaction among military families. Researcher A collects a sample of 22 married couples (
n
= 22); Researcher B collects a sample of 40 married couples (
n
= 40). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Two researchers make a test concerning standardized exam performance among senior high school students in one of two local communities. Researcher A tests performance from the population in the northern community, where the standard deviation of test scores is 110 (
); Researcher B tests performance from the population in the southern community, where the standard deviation of test scores is 60 (
). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________
Problem Set 3.3: Hypothesis, Direction, and Population Mean
Criterion:
Explain the relationship between hypothesis, tests, and population mean.
Instructions:
Read the following and answer the questions.
STAT 200 Final ExaminationFall 2016 OL1US1Page 9 of 9STAT 200.docxwhitneyleman54422
STAT 200 Final ExaminationFall 2016 OL1/US1Page 9 of 9
STAT 200 Introduction to Statistics Name______________________________
Final Examination: Fall 2016 OL1/US1 Instructor __________________________
Answer Sheet
Instructions:
This is an open-book exam. You may refer to your text and other course materials as you work on the exam, and you may use a calculator.
Record your answers and work in this document.
Answer all 20 questions. Make sure your answers are as complete as possible. Show all of your work and reasoning. In particular, when there are calculations involved, you must show how you come up with your answers with critical work and/or necessary tables. Answers that come straight from calculators, programs or software packages without explanation will not be accepted. If you need to use technology to aid in your calculation, you have to cite the source and explain how you get the results. For example, state the Excel function along with the required parameters when using Excel; describe the detailed steps when using a hand-held calculator; or provide the URL and detailed steps when using an online calculator, and so on.
Show all supporting work and write all answers in the spaces allotted on the following pages. You may type your work using plain-text formatting or an equation editor, or you may hand-write your work and scan it. In either case, show work neatly and correctly, following standard mathematical conventions. Each step should follow clearly and completely from the previous step. If necessary, you may attach extra pages.
You must complete the exam individually. Neither collaboration nor consultation with others is allowed. It is a violation of the UMUC Academic Dishonesty and Plagiarism policy to use unauthorized materials or work from others. Your exam will receive a zero grade unless you complete the following honor statement.
Please sign (or type) your name below the following honor statement:
I understand that it is a violation of the UMUC Academic Dishonesty and Plagiarism policy to use unauthorized materials or work from others. I promise that I did not discuss any aspect of this exam with anyone other than my instructor. I further promise that I neither gave nor received any unauthorized assistance on this exam, and that the work presented herein is entirely my own.
Name _____________________Date___________________
Record your answers and work.
Problem Number
Solution
1
Answer:
(a)
(b)
(c)
(d)
(e)
Justification:
2
Answer:
(a)
(b)
(c)
Justification:
3
Answer:
(a)
(b)
Justification:
4
Answer:
(a)
IQ Scores
Frequency
Relative Frequency
50 - 69
23
70 - 89
249
90 -109
0.450
110 - 129
130 - 149
25
Total
1000
(b)
(c)
Work for (a) and (b):
5
Answer:
(a)
(b)
(c)
Justification:
6
Answer:
(a)
(b)
Work for (a) and (b):
7
Answer:
(a)
(b)
Work for (b):
8
Answer:
(.
Question 1 of 201.0 PointsA sample of 20 observations has a st.docxhildredzr1di
Question 1 of 20
1.0 Points
A sample of 20 observations has a standard deviation of 4. The sum of the squared deviations from the sample mean is:
A.
320
B.
304
C.
288
D.
400
Reset Selection
Question 2 of 20
1.0 Points
Suppose that a histogram of a data set is approximately symmetric and "bell shaped". Approximately, what percent of the observations are within three standard deviations of the mean?
A.
50%
B.
99.7%
C.
95%
D.
68%
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Question 3 of 20
1.0 Points
Which of the following correctly describes the relationship between a sample and a population?
A.
A sample is a group of populations that are subject to observation.
B.
A population and a sample are not related.
C.
A population is a group of samples that may or may not be included in a study
D.
A sample is a group of subjects selected from a population to be studied.
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Question 4 of 20
1.0 Points
A histogram that has a single peak and looks approximately the same to the left and right of the peak is called:
A.
bimodal
B.
symmetric
C.
proportional
D.
balanced
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Question 5 of 20
1.0 Points
Which of the following statements is true for the following data values: 7, 5, 6, 4, 7, 8, and 12?
A.
Only the mean and median are equal
B.
The mean, median and mode are all equal
C.
Only the median and mode are equal
D.
Only the mean and mode are equal
Reset Selection
Question 6 of 20
1.0 Points
If a variable has possible values –2, 6, and 17, then this variable is
A.
both a continuous and a discrete variable
B.
a discrete variable
C.
neither a continuous nor a discrete variable
D.
a continuous variable
Reset Selection
Question 7 of 20
1.0 Points
Which of the following statements is true regarding the data set 10, 10, 10, 10, and 10?
A.
The range is zero
B.
The standard deviation equals zero
C.
The interquartile range equals zero
D.
all of the above
Reset Selection
Question 8 of 20
1.0 Points
Gender and State are examples of which type of data?
A.
Discrete data
B.
Continuous data
C.
Categorical data
D.
Ordinal data
Reset Selection
Question 9 of 20
1.0 Points
If a value represents the 95th percentile, this means that
A.
95% of the time you will observe this value
B.
95% of all values are below this value
C.
95% of all values are above this value
D.
there is a 5% chance that this value is incorrect
Reset Selection
Question 10 of 20
1.0 Points
A scatter plot would be useful for
A.
Showing the trend of sales, over time, of five different brands of blank DVDs
B.
Showing the relationship between the sales of blank CDs and blank DVDs
C.
Showing the top selling brands of blank DVDs
D.
Showing the relative number of sales of four different brands of blank DVDs
Reset Selection
Question 11 of 20
1.0 Points
Which of the following indicates how many observations fall into various categories?
A.
The frequency table
B.
The tabulation scale
C.
The Likert scale
D.
The sample table
Reset .
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How to Fix the Import Error in the Odoo 17Celine George
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Chapter 01, Section 1.1, Problem 001
Select the two meanings of the word statistics.
Chapter 01, Section 1.3, Problem 008b
Indicate if the following variable is quantitative or qualitative.
The amount of rain last year in 30 cities is a ..................variable.
Chapter 01, Section 1.5, Problem 015
Select the correct explanation of the difference between a
census and a sample survey.
2. Select each reason why conducting a sample survey is
preferable to conducting a census.
Chapter 02, Testbank, Question 009-013
The following table gives the frequency distribution of opinions
of 50 persons in regard to an issue.
Opinion
f
In favor 23
Against 19
No
opinion
8
The percentage of persons who have no opinion is:
The relative frequency, expressed to two decimal places, of the
"Against" category is:
The sample size is:
The percentage of persons who are either against this issue or
have no opinion is:
The percentage of persons who are either in favor of this issue
or have no opinion is:
Chapter 03, Testbank, Question 008-010
3. The annual salaries of six employees of a company are as
follows:
$22,000 $35,000 $22,000 $46,000 $57,000 $63,000
The mean salary of these employees is: $........(rounded to 2
decimal places)
The median salary of these employees is:
The mode of the salaries of these employees is
Chapter 03, Testbank, Question 019
The value of the standard deviation of a data set is:
Chapter 03, Testbank, Question 047
According to the empirical rule, the percentage of values that
fall within one standard deviation of the mean is
approximately:
Chapter 03, Testbank, Question 091
Based on the box-and-whisker plot,
complete the table.
4. Minimum
Q1
Media
n Q3
Maximum
Chapter 04, Supplementary Exercises, Problem 097a
A random sample of 300 college students was asked if college
athletes should be paid. The following table gives a two-way
classification of the responses.
Should Be Paid Should Not Be Paid
Student athlete 40 10
Student nonathlete 210 40
Round your answers to three decimal places.
If one student is randomly selected from these 300 students,
find the probability that this student
i. is in favor of paying college athletes.
ii. favors paying college athletes given that the student selected
is a nonathlete.
iii. is an athlete and favors paying student athletes.
5. iv. is a nonathlete or is against paying student athletes.
Chapter 04, Section 4.2, Additional Question 012
A sample of 820 adults showed that 85 of them had no credit
cards, 146 had one card each, 52 had two cards each, 75 had
three cards each, 59 had four cards each, and 403 had five or
more cards each. Suppose one adult is randomly selected from
these 820 adults. Find the probability that this adult has exactly
three credit cards.
Round your answer to two decimal places. P(A)=
8th-ed Chapter 04, Section 4.1, Problem 013a
A box contains a certain number of computer parts, a few of
which are defective. Two parts are selected at random from this
box and inspected to determine if they are good or defective.
Indicate whether the following is a simple or a compound
event.
At least one part is good.
8th-ed Chapter 04, Section 4.2, Problem 020
Which of the following values cannot be probabilities of events?
0.41 23 -0.05 1.43 0.93 94 -14 0.02
6. Chapter 05, Testbank, Question 002
A discrete random variable is a random variable:
Chapter 05, Testbank, Question 032-033
The following table lists the probability distribution of a
discrete random variable x:
x
0 1 2 3 4 5 6 7
P(x
)
0.040.110.180.280.150.120.090.03
The mean of the random variable x is
The standard deviation of the random variable x, rounded to
three decimal places, is
Chapter 06, Section 6.1, Problem 016c
Determine the following probability for the standard normal
distribution.
Round your answer to four decimal places.
P(-1.84≤z≤0)=
7. Chapter 06, Section 6.2, Problem 020
Find the area between x=23 and x=25 under a normal
distribution curve with μ=20 and σ=4.
Round your answer to four decimal places.
A=
Chapter 06, Section 6.2, Problem 024d
Let x be a continuous random variable that is normally
distributed with a mean of 42 and a standard deviation of 16.
Find the probability that x assumes a value less than 51.
Round your answer to four decimal places.
Chapter 07, Testbank, Question 006
The sampling error is:
Chapter 07, Testbank, Question 008
An error that occurs because of human mistakes is called:
Chapter 07, Testbank, Question 009
8. The mean age of all students at a university is 24 years. The
mean age of a random sample of 100 students selected from
this university is 23.6 years. The difference (23.6 - 24 = -0.4) is
the: