proof of Theorem : Sides opposite to equal angles of a triangle are equal. class 9th, chapter 7th triangle.

1. WE ARE ADDICTED TO LEARN

2. Name : Ramesh
Integrated B.Sc. - B.Ed.
School of education

3. Theorem : Sides opposite to equal angles of a triangle are equal.

4. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC

5. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB

6. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
D

7. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
D

8. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
D

9. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
D

10. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
D

11. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
∴ ∆ABD ≅∆ACD (AAS congruence rule rule)
D

12. Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
∴ ∆ABD ≅∆ACD (AAS congruence rule rule)
so, AB = AC (CPCT)
hence proved
D

13. Thank you