WE ARE ADDICTED TO LEARN
Name : Ramesh
Integrated B.Sc. - B.Ed.
School of education
Theorem : Sides opposite to equal angles of a triangle are equal.
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
∴ ∆ABD ≅∆ACD (AAS congruence rule rule)
D
Theorem : Sides opposite to equal angles of a triangle are equal.
To prove : AB = AC
Given : ∠ABC = ∠ACB
proof : let us take line AD bisecting ∠A
In ∆ABD and ∆ACD
∠BAD = ∠CAD
AD (common)
∠ABD = ∠ACD (given)
∴ ∆ABD ≅∆ACD (AAS congruence rule rule)
so, AB = AC (CPCT)
hence proved
D
Thank you

theorem of isosceles triangle

  • 1.
  • 2.
    Name : Ramesh IntegratedB.Sc. - B.Ed. School of education
  • 3.
    Theorem : Sidesopposite to equal angles of a triangle are equal.
  • 4.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC
  • 5.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB
  • 6.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A D
  • 7.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD D
  • 8.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD ∠BAD = ∠CAD D
  • 9.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD ∠BAD = ∠CAD AD (common) D
  • 10.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD ∠BAD = ∠CAD AD (common) ∠ABD = ∠ACD (given) D
  • 11.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD ∠BAD = ∠CAD AD (common) ∠ABD = ∠ACD (given) ∴ ∆ABD ≅∆ACD (AAS congruence rule rule) D
  • 12.
    Theorem : Sidesopposite to equal angles of a triangle are equal. To prove : AB = AC Given : ∠ABC = ∠ACB proof : let us take line AD bisecting ∠A In ∆ABD and ∆ACD ∠BAD = ∠CAD AD (common) ∠ABD = ∠ACD (given) ∴ ∆ABD ≅∆ACD (AAS congruence rule rule) so, AB = AC (CPCT) hence proved D
  • 13.