The way you would solve this problem is to look a.pdf
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The way you would solve this problem is to look at the polarity of the molecules-- which has to deal with the electronegativity of the atoms themselves, and the atomic size and mass. Polarity affects intermolecular forces and causes molecules and atoms to deviate from the ideal behavior. H2 would be expected to behave most ideally because it has a dipole moment of 0 (non-polar). Also, it has smaller mass, it is not as easily polarizable. F2 may behave ideally, because it has a dipole moment of 0 also. But, it\'s mass is bigger and it is highly electronegative HF would be expected to deviate because it has a higher dipole moment, and it\'s polar. That dipole moment creates an intermolecular force that influecnes other polar molecules. Source(s): General Chemistry 4th edition (Hill, Petrucci, McCreary, Perry) Solution The way you would solve this problem is to look at the polarity of the molecules-- which has to deal with the electronegativity of the atoms themselves, and the atomic size and mass. Polarity affects intermolecular forces and causes molecules and atoms to deviate from the ideal behavior. H2 would be expected to behave most ideally because it has a dipole moment of 0 (non-polar). Also, it has smaller mass, it is not as easily polarizable. F2 may behave ideally, because it has a dipole moment of 0 also. But, it\'s mass is bigger and it is highly electronegative HF would be expected to deviate because it has a higher dipole moment, and it\'s polar. That dipole moment creates an intermolecular force that influecnes other polar molecules. Source(s): General Chemistry 4th edition (Hill, Petrucci, McCreary, Perry).
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YearTotal DividendPreferred dividend ($)Per shareCommon divi.pdf
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Average Dividend per share for common stock six years is $0.4
Year
Total dividend ($)
Preferred dividend
Common dividend
Total ($)
Paid ($)
Per share ($)
Total ($)
Per share
2009
24000
50,000
-26,000
2
2010
10000
50,000
-40,000
2
2011
126000
50,000
116,000
2
10,000
0.1
2012
100000
50,000
50,000
2
50,000
0.5
2013
125000
50,000
50,000
2
75,000
0.75
2014
125000
50,000
50,000
2
75,000
0.75
Average dividend per share for common stock is $ 0.35 and for preferred stock is $2
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Solution
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Average Dividend per share for common stock six years is $0.4
Year
Total dividend ($)
Preferred dividend
Common dividend
Total ($)
Paid ($)
Per share ($)
Total ($)
Per share
2009
24000
50,000
-26,000
2
2010
10000
50,000
-40,000
2
2011
126000
50,000
116,000
2
10,000
0.1
2012
100000
50,000
50,000
2
50,000
0.5
2013
125000
50,000
50,000
2
75,000
0.75
2014
125000
50,000
50,000
2
75,000
0.75
Average dividend per share for common stock is $ 0.35 and for preferred stock is $2
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4.
THis can be explained easily by using an example.Let consider a sc.pdf
THis can be explained easily by using an example.
Let consider a scenario where billions of devices are connected through each other (Like mobile
phones, Smart devices, laptops, PC everything ). They are sharing data with each other, Now
assume that the data transfer is just a stream of bit patterns like 1010001....
So we are collecting a very huge data. So first thing comes in our mind to retrive valuable
information from this data. Let this data is labelled as MASSIVE data. Is it possible to take real
time decisions from this MASSIVE data?
Yes it is possible but only when we prefetch valuable information from the MASSIVE data,
Then only this is possible in real time else we need much time to evaluate the decision process.
There are some essential steps before decision Making
1. Data Analytics
2. Semantic Derivation and Knowledge Discovery
So this data analytics is used to process data and then this data is used to derive semantics and
knowledge. After step 2 we can perform real time decision making.
Solution
THis can be explained easily by using an example.
Let consider a scenario where billions of devices are connected through each other (Like mobile
phones, Smart devices, laptops, PC everything ). They are sharing data with each other, Now
assume that the data transfer is just a stream of bit patterns like 1010001....
So we are collecting a very huge data. So first thing comes in our mind to retrive valuable
information from this data. Let this data is labelled as MASSIVE data. Is it possible to take real
time decisions from this MASSIVE data?
Yes it is possible but only when we prefetch valuable information from the MASSIVE data,
Then only this is possible in real time else we need much time to evaluate the decision process.
There are some essential steps before decision Making
1. Data Analytics
2. Semantic Derivation and Knowledge Discovery
So this data analytics is used to process data and then this data is used to derive semantics and
knowledge. After step 2 we can perform real time decision making..
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This document discusses intermolecular forces (IMF), the forces that bond molecules to each other. There are five main types of IMF: dipole-dipole forces, ion-dipole forces, induced dipole forces, dispersion forces, and hydrogen bonding. Hydrogen bonding is the strongest IMF due to the electrostatic attraction between a hydrogen atom covalently bonded to a highly electronegative atom like N, O, or F, and another polar molecule. Stronger IMF require more energy to overcome, resulting in higher melting and boiling points. Practice problems are provided to identify the types of IMF present in different molecules.
HISTORY OF ATOMIC THEORY
John Dalton proposed the atomic theory in 1804, stating that all matter is composed of tiny, indivisible particles called atoms that cannot be divided further. Later discoveries found that atoms consist of even smaller subatomic particles, including electrons discovered by J.J. Thomson in 1897 and the nucleus discovered by Ernest Rutherford in 1910. The quantum mechanical model developed in 1926 by Schrodinger, Heisenberg and others proposed that electrons exist as waves of energy around the nucleus, rather than following fixed orbits as proposed by Niels Bohr's 1913 planetary model of the atom.
Intermolecular forces
The document discusses the three main types of intermolecular forces: dipole-dipole forces, London dispersion forces, and hydrogen bonding. It describes each type of force, including that dipole-dipole forces exist between polar molecules, London dispersion forces exist between all molecules, and hydrogen bonding specifically refers to the attraction between hydrogen atoms bonded to electronegative atoms like N, O, or F. The document also discusses how these intermolecular forces can explain the physical properties of liquids and some solids.
Unit 1 State of matter.pptx
Forces of attraction determine the different states of matter. Intramolecular forces like ionic bonds and covalent bonds occur within molecules. Intermolecular forces like van der Waals forces, hydrogen bonding, and London dispersion forces occur between molecules. These intermolecular forces are responsible for solids, liquids, and gases having distinct properties based on the strength of attraction between molecules. In solids, strong intermolecular forces create a rigid structure. In liquids, weaker intermolecular forces allow molecules to flow freely past one another. In gases, intermolecular forces are very weak, causing molecules to move randomly in all directions.
Similar to The way you would solve this problem is to look a.pdf (20)
Chem 2 - Intermolecular Forces & Phases of Matter II
Chem 2 - Intermolecular Forces & Phases of Matter II
7 polar and nonpolar molecules almocera & almocera
7 polar and nonpolar molecules almocera & almocera
Chapter 2 - Detailed Study of The Covalent Bond Theories.pdf
Chapter 2 - Detailed Study of The Covalent Bond Theories.pdf
Engineering chemistry textbook chapter 1 chemical bonding
Engineering chemistry textbook chapter 1 chemical bonding
Structure of matter /cosmetic dentistry course by Indian dental academy
Structure of matter /cosmetic dentistry course by Indian dental academy
More from aptelecom16999
YearTotal DividendPreferred dividend ($)Per shareCommon divi.pdf
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Average Dividend per share for common stock six years is $0.4
Year
Total dividend ($)
Preferred dividend
Common dividend
Total ($)
Paid ($)
Per share ($)
Total ($)
Per share
2009
24000
50,000
-26,000
2
2010
10000
50,000
-40,000
2
2011
126000
50,000
116,000
2
10,000
0.1
2012
100000
50,000
50,000
2
50,000
0.5
2013
125000
50,000
50,000
2
75,000
0.75
2014
125000
50,000
50,000
2
75,000
0.75
Average dividend per share for common stock is $ 0.35 and for preferred stock is $2
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Solution
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4
Average Dividend per share for common stock six years is $0.4
Year
Total dividend ($)
Preferred dividend
Common dividend
Total ($)
Paid ($)
Per share ($)
Total ($)
Per share
2009
24000
50,000
-26,000
2
2010
10000
50,000
-40,000
2
2011
126000
50,000
116,000
2
10,000
0.1
2012
100000
50,000
50,000
2
50,000
0.5
2013
125000
50,000
50,000
2
75,000
0.75
2014
125000
50,000
50,000
2
75,000
0.75
Average dividend per share for common stock is $ 0.35 and for preferred stock is $2
Year
Total Dividend
Preferred dividend ($)
Per share
Common dividend
Per share
2009
24000
45,000
-21000
1.8
2010
10000
45,000
-35000
1.8
2011
126000
45,000
101000
1.8
25,000
0.25
2012
100000
45,000
45,000
1.8
55,000
0.55
2013
125000
45,000
45,000
1.8
80,000
0.8
2014
125000
45,000
45,000
1.8
80,000
0.8
1.8
240,000
0.4.
THis can be explained easily by using an example.Let consider a sc.pdf
THis can be explained easily by using an example.
Let consider a scenario where billions of devices are connected through each other (Like mobile
phones, Smart devices, laptops, PC everything ). They are sharing data with each other, Now
assume that the data transfer is just a stream of bit patterns like 1010001....
So we are collecting a very huge data. So first thing comes in our mind to retrive valuable
information from this data. Let this data is labelled as MASSIVE data. Is it possible to take real
time decisions from this MASSIVE data?
Yes it is possible but only when we prefetch valuable information from the MASSIVE data,
Then only this is possible in real time else we need much time to evaluate the decision process.
There are some essential steps before decision Making
1. Data Analytics
2. Semantic Derivation and Knowledge Discovery
So this data analytics is used to process data and then this data is used to derive semantics and
knowledge. After step 2 we can perform real time decision making.
Solution
THis can be explained easily by using an example.
Let consider a scenario where billions of devices are connected through each other (Like mobile
phones, Smart devices, laptops, PC everything ). They are sharing data with each other, Now
assume that the data transfer is just a stream of bit patterns like 1010001....
So we are collecting a very huge data. So first thing comes in our mind to retrive valuable
information from this data. Let this data is labelled as MASSIVE data. Is it possible to take real
time decisions from this MASSIVE data?
Yes it is possible but only when we prefetch valuable information from the MASSIVE data,
Then only this is possible in real time else we need much time to evaluate the decision process.
There are some essential steps before decision Making
1. Data Analytics
2. Semantic Derivation and Knowledge Discovery
So this data analytics is used to process data and then this data is used to derive semantics and
knowledge. After step 2 we can perform real time decision making..
The equation given is incorrect. The given possible roots give the.pdf
The equation given is incorrect.
The given possible roots give the equation as
x^4-4x^3-4x^2-24x+15=0
So x^4 +4x^3+6x^2+12x+9 cannot have the given roots.
Solution
The equation given is incorrect.
The given possible roots give the equation as
x^4-4x^3-4x^2-24x+15=0
So x^4 +4x^3+6x^2+12x+9 cannot have the given roots..
Role of gender in health of womenMany of the health challenges dur.pdf
Role of gender in health of women
Many of the health challenges during the reproductive period are ones that only young girls and
women face.According to a recent publication of WHO complications of pregnancy and
childbirth are the leading cause of death in young women aged between 15 and 19 years old in
developing countries. Other causes of death among women of reproductive age is HIV/ AIDS
and also cervical cancer caused by the infection of Human Pappiloma virus, which affect only
the women. Girls and women are particularly vulnerable to HIV infection due to a combination
of biological factors and gender-based inequalities, particularly in cultures that limit women’s
knowledge about HIV and their ability to protect themselves and negotiate safer sex. The most
important risk factors for death and disability in this age group in low- and middle-income
countries are lack of contraception and unsafe sex. Violence is an additional significant risk to
women’s sexual and reproductive health and can also result in mental ill-health and other chronic
health problems.
After, the reproductive age one common cause of physical disability is arthritis or gout which
affect the elderly women more than the elderly men. This is most probably because the bones of
women, decay calcium more than that of men.
Role of gender in health of men
The Y chromosome establishes male sexual differentiation and the formation of the testis,
epididymis and accessory sex glands, the prostate and seminal vesicles and the penis. The
disorders of these organs and the variation in the levels of production of the androgens secreted
by the testis define a group of disorders that form the discipline of andrology.These disorders can
impact on males at all ages of their life. In the younger population, disorders of genital
differentiation, testicular cancer, male infertility and sexually transmitted disease are major
issues. In some genetic males, androgen insensitivity resulting from mutations of the androgen
receptor gene can result in external genitalia that cannot be distinguished from normal
female.The occurrence of genital herpes, gonorrhoea, syphilis and HIV constitute a burden of
disease that requires attention in male health policies with a very significant emphasis on
prevention through adequate barrier protection by the use of condoms and effective diagnosis
and prompt treatment of episodes.
Solution
Role of gender in health of women
Many of the health challenges during the reproductive period are ones that only young girls and
women face.According to a recent publication of WHO complications of pregnancy and
childbirth are the leading cause of death in young women aged between 15 and 19 years old in
developing countries. Other causes of death among women of reproductive age is HIV/ AIDS
and also cervical cancer caused by the infection of Human Pappiloma virus, which affect only
the women. Girls and women are particularly vulnerable to HIV infection due to a combination
of .
Please post properly..SolutionPlease post properly...pdf
This very short document consists of two identical sentences stating "Please post properly.." without any other context or details provided. It appears to be requesting whoever is reading it to post something properly, but does not specify what should be posted or in what manner.
Deoxyribonucleic acid (DNA) is a nucleic acid that contains the gen.pdf
Deoxyribonucleic acid (DNA) is a nucleic acid that contains the genetic instructions used in the
development and functioning of all known living organisms and some viruses. The main role of
DNA molecules is the long-term storage of information. DNA is often compared to a set of
blueprints or a recipe, since it contains the instructions needed to construct other components of
cells, such as proteins and RNA molecules. The DNA segments that carry this genetic
information are called genes, but other DNA sequences have structural purposes, or are involved
in regulating the use of this genetic information.
Chemically, DNA consists of two long polymers of simple units called nucleotides, with
backbones made of sugars and phosphate groups joined by ester bonds. These two strands run in
opposite directions to each other and are therefore anti-parallel. Attached to each sugar is one of
four types of molecules called bases. It is the sequence of these four bases along the backbone
that encodes information. This information is read using the genetic code, which specifies the
sequence of the amino acids within proteins. The code is read by copying stretches of DNA into
the related nucleic acid RNA, in a process called transcription.
Within cells, DNA is organized into structures called chromosomes. These chromosomes are
duplicated before cells divide, in a process called DNA replication. Eukaryotic organisms
(animals, plants, fungi, and protists) store their DNA inside the cell nucleus, while in prokaryotes
(bacteria and archae) it is found in the cell\'s cytoplasm. Within the chromosomes, chromatin
proteins such as histones compact and organize DNA. These compact structures guide the
interactions between DNA and other proteins, helping control which parts of the DNA are
transcribed.
Solution
Deoxyribonucleic acid (DNA) is a nucleic acid that contains the genetic instructions used in the
development and functioning of all known living organisms and some viruses. The main role of
DNA molecules is the long-term storage of information. DNA is often compared to a set of
blueprints or a recipe, since it contains the instructions needed to construct other components of
cells, such as proteins and RNA molecules. The DNA segments that carry this genetic
information are called genes, but other DNA sequences have structural purposes, or are involved
in regulating the use of this genetic information.
Chemically, DNA consists of two long polymers of simple units called nucleotides, with
backbones made of sugars and phosphate groups joined by ester bonds. These two strands run in
opposite directions to each other and are therefore anti-parallel. Attached to each sugar is one of
four types of molecules called bases. It is the sequence of these four bases along the backbone
that encodes information. This information is read using the genetic code, which specifies the
sequence of the amino acids within proteins. The code is read by copying stretches of DNA into
the rela.
HBr is a strong acid and will fully dissociate in water. You wil.pdf
HBr is a strong acid and will fully dissociate in water.
You will find a mixture of H+ and Br- ions in the solution.
Solution
HBr is a strong acid and will fully dissociate in water.
You will find a mixture of H+ and Br- ions in the solution..
e) Cash flow from Assets for 2017cash flow from assets = cash flow.pdf
e) Cash flow from Assets for 2017
cash flow from assets = cash flow generated from operations + change in working capital + cash
flow from fixed assets
cash flow from operations
Note: Net income = sales (40000) - costs(30000)-depreciation(2000)- interest (400)
Chnage in working capital = change in current assets - change in current liabilities
= 800-200
= $600
Cash flow from fixed assets = change in fixed assets = $3000
Cash flow from assets = 9000 + 600+3000
= $12,600
f) Cash flow to creditors
New debt raised = $4000
Long term debt in 2017 = $3000
cash flow to creditrs = 4000-3000
= $1,000
g) Cash flow to equity holders in 2017 = dividends paid + share repurchased
= 5404 + 1000
= $6,404
h)Net income$7,600Depreciation$2,000increase in current assets-$800increase in current
liabilities$200Cash from operations$9,000
Solution
e) Cash flow from Assets for 2017
cash flow from assets = cash flow generated from operations + change in working capital + cash
flow from fixed assets
cash flow from operations
Note: Net income = sales (40000) - costs(30000)-depreciation(2000)- interest (400)
Chnage in working capital = change in current assets - change in current liabilities
= 800-200
= $600
Cash flow from fixed assets = change in fixed assets = $3000
Cash flow from assets = 9000 + 600+3000
= $12,600
f) Cash flow to creditors
New debt raised = $4000
Long term debt in 2017 = $3000
cash flow to creditrs = 4000-3000
= $1,000
g) Cash flow to equity holders in 2017 = dividends paid + share repurchased
= 5404 + 1000
= $6,404
h)Net income$7,600Depreciation$2,000increase in current assets-$800increase in current
liabilities$200Cash from operations$9,000.
conjugate base substance formed when an acid loses a hydrogen ion.pdf
conjugate base: substance formed when an acid loses a hydrogen ion
Conjugate base of HSO4- is SO42-
conjugate acid: substance formed when a base gains a hydrogen ion.
Conjugate acid of HSO4- is H2SO4
Solution
conjugate base: substance formed when an acid loses a hydrogen ion
Conjugate base of HSO4- is SO42-
conjugate acid: substance formed when a base gains a hydrogen ion.
Conjugate acid of HSO4- is H2SO4.
cash flow financing activities includes proceeds from selling stock..pdf
cash flow financing activities includes proceeds from selling stock.Financing activities are the
activities through which capital are raised and pays it back to investors through capital invested
by them.
Solution
cash flow financing activities includes proceeds from selling stock.Financing activities are the
activities through which capital are raised and pays it back to investors through capital invested
by them..
C) interference with biotransformation enzyme activitesReason.pdf
C) interference with biotransformation enzyme activites
Reason:
The size of the nanoparticle is always in nanoscale 10um to 100nm in which active drug
molecules are coated on the neutral chanrged cyclodextrins such as hydroxyl propyl methyl
cellulose, methylcellulose in the form of liposomoes. These liposomes can have higher affinity
towards the cell membrane negative change and allow the drug molecules to reach the active
target regions. These liposomes (acts as surfactant i.e. both hydrophilic & lipophillic properties)
can release the drug in controlled level of sustained novel drug delivery systems.
Liver biotransformation enzymes are mainly involved in detoxification of foreign materials
which are incompatable to the host body therefore, when nanoparticles are going to interact with
live CYP enzymes finally reduce toxicity of prodrug or liposome based -nanoparticle drug.
Nanoparticles are going to induce toxicity by producing reactive oxygen species (ROS) finally
result in oxidative stress due to activation of signaling pathways to cause damage to DNA
1. Pharmaceutical nanoparticle drug delivery in breast cancer chemotherapies include the making
the anticancer drug molecules into the “liposome coated” to make efficient drug delivery with
efficient bioavailability associated with higher penetration rate into the breast cancer cells.
2. For example “making microRNAs to treat the breast cancer” into the liposome formulation as
they can form micelle composed of polymers including methylcellulose, hydroxyl propyl
methylcellulose. These polymers have the capability to incorporate the drug moieties into the
cancer cells in naoscale.
Solution
C) interference with biotransformation enzyme activites
Reason:
The size of the nanoparticle is always in nanoscale 10um to 100nm in which active drug
molecules are coated on the neutral chanrged cyclodextrins such as hydroxyl propyl methyl
cellulose, methylcellulose in the form of liposomoes. These liposomes can have higher affinity
towards the cell membrane negative change and allow the drug molecules to reach the active
target regions. These liposomes (acts as surfactant i.e. both hydrophilic & lipophillic properties)
can release the drug in controlled level of sustained novel drug delivery systems.
Liver biotransformation enzymes are mainly involved in detoxification of foreign materials
which are incompatable to the host body therefore, when nanoparticles are going to interact with
live CYP enzymes finally reduce toxicity of prodrug or liposome based -nanoparticle drug.
Nanoparticles are going to induce toxicity by producing reactive oxygen species (ROS) finally
result in oxidative stress due to activation of signaling pathways to cause damage to DNA
1. Pharmaceutical nanoparticle drug delivery in breast cancer chemotherapies include the making
the anticancer drug molecules into the “liposome coated” to make efficient drug delivery with
efficient bioavailability associated with higher penetration rate i.
c++ program to operate on binary search tree#includeiostream.pdf
This C++ program implements functions to operate on a binary search tree including insert, delete, display, and search functions. The main function initializes an array to represent the tree and presents a menu to allow the user to insert, delete, display, and search for elements in the tree by calling the respective functions.
As per section 10.29(a) of Treasury Circular 230 a conflict of inter.pdf
As per section 10.29(a) of Treasury Circular 230 a conflict of interest exists if – (i)
representation of one party by the tax preparer will affect any other party adversely (ii) the tax
preparer’s responsibility to another client will materially limit representation of one or more
parties.
However in case of conflict of interest a tax preparer can represent a party or a client provided
that each affected client or party waives the conflict and gives and informed and written consent
to the representation. Law requires the tax preparer to obtain the written consent within a
reasonable period of time but it should be no longer than 30 days after the conflict has come to
the knowledge of the tax preparer.
Solution
As per section 10.29(a) of Treasury Circular 230 a conflict of interest exists if – (i)
representation of one party by the tax preparer will affect any other party adversely (ii) the tax
preparer’s responsibility to another client will materially limit representation of one or more
parties.
However in case of conflict of interest a tax preparer can represent a party or a client provided
that each affected client or party waives the conflict and gives and informed and written consent
to the representation. Law requires the tax preparer to obtain the written consent within a
reasonable period of time but it should be no longer than 30 days after the conflict has come to
the knowledge of the tax preparer..
AnswerGenerally chromosome reduction occurs during formation of ga.pdf
Answer
Generally chromosome reduction occurs during formation of gametes. The gametes are haploid
as they are produced from diploid parent by meiosis.
If the reduction doesn\'t occur, the ploidy of organism that is produced by sexually reproduction
will be increased. The ploidy may be come tetraploid or hexaploid or polyploid. These polyploid
organisms are mostly sterile.
Ex.
The gametes produced from diploid parents are also diploid due to the absence of reduction. If
the two diploid gametes fuse, it develops into tetraploid organism. It may or may not alive. Even
if it is alive, the tetraploid organism will be sterile.
Solution
Answer
Generally chromosome reduction occurs during formation of gametes. The gametes are haploid
as they are produced from diploid parent by meiosis.
If the reduction doesn\'t occur, the ploidy of organism that is produced by sexually reproduction
will be increased. The ploidy may be come tetraploid or hexaploid or polyploid. These polyploid
organisms are mostly sterile.
Ex.
The gametes produced from diploid parents are also diploid due to the absence of reduction. If
the two diploid gametes fuse, it develops into tetraploid organism. It may or may not alive. Even
if it is alive, the tetraploid organism will be sterile..
AnsFalseExplantionIn a communication diagram, a(n) sequence .pdf
Ans:
False
Explantion:
In a communication diagram, a(n) sequence number is not indicates the order of the messages
Solution
Ans:
False
Explantion:
In a communication diagram, a(n) sequence number is not indicates the order of the messages.
a. less severe immunophenotypeb. strong growth increase of strain..pdf
a. less severe immunophenotype
b. strong growth increase of strain.
c. results in a non-chemotactic cells that incessantly tumble.
d. mediates aerotactic migration on media.
Solution
a. less severe immunophenotype
b. strong growth increase of strain.
c. results in a non-chemotactic cells that incessantly tumble.
d. mediates aerotactic migration on media..
a)They offer defined benefit retirement pension plans to certain e.pdf
a)
They offer defined benefit retirement pension plans to certain employees. These benefits relate
primarily to local plans outside the U.S. and, to a lesser extent, plans assumed in previous
acquisitions covering U.S. employees.
They also provide certain other retiree benefits, primarily health care and life insurance, for the
majority of our U.S. employees who become eligible for these benefits when they meet
minimum age and service requirements. Generally, the health care plans require cost sharing
with retirees and pay a stated percentage of expenses, reduced by deductibles and other
coverages. These benefits are primarily funded by ESOP Series B shares and certain other assets
contributed by the Company.
b) Total global defined contribution expense was $347, $344 and $364 in 2011, 2010 and 2009,
respectively.The primary U.S. defined contribution plan comprises the majority of the balances
and expense for the Company’s defined contribution plans. For the U.S. DC plan, the
contribution rate is set annually. Total contributions for this plan approximated 15% of total
participants’ annual wages and salaries in 2011, 2010 and 2009.
c) Their investment objective for defined benefit retirement plan assets is to meet the plan\'s
benefit obligations, while minimizing the potential for future required Company plan
contributions. The investment strategies focus on asset class diversification, liquidity to meet
benefit payments and an appropriate balance of long-term investment return and risk. Target
ranges for asset allocations are determined by matching the actuarial projections of the plan\'s
future liabilities and benefit payments with expected long-term rates of return on the assets,
taking into account investment return volatility and correlations across asset classes. Plan assets
are diversified across several investment managers and are generally invested in liquid funds that
are selected to track broad market equity and bond indices. Investment risk is carefully
controlled with plan assets rebalanced to target allocations on a periodic basis and continual
monitoring of investment manager\'s performance relative to the investment guidelines
established with each investment manager.
Several factors are considered in developing the estimate for the longterm expected rate of return
on plan assets. For the defi ned benefi t retirement plans, these factors include historical rates of
return of broad equity and bond indices and projected long-term rates of return obtained from
pension investment consultants. The expected longterm rates of return for plan assets are 8–9%
for equities and 5–6% for bonds. For other retiree benefit plans, the expected long-term rate of
return reflects the fact that the assets are comprised primarily of Company stock. The expected
rate of return on Company stock is based on the long-term projected return of 9.5% and reflects
the historical pattern of favorable returns.
Solution
a)
They offer defined benefit retirement.
61nSolution61n.pdf
This very short document contains a single line of text that reads "61/n". It appears to be providing a solution to some unspecified problem or question, with "61/n" representing the answer or result in a concise mathematical format. The essential information and context is not clear from this single line alone.
29Solution29.pdf
The document provides a solution to an unspecified problem or question. However, it only contains the number "29" with no other context or explanation. Therefore, a meaningful summary cannot be generated from the limited information provided.
Not at all. Most coloured salts contain transitio.pdf
Not at all. Most coloured salts contain transition metals or heavy p-block elements,
but even the largest alkali metal ions give colourless salts. It depends on electron distribution in
the ions, not how large they are.
Solution
Not at all. Most coloured salts contain transition metals or heavy p-block elements,
but even the largest alkali metal ions give colourless salts. It depends on electron distribution in
the ions, not how large they are..
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THis can be explained easily by using an example.Let consider a sc.pdf
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The equation given is incorrect. The given possible roots give the.pdf
The equation given is incorrect. The given possible roots give the.pdf
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Please post properly..SolutionPlease post properly...pdf
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HBr is a strong acid and will fully dissociate in water. You wil.pdf
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conjugate base substance formed when an acid loses a hydrogen ion.pdf
conjugate base substance formed when an acid loses a hydrogen ion.pdf
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c++ program to operate on binary search tree#includeiostream.pdf
c++ program to operate on binary search tree#includeiostream.pdf
As per section 10.29(a) of Treasury Circular 230 a conflict of inter.pdf
As per section 10.29(a) of Treasury Circular 230 a conflict of inter.pdf
AnswerGenerally chromosome reduction occurs during formation of ga.pdf
AnswerGenerally chromosome reduction occurs during formation of ga.pdf
AnsFalseExplantionIn a communication diagram, a(n) sequence .pdf
AnsFalseExplantionIn a communication diagram, a(n) sequence .pdf
a. less severe immunophenotypeb. strong growth increase of strain..pdf
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https://app.box.com/s/y977uz6bpd3af4qsebv7r9b7s21935vdChapter wise All Notes of First year Basic Civil Engineering.pptx
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Syllabus
Chapter-1
Introduction to objective, scope and outcome the subject
Chapter 2
Introduction: Scope and Specialization of Civil Engineering, Role of civil Engineer in Society, Impact of infrastructural development on economy of country.
Chapter 3
Surveying: Object Principles & Types of Surveying; Site Plans, Plans & Maps; Scales & Unit of different Measurements.
Linear Measurements: Instruments used. Linear Measurement by Tape, Ranging out Survey Lines and overcoming Obstructions; Measurements on sloping ground; Tape corrections, conventional symbols. Angular Measurements: Instruments used; Introduction to Compass Surveying, Bearings and Longitude & Latitude of a Line, Introduction to total station.
Levelling: Instrument used Object of levelling, Methods of levelling in brief, and Contour maps.
Chapter 4
Buildings: Selection of site for Buildings, Layout of Building Plan, Types of buildings, Plinth area, carpet area, floor space index, Introduction to building byelaws, concept of sun light & ventilation. Components of Buildings & their functions, Basic concept of R.C.C., Introduction to types of foundation
Chapter 5
Transportation: Introduction to Transportation Engineering; Traffic and Road Safety: Types and Characteristics of Various Modes of Transportation; Various Road Traffic Signs, Causes of Accidents and Road Safety Measures.
Chapter 6
Environmental Engineering: Environmental Pollution, Environmental Acts and Regulations, Functional Concepts of Ecology, Basics of Species, Biodiversity, Ecosystem, Hydrological Cycle; Chemical Cycles: Carbon, Nitrogen & Phosphorus; Energy Flow in Ecosystems.
Water Pollution: Water Quality standards, Introduction to Treatment & Disposal of Waste Water. Reuse and Saving of Water, Rain Water Harvesting. Solid Waste Management: Classification of Solid Waste, Collection, Transportation and Disposal of Solid. Recycling of Solid Waste: Energy Recovery, Sanitary Landfill, On-Site Sanitation. Air & Noise Pollution: Primary and Secondary air pollutants, Harmful effects of Air Pollution, Control of Air Pollution. . Noise Pollution Harmful Effects of noise pollution, control of noise pollution, Global warming & Climate Change, Ozone depletion, Greenhouse effect
Text Books:
1. Palancharmy, Basic Civil Engineering, McGraw Hill publishers.
2. Satheesh Gopi, Basic Civil Engineering, Pearson Publishers.
3. Ketki Rangwala Dalal, Essentials of Civil Engineering, Charotar Publishing House.
4. BCP, Surveying volume 1
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Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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The way you would solve this problem is to look a.pdf
- 1. The way you would solve this problem is to look at the polarity of the molecules-- which has to deal with the electronegativity of the atoms themselves, and the atomic size and mass. Polarity affects intermolecular forces and causes molecules and atoms to deviate from the ideal behavior. H2 would be expected to behave most ideally because it has a dipole moment of 0 (non-polar). Also, it has smaller mass, it is not as easily polarizable. F2 may behave ideally, because it has a dipole moment of 0 also. But, it's mass is bigger and it is highly electronegative HF would be expected to deviate because it has a higher dipole moment, and it's polar. That dipole moment creates an intermolecular force that influecnes other polar molecules. Source(s): General Chemistry 4th edition (Hill, Petrucci, McCreary, Perry) Solution The way you would solve this problem is to look at the polarity of the molecules-- which has to deal with the electronegativity of the atoms themselves, and the atomic size and mass. Polarity affects intermolecular forces and causes molecules and atoms to deviate from the ideal behavior. H2 would be expected to behave most ideally because it has a dipole moment of 0 (non-polar). Also, it has smaller mass, it is not as easily polarizable. F2 may behave ideally, because it has a dipole moment of 0 also. But, it's mass is bigger and it is highly electronegative HF would be expected to deviate because it has a higher dipole moment, and it's polar. That dipole moment creates an intermolecular force that influecnes other polar molecules. Source(s): General Chemistry 4th edition (Hill, Petrucci, McCreary, Perry)