This unit speaks about testing and its importance along with various types of tests and procedure to administer. In addition, it deals with the evaluation patterns and its significance of assessment.

2. Learning
Experiences
Evaluation
Objectives

3.  AN INSTRUMENT OR EXAMINATION USED
TO MEASURE
ABLITIES,KNOWLEDGE,APTITUDE OR
QUALIFICATION. A SET OF QUESTIONS OR
EXERCISE OR PROBLEMS

4. The process of quantifying
observations about a quality
or attribute of a thing or
person.

5. In general, it is an act or a
process that allows one to
make a judgment about the
desirability or value of a
measure

6.  A) For grading, promoting students and
reporting parents.
 B) To evaluate effectiveness of curricular
experiences and instructional methods.
 C) For building growth of the pupils,
diagnosing their weakness for providing
remedial measures.
 D) To motivate pupils for better attainment.

7. EVALUATION=
MEASUREMENT+
VALUE JUDGEMENT

8.  FORMATIVE EVALUATION
 SUMMATIVE EVALUATION

9.  CHARACTERISTICS OF GOOD TEST
VALIDITY
RELIABILITY
OBJECTIVITY

10. ACHIEVEMENT TEST
DIAGNOSTIC TEST

11. Objective-type tests
Short-Answer type tests
Essay-Type tests

12.  WEIGHTAGE TO THE OBJECTIVES
 WEIGHTAGE TO THE CONTENT
 WEIGHTAGE TO THE QUESTIONS

13. BLUE PRINT
KNOWLEDGE
UNDERSTANDING
APPLICATION
SKILL

14. QUESTION PAPER
ANSWER/SCORING KEY

15.  Mean
 Median
 Mode

16. Method 1
C.I. f Mid Point (x) d=(x-A)/i fd
0 - 10 3 5 - 4 -12
10 - 20 5 15 - 3 -15
20 - 30 1 25 - 2 -2
30 – 40 5 35 -1 -5
40 – 50 2 A 0 0
50 – 60 4 55 1 4
60 – 70 7 65 2 14
70 – 80 6 75 3 18
80 – 90 9 85 4 36
90 - 100 4 95 5 20
Total 46 92-34=58
45

17. Mean = A + ( ∑ fd / ∑ f ) x i
= 45 + (58 / 46) x10
= 45 + 12.61
= 57.61

18. C.I. f cf
0 - 10 3 3
10 - 20 5 8
20 - 30 1 9
30 – 40 5 14
40 – 50 2 16
50 – 60 4 20
60 – 70 7 27
70 – 80 6 33
80 – 90 9 42
90 - 100 4 46
Total 46

19.  N / 2 = 46 / 2 = 23
 Median = L + ( (N/2 – cf) / f) x i
= 60 + ( (23 – 20) / 7) x 10
= 60 + (30 / 7)
= 60 + 4.29 = 64.29
Median value lies in the Median Class

20.  Mode = 3 (Median) – 2 (Mean)
= 3 (64.29) – 2 (57.61)
= 192.87 – 115.22
= 77.65
Mean, Median and Mode will be either in the
ascending or descending order.

21.  MEAN < MEDIAN < MODE
 MEAN > MEDIAN > MODE
 MEAN = MEDIAN = MODE

22.  RANGE
 QUARTILE DEVIATION
 MEAN DEVIATION
 STANDARD DEVIATION

23.  Range = Highest Value – Lowest Value

24. C.I. f cf
0 - 10 3 3
10 - 20 5 8
20 - 30 1 9
30 – 40 5 14
40 – 50 2 16
50 – 60 4 20
60 – 70 7 27
70 – 80 6 33
80 – 90 9 42
90 - 100 4 46
Total 46

25. Q1 = L + ( (N/4 – cf) / f) x i
= 30 + ( (11.5– 9) / 5) x 10
= 30 + (25 / 5)
= 30 + 5 = 35

26. Q3 = L + ( (3N/4 – cf) / f) x i
= 80 + ( (34.5– 33) / 9) x 10
= 80 + (15 / 9)
= 80 + 1.667 = 81.667

27.  Quartile Deviation
Q.D. = (Q3 – Q1) / 2
= (81.667 – 35) / 2
= 46.667 / 2
= 23.334

28. C.I. f Mid Point (x) d = x – x
= x– 57.61
fd |fd|
0 - 10 3 5 - 52.61 - 157.83 157.83
10 - 20 5 15 - 42.61 - 213.05 213.05
20 - 30 1 25 - 32.61 - 32.61 32.61
30 – 40 5 35 - 22.61 - 113.05 113.05
40 – 50 2 45 - 12.61 - 25.22 25.22
50 – 60 4 55 - 2.61 - 10.44 10.44
60 – 70 7 65 7.39 51.73 51.73
70 – 80 6 75 17.39 104.34 104.34
80 – 90 9 85 27.39 246.51 246.51
90 - 100 4 95 37.39 149.56 149.56
Total 46 1104.34

29. Average Deviation = ( ∑ |fd| ) /N
= 1104.34 / 46
= 24.007

30. C.I. f Mid Point (x) d=(x-A)/i fd d2 fd2
0 - 10 3 5 - 4 -12 16 48
10 - 20 5 15 - 3 -15 9 45
20 - 30 1 25 - 2 -2 4 4
30 – 40 5 35 -1 -5 1 5
40 – 50 2 A 0 0 0 0
50 – 60 4 55 1 4 1 4
60 – 70 7 65 2 14 4 28
70 – 80 6 75 3 18 9 54
80 – 90 9 85 4 36 16 144
90 - 100 4 95 5 20 25 100
Total 46 92-34=58 432
45

31.  SD = i x √((∑fd2 / N) – (∑fd / N)2)
= 10 x√((432 / 46) – (58 / 46)2)
= 10 x√( 9.391 – 1.589)
= 10 x √7.802 = 10 x 2.793
= 27.93
QD ≤ MD ≤ SD

32. QD ≤ MD ≤ SD

33. Marks in
English
Marks in
Maths
R1 R2 d = R1 - R2 d2
62 64 2.5 4 -1.5 2.25
78 73 1 2 -1 1
56 55 6 5.5 0.5 0.25
35 39 9 9 0 0
62 73 2.5 2 0.5 0.25
58 55 4 5.5 -1.5 2.25
39 45 8 8 0 0
45 73 7 2 5 25
57 50 5 7 -2 4
17 21 10 10 0 0
Total
∑d = 6 – 6 =0
35

34. = 1 – (210 / 990)
= 1 – 0.21
= 0.79
Positive Correlation
ℓ = 1 – (( 6∑d2) / N (N2 – 1))

35. 20
49
90
0
10
20
30
40
50
60
70
80
90
100
A B C
Series1

36. 0
1
2
3
4
5
6
Category 1 Category 2 Category 3 Category 4
Series 1
Series 2
Series 3

37. 0%
10%
20%
30%
40%
50%
60%
70%
80%
90%
100%
Category 1 Category 2 Category 3 Category 4
Series 3
Series 2
Series 1

38. 0
0.5
1
1.5
2
2.5
3
3.5
0 0.5 1 1.5 2 2.5 3
Y-Values
Y-Values

39. 0
10
20
30
40
50
60
70
80
90
100
110
1 2 3 4 5 6 7 8 9 10
Upper Limit
%
of
cf
Series1

40. THANK YOU