Step 2 Formulate a HypothesisFormulate a hypothesis by making an .pdf

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Step 2: Formulate a Hypothesis Formulate a hypothesis by making an explicit statement about the cause of the common cold based on the observations and generalizations you made in Step 1. based on the 3 things below HypothesisObservation 1: Common cold is caused by bacterial or viral infection and transmitted from one person to other through droplets from infected person. The person infected with common cold show protect his nose or mouth with steril mask, which covers mouth and nose. If nose or mouth is not covered by mask, droplets can transmit common cold to many people in surrounding environment. Observation 2: Common cold is widely transmitted very easily, if a person infected with common cold and he sneezes in public places which is having high population, several thousands of droplets can be transported through air at onetime, when person sneezes, so avoid moving in public places when common cold is rampant in specific area. Observation 3: Doctors who examine the persons suffering with common cold should be careful, the physician should use antibiotics or vaccines to prevent common cold infection. Solution The hypothesis is this statement: Common cold is a viral infectious disease which can be transmistted from one person to another on sneezing.It can be prevented by taking antibiotics and vaccines by the physicians while check-up..

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A common viral infection that can be deadly, especially in high-risk groups. The flu attacks the lungs, nose and throat. Young children, older adults, pregnant women and people with chronic disease or weak immune systems are at high risk. Symptoms include fever, chills, muscle aches, cough, congestion, runny nose, headaches and fatigue. Flu is primarily treated with rest and fluid intake to allow the body to fight the infection on its own. Paracetamol may help cure the symptoms but NSAIDs should be avoided. An annual vaccine can help prevent the flu and limit its complications.

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Write a complete PUP enabled website using WebMatrix. At the beginning, choose the template of empty PHP website or empty HTML website. In the major PUP file of this site, i.e. index.php, inside PHP script block, write PHP code to print out first 10 prime numbers inclusively starting with 2. Print these numbers in one line and separate them with two spaces. You MUST use PHP output statement, flow control statements for selection and loop control structures in PHP. Solution Need to create two files named template.php and index.php template.php PHP include Website Template index.php.

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Which of the following is a flaw, loophole, oversight, or error that makes an organization susceptible to attack or damage? A. Risk B. Vulnerability C. Threat D. Exploit Solution B. Vulnerability is a flaw, loophole, oversight, or error that makes the organization susceptible to attack or damage. All other answers are incorrect: A risk can be defined as the potential harm that can arise from some present process or from some future event; a threat is an unwanted event that can result in harm to an asset or service; and an exploit takes advantage of a bug, glitch, or vulnerability..

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Use the series and parallel commands in Matlab to find the transfer functions of 1. G(s) in series/parallel with H(s) 2. H(s) in series/parallel with T(s) G(s) = (s+1)/(s^2+4s+10) H(s) =(s ^2+5s+1)/(s^4+s^3+3s+10) T(s) = (s+1)/(s+1)(s+2)(s+3)(s+4) Solution MATLAB CODE G = tf([1,1],[1 3 0]) A.) % SERIES CONNECTION S = G * H % PARALLEL CONNECTION P = G + H B.) % SERIES CONNECTION S1= H * T % PARALLEL CONNECTION P1= H + T.

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This is my code but not complete, please complete my code related by lab#4 And i wans results for output in black screen. #include #include #define MAX 100; using namespace std; struct date { int day,month,year\' }; struct STUDENT_TYPE { string name; int id; double GPA; date DOB; }; int i=0; int main() { STUDENT_TYPE student[MAX]; int choice=-1; while(choice!=0) { cout<<\"\ 0-Exit\ 1-Insert\ 2-Delete_last\ 3-Display\ 4-Search\ 5-Deletion_particular_record\ 6- Insert_after_record\ 7-Sort(acending)\"; cout<<\"Enter your choice:\"; cin>>choice; switch(choice) { case 0exit(0); case 1:insert();break; case 2:delete();break; case 3:display();break; case 4:searcht();break; case 5:delete();break; case 6:insert();break; case 7:sort();break; default:cout<<\"Wrong selection\"; } } return 0; } void insert() { cout<<\"Enter the student details:\"; cout<<\"student name:\"; cin>>student[i].name; cout<<\"student id:\"; cin>>student[i].id; cout<<\"student GPA:\"; cin>>student[i].GPA; cout<<\"student DOB\"; cin>>student[i].DOB.day>>student[i].DOB.month>>student[i].DOB.year; i++; } void delete() { //assign 0 to last pointed record student[i].name=0; student[i].id=0; student[i].GPA=0; student[i].DOB.day=0;student[i].DOB.month=0;student[i].DOB.year=0; i--; } void display () { cout<<\"student details are\ \"; for(int n=0; n>id; for(int n=0;n>record; for(int n=0;n>id; for(int n=0;npos;p--) { // move all record towards right to make space for insertion of new record student[p].name=student[p-1].name; student[p].id=student[p-1].id; student[p].GPA=student[p-1].GPA; student[p].DOB.day=student[p-1].DOB.day; student[p].DOB.month=student[p-1].DOB.month; student[p].DOB.year=student[p-1].DOB.year; } cout<<\"enter the student details:\"; cout<<\"student name:\"; cin>>student[pos].name; cout<<\"student id:\"; cin>>student[pos].id; cout<<\"student GPA:\"; cin>>student[pos].GPA; cout<<\"student DOB:\"; cin>>student[pos].DOB.day>>student[pos].DOB.month>>student[pos].DOB.year; } void sort() { // bubble sorting technique is used struct STUDENT_TYPE TEMP[2]; for(intx=0;xstudent[y+1]id) { //move all the record information to temp and swap them temp[0].name=student[j].name; temp[j].name=student[j+1].name; temp[j+1].name=student[0].name; //the above three lines are repeated for all the student fields } } } } #include #include #define MAX 100; using namespace std; struct date { int day,month,year\' }; struct STUDENT_TYPE { string name; int id; double GPA; date DOB; }; int i=0; int main() { STUDENT_TYPE student[MAX]; int choice=-1; while(choice!=0) { cout<<\"\ 0-Exit\ 1-Insert\ 2-Delete_last\ 3-Display\ 4-Search\ 5-Deletion_particular_record\ 6- Insert_after_record\ 7-Sort(acending)\"; cout<<\"Enter your choice:\"; cin>>choice; switch(choice) { case 0exit(0); case 1:insert();break; case 2:delete();break; case 3:display();break; case 4:searcht();break; case 5:delete();break; case 6:insert();break; case 7:sort();break; default:cout<<\"Wrong selection\"; } } return 0; } void insert() { cout.

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The terminology employed in factory automation is often confusing in part because the names are so similar and in part because the sub areas do indeed overlap. Carefully distinguish among CIM , CAD , CAE , CAM and CAPP indicating any overlaps. Solution CIM(computer integrated manufacturing): It is the approach of using computers for controling the entire production process. This integration allows individual processes to exchange information with each other and initiate actions among them. It simply means the fully use of computer controlled machines and fully automation system in manufacturing products. CAD(computer aided design): It is a software and is used by architects, engineers or artists for the creation of precision drawing for technical overview. it is also helpful in the creation of 2D or 3D models. CAE(computer aided engineering): Is a process of solving problems related to engineering through the help of interactive graphical software.It can be graphical or mathematical or modeling. CAM(computer aided manufacturing): is the software for the controlling of maching tools or to assist all the process for the manufacturing of the machine. CIPP(computer aided process planning): Is the use of technology for the process and planning of a part or product in manufacturing. CAPP is the process in between CAD and CAM. It provides the planning for the process for producing a specific part. ///////////////////////////////////////////////////////////////// differences //////////////////////////////////////////////////////////////// The logic is that CAD/CAM provide the tools, CIM provides the internal logic and that is used while organizing the computers or the programs and the information that flows among them. Computer-aided manufacturing moto is to use the computer software to control machine tools and related machinery(or machine parts) in the manufacturing process. It is not technically or logically considered a system for engineering software programs, but rather than for hardware solution.But on the other side computer aided engineering involves the processes the software work, like the analysis or simulation part of the actual work done..

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It\'s all worked out, but I\'m still very confused by the steps they took to get each part. Like why multiply everything by (x^2 + 9) and then in the next step, how did they end up with those answers? I\'m just very confused. Solution they just multiplide (x^2 + 9) for simpification LIKE EXAMPLE eq 2+3=5 if we multify both sides with 2 (2+3)2=5*2 10=10 equality not changed ,,,like we use this in mathematics after solving eq they got X parameters and they cheked in original eq.

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