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Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute Static Aeroelasticity
Carlo L. Bottasso, Stefano Cacciola
October 2015
Static
Aeroelasticity
-2-
Contents
• Divergence of the typical section
• Aileron effectiveness and reversal
• Operators
• Straight and swept cantilever wings: divergence and load redistribution
Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute
Divergence of the
Typical Section
Static
Aeroelasticity
-4-
Divergence
Structural deflection under aerodynamic loading that enhances further the
aerodynamic loading itself
It is a static aeroelastic phenomenon (no presence of inertial or unsteady
aerodynamics effects)
Typical section (simplest model of blade torsional deformation):
Zero lift line
Aerodynamic
center
Elastic
axis
Structural
deformation
𝐟
𝑒𝑐
𝛌𝑟
𝑈
𝜃
𝛌𝑟
Static
Aeroelasticity
-5-
Reminder: Resultants on Airfoils
Aerodynamic center:
• Point about which moment is constant wrt AoA 𝜶 (typically 𝑎𝑚𝑪 < 𝟎)
• Close to 𝒄/𝟒 and rather constant for a wide range of AoAs before stall
Center of pressure: 𝒙𝑪𝑷 = 𝒙𝑚𝑪 − ΀
𝑎𝑚𝑪 𝑳, ΀
𝒙𝑪𝑷
𝒄 = ΀
𝒙𝑚𝑪
𝒄 − ΀
𝑪𝑎𝑚𝑪
𝑪𝑳
• Point of application of the aerodynamic pressure field resultant (i.e. pressure
field is reduced to a single force vector with null moment)
• Changes with lift (i.e. AoA). Pre-stall:𝑪𝑳 = 𝑪𝑳𝜶𝜶 and therefore
ൗ
𝒙𝑪𝑷
𝒄 = ൗ
𝒙𝑚𝑪
𝒄 − ΀
𝑪𝑎𝑚𝑪
𝑪𝑳𝜶𝜶
TE
LE
AC ≈ c/4
Aerodynamic force resultant
(due to pressure and shear)
ൗ
𝒙𝑪𝑷
𝒄
𝒂
𝑚𝑪
Non-dimensionalization (forces and
moment per unit span):
𝑳 =
𝟏
𝟐
𝝆𝑜𝟐
𝒄𝑪𝑳
𝑫 =
𝟏
𝟐
𝝆𝑜𝟐
𝒄𝑪𝑫
𝑎𝑚𝑪 =
𝟏
𝟐
𝝆𝑜𝟐
𝒄𝟐
𝑪𝑎𝑚𝑪
Static
Aeroelasticity
-6-
Reminder: Resultants on Airfoils
Re dependence at high a
Separation and Stall
cD vs. a
dependent on Re
(source: I.H. Abbott, A.E. von Doenhoff, “Theory of Wing Sections: Including a Summary of Airfoil Data”)
𝑪𝑳 𝒎𝒂𝒙
𝑪𝑫 𝒎𝒊𝒏
Lift coefficient
Moment coefficient wrt c/4 point
Drag coefficient
Moment coefficient wrt AC
Example: NACA 2412 Airfoil
Static
Aeroelasticity
-7-
tan−𝟏 𝑪𝑳𝜶
𝑪𝑳 = 𝑪𝑳𝜶𝜶 in the pre-stall region, where the
flow is attached
For inviscid flows over thin airfoils: 𝑪𝑳𝜶 = 𝟐π
In general: 𝑪𝑳𝜶 < 𝟐π (depending on airfoil and
operating condition)
𝒄𝑳
𝒂𝒈 = 𝒂𝟎
Angle of zero lift
𝒂𝒈
LE
TE
Geometric angle of attack
𝒄𝑳
𝒂𝒂
Aerodynamic angle of attack
𝒂𝒈 = 𝟎
𝒂𝒂 = 𝟎
Reminder: Resultants on Airfoils
𝑪𝑳 = 𝑪𝑳𝟎 + 𝑪𝑳𝜶𝜶 𝑪𝑳 = 𝑪𝑳𝜶𝜶
Static
Aeroelasticity
-8-
Divergence
Lift (per unit span): 𝐿 = 𝑞𝑐𝐶𝐿 = 𝑞𝑐𝐶𝐿𝛌
𝛌𝑟 + 𝜃 with 𝑞 =
1
2
𝜌𝑈2
Aerodynamic moment: 𝑀𝐞𝐎
𝐎
= 𝑀𝐎𝐶 + 𝐿𝑒𝑐 = 𝑞𝑐2
𝐶𝑚𝐎𝐶
+ 𝑒𝐶𝐿𝛌
𝛌𝑟 + 𝜃
Structural moment: 𝑀𝐞𝐎
𝑆
= 𝐟𝜃
Equilibrium: 𝑀𝐞𝐎
𝐎
= 𝑀𝐞𝐎
𝑆
Structural torsional deflection:
𝜃 =
𝑞𝑐2 𝐶𝑚𝐎𝐶
+𝑒𝐶𝐿𝛌𝛌𝑟
𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌
Static
Aeroelasticity
-9-
Divergence
Structural torsional deflection:
𝜃 =
𝑞𝑐2 𝐶𝑚𝐎𝐶
+𝑒𝐶𝐿𝛌𝛌𝑟
𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌
Divergence:
𝑒 > 0 𝑞 → 𝑞𝐷 =
𝐟
𝑒𝑐2𝐶𝐿𝛌
𝜃 → ∞
𝐿 = 1 +
𝑞/𝑞𝐷
1−𝑞/𝑞𝐷
𝑞𝑐𝐶𝐿𝛌
𝛌𝑟 +
𝑞/𝑞𝐷
1−𝑞/𝑞𝐷
𝑞
𝑐
𝑒
𝐶𝑚𝐎𝐶
The divergence speed could be increased by
increasing torsional stiffness, but this must be
traded against increased weight/cost
Divergence
dynamic pressure
𝜃
𝑞
𝑞𝐷
𝐿
𝑞
𝑞𝐷
Elastic lift (limited by stall)
Rigid lift
𝐿𝑟 = 𝑞𝑐𝐶𝐿𝛌
𝛌𝑟
Static
Aeroelasticity
-10-
𝑜
𝒏
Why Divergence Matters
It is a crucial design parameter for ensuring safety and structural integrity
Flight envelope in terms of the 𝑜-𝒏 diagram:
Structural damage or
failure because of
divergence or flutter
𝑜𝑵𝑬
Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute
Aileron Effectiveness
and Reversal
Static
Aeroelasticity
-12-
Aileron Effectiveness and Reversal
• To increase lift, deflect aileron (down) to increase camber
• Resulting nose-down moment decreases AoA and hence lift, when wing is
torsionally flexible
• If lift decrease due to AoA change is larger than lift increase due to increase in
camber, then lift decreases instead of increasing (aileron reversal)
• Same for aileron up deflection
Zero lift line
Aerodynamic
center
Elastic
axis
Structural
deformation
𝛿
𝐟
𝑒𝑐
𝛌𝑟
𝑈
𝜃
𝛌𝑟
Static
Aeroelasticity
-13-
Aileron Effectiveness and Reversal
Lift (per unit span): 𝐿 = 𝑞𝑐𝐶𝐿 = 𝑞𝑐𝐶𝐿𝛌
𝛌𝑟 + 𝜃 + 𝑞𝑐𝐶𝐿𝛿
𝛿 with 𝑞 =
1
2
𝜌𝑈2
Aerodynamic moment:
𝑀𝐞𝐎
𝐎
= 𝑀𝐎𝐶 + 𝐿𝑒𝑐 = 𝑞𝑐2
𝐶𝑚𝐎𝐶
+ 𝐶𝑚𝐎𝐶 𝛿
𝛿 + 𝑒 𝐶𝐿𝛌
𝛌𝑟 + 𝜃 + 𝐶𝐿𝛿
𝛿
Structural moment: 𝑀𝐞𝐎
𝑆
= 𝐟𝜃
Equilibrium: 𝑀𝐞𝐎
𝐎
= 𝑀𝐞𝐎
𝑆
Structural torsional deflection:
𝜃 =
𝑞𝑐2 𝐶𝑚𝐎𝐶
+𝐶𝑚𝐎𝐶 𝛿
𝛿+𝑒 𝐶𝐿𝛌𝛌𝑟+𝐶𝐿𝛿
𝛿
𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌
Static
Aeroelasticity
-14-
Aileron Effectiveness and Reversal
(assuming 𝐶𝑚𝐎𝐶
= 0 for simplicity)
Lift:
𝐿 = 1 +
𝑞𝑐2
𝑒𝐶𝐿𝛌
𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌
𝑞𝑐𝐶𝐿𝛌
𝛌𝑟 +
𝑘 + 𝑞𝑐2 ΀
𝐶𝑚𝐎𝐶 𝛿
𝐶𝐿𝛌
𝐶𝐿𝛿
𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌
𝑞𝑐𝐶𝐿𝛿
𝛿
Reordering:
𝐿 = 1 +
΀
𝑞 𝑞𝐷
1 − ΀
𝑞 𝑞𝐷
𝑞𝑐𝐶𝐿𝛌
𝛌𝑟 +
1 − ΀
𝑞 𝑞𝑅
1 − ΀
𝑞 𝑞𝐷
𝑞𝑐𝐶𝐿𝛿
𝛿
with:
• Divergence dynamic pressure: 𝑞𝐷 =
𝐟
𝑒𝑐2𝐶𝐿𝛌
where if 𝑒 > 0, 𝑞 → 𝑞𝐷, 𝜃 → ∞
• Reversal dynamic pressure: 𝑞𝑅 = −
𝐟𝐶𝐿𝛿
𝑐2𝐶𝑚𝐎𝐶 𝛿
𝐶𝐿𝛌
(notice: 𝐶𝑚𝐎𝐶 𝛿
< 0)
Remark: typically 𝑞𝑅 < 𝑞𝐷
Lift due to
elastic effect at
null
Rigid
lift
Lift due to
aileron
deflection
Static
Aeroelasticity
-15-
Aileron Effectiveness and Reversal
Aileron Effectiveness (𝐎𝐞):
𝐎𝐞 =
𝐿𝛿
𝐿𝛿𝑟
=
1 − ΀
𝑞 𝑞𝑅
1 − ΀
𝑞 𝑞𝐷
𝑞𝑐𝐶𝐿𝛿
𝑞𝑐𝐶𝐿𝛿
=
1 − ΀
𝑞 𝑞𝑅
1 − ΀
𝑞 𝑞𝐷
Structural torsional deflection:
𝜃 =
𝑞𝑐2
𝐶𝑚𝐎𝐶
+ 𝐶𝑚𝐎𝐶 𝛿
𝛿 + 𝑒 𝐶𝐿𝛌
𝛌𝑟 + 𝑒𝐶𝐿𝛿
𝛿
𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌
=
΀
𝑞 𝑞𝐷
1 − ΀
𝑞 𝑞𝐷
𝛌𝑟 −
𝑞
𝑞𝑅
1 − ΀
𝑞𝑅 𝑞𝐷
1 − ΀
𝑞 𝑞𝐷
𝐶𝐿𝛿
𝐶𝐿𝛌
𝛿
>0 (nose up)
<0 (nose down) for
(reduces AoA)
𝐎𝐞
΀
𝑞 𝑞𝐷
1
1
Stick right, roll left
(and viceversa)!
Static
Aeroelasticity
-16-
Why Aileron Effectiveness Matters
Increase torsional stiffness to increase 𝑞𝑅, but significant weight penalty
Better solution: high speed ailerons, spoilerons, flaperons
Additional benefit: no adverse yaw effect
Roll by the use of spoilers ▶
(notice left wing spoiler up,
left wing down,
positive direct yaw effect)
Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute
Operators
Static
Aeroelasticity
-18-
Structural Operators
Structural operator: relates elastic deflections (rotations) to forces (and moments)
𝒇 = 𝒮 𝒒
Simplest possible example: spring-force system
𝑓 = 𝑘 𝑥
Governing equilibrium equation
Applied forces
(and/or moments)
Elastic deflections
(and/or rotations)
Structural
operator
𝑓
𝑥
𝑘
Applied force
Displacement
Structural
operator
𝒮 = 𝑘
Static
Aeroelasticity
-19-
Structural Operators
Example: wing bending
The wing is modeled as a beam subjected to a distributed load:
• Depending on the technique used to model the structure, the operator can
be differential, integral or a matrix
• For real life problems, numerical methods are typically necessary and the
matrix approach is often the most effective (see FEM)
𝑓(𝑥)
Deformed
configuration
Undeformed
configuration
Governing equation Structural operator
𝜕2
𝜕𝑥2
𝐞𝐌(𝑥)
𝜕2𝑀 𝑥
𝜕𝑥2
= 𝑓(𝑥) 𝒮 =
𝜕2
𝜕𝑥2
𝐞𝐌(𝑥)
𝜕2 ∙
𝜕𝑥2
𝑥
𝑀
nur von einer variable
abhÀngig (x) = ordinary
equation
Static
Aeroelasticity
-20-
Structural Operators
Finite Element Method (FEM)
Governing equation in “weak form” (multiply both sides by arbitrary test
function 𝑣(𝑥), then integrate over the span of the beam):
න 𝑣𝑇
𝜕2
𝜕𝑥2
𝐞𝐌(𝑥)
𝜕2
𝑀 𝑥
𝜕𝑥2
d𝑥 = න 𝑣𝑇
𝑓 𝑥 d𝑥 , ∀ 𝑣(𝑥)
Integrate by parts (twice) the left hand side:
න
𝜕2
𝑣(𝑥)
𝜕𝑥2
𝑇
𝐞𝐌(𝑥)
𝜕2
𝑀 𝑥
𝜕𝑥2
d𝑥 = න 𝑣𝑇
𝑓 𝑥 d𝑥 , ∀ 𝑣(𝑥)
Boundary conditions:
ቚ
𝑣
𝑥=0
= 0 (null displacement) àž­
𝜕2
𝑀
𝜕𝑥2
𝑥=𝐿
= 0 (null bending moment)
ቀ
𝜕𝑣
𝜕𝑥 𝑥=0
= 0 (null slope) àž­
𝜕3
𝑀
𝜕𝑥3
𝑥=𝐿
= 0 (null shear force)
Static
Aeroelasticity
-21-
Structural Operators
The beam is represented as a collection of finite elements:
On each element, the elastic displacements and the test functions are
approximated using suitable shape functions:
element
1
element
2


element
i


Elemental DoFs:
nodal displacements
and rotations
𝑣 𝑥 = 𝑵𝑇
𝑥 𝒒e
𝑀 𝑥 = 𝑵𝑇 𝑥 𝒉e
Nodal DoFs of
test function
Nodal DoFs of elastic
displacement field
𝑵 𝑥 =
𝑢1
𝑟1
𝑢2
𝑟2
𝑢1 = 1
𝑟1 = 𝑢2 = 𝑟2 = 0
𝑟1 = 1
𝑢1 = 𝑢2 = 𝑟2 = 0
𝑢2 = 1
𝑢1 = 𝑟1 = 𝑟2 = 0
𝑟2 = 1
𝑟1 = 𝑢2 = 𝑢2 = 0
Static
Aeroelasticity
-22-
Structural Operators
Insert interpolating approximations into weak form:
𝒒𝑇
න
𝜕2
𝑵(𝑥)
𝜕𝑥2
𝐞𝐌(𝑥)
𝜕2
𝑵
𝜕𝑥2
𝑇
d𝑥 𝒉e = 𝒒𝑇
න 𝑵 𝑥 𝑓 𝑥 d𝑥 , ∀ 𝒒
Due to arbitrarity of 𝒒, the local equilibrium 𝑲e𝒉e = 𝒇e holds true for each element
Global equilibrium is obtained by assembling the contributions over all elements:
𝒇 = 𝑲 𝒉 → 𝒉 = 𝑲−1
𝒇 = 𝑪𝒉𝒉
𝒇
Element stiffness matrix
𝑲e
Element load vector
𝒇e
Load vector
Nodal displacements
and rotations
Structural
operator
𝒮 = 𝑲
Influence coefficient
(or compliance) matrix
𝑪𝒉𝒉 = 𝒮 −1
Static
Aeroelasticity
-23-
Structural Operators
Example: wing torsion
The wing is modelled as a beam subjected to a torsional distributed load:
Similarly to the bending case, use of the FEM leads to:
𝒎 = 𝑯 𝝑 → 𝝑 = 𝑯−1𝒎 = 𝑪𝜜𝜜𝒎
Deformed
configuration
Undeformed
configuration
Governing equation Structural operator
𝜕
𝜕𝑥
𝐺𝐌(𝑥)
𝜕𝜗 𝑥
𝜕𝑥
= 𝑚(𝑥) 𝒮 =
𝜕
𝜕𝑥
𝐺𝐌(𝑥)
𝜕 ∙
𝜕𝑥
𝑚(𝑥)
𝑥
Moment vector
Nodal rotations
Structural
operator
𝒮 = 𝑯
Matrix of influence coefficients
(compliance matrix)
𝑪𝜜𝜜 = 𝒮 −1
torsional stiffness
Static
Aeroelasticity
-24-
Elastic Equilibrium of the Wing
The elastic behavior of the structure is represented by matrices of influence
coefficients:
Similarly, an aerodynamic operator can be defined as well
Δ𝑊1
Δ𝑊3
Δ𝑊2
Δ𝑊𝑖


A.C.
E.A.
𝑓𝑖
𝑚EA𝑖
𝑒𝑖
1
2
3
i
𝒉 = 𝑪𝒉𝒉
𝒇
𝝑 = 𝑪𝝑𝝑
𝒎𝑬𝑚
Static
Aeroelasticity
-25-
Aerodynamic Operators
Aerodynamic operator: relates deflections (and in turn angles of attack) to
aerodynamic loads
Simple example: single airfoil
Depending on need, it may be more convenient to relate AoA and non-
dimensional aerodynamic coefficients
𝑈 A. C.
𝛌
𝐿
𝑐
𝐿 =
𝜌𝑈2
2
𝑐
𝜕𝐶𝐿
𝜕𝛌
𝛌
Aerodynamic
loads
Angle of attack
Aerodynamic
operator
𝑓 = 𝒜 𝛌
𝑞 𝑎0
𝒜 = 𝑞𝑐𝑎0
Cl alpha
Static
Aeroelasticity
-26-
Example: 2-D strip theory
Assumption: each strip acts
independently from the others
Goal: describe the relationship between
lift distribution and angle of attack
Aerodynamic Operators
𝐿𝑖 = 𝑞∆𝑊𝑖𝑐𝑖𝑎0𝑖
𝛌𝑖
𝐶𝐿𝑖 = 𝑎0𝑖
𝛌𝑖
𝛌1
𝛌2
⋮
𝛌𝑛
=
ൗ
1
𝑎01
ൗ
1
𝑎02
0
0
⋱
ൗ
1
𝑎0𝑛
𝐿1/𝑐1𝑞
𝐿2/𝑐2𝑞
⋮
𝐿𝑛/𝑐𝑛𝑞
∆𝑊𝑖
𝑊
1 2 3 
 𝑖 
 𝑛
𝜶 = 𝓐 −1
𝑪𝐿
Non-dimensional lift
distribution
Angles of
attack
Inverse of the
aerodynamic operator
Static
Aeroelasticity
-27-
Aerodynamic Operators
Example: 3D lifting line theory (Prandtl) for steady incompressible flow
𝛌 𝑊 =
𝐿(𝑊)
𝑎0 𝑊 𝑐 𝑊 𝑞
+
1
8𝜋
න
ൗ
−𝑙
2
ൗ
𝑙
2 d
d𝜂
𝑐 𝑊 𝐶𝐿 𝑊
d𝜂
𝑊 − 𝜂
Approximating the integral with a quadrature rule:
𝛌1
𝛌2
⋮
𝛌𝑛
=
ൗ
1
𝑎01
ൗ
1
𝑎02
0
0
⋱
ൗ
1
𝑎0𝑛
+
1
8𝑙
𝑏11 ⋯ 𝑏1𝑛
⋮ ⋱ ⋮
𝑏𝑛1 ⋯ 𝑏𝑛𝑛
𝐿1/𝑐1𝑞
𝐿2/𝑐2𝑞
⋮
𝐿𝑛/𝑐𝑛𝑞
More sophisticated models can be used to account for compressibility/Mach
number effects
Correction for finite length wing
Strip theory
Correction for
finite length wing
Strip theory
Static
Aeroelasticity
-28-
Inertial Operator
Inertial operator: relates deflections (rotations) to inertial forces (and moments)
𝒇𝑰 = ℐ 𝒒
Simplest possible example: spring-mass system
𝒇𝑰 = 𝑚
𝑑2𝑥
𝑑𝑡2
Inertial forces
(and/or moments)
Elastic deflections
(and/or rotations)
Inertial
operator
𝑥
𝑘
Inertial force
Displacement
Inertial operator
ℐ = 𝑚
𝑑2
∙
𝑑𝑡2
𝑚
Static
Aeroelasticity
-29-
Equilibrium
Dynamic aeroelasticity:
ℐ 𝒒 = 𝒜 𝒒 + 𝒮 𝒒 + 𝒬
Static aeroelasticity:
0 = 𝒜 𝒒 + 𝒮 𝒒 + 𝒬
Vibration problems:
ℐ 𝒒 = 𝒮 𝒒 + 𝒬
Flight mechanics:
ℐ 𝒒 = 𝒜 𝒒 + 𝒬
Inertial forces
Aerodynamic
forces
Structural
forces
External
forces
vgl. collers triangle
Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute
Straight Cantilever Wing
Static
Aeroelasticity
-31-
Straight Cantilever Wing
Consider a straight wing clamped at the root:
∆𝑊𝑖
𝑊
𝑐𝑖
𝑈
E.A.
(Elastic axis)
𝑈
𝛌F
A. C.
E. A.
𝛌
ℎ 𝑊
𝑒
𝐿
𝑀AC
𝛌 = 𝛌B
𝑊 + 𝜗 𝑊
𝛌B
𝑊 = 𝛌F
+ 𝛜 𝑊
Rigid angle
of attack
Elastic
twist
Angle of attack at wing root
(dof to trim the aircraft)
Built-in twist
(to delay tip stall)
Reference plane
through wing root
Deflection of
elastic axis
unterschiedliche cord line
Static
Aeroelasticity
-32-
Loads Acting on the Wing
Goal: look for lift distribution over the wing
The wing is divided into strips of width 𝛥𝑊𝑖
Force and moment acting on strip 𝑖:
𝑓𝑖 = 𝑞𝑐𝑖𝛥𝑊𝑖𝑎0𝛌𝑖
𝑚EA𝑖
= 𝑞𝑐𝑖Δ𝑊𝑖𝑒𝑖𝑎0𝛌𝑖 + 𝑞𝑐𝑖
2
Δ𝑊𝑖𝐶𝑀AC𝑖
𝑞: dynamic pressure
𝑐𝑖: mean chord of the 𝒊-th strip
𝑎0: slope of the lift coefficient
𝐶𝑀AC𝑖
: moment coefficient about the aerodynamic center of the 𝒊-th strip
Δ𝑊1
Δ𝑊3
Δ𝑊2
Δ𝑊𝑖


A.C.
E.A.
𝑓𝑖
𝑚EA𝑖
𝑒𝑖
1
2
3
i
Auf die aerodynamische Achse bezogen
(structural Problem)
local aoa
Static
Aeroelasticity
-33-
Loads Acting on the Wing
Lift coefficient:
𝐶𝐿𝑖 = 𝑎0𝛌 𝑖 = 𝑎0𝛌B
𝑖
+ 𝑎0𝜗 𝑖 =
= 𝐶𝐿𝑖
B
+ 𝐶𝐿𝑖
E
Force and moment for the 𝒊-th strip:
𝑓𝑖 = 𝑞𝛥𝑊𝑖𝑐𝑖 𝐶𝐿𝑖
B
+ 𝐶𝐿𝑖
E
𝑚𝐞𝐎𝑖 = 𝑞Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝐶𝐿𝑖
B
+ 𝐶𝐿𝑖
E
+ 𝑞Δ𝑊𝑖𝑐𝑖
2
𝐶𝑀AC𝑖
Forces and moments for all strips (in vector/matrix notation):
𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄𝐿
B
+ 𝒄𝐿
E
𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄𝐿
B
+ 𝒄𝐿
E
+ 𝑞 diag Δ𝑊𝑖𝑐𝑖
2
𝒄𝑀AC
Rigid
lift coefficient
(known)
Elastic lift
coefficient
(unknown)
𝐜𝑳
(∙)
=
⋮
𝑪𝑳
(∙)
⋮
Static
Aeroelasticity
-34-
Loads Acting on the Wing
The elastic behavior of the structure is represented by matrices of influence
coefficients:
𝒉 = 𝑪ℎℎ
𝒇
𝝑 = 𝑪𝜗𝜗
𝒎EA
Similarly, aerodynamics can be expressed in matrix notation as:
𝜶 = 𝓐−1
𝑪𝑳
where
𝝑 = 𝓐−1
𝑪𝑳
E
𝜶𝐵 = 𝓐−1𝑪𝑳
B
Elastic bending
of the wing
Elastic torsion
of the wing
Static
Aeroelasticity
-35-
Equilibrium

 combining and rearranging the torsional equilibrium 

𝓐−1
− 𝑞𝑬 𝒄𝑳
𝐞
= 𝒕
where
𝒕 = 𝑞𝑬𝓐𝟏𝛌𝑭
+ 𝑞𝑬𝓐𝜷 + 𝑞𝑭𝒄𝑀AC
𝑬 = 𝑪𝜗𝜗
diag 𝛥𝑊𝑖𝑒𝑖𝑐𝑖 , 𝑭 = 𝑪𝜗𝜗
diag 𝛥𝑊𝑖𝑐𝑖
2
, 𝟏 =
1
1
⋮
1
Aerodynamic loads
𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄L
B
+ 𝒄L
E
𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄L
B
+ 𝒄L
E
+
+𝑞 diag Δ𝑊𝑖𝑐𝑖
2
𝒄𝑀AC
Elastic deflections
𝒉 = 𝑪ℎℎ
𝒇
𝝑 = 𝑪𝜗𝜗
𝒎EA
Aerodynamic angles
𝝑 = 𝓐−1
𝒄𝑳
E
𝜶𝐵
= 𝓐−1
𝒄𝑳
B
Moment due to root wing
angle of attack
Moment due to wing
built-in twist
Aerodynamic moment
System of n equations
for the n unknowns 𝑪𝑳
E
Static
Aeroelasticity
-36-
Equilibrium
Given vehicle AoA 𝛌𝑭
, use
𝓐−1 − 𝑞𝑬 𝒄𝑳
𝐞
= 𝒕
and solve for 𝒄𝑳
𝐞
Then compute:
- Load distribution: 𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄L
B
+ 𝒄L
E
- Moment distribution: 𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄L
B
+ 𝒄L
E
+ 𝑞 diag Δ𝑊𝑖𝑐𝑖
2
𝒄𝑀AC
- Elastic deflection: 𝒉 = 𝑪ℎℎ
𝒇
- Elastic twist: 𝝑 = 𝑪𝜗𝜗
𝑚EA
Static
Aeroelasticity
-37-
Divergence Speed
The divergence dynamic pressure 𝑞𝐷 of the wing is found by solving the
following eigenvalue problem:
det 𝓐−1
− 𝑞𝐷𝑬 = 0
If we consider compressibility effects, then 𝓐 = 𝓐 𝑀 = 𝓐 𝑞D
A similar analysis can be made for a free-flying vehicle (instead of a
cantilever wing), by adding the flight mechanics equilibrium equations
The solution yields the vehicle trim (AoA, elevator deflection), together with
the wing deflections
𝑞𝐷
𝑞
|eigs|
Determinante ist Produkt der
Eigenwerte. sobald ein Eigenwert 0 ist
der divergence Druck erreicht
Static
Aeroelasticity
-38-
Typical Results
• The total lift remains the same (to yield equilibrium), but elasticity causes
an outward redistribution of lift, because of increased twist at the wing tip
• Hence, the bending moment at the root is increased
Load 𝐹
Wing span
Elastic wing
Rigid wing
der getrimmte Zustand erfordert ein Gleichgewicht. daher muss FlÀche unter kurven und somit
der gesamt Auftrieb gleich sein
Technische
UniversitÀt
MÃŒnchen
Wind
Energy
Institute
Swept Wing
Static
Aeroelasticity
-40-
𝜗
High aspect ratio wing with elastic axis 𝑊:
Swept Wing
Remark:
• Bending and torsion are
decoupled when referring to 𝒚
but
• Better refer to 𝒚 when
expressing aerodynamic loads
𝑊
𝑈
E.A.
(Elastic axis)
𝑊
𝑥
𝛬
𝑧
𝛬
𝜗, 𝑚EA
𝜗, 𝑚EA
𝜙, 𝑚𝜙
𝑊
ℎ
𝜙
lÀngsstabilitÀt aufgrund
unterschiedlicher
Geschwindigkeiten senkrecht zur
flÃŒgelvorderkante
Static
Aeroelasticity
-41-
Swept Wing
Structural behavior:
Bending behavior: ൞
𝒉 = 𝑪
ℎℎ
𝒇 + 𝑪
ℎ𝜙
𝒎𝜙
𝝓 = 𝑪
𝜙ℎ
𝒇 + 𝑪
𝜙𝜙
𝒎𝜙
Torsional behavior: ቄ𝝑 = 𝑪
𝜃𝜃
𝒎𝜃
Change of reference:
𝒎𝜙 = −sin𝛬 𝒎EA
𝒎𝜗 = cos𝛬 𝒎EA
𝝑 = cos𝛬 𝝑 − sin𝛬 𝝓
Decoupled when referring
to structural axis 𝑊
Static
Aeroelasticity
-42-
Lift Distribution
Vertical displacement of wing sections:
𝒉 = 𝑪
ℎℎ
𝒇 − sin𝛬 𝑪
ℎ𝜙
𝒎EA
Rotation of wing sections:
𝝑 = cos2
𝛬 𝑪
𝜗𝜗
𝒎𝐞𝐎 − sin𝛬 𝑪
𝜙ℎ
𝒇 − 𝑪
𝜙𝜙
sin𝛬 𝒎𝐞𝐎 =
= −sin𝛬 𝑪
𝜙ℎ
𝒇 + cos2
𝛬𝑪
𝜗𝜗
+ sin2
𝛬 𝑪
𝜙𝜙
𝒎𝐞𝐎
and in turn
𝒉 = 𝑪ℎℎ
𝒇 + 𝑪ℎ𝜗
𝒎𝐞𝐎
𝝑 = 𝑪𝜗ℎ
𝒇 + 𝑪𝜗𝜗
𝒎𝐞𝐎
where 𝑪ℎℎ
= 𝑪
ℎℎ
, 𝑪𝜗ℎ
= −sinΛ 𝑪
𝜙ℎ
and 𝑪𝜗𝜗
= cos2
Λ 𝑪
𝜗𝜗
+ sin2
Λ 𝑪
𝜙𝜙
jetzt mit torsion-displacement
coupling da nicht mehr auf elastic axis
bezogen
Static
Aeroelasticity
-43-
Lift Distribution
All developments for the straight wing remain valid and the solution is
formally identical (only a redefinition of 𝑬 is needed)
Equilibrium:
𝓐−1
− 𝑞𝑬 𝒄𝑳
𝐞
= 𝒕
where
𝒕 = 𝑞𝑬𝓐𝟏𝛌𝐹
+ 𝑞𝑬𝓐𝜷 + 𝑞𝑭𝑪𝑎AC
and
𝑬 = 𝑪𝜗𝜗
diag(𝛥𝑊𝑖𝑒𝑖𝑐𝑖) + 𝑪𝜗ℎ
diag(𝛥𝑊𝑖𝑒𝑖𝑐𝑖), 𝑭 = 𝑪𝜗𝜗
diag 𝛥𝑊𝑖𝑐𝑖
2
,
Solve for 𝒄𝑳
𝐞
, then compute complete deflected configuration of the wing
The divergence speed is found by solving the following eigenvalue problem:
det 𝓐−1
− 𝑞𝐷𝑬 = 0
Moment due to wing
root angle of attack
Moment due to wing
built-in twist
Aerodynamic
moment
New term from
lift-torsion coupling
due to sweep
System of n equations
for the n unknowns 𝑪𝑳
E
Static
Aeroelasticity
-44-
Typical Results
• Bending induces a nose-down rotation of the aerodynamic section:
𝑪𝜗ℎ
= −sinΛ 𝑪
𝜙ℎ
• The tip of the wing is easy to bend: the angle of attack decreases at the tip
• The total lift remains the same (to yield equilibrium), but elasticity causes an
inward redistribution of lift
Remark: for forward sweep, the effect is the opposite: bending increases the AOA
Load 𝐹
Wing span
Elastic wing
Rigid wing
Static
Aeroelasticity
-45-
Divergence Speed
Sweep angle, Λ
𝑞𝐷
-30 deg 30 deg
Notice the much lower
divergence dynamic
pressure for swept-
forward wings
Swept-forward Swept-back
self unload durch mehr bending
und dadurch weniger twist
Static
Aeroelasticity
-46-
Divergence Speed
Remark: forward sweeping has interesting possible advantages
• Configuration: better internal layout because of aft wing spar
• Flight mechanics: higher maneuverability (unstable in pitch and yaw); reduced
drag; delayed tip stall (better high AoA behavior), 

X-29 solution to counteract divergence without
excessive weight penalty: “aeroelastic tailoring”
(bend-twist coupling) by the use of anisotropic
composite materials
Similar solutions are used on
wind turbine blades for passive
load alleviation
Grumman X-29 ▌
Angle of composite
fibers
Bending
Resulting twisting
𝑪𝑐𝑜𝑚𝑝
𝜗ℎ < 0
Compression/extension
due to bending
aligned with fibers

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StaticAeroelasticity apuntes, vibraciones

  • 2. Static Aeroelasticity -2- Contents • Divergence of the typical section • Aileron effectiveness and reversal • Operators • Straight and swept cantilever wings: divergence and load redistribution
  • 4. Static Aeroelasticity -4- Divergence Structural deflection under aerodynamic loading that enhances further the aerodynamic loading itself It is a static aeroelastic phenomenon (no presence of inertial or unsteady aerodynamics effects) Typical section (simplest model of blade torsional deformation): Zero lift line Aerodynamic center Elastic axis Structural deformation 𝐟 𝑒𝑐 𝛌𝑟 𝑈 𝜃 𝛌𝑟
  • 5. Static Aeroelasticity -5- Reminder: Resultants on Airfoils Aerodynamic center: • Point about which moment is constant wrt AoA 𝜶 (typically 𝑎𝑚𝑪 < 𝟎) • Close to 𝒄/𝟒 and rather constant for a wide range of AoAs before stall Center of pressure: 𝒙𝑪𝑷 = 𝒙𝑚𝑪 − ΀ 𝑎𝑚𝑪 𝑳, ΀ 𝒙𝑪𝑷 𝒄 = ΀ 𝒙𝑚𝑪 𝒄 − ΀ 𝑪𝑎𝑚𝑪 𝑪𝑳 • Point of application of the aerodynamic pressure field resultant (i.e. pressure field is reduced to a single force vector with null moment) • Changes with lift (i.e. AoA). Pre-stall:𝑪𝑳 = 𝑪𝑳𝜶𝜶 and therefore ൗ 𝒙𝑪𝑷 𝒄 = ൗ 𝒙𝑚𝑪 𝒄 − ΀ 𝑪𝑎𝑚𝑪 𝑪𝑳𝜶𝜶 TE LE AC ≈ c/4 Aerodynamic force resultant (due to pressure and shear) ൗ 𝒙𝑪𝑷 𝒄 𝒂 𝑚𝑪 Non-dimensionalization (forces and moment per unit span): 𝑳 = 𝟏 𝟐 𝝆𝑜𝟐 𝒄𝑪𝑳 𝑫 = 𝟏 𝟐 𝝆𝑜𝟐 𝒄𝑪𝑫 𝑎𝑚𝑪 = 𝟏 𝟐 𝝆𝑜𝟐 𝒄𝟐 𝑪𝑎𝑚𝑪
  • 6. Static Aeroelasticity -6- Reminder: Resultants on Airfoils Re dependence at high a Separation and Stall cD vs. a dependent on Re (source: I.H. Abbott, A.E. von Doenhoff, “Theory of Wing Sections: Including a Summary of Airfoil Data”) 𝑪𝑳 𝒎𝒂𝒙 𝑪𝑫 𝒎𝒊𝒏 Lift coefficient Moment coefficient wrt c/4 point Drag coefficient Moment coefficient wrt AC Example: NACA 2412 Airfoil
  • 7. Static Aeroelasticity -7- tan−𝟏 𝑪𝑳𝜶 𝑪𝑳 = 𝑪𝑳𝜶𝜶 in the pre-stall region, where the flow is attached For inviscid flows over thin airfoils: 𝑪𝑳𝜶 = 𝟐π In general: 𝑪𝑳𝜶 < 𝟐π (depending on airfoil and operating condition) 𝒄𝑳 𝒂𝒈 = 𝒂𝟎 Angle of zero lift 𝒂𝒈 LE TE Geometric angle of attack 𝒄𝑳 𝒂𝒂 Aerodynamic angle of attack 𝒂𝒈 = 𝟎 𝒂𝒂 = 𝟎 Reminder: Resultants on Airfoils 𝑪𝑳 = 𝑪𝑳𝟎 + 𝑪𝑳𝜶𝜶 𝑪𝑳 = 𝑪𝑳𝜶𝜶
  • 8. Static Aeroelasticity -8- Divergence Lift (per unit span): 𝐿 = 𝑞𝑐𝐶𝐿 = 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟 + 𝜃 with 𝑞 = 1 2 𝜌𝑈2 Aerodynamic moment: 𝑀𝐞𝐎 𝐎 = 𝑀𝐎𝐶 + 𝐿𝑒𝑐 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 + 𝑒𝐶𝐿𝛌 𝛌𝑟 + 𝜃 Structural moment: 𝑀𝐞𝐎 𝑆 = 𝐟𝜃 Equilibrium: 𝑀𝐞𝐎 𝐎 = 𝑀𝐞𝐎 𝑆 Structural torsional deflection: 𝜃 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 +𝑒𝐶𝐿𝛌𝛌𝑟 𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌
  • 9. Static Aeroelasticity -9- Divergence Structural torsional deflection: 𝜃 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 +𝑒𝐶𝐿𝛌𝛌𝑟 𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌 Divergence: 𝑒 > 0 𝑞 → 𝑞𝐷 = 𝐟 𝑒𝑐2𝐶𝐿𝛌 𝜃 → ∞ 𝐿 = 1 + 𝑞/𝑞𝐷 1−𝑞/𝑞𝐷 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟 + 𝑞/𝑞𝐷 1−𝑞/𝑞𝐷 𝑞 𝑐 𝑒 𝐶𝑚𝐎𝐶 The divergence speed could be increased by increasing torsional stiffness, but this must be traded against increased weight/cost Divergence dynamic pressure 𝜃 𝑞 𝑞𝐷 𝐿 𝑞 𝑞𝐷 Elastic lift (limited by stall) Rigid lift 𝐿𝑟 = 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟
  • 10. Static Aeroelasticity -10- 𝑜 𝒏 Why Divergence Matters It is a crucial design parameter for ensuring safety and structural integrity Flight envelope in terms of the 𝑜-𝒏 diagram: Structural damage or failure because of divergence or flutter 𝑜𝑵𝑬
  • 12. Static Aeroelasticity -12- Aileron Effectiveness and Reversal • To increase lift, deflect aileron (down) to increase camber • Resulting nose-down moment decreases AoA and hence lift, when wing is torsionally flexible • If lift decrease due to AoA change is larger than lift increase due to increase in camber, then lift decreases instead of increasing (aileron reversal) • Same for aileron up deflection Zero lift line Aerodynamic center Elastic axis Structural deformation 𝛿 𝐟 𝑒𝑐 𝛌𝑟 𝑈 𝜃 𝛌𝑟
  • 13. Static Aeroelasticity -13- Aileron Effectiveness and Reversal Lift (per unit span): 𝐿 = 𝑞𝑐𝐶𝐿 = 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟 + 𝜃 + 𝑞𝑐𝐶𝐿𝛿 𝛿 with 𝑞 = 1 2 𝜌𝑈2 Aerodynamic moment: 𝑀𝐞𝐎 𝐎 = 𝑀𝐎𝐶 + 𝐿𝑒𝑐 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 + 𝐶𝑚𝐎𝐶 𝛿 𝛿 + 𝑒 𝐶𝐿𝛌 𝛌𝑟 + 𝜃 + 𝐶𝐿𝛿 𝛿 Structural moment: 𝑀𝐞𝐎 𝑆 = 𝐟𝜃 Equilibrium: 𝑀𝐞𝐎 𝐎 = 𝑀𝐞𝐎 𝑆 Structural torsional deflection: 𝜃 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 +𝐶𝑚𝐎𝐶 𝛿 𝛿+𝑒 𝐶𝐿𝛌𝛌𝑟+𝐶𝐿𝛿 𝛿 𝐟−𝑞𝑒𝑐2𝐶𝐿𝛌
  • 14. Static Aeroelasticity -14- Aileron Effectiveness and Reversal (assuming 𝐶𝑚𝐎𝐶 = 0 for simplicity) Lift: 𝐿 = 1 + 𝑞𝑐2 𝑒𝐶𝐿𝛌 𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟 + 𝑘 + 𝑞𝑐2 ΀ 𝐶𝑚𝐎𝐶 𝛿 𝐶𝐿𝛌 𝐶𝐿𝛿 𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌 𝑞𝑐𝐶𝐿𝛿 𝛿 Reordering: 𝐿 = 1 + ΀ 𝑞 𝑞𝐷 1 − ΀ 𝑞 𝑞𝐷 𝑞𝑐𝐶𝐿𝛌 𝛌𝑟 + 1 − ΀ 𝑞 𝑞𝑅 1 − ΀ 𝑞 𝑞𝐷 𝑞𝑐𝐶𝐿𝛿 𝛿 with: • Divergence dynamic pressure: 𝑞𝐷 = 𝐟 𝑒𝑐2𝐶𝐿𝛌 where if 𝑒 > 0, 𝑞 → 𝑞𝐷, 𝜃 → ∞ • Reversal dynamic pressure: 𝑞𝑅 = − 𝐟𝐶𝐿𝛿 𝑐2𝐶𝑚𝐎𝐶 𝛿 𝐶𝐿𝛌 (notice: 𝐶𝑚𝐎𝐶 𝛿 < 0) Remark: typically 𝑞𝑅 < 𝑞𝐷 Lift due to elastic effect at null Rigid lift Lift due to aileron deflection
  • 15. Static Aeroelasticity -15- Aileron Effectiveness and Reversal Aileron Effectiveness (𝐎𝐞): 𝐎𝐞 = 𝐿𝛿 𝐿𝛿𝑟 = 1 − ΀ 𝑞 𝑞𝑅 1 − ΀ 𝑞 𝑞𝐷 𝑞𝑐𝐶𝐿𝛿 𝑞𝑐𝐶𝐿𝛿 = 1 − ΀ 𝑞 𝑞𝑅 1 − ΀ 𝑞 𝑞𝐷 Structural torsional deflection: 𝜃 = 𝑞𝑐2 𝐶𝑚𝐎𝐶 + 𝐶𝑚𝐎𝐶 𝛿 𝛿 + 𝑒 𝐶𝐿𝛌 𝛌𝑟 + 𝑒𝐶𝐿𝛿 𝛿 𝐟 − 𝑞𝑒𝑐2𝐶𝐿𝛌 = ΀ 𝑞 𝑞𝐷 1 − ΀ 𝑞 𝑞𝐷 𝛌𝑟 − 𝑞 𝑞𝑅 1 − ΀ 𝑞𝑅 𝑞𝐷 1 − ΀ 𝑞 𝑞𝐷 𝐶𝐿𝛿 𝐶𝐿𝛌 𝛿 >0 (nose up) <0 (nose down) for (reduces AoA) 𝐎𝐞 ΀ 𝑞 𝑞𝐷 1 1 Stick right, roll left (and viceversa)!
  • 16. Static Aeroelasticity -16- Why Aileron Effectiveness Matters Increase torsional stiffness to increase 𝑞𝑅, but significant weight penalty Better solution: high speed ailerons, spoilerons, flaperons Additional benefit: no adverse yaw effect Roll by the use of spoilers ▶ (notice left wing spoiler up, left wing down, positive direct yaw effect)
  • 18. Static Aeroelasticity -18- Structural Operators Structural operator: relates elastic deflections (rotations) to forces (and moments) 𝒇 = 𝒮 𝒒 Simplest possible example: spring-force system 𝑓 = 𝑘 𝑥 Governing equilibrium equation Applied forces (and/or moments) Elastic deflections (and/or rotations) Structural operator 𝑓 𝑥 𝑘 Applied force Displacement Structural operator 𝒮 = 𝑘
  • 19. Static Aeroelasticity -19- Structural Operators Example: wing bending The wing is modeled as a beam subjected to a distributed load: • Depending on the technique used to model the structure, the operator can be differential, integral or a matrix • For real life problems, numerical methods are typically necessary and the matrix approach is often the most effective (see FEM) 𝑓(𝑥) Deformed configuration Undeformed configuration Governing equation Structural operator 𝜕2 𝜕𝑥2 𝐞𝐌(𝑥) 𝜕2𝑀 𝑥 𝜕𝑥2 = 𝑓(𝑥) 𝒮 = 𝜕2 𝜕𝑥2 𝐞𝐌(𝑥) 𝜕2 ∙ 𝜕𝑥2 𝑥 𝑀 nur von einer variable abhÀngig (x) = ordinary equation
  • 20. Static Aeroelasticity -20- Structural Operators Finite Element Method (FEM) Governing equation in “weak form” (multiply both sides by arbitrary test function 𝑣(𝑥), then integrate over the span of the beam): න 𝑣𝑇 𝜕2 𝜕𝑥2 𝐞𝐌(𝑥) 𝜕2 𝑀 𝑥 𝜕𝑥2 d𝑥 = න 𝑣𝑇 𝑓 𝑥 d𝑥 , ∀ 𝑣(𝑥) Integrate by parts (twice) the left hand side: න 𝜕2 𝑣(𝑥) 𝜕𝑥2 𝑇 𝐞𝐌(𝑥) 𝜕2 𝑀 𝑥 𝜕𝑥2 d𝑥 = න 𝑣𝑇 𝑓 𝑥 d𝑥 , ∀ 𝑣(𝑥) Boundary conditions: ቚ 𝑣 𝑥=0 = 0 (null displacement) àž­ 𝜕2 𝑀 𝜕𝑥2 𝑥=𝐿 = 0 (null bending moment) ቀ 𝜕𝑣 𝜕𝑥 𝑥=0 = 0 (null slope) àž­ 𝜕3 𝑀 𝜕𝑥3 𝑥=𝐿 = 0 (null shear force)
  • 21. Static Aeroelasticity -21- Structural Operators The beam is represented as a collection of finite elements: On each element, the elastic displacements and the test functions are approximated using suitable shape functions: element 1 element 2 
 element i 
 Elemental DoFs: nodal displacements and rotations 𝑣 𝑥 = 𝑵𝑇 𝑥 𝒒e 𝑀 𝑥 = 𝑵𝑇 𝑥 𝒉e Nodal DoFs of test function Nodal DoFs of elastic displacement field 𝑵 𝑥 = 𝑢1 𝑟1 𝑢2 𝑟2 𝑢1 = 1 𝑟1 = 𝑢2 = 𝑟2 = 0 𝑟1 = 1 𝑢1 = 𝑢2 = 𝑟2 = 0 𝑢2 = 1 𝑢1 = 𝑟1 = 𝑟2 = 0 𝑟2 = 1 𝑟1 = 𝑢2 = 𝑢2 = 0
  • 22. Static Aeroelasticity -22- Structural Operators Insert interpolating approximations into weak form: 𝒒𝑇 න 𝜕2 𝑵(𝑥) 𝜕𝑥2 𝐞𝐌(𝑥) 𝜕2 𝑵 𝜕𝑥2 𝑇 d𝑥 𝒉e = 𝒒𝑇 න 𝑵 𝑥 𝑓 𝑥 d𝑥 , ∀ 𝒒 Due to arbitrarity of 𝒒, the local equilibrium 𝑲e𝒉e = 𝒇e holds true for each element Global equilibrium is obtained by assembling the contributions over all elements: 𝒇 = 𝑲 𝒉 → 𝒉 = 𝑲−1 𝒇 = 𝑪𝒉𝒉 𝒇 Element stiffness matrix 𝑲e Element load vector 𝒇e Load vector Nodal displacements and rotations Structural operator 𝒮 = 𝑲 Influence coefficient (or compliance) matrix 𝑪𝒉𝒉 = 𝒮 −1
  • 23. Static Aeroelasticity -23- Structural Operators Example: wing torsion The wing is modelled as a beam subjected to a torsional distributed load: Similarly to the bending case, use of the FEM leads to: 𝒎 = 𝑯 𝝑 → 𝝑 = 𝑯−1𝒎 = 𝑪𝜜𝜜𝒎 Deformed configuration Undeformed configuration Governing equation Structural operator 𝜕 𝜕𝑥 𝐺𝐌(𝑥) 𝜕𝜗 𝑥 𝜕𝑥 = 𝑚(𝑥) 𝒮 = 𝜕 𝜕𝑥 𝐺𝐌(𝑥) 𝜕 ∙ 𝜕𝑥 𝑚(𝑥) 𝑥 Moment vector Nodal rotations Structural operator 𝒮 = 𝑯 Matrix of influence coefficients (compliance matrix) 𝑪𝜜𝜜 = 𝒮 −1 torsional stiffness
  • 24. Static Aeroelasticity -24- Elastic Equilibrium of the Wing The elastic behavior of the structure is represented by matrices of influence coefficients: Similarly, an aerodynamic operator can be defined as well Δ𝑊1 Δ𝑊3 Δ𝑊2 Δ𝑊𝑖 
 A.C. E.A. 𝑓𝑖 𝑚EA𝑖 𝑒𝑖 1 2 3 i 𝒉 = 𝑪𝒉𝒉 𝒇 𝝑 = 𝑪𝝑𝝑 𝒎𝑬𝑚
  • 25. Static Aeroelasticity -25- Aerodynamic Operators Aerodynamic operator: relates deflections (and in turn angles of attack) to aerodynamic loads Simple example: single airfoil Depending on need, it may be more convenient to relate AoA and non- dimensional aerodynamic coefficients 𝑈 A. C. 𝛌 𝐿 𝑐 𝐿 = 𝜌𝑈2 2 𝑐 𝜕𝐶𝐿 𝜕𝛌 𝛌 Aerodynamic loads Angle of attack Aerodynamic operator 𝑓 = 𝒜 𝛌 𝑞 𝑎0 𝒜 = 𝑞𝑐𝑎0 Cl alpha
  • 26. Static Aeroelasticity -26- Example: 2-D strip theory Assumption: each strip acts independently from the others Goal: describe the relationship between lift distribution and angle of attack Aerodynamic Operators 𝐿𝑖 = 𝑞∆𝑊𝑖𝑐𝑖𝑎0𝑖 𝛌𝑖 𝐶𝐿𝑖 = 𝑎0𝑖 𝛌𝑖 𝛌1 𝛌2 ⋮ 𝛌𝑛 = ൗ 1 𝑎01 ൗ 1 𝑎02 0 0 ⋱ ൗ 1 𝑎0𝑛 𝐿1/𝑐1𝑞 𝐿2/𝑐2𝑞 ⋮ 𝐿𝑛/𝑐𝑛𝑞 ∆𝑊𝑖 𝑊 1 2 3 
 𝑖 
 𝑛 𝜶 = 𝓐 −1 𝑪𝐿 Non-dimensional lift distribution Angles of attack Inverse of the aerodynamic operator
  • 27. Static Aeroelasticity -27- Aerodynamic Operators Example: 3D lifting line theory (Prandtl) for steady incompressible flow 𝛌 𝑊 = 𝐿(𝑊) 𝑎0 𝑊 𝑐 𝑊 𝑞 + 1 8𝜋 න ൗ −𝑙 2 ൗ 𝑙 2 d d𝜂 𝑐 𝑊 𝐶𝐿 𝑊 d𝜂 𝑊 − 𝜂 Approximating the integral with a quadrature rule: 𝛌1 𝛌2 ⋮ 𝛌𝑛 = ൗ 1 𝑎01 ൗ 1 𝑎02 0 0 ⋱ ൗ 1 𝑎0𝑛 + 1 8𝑙 𝑏11 ⋯ 𝑏1𝑛 ⋮ ⋱ ⋮ 𝑏𝑛1 ⋯ 𝑏𝑛𝑛 𝐿1/𝑐1𝑞 𝐿2/𝑐2𝑞 ⋮ 𝐿𝑛/𝑐𝑛𝑞 More sophisticated models can be used to account for compressibility/Mach number effects Correction for finite length wing Strip theory Correction for finite length wing Strip theory
  • 28. Static Aeroelasticity -28- Inertial Operator Inertial operator: relates deflections (rotations) to inertial forces (and moments) 𝒇𝑰 = ℐ 𝒒 Simplest possible example: spring-mass system 𝒇𝑰 = 𝑚 𝑑2𝑥 𝑑𝑡2 Inertial forces (and/or moments) Elastic deflections (and/or rotations) Inertial operator 𝑥 𝑘 Inertial force Displacement Inertial operator ℐ = 𝑚 𝑑2 ∙ 𝑑𝑡2 𝑚
  • 29. Static Aeroelasticity -29- Equilibrium Dynamic aeroelasticity: ℐ 𝒒 = 𝒜 𝒒 + 𝒮 𝒒 + 𝒬 Static aeroelasticity: 0 = 𝒜 𝒒 + 𝒮 𝒒 + 𝒬 Vibration problems: ℐ 𝒒 = 𝒮 𝒒 + 𝒬 Flight mechanics: ℐ 𝒒 = 𝒜 𝒒 + 𝒬 Inertial forces Aerodynamic forces Structural forces External forces vgl. collers triangle
  • 31. Static Aeroelasticity -31- Straight Cantilever Wing Consider a straight wing clamped at the root: ∆𝑊𝑖 𝑊 𝑐𝑖 𝑈 E.A. (Elastic axis) 𝑈 𝛌F A. C. E. A. 𝛌 ℎ 𝑊 𝑒 𝐿 𝑀AC 𝛌 = 𝛌B 𝑊 + 𝜗 𝑊 𝛌B 𝑊 = 𝛌F + 𝛜 𝑊 Rigid angle of attack Elastic twist Angle of attack at wing root (dof to trim the aircraft) Built-in twist (to delay tip stall) Reference plane through wing root Deflection of elastic axis unterschiedliche cord line
  • 32. Static Aeroelasticity -32- Loads Acting on the Wing Goal: look for lift distribution over the wing The wing is divided into strips of width 𝛥𝑊𝑖 Force and moment acting on strip 𝑖: 𝑓𝑖 = 𝑞𝑐𝑖𝛥𝑊𝑖𝑎0𝛌𝑖 𝑚EA𝑖 = 𝑞𝑐𝑖Δ𝑊𝑖𝑒𝑖𝑎0𝛌𝑖 + 𝑞𝑐𝑖 2 Δ𝑊𝑖𝐶𝑀AC𝑖 𝑞: dynamic pressure 𝑐𝑖: mean chord of the 𝒊-th strip 𝑎0: slope of the lift coefficient 𝐶𝑀AC𝑖 : moment coefficient about the aerodynamic center of the 𝒊-th strip Δ𝑊1 Δ𝑊3 Δ𝑊2 Δ𝑊𝑖 
 A.C. E.A. 𝑓𝑖 𝑚EA𝑖 𝑒𝑖 1 2 3 i Auf die aerodynamische Achse bezogen (structural Problem) local aoa
  • 33. Static Aeroelasticity -33- Loads Acting on the Wing Lift coefficient: 𝐶𝐿𝑖 = 𝑎0𝛌 𝑖 = 𝑎0𝛌B 𝑖 + 𝑎0𝜗 𝑖 = = 𝐶𝐿𝑖 B + 𝐶𝐿𝑖 E Force and moment for the 𝒊-th strip: 𝑓𝑖 = 𝑞𝛥𝑊𝑖𝑐𝑖 𝐶𝐿𝑖 B + 𝐶𝐿𝑖 E 𝑚𝐞𝐎𝑖 = 𝑞Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝐶𝐿𝑖 B + 𝐶𝐿𝑖 E + 𝑞Δ𝑊𝑖𝑐𝑖 2 𝐶𝑀AC𝑖 Forces and moments for all strips (in vector/matrix notation): 𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄𝐿 B + 𝒄𝐿 E 𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄𝐿 B + 𝒄𝐿 E + 𝑞 diag Δ𝑊𝑖𝑐𝑖 2 𝒄𝑀AC Rigid lift coefficient (known) Elastic lift coefficient (unknown) 𝐜𝑳 (∙) = ⋮ 𝑪𝑳 (∙) ⋮
  • 34. Static Aeroelasticity -34- Loads Acting on the Wing The elastic behavior of the structure is represented by matrices of influence coefficients: 𝒉 = 𝑪ℎℎ 𝒇 𝝑 = 𝑪𝜗𝜗 𝒎EA Similarly, aerodynamics can be expressed in matrix notation as: 𝜶 = 𝓐−1 𝑪𝑳 where 𝝑 = 𝓐−1 𝑪𝑳 E 𝜶𝐵 = 𝓐−1𝑪𝑳 B Elastic bending of the wing Elastic torsion of the wing
  • 35. Static Aeroelasticity -35- Equilibrium 
 combining and rearranging the torsional equilibrium 
 𝓐−1 − 𝑞𝑬 𝒄𝑳 𝐞 = 𝒕 where 𝒕 = 𝑞𝑬𝓐𝟏𝛌𝑭 + 𝑞𝑬𝓐𝜷 + 𝑞𝑭𝒄𝑀AC 𝑬 = 𝑪𝜗𝜗 diag 𝛥𝑊𝑖𝑒𝑖𝑐𝑖 , 𝑭 = 𝑪𝜗𝜗 diag 𝛥𝑊𝑖𝑐𝑖 2 , 𝟏 = 1 1 ⋮ 1 Aerodynamic loads 𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄L B + 𝒄L E 𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄L B + 𝒄L E + +𝑞 diag Δ𝑊𝑖𝑐𝑖 2 𝒄𝑀AC Elastic deflections 𝒉 = 𝑪ℎℎ 𝒇 𝝑 = 𝑪𝜗𝜗 𝒎EA Aerodynamic angles 𝝑 = 𝓐−1 𝒄𝑳 E 𝜶𝐵 = 𝓐−1 𝒄𝑳 B Moment due to root wing angle of attack Moment due to wing built-in twist Aerodynamic moment System of n equations for the n unknowns 𝑪𝑳 E
  • 36. Static Aeroelasticity -36- Equilibrium Given vehicle AoA 𝛌𝑭 , use 𝓐−1 − 𝑞𝑬 𝒄𝑳 𝐞 = 𝒕 and solve for 𝒄𝑳 𝐞 Then compute: - Load distribution: 𝒇 = 𝑞 diag Δ𝑊𝑖𝑐𝑖 𝒄L B + 𝒄L E - Moment distribution: 𝒎EA = 𝑞 diag Δ𝑊𝑖𝑒𝑖𝑐𝑖 𝒄L B + 𝒄L E + 𝑞 diag Δ𝑊𝑖𝑐𝑖 2 𝒄𝑀AC - Elastic deflection: 𝒉 = 𝑪ℎℎ 𝒇 - Elastic twist: 𝝑 = 𝑪𝜗𝜗 𝑚EA
  • 37. Static Aeroelasticity -37- Divergence Speed The divergence dynamic pressure 𝑞𝐷 of the wing is found by solving the following eigenvalue problem: det 𝓐−1 − 𝑞𝐷𝑬 = 0 If we consider compressibility effects, then 𝓐 = 𝓐 𝑀 = 𝓐 𝑞D A similar analysis can be made for a free-flying vehicle (instead of a cantilever wing), by adding the flight mechanics equilibrium equations The solution yields the vehicle trim (AoA, elevator deflection), together with the wing deflections 𝑞𝐷 𝑞 |eigs| Determinante ist Produkt der Eigenwerte. sobald ein Eigenwert 0 ist der divergence Druck erreicht
  • 38. Static Aeroelasticity -38- Typical Results • The total lift remains the same (to yield equilibrium), but elasticity causes an outward redistribution of lift, because of increased twist at the wing tip • Hence, the bending moment at the root is increased Load 𝐹 Wing span Elastic wing Rigid wing der getrimmte Zustand erfordert ein Gleichgewicht. daher muss FlÀche unter kurven und somit der gesamt Auftrieb gleich sein
  • 40. Static Aeroelasticity -40- 𝜗 High aspect ratio wing with elastic axis 𝑊: Swept Wing Remark: • Bending and torsion are decoupled when referring to 𝒚 but • Better refer to 𝒚 when expressing aerodynamic loads 𝑊 𝑈 E.A. (Elastic axis) 𝑊 𝑥 𝛬 𝑧 𝛬 𝜗, 𝑚EA 𝜗, 𝑚EA 𝜙, 𝑚𝜙 𝑊 ℎ 𝜙 lÀngsstabilitÀt aufgrund unterschiedlicher Geschwindigkeiten senkrecht zur flÃŒgelvorderkante
  • 41. Static Aeroelasticity -41- Swept Wing Structural behavior: Bending behavior: ൞ 𝒉 = 𝑪 ℎℎ 𝒇 + 𝑪 ℎ𝜙 𝒎𝜙 𝝓 = 𝑪 𝜙ℎ 𝒇 + 𝑪 𝜙𝜙 𝒎𝜙 Torsional behavior: ቄ𝝑 = 𝑪 𝜃𝜃 𝒎𝜃 Change of reference: 𝒎𝜙 = −sin𝛬 𝒎EA 𝒎𝜗 = cos𝛬 𝒎EA 𝝑 = cos𝛬 𝝑 − sin𝛬 𝝓 Decoupled when referring to structural axis 𝑊
  • 42. Static Aeroelasticity -42- Lift Distribution Vertical displacement of wing sections: 𝒉 = 𝑪 ℎℎ 𝒇 − sin𝛬 𝑪 ℎ𝜙 𝒎EA Rotation of wing sections: 𝝑 = cos2 𝛬 𝑪 𝜗𝜗 𝒎𝐞𝐎 − sin𝛬 𝑪 𝜙ℎ 𝒇 − 𝑪 𝜙𝜙 sin𝛬 𝒎𝐞𝐎 = = −sin𝛬 𝑪 𝜙ℎ 𝒇 + cos2 𝛬𝑪 𝜗𝜗 + sin2 𝛬 𝑪 𝜙𝜙 𝒎𝐞𝐎 and in turn 𝒉 = 𝑪ℎℎ 𝒇 + 𝑪ℎ𝜗 𝒎𝐞𝐎 𝝑 = 𝑪𝜗ℎ 𝒇 + 𝑪𝜗𝜗 𝒎𝐞𝐎 where 𝑪ℎℎ = 𝑪 ℎℎ , 𝑪𝜗ℎ = −sinΛ 𝑪 𝜙ℎ and 𝑪𝜗𝜗 = cos2 Λ 𝑪 𝜗𝜗 + sin2 Λ 𝑪 𝜙𝜙 jetzt mit torsion-displacement coupling da nicht mehr auf elastic axis bezogen
  • 43. Static Aeroelasticity -43- Lift Distribution All developments for the straight wing remain valid and the solution is formally identical (only a redefinition of 𝑬 is needed) Equilibrium: 𝓐−1 − 𝑞𝑬 𝒄𝑳 𝐞 = 𝒕 where 𝒕 = 𝑞𝑬𝓐𝟏𝛌𝐹 + 𝑞𝑬𝓐𝜷 + 𝑞𝑭𝑪𝑎AC and 𝑬 = 𝑪𝜗𝜗 diag(𝛥𝑊𝑖𝑒𝑖𝑐𝑖) + 𝑪𝜗ℎ diag(𝛥𝑊𝑖𝑒𝑖𝑐𝑖), 𝑭 = 𝑪𝜗𝜗 diag 𝛥𝑊𝑖𝑐𝑖 2 , Solve for 𝒄𝑳 𝐞 , then compute complete deflected configuration of the wing The divergence speed is found by solving the following eigenvalue problem: det 𝓐−1 − 𝑞𝐷𝑬 = 0 Moment due to wing root angle of attack Moment due to wing built-in twist Aerodynamic moment New term from lift-torsion coupling due to sweep System of n equations for the n unknowns 𝑪𝑳 E
  • 44. Static Aeroelasticity -44- Typical Results • Bending induces a nose-down rotation of the aerodynamic section: 𝑪𝜗ℎ = −sinΛ 𝑪 𝜙ℎ • The tip of the wing is easy to bend: the angle of attack decreases at the tip • The total lift remains the same (to yield equilibrium), but elasticity causes an inward redistribution of lift Remark: for forward sweep, the effect is the opposite: bending increases the AOA Load 𝐹 Wing span Elastic wing Rigid wing
  • 45. Static Aeroelasticity -45- Divergence Speed Sweep angle, Λ 𝑞𝐷 -30 deg 30 deg Notice the much lower divergence dynamic pressure for swept- forward wings Swept-forward Swept-back self unload durch mehr bending und dadurch weniger twist
  • 46. Static Aeroelasticity -46- Divergence Speed Remark: forward sweeping has interesting possible advantages • Configuration: better internal layout because of aft wing spar • Flight mechanics: higher maneuverability (unstable in pitch and yaw); reduced drag; delayed tip stall (better high AoA behavior), 
 X-29 solution to counteract divergence without excessive weight penalty: “aeroelastic tailoring” (bend-twist coupling) by the use of anisotropic composite materials Similar solutions are used on wind turbine blades for passive load alleviation Grumman X-29 â–Œ Angle of composite fibers Bending Resulting twisting 𝑪𝑐𝑜𝑚𝑝 𝜗ℎ < 0 Compression/extension due to bending aligned with fibers