The document contains 5 word problems involving simple equations about ages, costs, and numbers. Each problem is solved with 1-3 steps of algebraic equations. The answers are: 1) 8, 2) 18, 3) 32, 4) 12.5, 5) 18.

1. SIMPLE EQUATIONS LEVEL 2
C.S.VEERARAGAVAN

2. Numbers
Twice a number is 12 more than half the number.
What is the number?
1) 7 2) 6 3) 8 4) 9
2x = 12 +
x
2
4x = 24 + x
3x = 24
X = 8
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3. Ages
Three years ago, Anurag’s age was thrice that of
Bhragav.
Two years hence Anurag’s age will be twice that of
Bharagav.
What is the present age of Anurag?
1) 16 2) 18 3) 20 4) 22
x – 3 = 3(y – 3) (1)
(x + 2 ) = 2(y + 2) (2)
x – 3y = – 6
x – 2y = 2
Hence – y = – 8  y = 8.
X = 18.
II
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4. Ages
Goutam is four times as old as Girija.
Four years hence, the age of Goutam will be thrice
that of Girija.
What is the present age of Goutam?
1) 20 2) 24 3) 28 4) 32
x = 4y (1)
x + 4 = 3 ( y + 4) (2)
Using (1) in (2)
4y + 4 = 3y + 12
Y = 8
Hence x = 32
III
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5. ALGEBRA
2 Pencils and 3 pens cost Rs.8
2 Pens and 3 pencils cost Rs.7
What is the cost of 5 pencils and 5 pens?
1) 15 2) 12.50 3) 17.50 4) 20
2x + 3y = 8
3x + 2y = 7
Hence 5x + 5y = 15.
IV
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6. AGES
Rajani’s age is 9 years more than half of her age.
What is Rajani’s age?
1) 18 2) 20 3) 22 4) 24
x = 9 +
x
2
2x = 18 + x
x = 18.
V
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