SURDS & INDICES
If 32x = 81, what is the value of x?
1
2
3
4
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34 = 81.
2x = 4
X = 2.
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If 32x = 81, what is the value of x?
5 + 2
– 5 + 2
Either 1 or 2
None of these.
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What is the conjugate of 5–2?
1. 5 + 2
2. – 5 + 2
3. Either 1 or 2
4. None of these.
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Conjugate is – 5 – 2
2 – 2
2 – 3
3 – 2
2 – 2 2
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1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
= 3 − 2
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
= 3 − 2
1
2 + 3
𝑋
2 − 3
2 − 3
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
= 3 − 2
1
2 + 3
𝑋
2 − 3
2 − 3
=
2 − 3
4 − 3
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
= 3 − 2
1
2 + 3
𝑋
2 − 3
2 − 3
=
2 − 3
4 − 3
=2− 3
1
3+ 2
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=
1
3+ 2
x
3− 2
3− 2
=
3− 2
3−2
= 3 − 2
1
2 + 3
𝑋
2 − 3
2 − 3
=
2 − 3
4 − 3
=2− 3
Adding we get 2 – 2
What is the positive square root of 48 − 27?
3
1
2
3
1
8
3
1
4
None of these
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48 − 27 = 16(3) − 9(3)
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48 − 27 = 16(3) − 9(3)
4 3 − 3 3
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48 − 27 = 16(3) − 9(3)
4 3 − 3 3
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3
What is the positive square root of 7 + 4 3
3+1
2 + 2 3
2 + 3
2 + 3
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What is the positive square root of 7 + 4 3
3+1
2 + 2 3
2 + 3
2 + 3
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7 + 4 3 = 7 + 2 3(4)
What is the positive square root of 7 + 4 3
3+1
2 + 2 3
2 + 3
2 + 3
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7 + 4 3 = 7 + 2 3(4)
3 + 4 + 2 3(4) = 3 + 4
2
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
72 − 40
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
72 − 40
36(2) − 20(2)
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
72 − 40
36(2) − 20(2)
2 36 − 20
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
72 − 40
36(2) − 20(2)
2 36 − 20
2 6 − 2 5
What is the positive square root of 72 − 40
2 5−1
4
2 5−1
4
2 3 − 2
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4
2 5 − 3
72 − 40
36(2) − 20(2)
2 36 − 20
2 6 − 2 5
2 5 + 1 − 2 5
5
3
2
3−6
1
3+2
2
3
=
31 3
+ 21 3
31 3
− 21 3
21 3
− 31 3
32 3
+ 22 3
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5
3
2
3−6
1
3+2
2
3
=
31 3
+ 21 3
31 3
− 21 3
21 3
− 31 3
32 3
+ 22 3
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5
3
2
3−6
1
3+2
2
3
5
3
1
3
2
−(2)
1
3(3)
1
3+ 2
1
3
2
5
3
2
3−6
1
3+2
2
3
=
31 3
+ 21 3
31 3
− 21 3
21 3
− 31 3
32 3
+ 22 3
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5
3
2
3−6
1
3+2
2
3
5
3
1
3
2
−(2)
1
3(3)
1
3+ 2
1
3
2
5
3
1
3
2
−(2)
1
3(3)
1
3+ 2
1
3
2 𝑥
3
1
3+2
1
3
3
1
3+2
1
3
5
3
2
3−6
1
3+2
2
3
=
32 3
+ 21 3
31 3
− 21 3
21 3
− 31 3
32 3
+ 22 3
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5
3
2
3−6
1
3+2
2
3
5
3
1
3
2
−(2)
1
3(3)
1
3+ 2
1
3
2
5
3
1
3
2
−(2)
1
3(3)
1
3+ 2
1
3
2 𝑥
3
1
3+2
1
3
3
1
3+2
1
3
5 3
1
3+2
1
3
3+2
What is the rationalizing factor of 41 3
− 31 3
4
2
3 + 12 + 3
2
3
4
2
3 − 12 + 3
2
3
4
2
3 + 12
1
3 + 3
2
3
4
4
3 + 12
2
3 + 3
4
3
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What is the rationalizing factor of 41 3
− 31 3
4
2
3 + 12 + 3
2
3
4
2
3 − 12 + 3
2
3
4
2
3 + 12
1
3 + 3
2
3
4
4
3 + 12
2
3 + 3
4
3
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41 3
− 31 3
is of the form a – b
What is the rationalizing factor of 41 3
− 31 3
4
2
3 + 12 + 3
2
3
4
2
3 − 12 + 3
2
3
4
2
3 + 12
1
3 + 3
2
3
4
4
3 + 12
2
3 + 3
4
3
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41 3
− 31 3
is of the form a – b
a2+ab+ b2 should be multiplied
to get a3−b3
4
2
3 + 4
1
33
1
3 + 3
2
3
Simplify: x
a
a+b+c.x
b
a+b+c. x
c
a+b+c
1
x
0
xabc
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Which is greater?
1
8+ 5
,
1
2+ 5
1
8 + 5
1
2 + 5
Cannot be determined
None of these.
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Which is greater?
1
8+ 5
,
1
5+ 2
1
8+ 5
1
5+ 2
Cannot be determined
None of these.
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8 > 5
Which is greater?
1
8+ 5
,
1
5+ 2
1
8+ 5
1
5+ 2
Cannot be determined
None of these.
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8 > 5 5 > 2
Which is greater?
1
8+ 5
,
1
5+ 2
1
8+ 5
1
5+ 2
Cannot be determined
None of these.
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8 > 5 5 > 2
8 + 5 > 5 + 2
Which is greater? 222
, 322
222
322
Cannot be determined
Both are equal
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–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5 3(2) + 3 5
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5 3(2) + 3 5
3(2 + 5)
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5 3(2) + 3 5
3(2 + 5)
5 − 2 is the factor req.
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5 3(2) + 3 5
3(2 + 5)
5 − 2 is the factor req.
–6 – 3 5
5 − 2
– 5 − 2
None of these
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What is the rationalizing factor of 6 + 3 5
6 + 3 5 3(2) + 3 5
3(2 + 5)
5 − 2 is the factor req.
What is the value of x if 2 𝑥 𝑥
= 16
0
1
3
2
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If 2 𝑥
3 𝑦
= 216 and x and y are integers then x,y?
3,2
2,2
3,4
3,3
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If 3
1
23
3
23
5
23
7
2 = 9 𝑥
, what is the value of x?
4
3
2
1
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(17)3.5 x (17)? = 178
2.29
2.75
4.25
4.5
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If
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
,then the value of x is
2
1
1
2
7
2
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If
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
,then the value of x is
2
1
1
2
7
2
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𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
𝑎
𝑏
𝑥−1
=
𝑎
𝑏
−(𝑥−3)
If
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
,then the value of x is
2
1
1
2
7
2
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𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
𝑎
𝑏
𝑥−1
=
𝑎
𝑏
−(𝑥−3)
x – 1 = 3 – x
Solving x = 2
Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
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Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
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xz = y2
100.48z = 102*0.7
Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
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xz = y2
100.48z = 102*0.7
0.48z = 1.4
Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
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xz = y2
100.48z = 102*0.7
0.48z = 1.4
Z =
140
48
=
35
12
≈ 2.9
If 5a = 3125, then the value of 5a – 3 is?
25
125
625
1625
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If 3x – y = 27 and 3x + y = 243, then x =?
0
2
4
6
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If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
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3x – y = 27 = 33
3x + y = 243 = 35
If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
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3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
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3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
x + y = 5
If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
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3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
x + y = 5
Solving x = 4
2560.16 x 2560.09 = ?
4
16
64
256.25
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2560.16 x 2560.09 = ?
4
16
64
256.25
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2560.16 x 2560.09 = 2560.25
2560.16 x 2560.09 = ?
4
16
64
256.25
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2560.16 x 2560.09 = 2560.25
256 = 44
1
1+x b−a +x c−a
+
1
1+x a−b +x c−b
+
1
1+x b−c +x a−c
= ?
0
1
Xa – b – c
None of these
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1
1+x b−a +x c−a
+
1
1+x a−b +x c−b
+
1
1+x b−c +x a−c
= ?
0
1
Xa – b – c
None of these
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1
1+
xb
xa +
xc
xa
+
1
1+
xa
xb
+
xc
xb
+
1
1+
xb
xc +
xa
xc
1
1+x b−a +x c−a
+
1
1+x a−b +x c−b
+
1
1+x b−c +x a−c
= ?
0
1
Xa – b – c
None of these
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1
1+
xb
xa +
xc
xa
+
1
1+
xa
xb
+
xc
xb
+
1
1+
xb
xc +
xa
xc
xa
xa+xb+xc
+
xb
xa+xb+xc
+
xc
xa+xb+xc
257.5 x 52.5 ÷1251.5 = 5?
8.5
13
16
17.5
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243
n
5 X 32n+1
9nX3n−1
1
2
9
3n
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243
n
5 X 32n+1
9nX3n−1
1
2
9
3n
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35
n
5 X32n+1
32 n
X 3n−1
243
n
5 X 32n+1
9nX3n−1
1
2
9
3n
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35
n
5 X32n+1
32 n
X 3n−1
=
3 𝑛+2𝑛+1
32𝑛+𝑛−1
243
n
5 X 32n+1
9nX3n−1
1
2
9
3n
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35
n
5 X32n+1
32
n
X 3n−1
=
3n+2n+1
32n+n−1 = 33n + 1 – 3n + 1
1
1+a n−m +
1
1+a m−n = ?
0
1
2
1
am+n
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1
1+a n−m +
1
1+a m−n = ?
0
1
2
1
am+n
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1
1+an
am
+
1
1+am
an
=
1
1+a n−m +
1
1+a m−n = ?
0
1
2
1
am+n
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1
1+an
am
+
1
1+am
an
=
𝑎 𝑚
𝑎 𝑚+𝑎 𝑛 +
𝑎 𝑛
𝑎 𝑚+𝑎 𝑛
If mn = 121, the value of (m – 1)n+1 is
1
10
121
1000
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xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
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xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
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xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
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xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 88
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
= x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c)
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 89
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
= x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c)
=𝑥 𝑏2−𝑐2+𝑐2−𝑎2+𝑎2−𝑏2
∗ 𝑥 𝑏𝑎−𝑐𝑎+𝑏𝑐−𝑎𝑏+𝑎𝑐−𝑏𝑐
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 90
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 91
X = 3 + 2 2
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 92
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 93
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2
= 3 + 2 2 +
1
3 + 2 2
− 2
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 94
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2
= 3 + 2 2 +
1
3 + 2 2
− 2
= 3 + 2 2 +
1
3 + 2 2
𝑥
3 − 2 2
3 − 2 2
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 95
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2
= 3 + 2 2 +
1
3 + 2 2
− 2
= 3 + 2 2 +
1
3 + 2 2
𝑥
3 − 2 2
3 − 2 2
= 3 + 2 2 + (3 - 2 2) − 2
If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 96
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2
= 3 + 2 2 +
1
3 + 2 2
− 2
= 3 + 2 2 +
1
3 + 2 2
𝑥
3 − 2 2
3 − 2 2
= 3 + 2 2 + (3 - 2 2) − 2
= 4

Number system 1surds & indices

  • 1.
  • 2.
    If 32x =81, what is the value of x? 1 2 3 4 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 2
  • 3.
    34 = 81. 2x= 4 X = 2. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 3 If 32x = 81, what is the value of x?
  • 4.
    5 + 2 –5 + 2 Either 1 or 2 None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 4 What is the conjugate of 5–2?
  • 5.
    1. 5 +2 2. – 5 + 2 3. Either 1 or 2 4. None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 5 Conjugate is – 5 – 2
  • 6.
    2 – 2 2– 3 3 – 2 2 – 2 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 6
  • 7.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 7 = 1 3+ 2 x 3− 2 3− 2
  • 8.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 8 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2
  • 9.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 9 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2 = 3 − 2
  • 10.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 10 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2 = 3 − 2 1 2 + 3 𝑋 2 − 3 2 − 3
  • 11.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 11 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2 = 3 − 2 1 2 + 3 𝑋 2 − 3 2 − 3 = 2 − 3 4 − 3
  • 12.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 12 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2 = 3 − 2 1 2 + 3 𝑋 2 − 3 2 − 3 = 2 − 3 4 − 3 =2− 3
  • 13.
    1 3+ 2 12-Jun-15 C.S.VEERARAGAVAN98948 34264 veeraa1729@gmail.com 13 = 1 3+ 2 x 3− 2 3− 2 = 3− 2 3−2 = 3 − 2 1 2 + 3 𝑋 2 − 3 2 − 3 = 2 − 3 4 − 3 =2− 3 Adding we get 2 – 2
  • 14.
    What is thepositive square root of 48 − 27? 3 1 2 3 1 8 3 1 4 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 14
  • 15.
    48 − 27= 16(3) − 9(3) 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 15
  • 16.
    48 − 27= 16(3) − 9(3) 4 3 − 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 16
  • 17.
    48 − 27= 16(3) − 9(3) 4 3 − 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 17 3
  • 18.
    What is thepositive square root of 7 + 4 3 3+1 2 + 2 3 2 + 3 2 + 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 18
  • 19.
    What is thepositive square root of 7 + 4 3 3+1 2 + 2 3 2 + 3 2 + 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 19 7 + 4 3 = 7 + 2 3(4)
  • 20.
    What is thepositive square root of 7 + 4 3 3+1 2 + 2 3 2 + 3 2 + 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 20 7 + 4 3 = 7 + 2 3(4) 3 + 4 + 2 3(4) = 3 + 4 2
  • 21.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 21 4 2 5 − 3
  • 22.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 22 4 2 5 − 3 72 − 40
  • 23.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 23 4 2 5 − 3 72 − 40 36(2) − 20(2)
  • 24.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 24 4 2 5 − 3 72 − 40 36(2) − 20(2) 2 36 − 20
  • 25.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 25 4 2 5 − 3 72 − 40 36(2) − 20(2) 2 36 − 20 2 6 − 2 5
  • 26.
    What is thepositive square root of 72 − 40 2 5−1 4 2 5−1 4 2 3 − 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 26 4 2 5 − 3 72 − 40 36(2) − 20(2) 2 36 − 20 2 6 − 2 5 2 5 + 1 − 2 5
  • 27.
    5 3 2 3−6 1 3+2 2 3 = 31 3 + 213 31 3 − 21 3 21 3 − 31 3 32 3 + 22 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 27
  • 28.
    5 3 2 3−6 1 3+2 2 3 = 31 3 + 213 31 3 − 21 3 21 3 − 31 3 32 3 + 22 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 28 5 3 2 3−6 1 3+2 2 3 5 3 1 3 2 −(2) 1 3(3) 1 3+ 2 1 3 2
  • 29.
    5 3 2 3−6 1 3+2 2 3 = 31 3 + 213 31 3 − 21 3 21 3 − 31 3 32 3 + 22 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 29 5 3 2 3−6 1 3+2 2 3 5 3 1 3 2 −(2) 1 3(3) 1 3+ 2 1 3 2 5 3 1 3 2 −(2) 1 3(3) 1 3+ 2 1 3 2 𝑥 3 1 3+2 1 3 3 1 3+2 1 3
  • 30.
    5 3 2 3−6 1 3+2 2 3 = 32 3 + 213 31 3 − 21 3 21 3 − 31 3 32 3 + 22 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 30 5 3 2 3−6 1 3+2 2 3 5 3 1 3 2 −(2) 1 3(3) 1 3+ 2 1 3 2 5 3 1 3 2 −(2) 1 3(3) 1 3+ 2 1 3 2 𝑥 3 1 3+2 1 3 3 1 3+2 1 3 5 3 1 3+2 1 3 3+2
  • 31.
    What is therationalizing factor of 41 3 − 31 3 4 2 3 + 12 + 3 2 3 4 2 3 − 12 + 3 2 3 4 2 3 + 12 1 3 + 3 2 3 4 4 3 + 12 2 3 + 3 4 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 31
  • 32.
    What is therationalizing factor of 41 3 − 31 3 4 2 3 + 12 + 3 2 3 4 2 3 − 12 + 3 2 3 4 2 3 + 12 1 3 + 3 2 3 4 4 3 + 12 2 3 + 3 4 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 32 41 3 − 31 3 is of the form a – b
  • 33.
    What is therationalizing factor of 41 3 − 31 3 4 2 3 + 12 + 3 2 3 4 2 3 − 12 + 3 2 3 4 2 3 + 12 1 3 + 3 2 3 4 4 3 + 12 2 3 + 3 4 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 33 41 3 − 31 3 is of the form a – b a2+ab+ b2 should be multiplied to get a3−b3 4 2 3 + 4 1 33 1 3 + 3 2 3
  • 34.
    Simplify: x a a+b+c.x b a+b+c. x c a+b+c 1 x 0 xabc 12-Jun-15C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 34
  • 35.
    Which is greater? 1 8+5 , 1 2+ 5 1 8 + 5 1 2 + 5 Cannot be determined None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 35
  • 36.
    Which is greater? 1 8+5 , 1 5+ 2 1 8+ 5 1 5+ 2 Cannot be determined None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 36 8 > 5
  • 37.
    Which is greater? 1 8+5 , 1 5+ 2 1 8+ 5 1 5+ 2 Cannot be determined None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 37 8 > 5 5 > 2
  • 38.
    Which is greater? 1 8+5 , 1 5+ 2 1 8+ 5 1 5+ 2 Cannot be determined None of these. 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 38 8 > 5 5 > 2 8 + 5 > 5 + 2
  • 39.
    Which is greater?222 , 322 222 322 Cannot be determined Both are equal 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 45
  • 40.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 46 What is the rationalizing factor of 6 + 3 5
  • 41.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 47 What is the rationalizing factor of 6 + 3 5 6 + 3 5
  • 42.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 48 What is the rationalizing factor of 6 + 3 5 6 + 3 5 3(2) + 3 5
  • 43.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 49 What is the rationalizing factor of 6 + 3 5 6 + 3 5 3(2) + 3 5 3(2 + 5)
  • 44.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 50 What is the rationalizing factor of 6 + 3 5 6 + 3 5 3(2) + 3 5 3(2 + 5) 5 − 2 is the factor req.
  • 45.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 51 What is the rationalizing factor of 6 + 3 5 6 + 3 5 3(2) + 3 5 3(2 + 5) 5 − 2 is the factor req.
  • 46.
    –6 – 35 5 − 2 – 5 − 2 None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 52 What is the rationalizing factor of 6 + 3 5 6 + 3 5 3(2) + 3 5 3(2 + 5) 5 − 2 is the factor req.
  • 47.
    What is thevalue of x if 2 𝑥 𝑥 = 16 0 1 3 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 53
  • 48.
    If 2 𝑥 3𝑦 = 216 and x and y are integers then x,y? 3,2 2,2 3,4 3,3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 54
  • 49.
    If 3 1 23 3 23 5 23 7 2 =9 𝑥 , what is the value of x? 4 3 2 1 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 55
  • 50.
    (17)3.5 x (17)?= 178 2.29 2.75 4.25 4.5 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 56
  • 51.
    If 𝑎 𝑏 𝑥−1 = 𝑏 𝑎 𝑥−3 ,then the valueof x is 2 1 1 2 7 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 57
  • 52.
    If 𝑎 𝑏 𝑥−1 = 𝑏 𝑎 𝑥−3 ,then the valueof x is 2 1 1 2 7 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 58 𝑎 𝑏 𝑥−1 = 𝑏 𝑎 𝑥−3 𝑎 𝑏 𝑥−1 = 𝑎 𝑏 −(𝑥−3)
  • 53.
    If 𝑎 𝑏 𝑥−1 = 𝑏 𝑎 𝑥−3 ,then the valueof x is 2 1 1 2 7 2 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 59 𝑎 𝑏 𝑥−1 = 𝑏 𝑎 𝑥−3 𝑎 𝑏 𝑥−1 = 𝑎 𝑏 −(𝑥−3) x – 1 = 3 – x Solving x = 2
  • 54.
    Given 100.48 =x, 100.7 = y and xz = y2, value of z = ? 1.45 1.88 2.9 3.7 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 60
  • 55.
    Given 100.48 =x, 100.7 = y and xz = y2, value of z = ? 1.45 1.88 2.9 3.7 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 61 xz = y2 100.48z = 102*0.7
  • 56.
    Given 100.48 =x, 100.7 = y and xz = y2, value of z = ? 1.45 1.88 2.9 3.7 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 62 xz = y2 100.48z = 102*0.7 0.48z = 1.4
  • 57.
    Given 100.48 =x, 100.7 = y and xz = y2, value of z = ? 1.45 1.88 2.9 3.7 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 63 xz = y2 100.48z = 102*0.7 0.48z = 1.4 Z = 140 48 = 35 12 ≈ 2.9
  • 58.
    If 5a =3125, then the value of 5a – 3 is? 25 125 625 1625 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 64
  • 59.
    If 3x –y = 27 and 3x + y = 243, then x =? 0 2 4 6 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 65
  • 60.
    If 3x –y = 27 and 3x + y = 243, then x = ? 0 2 4 6 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 66 3x – y = 27 = 33 3x + y = 243 = 35
  • 61.
    If 3x –y = 27 and 3x + y = 243, then x = ? 0 2 4 6 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 67 3x – y = 27 = 33 3x + y = 243 = 35 x – y = 3
  • 62.
    If 3x –y = 27 and 3x + y = 243, then x = ? 0 2 4 6 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 68 3x – y = 27 = 33 3x + y = 243 = 35 x – y = 3 x + y = 5
  • 63.
    If 3x –y = 27 and 3x + y = 243, then x = ? 0 2 4 6 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 69 3x – y = 27 = 33 3x + y = 243 = 35 x – y = 3 x + y = 5 Solving x = 4
  • 64.
    2560.16 x 2560.09= ? 4 16 64 256.25 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 70
  • 65.
    2560.16 x 2560.09= ? 4 16 64 256.25 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 71 2560.16 x 2560.09 = 2560.25
  • 66.
    2560.16 x 2560.09= ? 4 16 64 256.25 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 72 2560.16 x 2560.09 = 2560.25 256 = 44
  • 67.
    1 1+x b−a +xc−a + 1 1+x a−b +x c−b + 1 1+x b−c +x a−c = ? 0 1 Xa – b – c None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 73
  • 68.
    1 1+x b−a +xc−a + 1 1+x a−b +x c−b + 1 1+x b−c +x a−c = ? 0 1 Xa – b – c None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 74 1 1+ xb xa + xc xa + 1 1+ xa xb + xc xb + 1 1+ xb xc + xa xc
  • 69.
    1 1+x b−a +xc−a + 1 1+x a−b +x c−b + 1 1+x b−c +x a−c = ? 0 1 Xa – b – c None of these 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 75 1 1+ xb xa + xc xa + 1 1+ xa xb + xc xb + 1 1+ xb xc + xa xc xa xa+xb+xc + xb xa+xb+xc + xc xa+xb+xc
  • 70.
    257.5 x 52.5÷1251.5 = 5? 8.5 13 16 17.5 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 76
  • 71.
    243 n 5 X 32n+1 9nX3n−1 1 2 9 3n 12-Jun-15C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 77
  • 72.
    243 n 5 X 32n+1 9nX3n−1 1 2 9 3n 12-Jun-15C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 78 35 n 5 X32n+1 32 n X 3n−1
  • 73.
    243 n 5 X 32n+1 9nX3n−1 1 2 9 3n 12-Jun-15C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 79 35 n 5 X32n+1 32 n X 3n−1 = 3 𝑛+2𝑛+1 32𝑛+𝑛−1
  • 74.
    243 n 5 X 32n+1 9nX3n−1 1 2 9 3n 12-Jun-15C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 80 35 n 5 X32n+1 32 n X 3n−1 = 3n+2n+1 32n+n−1 = 33n + 1 – 3n + 1
  • 75.
    1 1+a n−m + 1 1+am−n = ? 0 1 2 1 am+n 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 81
  • 76.
    1 1+a n−m + 1 1+am−n = ? 0 1 2 1 am+n 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 82 1 1+an am + 1 1+am an =
  • 77.
    1 1+a n−m + 1 1+am−n = ? 0 1 2 1 am+n 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 83 1 1+an am + 1 1+am an = 𝑎 𝑚 𝑎 𝑚+𝑎 𝑛 + 𝑎 𝑛 𝑎 𝑚+𝑎 𝑛
  • 78.
    If mn =121, the value of (m – 1)n+1 is 1 10 121 1000 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 84
  • 79.
    xb xc b + c− a xc xa c +a −b xa xb a +b −c xabc 1 xab+bc+ca xa+b+c 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 85
  • 80.
    xb xc b + c− a xc xa c +a −b xa xb a +b −c xabc 1 xab+bc+ca xa+b+c 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 86 xb xc b + c − a xc xa c +a −b xa xb a +b −c
  • 81.
    xb xc b + c− a xc xa c +a −b xa xb a +b −c xabc 1 xab+bc+ca xa+b+c 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 87 xb xc b + c − a xc xa c +a −b xa xb a +b −c = x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
  • 82.
    xb xc b + c− a xc xa c +a −b xa xb a +b −c xabc 1 xab+bc+ca xa+b+c 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 88 xb xc b + c − a xc xa c +a −b xa xb a +b −c = x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c) = x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c)
  • 83.
    xb xc b + c− a xc xa c +a −b xa xb a +b −c xabc 1 xab+bc+ca xa+b+c 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 89 xb xc b + c − a xc xa c +a −b xa xb a +b −c = x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c) = x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c) =𝑥 𝑏2−𝑐2+𝑐2−𝑎2+𝑎2−𝑏2 ∗ 𝑥 𝑏𝑎−𝑐𝑎+𝑏𝑐−𝑎𝑏+𝑎𝑐−𝑏𝑐
  • 84.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 90
  • 85.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 91 X = 3 + 2 2
  • 86.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 92 X = 3 + 2 2 𝑥 − 1 𝑥 2 = 𝑥 + 1 𝑥 − 2
  • 87.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 93 X = 3 + 2 2 𝑥 − 1 𝑥 2 = 𝑥 + 1 𝑥 − 2 = 3 + 2 2 + 1 3 + 2 2 − 2
  • 88.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 94 X = 3 + 2 2 𝑥 − 1 𝑥 2 = 𝑥 + 1 𝑥 − 2 = 3 + 2 2 + 1 3 + 2 2 − 2 = 3 + 2 2 + 1 3 + 2 2 𝑥 3 − 2 2 3 − 2 2
  • 89.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 95 X = 3 + 2 2 𝑥 − 1 𝑥 2 = 𝑥 + 1 𝑥 − 2 = 3 + 2 2 + 1 3 + 2 2 − 2 = 3 + 2 2 + 1 3 + 2 2 𝑥 3 − 2 2 3 − 2 2 = 3 + 2 2 + (3 - 2 2) − 2
  • 90.
    If x =3 + 2 2, then 𝑥 − 1 𝑥 is 1 2 2 2 3 3 12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 96 X = 3 + 2 2 𝑥 − 1 𝑥 2 = 𝑥 + 1 𝑥 − 2 = 3 + 2 2 + 1 3 + 2 2 − 2 = 3 + 2 2 + 1 3 + 2 2 𝑥 3 − 2 2 3 − 2 2 = 3 + 2 2 + (3 - 2 2) − 2 = 4