The document describes the components and design considerations for steam-driven and electric-driven cargo cranes. It details the parts of each type of winch system including gears, clutches, barrels and engines. Equations are provided to calculate key specifications like winch barrel diameter, gear ratios, torque and power requirements based on the load weight and other factors. The goal is to select appropriate dimensions and power sources to safely lift and lower cargo while optimizing efficiency.

1. SHIP CARGO HANDLING
(CARGO CRANE)

3. Steam Driven Winch
1. Driving shaft
2. Gear
3. Clutch
4. Levers
5. shaft
6. gear
7. gear
8. Clutch
9. lever
10. gear
11. shaft
12. gear
13. whinch head
14. clutch
15. whinch head
16. Whinch head
17. Steam engine

4. Electric Driven Winch
1. Baseplate
2. Support
3. Barrel
4. Whinch Head
5. Load Shaft
6. Electric motor
7. Controller
8. Flexible couplings
9. Housing
10. Pinion
11. Gear
12. Clutch Member
13. Hub of Disk
14. Lever
15. Electromagnetic Brake
16. Band of Brake
17. Weight
18. Pedal

5. Steam Winch Design
1. Gaya Tarik Tb pada winch barrel :
P +Q
Tb = k = Pg
ηg
P = berat beban yang diangkat, kg
Q = 0.0028 ~ 0.0022 x P (berat hook dan shackle)
ηg = 0.9 ~ 0.96 = effisiensi dari satu puli
k = jumlah puli itenmediate antara boom dan barell winch.

6. Steam Winch Design
2. Diameter winch barrel (cm) Panjang Keseluruhan Tali
Db = (16.5 ~18).dr L m1 = lm1 = π (D b + d r ).m
Kekuatan putus tali (kg) L m2 = lm1 + lm 2 = π (Db + d r ).m + π (D b + 3d r ).m = π (2D b + 4d r ).m
Rbr = 6.Pg Rrb ≥ K m .Pg . kg L m3 = Lm 2 + lm3 = π (2D b + 4d r ).m + π (D b + 5d r ).m = π (3D b + 9d r ).m
L mz = π (zD b + z 2 .d r ).m
3. Panjang barrel winch (cm)
Memperhitungkan faktor uniformity in arrangement :
Lb = (1.1~1.6) Db
L mz = βb .π .m (D b + 5d r ).m
4.TALI
Jumlah lilittan tali
βb ≈ 0.9
Lb
m=
dr
Panjang Tali pada layer
lm1 = π (D b + d r ).m
lm2 = π [D b + (4d r - d r )].m = π (D b + 3d r ).m
lm3 = π [D b + (6d r - d r )].m = π (D b + 5d r ).m
lmz = π [D b + (2 zd r - d r )].m = π [D b + (2 z −1)d r ].m

7. Steam Winch Design
Jumlah layer:
β b .π .m.d r .z 2 + β b .π .m.Db .z − Lmz = 0
Db Lmz
z2 + .z − =0
dr β b .π .m.d r
2
Db  Db  Lmz Db Db2  4 Lmz .d r2 
z=− +  ÷+ =− + + 1 + 2 ÷
2d r  2d r  β b .π .m.d r 2d r 4d r2  Db .β b .π .m.d r 
D  4 Lmz .d r 
z= b  1+ 2 − 1÷
2d r  Db .β b .π .m. ÷
 
5.Diameter Barrel
Dbd = Db + d r (2 z −1)
6. Torsi Pada Poros Barrel
1 T
M bd =
2
( Db + d r ( 2 z − 1) ) . b
ηb
ηb = effisiensi barrel

8. Steam Winch Design
Effisiensi double gear barrel 9.Torsi yang diperlukan (kg-m):
60.vid v M bd
ηbd = = 19.1 id M md =
π .Dbd Dbd iwd .η wd
10. Diameter silinder steam engine
7.Rasio gear
n n n .π .Dbd M md
iwd = m = m = m Dcw = 1.37. 3
nbd 60.vid 60.vid ψ r . .η m . ( α i. ki pts − pss )
π .Dbd Ptss = tekanan desain dalam silinder (3~4 atm)
8.Effisiensi Total Pss = tekanan akhir dalam silinder (0.2 ~ 0.3atm)
ηwd =η .η .ηb.η wg
a
sh
c
pg ψ r . = ratio tekanan silinder
η sh ~ eff . shaft α i. = indicator diagram faktor
η pg ~ eff spur gear l + ln ∆
ki = = koefisien yang menunjukan
ηb ~ eff barrel ∆
η wg ~ eff worm gear ratio tekanan ekspansi
ki = dicari dari tabel terhadap fungsi δ
η wd = 0.7 ~ 0.8 untuk winches dengan spur gear
0.65 ~ 0.75 untuk winches worm gear

9. Steam Winch Design
1
δ= 0.5 0.6 0.7 0.8 0.9 1
∆
ki 0.848 0.907 0.95 0.979 0.995 1
Indicated power of the engine kecepatan barrel pada satu roda gigi
Ni =
3
(
Dcw ψ r . .ηm . ( α i . ki pts − pss ) ) nbs =
nm
143.300 iws
Torsi yang diaplikasikan pada barrel Kecepatan angkat
1 π Dbd nbr
M bs =
2
( Db + dr ( 2 z −1) ) .Tbr vi =
60
Assumsi poros berotasi pada putaran kons tan:
M bd M bs
=
iwd .ηwd iws .η ws
Rasio gear
M bs η wd
iws = iwd
M bd η ws

10. Steam Winch Design
Power yang dibutuhkan
M md
M md iwdη wd
Dcw =2 3 =2 3
π .ψ r . .ηm . ( α i. ki pts − pss ) π .ψ r ..ηm . ( α i . ki pts − pss )
0.5 ( Db + d r ( 2 z − 1) ) .Tbr
=1.37. 3
π .ψ r . .η m . ( α i. ki pts − pss ) . iwd .η wd
Konsumsi steam dan listrik
Gsw = ( (1.5.z w + 1.2.g ) . ( 0.54 H h + 3 ) kg
Wcw = ( 0.42 z w + 0.02 g s ) ( 0.5H h + 3 ) Kw