ejercicio de mecanica vectorial estatica

1. Jose Colmenarez III-152-00120p
Datos:
Mb= 24 Mc=81 G= 9,8 m/s2
Solución:
∑ Mc = 0 ; Dy ( 4m) – Dx ( 3m) = 0 Dy= ¾ Dx
1. ∑ MA = 0 ; ¾ Dx(14m) – Wb (4m) - Wc (10m) – P(5m) = 0
2. ∑ MB = 0 ; ¾ Dx (10m) - Dx(5m) – Wc (6m) = 0
Solución 2 ecuacion Dx = 2, 4 Wc
Mb= Wb = 24 Kg
Mc= Wc = 81 Kg
Dx = 2, 4 Wc Dx = 2, 4 x 81 Dx = 195
Solucion ecuacion 1
¾ Dx(14m) – Wb (4m) - Wc (10m) – P(5m) = 0
¾ 195 (14m) – 24 (4m) - 81 (10m) – P(5m) = 0
P = 228,3 x G P = 228,3 x 9,8
P = 2237.3 N