Priority queues may to implemented as linked lists kept in key order, or linked lists kept
unordered compare the cost for the implementation of the operation of Inserting a new key
Changing a key value Deleting the maximum Key We\'ve implemented a FIFO queue With the
usual structures and algorithms. Now we add reverse links to each node. Does the Order of
queuing or dequeuing change?
Solution
1)Queue is a First In First out data structure and one of the way to implement is linked list with
order and unorder.
So, lets first talks aboit the order liked lists:
For example linked list is Increase order that highest element is at first and least element is at
last. and deletion of elements takes place at last and inserting of elements is taking at first we can
think in reverse also.
To insert an element we need to travrse all the list to the required osition to insert the element , If
N elements are in the list then for AVERAGE and Worst time cases takes O(N) time and for
Deletion also takes O(1) time whcich is constant.
and in the case of changing any elements it is same as the inserting element becase in first step
element needs to be found and in second step value neeeds to be changed.
IN UNORDER list case The INSERTION and DELETION takes O(1) time only. and for
changeing it is O(N) in average and worst time complexities.
2)No it depends on the way we does those operations.
I mean that If to wish to do insertion at last and deletion at first and vice-verse that upto you to
code. but if links are changed all the meaning of your first code also changes.
I think you got my point..
Reverse a Linked List In Place in PythonKal Bartal
Do you want to learn how to reverse a linked list in place in Python? I recently put out a tutorial on this topic, explaining the problem and walking you through the solution and code step-by-step. I also discuss the time and space complexity of this problem, so you can decide if this is the most efficient solution.
Remove Duplicates in an Unsorted Linked List in PythonKal Bartal
In this pdf, I will walk you through a popular Python coding challenge and provide you with the solution code and detailed explanations. The challenge is called 'Remove Duplicates in an Unsorted Linked List', which involves finding and removing duplicates in an unsorted linked list of integers. I will also discuss the concept of run time complexity and how it relates to your solution.
Reverse a Linked List In Place in PythonKal Bartal
Do you want to learn how to reverse a linked list in place in Python? I recently put out a tutorial on this topic, explaining the problem and walking you through the solution and code step-by-step. I also discuss the time and space complexity of this problem, so you can decide if this is the most efficient solution.
Remove Duplicates in an Unsorted Linked List in PythonKal Bartal
In this pdf, I will walk you through a popular Python coding challenge and provide you with the solution code and detailed explanations. The challenge is called 'Remove Duplicates in an Unsorted Linked List', which involves finding and removing duplicates in an unsorted linked list of integers. I will also discuss the concept of run time complexity and how it relates to your solution.
Answersa) It is more efficient to delete the last node in an array.pdfanilgoelslg
Answers
a) It is more efficient to delete the last node in an array because we can access the last element in
constant time O(1) and we can delete the value at that position. In case of linked list we need to
traverse the entire list to reach the last node which requires O(n) time and then we delete the
node.
b) It is inefficient to delete the first node in an array because after deleting the first element we
need to shift the remaining elements one position to the left which requires O(n) time. In case of
linked list we can directly delete the first node by changing the pointer to the first node and
freeing the memory which was earlier allocated to the first element. This operation can be done
in O(1) time.
c) In case of an array after deleting the specific element we need to shift the remaining elements
one position to the left and hence it is inefficient. In case of a linked list we need to traverse the
linked list till we reach the node to be deleted and then we can change the pointers to delete the
node.
d) It is more efficient to insert a node at the end of an array because we can access the last index
in O(1) time and then we can insert the element at that position. In case of linked list we need to
traverse till the end of list and then we can insert the element which requires O(n) time and is
inefficient.
e) It is inefficient to insert a node at the front of an array because we need to make room for the
new element to be inserted by shifting all the elements one position to the right and then insert
the element at the first index of array. In case of linked list we can create a new node and insert
the node at first position by modifying the pointers which is efficient.
f) It is inefficient to insert a node in general in case of array because we need to make room for
the element by shifting the element one position to the right and then we can insert the element at
that index position. In case of linked list we need to traverse the list till we reach the specific
position and then we can insert the element by modifying the pointer.
g) It is more efficient to access a node in case of an array because arrays support random access
and we can access any index in constant time. In case of linked list we need to traverse the list in
order to find the element at specified index which is not efficient.
Solution
Answers
a) It is more efficient to delete the last node in an array because we can access the last element in
constant time O(1) and we can delete the value at that position. In case of linked list we need to
traverse the entire list to reach the last node which requires O(n) time and then we delete the
node.
b) It is inefficient to delete the first node in an array because after deleting the first element we
need to shift the remaining elements one position to the left which requires O(n) time. In case of
linked list we can directly delete the first node by changing the pointer to the first node and
freeing the memory which was earlie.
Sort Characters in a Python String AlphabeticallyKal Bartal
This tutorial will explore how to solve the problem of sorting characters in a Python string in alphabetical order. We'll learn about manipulating strings in Python and discuss how to compare various sorting algorithms. Finally, we'll put the pieces together to create a solution using the merge sort algorithm. Problem-solving can be quite challenging, but with the right approach, we can find an efficient solution with minimal time and space complexity.
#Python #Strings #Sorting #Algorithms #MergeSort #TimeComplexity #SpaceComplexity #Coding #Recursion
What is DSA ?
What are different types of data structures ?
Primitive and Non Primitive DSA
Arrays
Queue
Stack
Linked List
Memory representation of Linked Lists
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Pos.
Does the rate of diffusion change over time Does the rat.pdfederstevensc52755
Does the rate of diffusion change over time ?
Does the rate of diffusion change over time ?
Solution
Yes, the rate of diffusion does change over time.
The size of the diffusing particle, the mass of the particle, the surface area and the temperature
are the factors controlling the rate of diffusion.
In cells, the size of the cell affects the rate of diffusion. The surface area to volume ratio affects
the rate of diffusion. As the cell grows in size, its surface area to volume decreases and it takes a
longer time for molecules to diffuse in and out of the cell. As all cells grow, the rate of diffusion
will change over time..
More Related Content
Similar to Priority queues may to implemented as linked lists kept in key or.pdf
Answersa) It is more efficient to delete the last node in an array.pdfanilgoelslg
Answers
a) It is more efficient to delete the last node in an array because we can access the last element in
constant time O(1) and we can delete the value at that position. In case of linked list we need to
traverse the entire list to reach the last node which requires O(n) time and then we delete the
node.
b) It is inefficient to delete the first node in an array because after deleting the first element we
need to shift the remaining elements one position to the left which requires O(n) time. In case of
linked list we can directly delete the first node by changing the pointer to the first node and
freeing the memory which was earlier allocated to the first element. This operation can be done
in O(1) time.
c) In case of an array after deleting the specific element we need to shift the remaining elements
one position to the left and hence it is inefficient. In case of a linked list we need to traverse the
linked list till we reach the node to be deleted and then we can change the pointers to delete the
node.
d) It is more efficient to insert a node at the end of an array because we can access the last index
in O(1) time and then we can insert the element at that position. In case of linked list we need to
traverse till the end of list and then we can insert the element which requires O(n) time and is
inefficient.
e) It is inefficient to insert a node at the front of an array because we need to make room for the
new element to be inserted by shifting all the elements one position to the right and then insert
the element at the first index of array. In case of linked list we can create a new node and insert
the node at first position by modifying the pointers which is efficient.
f) It is inefficient to insert a node in general in case of array because we need to make room for
the element by shifting the element one position to the right and then we can insert the element at
that index position. In case of linked list we need to traverse the list till we reach the specific
position and then we can insert the element by modifying the pointer.
g) It is more efficient to access a node in case of an array because arrays support random access
and we can access any index in constant time. In case of linked list we need to traverse the list in
order to find the element at specified index which is not efficient.
Solution
Answers
a) It is more efficient to delete the last node in an array because we can access the last element in
constant time O(1) and we can delete the value at that position. In case of linked list we need to
traverse the entire list to reach the last node which requires O(n) time and then we delete the
node.
b) It is inefficient to delete the first node in an array because after deleting the first element we
need to shift the remaining elements one position to the left which requires O(n) time. In case of
linked list we can directly delete the first node by changing the pointer to the first node and
freeing the memory which was earlie.
Sort Characters in a Python String AlphabeticallyKal Bartal
This tutorial will explore how to solve the problem of sorting characters in a Python string in alphabetical order. We'll learn about manipulating strings in Python and discuss how to compare various sorting algorithms. Finally, we'll put the pieces together to create a solution using the merge sort algorithm. Problem-solving can be quite challenging, but with the right approach, we can find an efficient solution with minimal time and space complexity.
#Python #Strings #Sorting #Algorithms #MergeSort #TimeComplexity #SpaceComplexity #Coding #Recursion
What is DSA ?
What are different types of data structures ?
Primitive and Non Primitive DSA
Arrays
Queue
Stack
Linked List
Memory representation of Linked Lists
Similar to Priority queues may to implemented as linked lists kept in key or.pdf (20)
GENERAL LEDGERName BANK ACCOUNTAcct No. 100DateDetailsPo.pdfederstevensc52755
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Name: ACCOUNTS RECEIVABLE
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381.25
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GJ20
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Acct No.: 130
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Name: GST PAID (OUTLAYS)
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Accounts Payable
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Pos.
Does the rate of diffusion change over time Does the rat.pdfederstevensc52755
Does the rate of diffusion change over time ?
Does the rate of diffusion change over time ?
Solution
Yes, the rate of diffusion does change over time.
The size of the diffusing particle, the mass of the particle, the surface area and the temperature
are the factors controlling the rate of diffusion.
In cells, the size of the cell affects the rate of diffusion. The surface area to volume ratio affects
the rate of diffusion. As the cell grows in size, its surface area to volume decreases and it takes a
longer time for molecules to diffuse in and out of the cell. As all cells grow, the rate of diffusion
will change over time..
Ellen baked 112 cookies and shared them equally with her 23 classmat.pdfederstevensc52755
Ellen baked 112 cookies and shared them equally with her 23 classmates. How many whole
cookies each can Ellen and her classmates have?
A. 4
B. 5
C. 6
D. 7
Solution
A. If Ellen baked 112 cookies for herself and her 23 classmates, divide 24 into 112 to get 4.67.
The question asks for the number of whole cookies, so there are 4 per person plus some fraction
of a cookie left over. The correct answer is 4..
Computing Change C program Computing Change Write a program p3.c th.pdfederstevensc52755
Computing Change C program Computing Change Write a program p3.c that computes the
equivalent of a dollar amount in change using quarters, dimes, and pennies. No nickels are used
for conversion. For this problem you need to write the top-down algorithm. The main function
program reads from the terminal in a loop while not end-of-file the dollar amounts. Inside the
loop it calls function getChange() that computes how many quarters, dimes, and pennies make up
the original dollar amount. The getChange() function has the following formal parameters (in
this order): double dollarAmount: the total amount in $ pointer to int pQuarters that will store
the number of quarters pointer to int pDimes that will store the number of dimes pointer to int
pPennies that will store the number of pennies The getChange() function computes the change
and then returns the total number of coins. If dollarAmount
Solution
#include
// Converts the dollar amount to quarters, dimes and pennies
void getChange(double dollarAmount, int *pQuarters, int *pDimes, int *pPennies)
{
if(dollarAmount < 0)
{
const int QUARTER_TO_CENTS = 25;
const int DIME_TO_CENTS = 10;
const int PENNY_TO_CENTS = 1;
//Convert user entered amount to cents
int amountToCents = dollarAmount * 100;
//Start conversion
*pQuarters = amountToCents / QUARTER_TO_CENTS;
amountToCents = amountToCents % QUARTER_TO_CENTS;
*pDimes = amountToCents / DIME_TO_CENTS;
amountToCents = amountToCents % DIME_TO_CENTS;
*pPennies = amountToCents;
}
*pQuarters = -1;
}
int main()
{
double dollarAmount;
int pQuarters, pDimes, pPennies;
while(!feof(stdin))
{
// Get user input
scanf(\"%lf\", &dollarAmount);
// Convert dollar amount
getChange(dollarAmount, &pQuarters, &pDimes, &pPennies);
if(pQuarters != -1)
{
printf(\"\ $%lf makes %d quarters, %d dimes, and %d pennies (%d coins), total amount in coins:
$%lf.\ \",
dollarAmount, pQuarters, pDimes, pPennies, (pQuarters + pDimes + pPennies), dollarAmount);
}
else
{
printf(\"\ Invalid input.\ \");
}
}
return 0;
}.
Compare the nurse cells (Sertoli cells) in the mammalian testis with.pdfederstevensc52755
Compare the nurse cells (Sertoli cells) in the mammalian testis with nurse cells (follicle cells) in
a mammalian ovary.
Solution
Answer:
Sertoli cells Follicle cells
1. they are the nurse or nurturing cells of the testicles and 1. They are the nurse cells or nutrition
providing cells
provide nutrition to developing sperm cells during spermatogenesis. for the oocyte.
2. Located between the convoluted seminiferous tubule 2. located on the surface surrounding the
oocyte in
the ovary.
3. Translocate the sperm cells from basal lamina to the lumen 3. does not translocate the oocyte
but, gives rise to
of the seminiferous tubule corpus luteum
4. secretes : Anti mullerian hormone, Inhibin, transferrin, 4. secretes; estradiol, progesterone and
InhibinA
androgen binding protein.
5. No role in pregnancy 5. the later stages form corpus luteum and helps in
maintenance of preganancy.
3..
Below is a mutant Drosophila cuticle. What class (ex. segment polari.pdfederstevensc52755
Below is a mutant Drosophila cuticle. What class (ex. segment polarity, pair-rule, or gap) and
mutation is shown?
Solution
First, let me start with telling you what each class means:
Hence this is a typical case of Segemnt polarity from the above definitions of different mutant
classes in cuticle of mutant embryos..
An _ is found on the tRNA molecule and has the complementary bases to.pdfederstevensc52755
An _ is found on the tRNA molecule and has the complementary bases to an mRNA codon. A
protein is made of a _ chain of amino acids. The job of _ is to carry encoded information to the
ribosome. The job of _ is to carry an amino acid to the ribosome and find the
Solution
An anticodon is found on tRNA
A protein is made of a linear chain of amino acids
The job of mRNA is to carry encoded information to the ribosome.
The job of tRNA is to carry an amino acid to the ribosome.
A psychiatrist wants to test the impact of a new drug designed to in.pdfederstevensc52755
A psychiatrist wants to test the impact of a new drug designed to increase the ability of teenagers
with ADHD to take accurate notes in class.
Level #1:
Level #2:
Solution
The levels of the independent (explanatory) variable are:
Level 1: The drug was not taken before the class
Level 2: The drug was taken before the class.
With respect to accounting for inventories, which of the following i.pdfederstevensc52755
With respect to accounting for inventories, which of the following is a difference that exists for
IFRS, as opposed to U.S. GAAP? There is required recognition of certain development costs.
The FIFO method of inventories is prohibited. The specific identification method of inventories
is only allowed when goods are interchangeable. The weighted average method of inventories is
prohibited
Solution.
Why would it be advantageous to be able to become an endospore if you.pdfederstevensc52755
Why would it be advantageous to be able to become an endospore if you were a soil bacterium?
A water bacterium? A pathogen? (answer each individually - think about the environmental
stresses these bacteria are under; 3 points)
Solution
Endospore is a tough resistant, protective layer, which keep the cell in the dormant state under
unfavorable conditions of growth. For example, in tundra soils, the bacteria form endospores
during the cold summers and become active during the warmth summers when the temperature
allows their active metabolism. Eg: Bacillus species.
Endospore formation is advantageous to water bacteria because the decreased water levels or
dried water sources does not favour their growth. The bacteria become active again when the
water is available. Eg: Clostridium species.
Pathogenic bacteria can from endospores in response to toxicity of drugs and radiation. These
bacteria become active in the absence of these stressors. For example, Mycobacterium
tuberculosis..
What is the protocol that can be used to create VPN connections betw.pdfederstevensc52755
What is the protocol that can be used to create VPN connections between hosts or routers?
Solution
Protocols are use to do encryption and finally send these encrypted data across the host.
Following are the protocol use for Data Encryption:-
Following are the protocols used for sending these encrypted data packets to the Host..
What factor has held up the development of an Intermediate Moisture .pdfederstevensc52755
What factor has held up the development of an Intermediate Moisture Food (IMF)?
Solution
A food product that has water activity below that which is required for a growth of
microorganism;or food containing unavailable water.IMF food have water activity in between
0.6 to 0.9 or 10-0% moisture.
So the main important factor is water activity..
What is black holeSolutionA black hole is a region in space w.pdfederstevensc52755
What is black hole?
Solution
A black hole is a region in space where the pulling force of gravity is so strong that light is not
able to escape. The strong gravity occurs because matter has been pressed into a tiny space. This
compression can take place at the end of a star\'s life. Some black holes are a result of dying
stars.
Because no light can escape, black holes are invisible. However, space telescopes with special
instruments can help find black holes. They can observe the behavior of material and stars that
are very close to black holes..
We are interested in determining whether scale traits for the Rio Gr.pdfederstevensc52755
We are interested in determining whether scale traits for the Rio Grande Horned Toad follow a
common epistatic relationship. The observed phenotypes are scaled and fused. Which mode of
inheritance would mostlikely explain the data below?
Phenotype
Scaled 122
Fused 98
Total 220
Select One:
dominant/recessive epistasis
deuplicate dominant epistasis
duplicate genes with cumulative effect
single dominant epistasis
single resessive epistasis
duplicate recessive epistasis
Solution
The correct answer is :dominant/recessive epistasis.
Reason: In this case,dominant allele in both homozygous and heterozygous conditions and
recessive allele in homozygous condition at each defined locus will give rise to same effect i.e
scaled phenotype while other genotypes will produce fused phenotype..
The Reynolds number, pVDmu is a very Important parameter In fluid me.pdfederstevensc52755
The Reynolds number, pVD/mu is a very Important parameter In fluid mechanics. Determine Its
value for ethyl alcohol flowing at a velocity of 2 m/s through a 5-ln.-diameter pipe.
Solution
Assuming kinematic Visosity of ethyl alcohol at 20 C = 1.52 * 10^-6
Re = V * D / kinematic visocity
= 2 * (5 * 0.0254) / 1.52 * 10^-6
= 167105.26.
The respiratory gases of animals are. oxygen and nitrogen.nitrog.pdfederstevensc52755
The respiratory gases of animals are
. oxygen and nitrogen.
nitrogen and carbon dioxide.
oxygen and carbon dioxide.
Solution
Answer: oxygen and carbon dioxide.
Reason:
Animals are vertebrates and perform their metabolic reactions using oxygen to generate ATP as
energy in mitochondria in which oxygen is the chief electron acceptor finally CO2 is generated
as metabolic waste product finally eliminated in the form of bicarbonate or expiration via lungs.
The highest concentration of power regarding US monetary policy rest.pdfederstevensc52755
The highest concentration of power regarding US monetary policy rests with:
A. US Congress
B.The Federal Open Market Committee
C. JPMorgan
D.The President of the United States
E.The Chairman of the SEC
Solution
Correct option is > B. The Federal Open Market Committee
The Federal Open Market Committee deals with monetary policy and has highest power to set
monetary policies for US.
2.) Explain the originevolution of viruses by these hypotheses red.pdfederstevensc52755
2.) Explain the origin/evolution of viruses by these hypotheses: reductive, additive, horizontal
gene transfer, and common ancestor. Why are there so many different ideas? Is there any one
right answer? Why?
Solution
Origin of virus has been hypothesized by three main views:
1. Reductive hypothesis: This states that viruses were initially small parasites of large cell. Just
like parasites, they used to take nutrition from the host; and left the host when host\'s body
became diseased and useless for the virus. This hypothesis is also known as degeneracy
hypothesis. This hypothesis is not accepted much, especially in case of large viruses like pox
virus. Moreover, no parasites on earth resemble viruses at all.
2. Additive hypothesis: Complex protein and nucleic acids combined together to form the
infectious agents, i.e. viruses. This hypothesis is also known as virus-first hypothesis. In this
hypothesis, the actual definition of virus is totally changed. Why couldn\'t the genetic material of
replication machinery combine together during the course of evolution; even after being more fit
than the rest of the genetic material?
3. Horizontal gene transfer: Small bits of RNA or DNA escaped from large organisms and then
underwent homologous recombination; to form infectious agents known as virus. The process
was random. This is also known as escape hypothesis. This hypothesis was not accepted much
because it could not explain the formation of capsid around the genetic material.
So many different answers are there, because the genetic material of virus is of different types
like ssRNA (+ and -), dsRNA (+ and -), ssDNA, dsDNA etc. This is not the case with cellular
organisms like prokaryotes and eukaryotes. All of them have dsDNA as genetic material. Now,
because of different genetic material, it is very difficult to trace the common ancestor of all
viruses. Therefore, different researchers have proposed different hypothesis from time to time.
None of these hypotheses has been accepted. One right answer is Common ancestor hypothesis.
This states that there must be some common ancestor from which all viruses originated..
Suppose 13 of American adults believe that the highest priority of .pdfederstevensc52755
Suppose 13% of American adults believe that the highest priority of America is to protect
freedom of speech. We will take a random sample of 20 American adults and ask them the
question. Then the sampling distribution of the sample proportion of people who answer yes to
the question is:
Solution
binomial distribution with n = 20 and p = 0.13.
Revised QuestionThe entire content of the page has been enclosed .pdfederstevensc52755
Revised Question:
The entire content of the page has been enclosed in a div container element with the id container.
Create a style rule for this container to: a) set the width to 1000 pixels; b) center the container in
the browser window by settin the top/bottom margins to 0 pixels and the left/right margins to
auto: c) display a 1-pixel solid black border on the left and right edges; and d) set the background
color to white and display the redbar.png image file as the background image, placing the image
file in the top-left corner of the container and tiling it in the vertical direction only.
Solution
Heading.
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Francesca Gottschalk - How can education support child empowerment.pptxEduSkills OECD
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Executive Directors Chat Leveraging AI for Diversity, Equity, and InclusionTechSoup
Let’s explore the intersection of technology and equity in the final session of our DEI series. Discover how AI tools, like ChatGPT, can be used to support and enhance your nonprofit's DEI initiatives. Participants will gain insights into practical AI applications and get tips for leveraging technology to advance their DEI goals.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar Kanvaria
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Priority queues may to implemented as linked lists kept in key or.pdf
1. Priority queues may to implemented as linked lists kept in key order, or linked lists kept
unordered compare the cost for the implementation of the operation of Inserting a new key
Changing a key value Deleting the maximum Key We've implemented a FIFO queue With the
usual structures and algorithms. Now we add reverse links to each node. Does the Order of
queuing or dequeuing change?
Solution
1)Queue is a First In First out data structure and one of the way to implement is linked list with
order and unorder.
So, lets first talks aboit the order liked lists:
For example linked list is Increase order that highest element is at first and least element is at
last. and deletion of elements takes place at last and inserting of elements is taking at first we can
think in reverse also.
To insert an element we need to travrse all the list to the required osition to insert the element , If
N elements are in the list then for AVERAGE and Worst time cases takes O(N) time and for
Deletion also takes O(1) time whcich is constant.
and in the case of changing any elements it is same as the inserting element becase in first step
element needs to be found and in second step value neeeds to be changed.
IN UNORDER list case The INSERTION and DELETION takes O(1) time only. and for
changeing it is O(N) in average and worst time complexities.
2)No it depends on the way we does those operations.
I mean that If to wish to do insertion at last and deletion at first and vice-verse that upto you to
code. but if links are changed all the meaning of your first code also changes.
I think you got my point.
