Please assist. Done perfectly. Portland uses sodium hydroxide (NaOH) to increase the pH of its drinking water to 8.0 as a high pH values, lead wil form lead hydroxides (Pb(OH)2) What concentration of Pb2* is expected to be found in the drinking water supply if lead pipes/fixtures are present (assume euilibrium conditions)? Is this concentration below the EPA action level threshold of 15 ppb? HINTS: Pb(OH)2(s) ?? Pb2+ + 2OH\' Ksp : 1.2*10-15 Recall, when using the Ksp equation, the concentrations are all in M (moles/L). Solution Pb(OH) 2 -----> Pb +2 + 2OH - K sp = [Pb +2 ] [OH - ] 2 = 1.2 x 10 -15 pOH = -log[OH - ] = 6 (pOH = 14-pH = 14-8 =6) [OH - ] = 10 -6 = 0.000001 K sp = [Pb +2 ] [OH - ] 2 = 1.2 x 10 -15 [Pb +2 ] (10 -6 ) 2 = 1.2 x 10 -15 [Pb +2 ] = 1.2 x 10 -15 /10 -12 = 1.2 x 10 -3 M [Pb +2 ] = 0.0012 moles/lt = 0.0012x mol wt = 12 x 207.2x 10 -4 = 2486.4 × 10 -4 g/lt = 24864 ppb No, the concentration of lead is more than thresold 15ppb .