1. The coordinates of point M are (2, -3) and the gradient of the straight line MN is -2. 2. The coordinates of point N could be determined based on the information provided about point M and the gradient of line MN. 3. Find the y-intercept of the straight line PQ in Diagram 15.

1. t
^lL
F{rmU- Maths
alfa
dird!
1li' The coordinatcs of pot t M ar€ (2, -3) and
une (focus on paPer 1l the gradimt of tlle straiglt line MIV is -2.
Yisht Thc coordioates of point N could be
K@diw, bgi filik M talah (2,-3'1 dot lzccwn
Formula ' gark luru filN.ldlah --2..
Knrdtnat bagi titi* N yMB MgAn hlah
Io Diagram 15, PQ is a straight Ifurc with Find the y-intercc$ of thc straight line PQ.
Cari pittuw-y bagi gais lurc PQ.
a gradient of
{.
Dalan Rajah 15, PA ddh garls latus dagan
Example of ouestlons: Find the gradient ofthe below StraiSht Line.
a*nanaf B+ D4
Di.8m Is/&riat 15
(a) (b)
Which gryh rlprcscots Y * '2r' - 4?
Gdwbhgng rewakiliY = -*-4'l
4' Ilrc rinterccF of the staight linc 3l + 4y
)q =-7ic
Find the vrtrr of lif &a sftight liD joidtrg rhe
pointll{1, ft) andil(t,3l) hu agndhntof3,
d) ) nrro*rrUrl guis luntsix + 4Y ='7 ifutt
$re dF j-inerc.lt ardtlrclinrrc@of tte
sraieht li&r, itr tb obovc dirgras. In Dlegrcm 15. PAQ is r etralght lirE aDd
O is the oriSin,
htqn Rdah 15, POQ ialoh gork brc daa
o talahaubn
Dllfram 15/
R4ld, It
Fhd th. tf,ldiont of tlE erroight line POO.
Carlbxmbagi garis luru POQ-
a,-{ c+
" " '="'
J"""-.'"

2. oiagram 13, PQ is a straiSht lin€.
rDalam Rqlah 13, PQ
ial^h garis lurc-.
_v
l/
ia{o'e'
,/l
/t
P(-2.3)/ |
-_-?-----ol-r
Thc r-iniercept ofthe 8trEtgltt linc
ABie
DiaAffi lMRqidh lX
Find the.r-intercept of the straight line PQ. o',+ c +
Carl plntasan-x bad garis lurus PA
A-6 c-2 B+ Dro+
B-3 D-l
t2' Ftndrhcy-htcrcatofthosraight
7, InDia8ram 14,thestraiahtlineGffisparailel 15.
to thc straight linc PR. 1|$linc3:-5]=
Dabm Rqiah l4 Alrts luns GH dalah sctai
*^* c-3
&ngu garts lurc PR.
R(&,9) B-+ D3
v
L3' Inthcdiagrubclow,PQiaa
straisrhtlirc'
) llH I
Dirg,.m l4lR4lah 14
Find thc value of ,t.
Carl nllai k
L2 c4
83 D6
8.
C.leLtc thc gradiot o'f th€
srretght lirc Pe.
,--2 c+
D-+ D2
L4' In ttp diagrembclow, POts a
lS otaien rim wio a eraaicnt or-{'
Th. gradictrlofAB i8
r2-3
cZ
^-+ D+
B-+
9' Thocoordinateofpointfarc CalcularE thr r-htcrccpt of dF
($ (2. and thc gradicnt of ttc 6Eri8htltrcPO.
-3)
Gl straigl* lirc EF iB
+. 7k
e-$ c-s
coo,rdinatce of points Fcould be B--l9 D-1o
A (4r) C (o, 1) 15.
B (lo, 1) D (-6, r) Thcgradiontoforcstraightline
10' Thcdiagromahowaeeqaightlinc
eEonaCertasimplam.
*^-*
ar-3r-
,gg 12 is
c+
ffi
D-+ D+
A(-z, r) The gradientofthe straight linc
fl 4r+5y=5is
*A-4 c-i 4
Find drc gradicnt of.AB,
A4 c+ B-5 .o-l
l
J
B2 o] (

3. Ed thcy-imorccpt of thc stnight
a+
linc6r+3y+7=0.
c+
n-I o-l
Slate tto.r-intam6 of thc ctraiSht
lirc5r-3y- 15=O.
A-5
x-3
c3
D5
fiod frr g.did of 6c rtnight litrc O- l5r = 30'
Cut tudnw fugi glrrt luw 6, - 15r = 30'
A:2 c;
B-1 Ds
@rrutfuJe* t
Tlrc grrdimt 6 PQ'B
Ikcerurutt PQ falah
Dirgrur 2 rhocl teo drdgtrt
m r Ctccirn phm.
n&l Z rrawtiunan fu gotr h$us W'( fur
Xt pada aur omi Cotcwr.
firdB1fa*z
itc gdicnt of Wf k 3 nd ll& dirranoc of XI
ir tfuniu. Find tho coordtrnrr od L
Kcccrutan WX ,aldh ! fua iarat Xy talah
13 unit. Cori kmrdfrrd }ati Y.
A (3,0) c (6,0)
D
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