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Two important examples of
s.h.m.
© D Hoult 2010
The mass / spring oscillator
The mass / spring oscillator
net force acting on the mass = zero
A graph of force against extension for a spring is a
straight line passing through the origin:
force a extension
A graph of force against extension for a spring is a
straight line passing through the origin:
force a extension
The constant of proportionality, k is called the
elastic constant of the spring (usually considered
to be a positive number)
When the displacement is downwards, the net
force is upwards and vice versa
So a better way to draw the graph would be
In this case, F represents the force with which the
spring “pulls back” when it is given an extension x
by some external agency
slope = - k
F = - k x
F = - k x
If the mass is released after having been given a
displacement, x, then its acceleration will be
a =
F = - k x
If the mass is released after having been given a
displacement, x, then its acceleration will be
a =
m
- k x
F = - k x
If the mass is released after having been given a
displacement, x, then its acceleration will be
a =
m
- k x
So the motion is s.h.m. and the constant of
proportionality between a and x has magnitude
F = - k x
If the mass is released after having been given a
displacement, x, then its acceleration will be
a =
m
- k x
So the motion is s.h.m. and the constant of
proportionality between a and x has magnitude
m
k
F = - k x
If the mass is released after having been given a
displacement, x, then its acceleration will be
a =
m
- k x
So the motion is s.h.m. and the constant of
proportionality between a and x has magnitude
m
k
which is equal to w2 in the “shm equation”
Remembering that
w
2p
T =
we can suggest that the time period of a mass
spring oscillator is given by
Remembering that
w
2p
T =
we can suggest that the time period of a mass
spring oscillator is given by
2p
T = m
k
The simple pendulum
F =
F = mg sin q
F =
F = - mg sin q
a =
a = - g sin q
q =
q =
x
L
If we make sure that q is
a small angle
If we make sure that q is
a small angle, sin q can
be replaced by q
a = -
g
L
x

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Mech_Oscillations03.ppt

  • 1. Two important examples of s.h.m. © D Hoult 2010
  • 2. The mass / spring oscillator
  • 3. The mass / spring oscillator
  • 4.
  • 5. net force acting on the mass = zero
  • 6.
  • 7.
  • 8.
  • 9. A graph of force against extension for a spring is a straight line passing through the origin: force a extension
  • 10. A graph of force against extension for a spring is a straight line passing through the origin: force a extension The constant of proportionality, k is called the elastic constant of the spring (usually considered to be a positive number)
  • 11.
  • 12. When the displacement is downwards, the net force is upwards and vice versa
  • 13. So a better way to draw the graph would be
  • 14.
  • 15. In this case, F represents the force with which the spring “pulls back” when it is given an extension x by some external agency
  • 17. F = - k x
  • 18. F = - k x If the mass is released after having been given a displacement, x, then its acceleration will be a =
  • 19. F = - k x If the mass is released after having been given a displacement, x, then its acceleration will be a = m - k x
  • 20. F = - k x If the mass is released after having been given a displacement, x, then its acceleration will be a = m - k x So the motion is s.h.m. and the constant of proportionality between a and x has magnitude
  • 21. F = - k x If the mass is released after having been given a displacement, x, then its acceleration will be a = m - k x So the motion is s.h.m. and the constant of proportionality between a and x has magnitude m k
  • 22. F = - k x If the mass is released after having been given a displacement, x, then its acceleration will be a = m - k x So the motion is s.h.m. and the constant of proportionality between a and x has magnitude m k which is equal to w2 in the “shm equation”
  • 23. Remembering that w 2p T = we can suggest that the time period of a mass spring oscillator is given by
  • 24. Remembering that w 2p T = we can suggest that the time period of a mass spring oscillator is given by 2p T = m k
  • 26.
  • 27.
  • 28.
  • 29.
  • 30.
  • 31.
  • 32.
  • 33.
  • 34. F =
  • 35. F = mg sin q
  • 36. F =
  • 37. F = - mg sin q
  • 38. a =
  • 39. a = - g sin q
  • 40. q =
  • 42. If we make sure that q is a small angle
  • 43. If we make sure that q is a small angle, sin q can be replaced by q