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ENZO EXPOSYTO
MATHS
SYMBOLS
ROOTS and THEIR PROPERTIES

Enzo Exposyto 1
2√16 2√9 2√4 2√1 2√0
ROOTS
3√-27 3√-8 3√-1 3√0

Enzo Exposyto 2


Enzo Exposyto 3
1 - Squares and Square Roots 6
2 - Definitions 10
3 - Roots and Their Properties 20
4 - Property 0 22
5 - Property 1 25
6 - Property 2 31
7 - Property 3 34
8 - Property 4 38
9 - Property 5 42
Enzo Exposyto 4
10 - Property 6 46
11 - Property 7 51
12 - Property 8 55
13 - Property 9 - Rationalising the Denominator 63
14 - Equation 76
15 - SitoGraphy 78
Enzo Exposyto 5
ROOTS
and
THEIR
PROPERTIES
Enzo Exposyto 20
REMEMBERING
the 4th Property of Exponents:
Example:
and the Property
Example:
2√4 = 4½
Enzo Exposyto 21
we get …
PROPERTY 0)
(n√a)m = n√am
and
(n√am)p = n√am*p
IF n IS EVEN,
a must be ≥ 0
Enzo Exposyto 22
PROPERTY 0)
Proof
(n√a)m = (a1/n)m
= am/n
= n√am
and
(n√am)p = (am/n)p
= am*p/n
= n√am*p

Enzo Exposyto 23
PROPERTY 0)
Example:
(2√4)3 = 2√43
23 = 2√64
8 = 8
and
(2√24)3 = 2√24*3
(2√16)3 = 2√24*3
43 = 2√212
64 = 212/2
64 = 26
64 = 64

Enzo Exposyto 24
PROPERTY 1)
n√a * n√b = n√(a*b)
IF n IS EVEN,
a and b
must both be
≥ 0
Enzo Exposyto 25
PROPERTY 1)
Proof
n√a * n√b = a1/n * b1/n
= (a*b)1/n
= n√(a*b)
Example:
2√4 *
2√9 = 2√(4 * 9)
2 * 3 = 2√36
6 = 6
Enzo Exposyto 26
PROPERTY 1A)
From PROPERTY 1)
we get
IF n IS EVEN,
a and b
must both be
≥ 0
Example:
Enzo Exposyto 27
PROPERTY 1B)
From PROPERTY 1)
we get
a ≥ 0
Example:
√4 * √4 = √(4 * 4) = √42 = (42)½ = 42/2 = 4
Enzo Exposyto 28
PROPERTY 1C)
From PROPERTY 1)
we get
Example:
3√8 *
3√8 *
3√8 = 3√(8 * 8 * 8) = 3√83 = (83)1/3 = 83/3 = 8
Enzo Exposyto 29
PROPERTY 1D)
From PROPERTY 1)
we get
IF n IS EVEN,
a must be
≥ 0
Example:
5√3 *
5√3 *
5√3 *
5√3 *
5√3 = ... = 5√35 = (35)1/5 = 35/5 = 3
Enzo Exposyto 30
PROPERTY 2)
IF n IS EVEN,
a must be ≥ 0
and
b must be > 0
IF n IS ODD,
a can be < = > 0
and
b must be < > 0
b CAN’T BE ZERO,
since we can't divide by zero
Enzo Exposyto 31
PROPERTY 2)
PROOF
n√( a ) = ( a )1/n
b b
= a1/n
b1/n
= n√a
n√b
Example:


Enzo Exposyto 32
PROPERTY 2A)
From PROPERTY 2)
we get
n√a = n√( a )
n√b b
IF n IS EVEN,
a must be ≥ 0
and
b must be > 0
IF n IS ODD,
a can be < = > 0
and
b must be < > 0
b CAN’T BE ZERO,
since we can't divide by zero

Enzo Exposyto 33

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MATHS SYMBOLS - ROOTS - #2 - PROPERTIES 0 - 2A

  • 1. ENZO EXPOSYTO MATHS SYMBOLS ROOTS and THEIR PROPERTIES
 Enzo Exposyto 1
  • 2. 2√16 2√9 2√4 2√1 2√0 ROOTS 3√-27 3√-8 3√-1 3√0
 Enzo Exposyto 2
  • 4. 1 - Squares and Square Roots 6 2 - Definitions 10 3 - Roots and Their Properties 20 4 - Property 0 22 5 - Property 1 25 6 - Property 2 31 7 - Property 3 34 8 - Property 4 38 9 - Property 5 42 Enzo Exposyto 4
  • 5. 10 - Property 6 46 11 - Property 7 51 12 - Property 8 55 13 - Property 9 - Rationalising the Denominator 63 14 - Equation 76 15 - SitoGraphy 78 Enzo Exposyto 5
  • 7. REMEMBERING the 4th Property of Exponents: Example: and the Property Example: 2√4 = 4½ Enzo Exposyto 21
  • 8. we get … PROPERTY 0) (n√a)m = n√am and (n√am)p = n√am*p IF n IS EVEN, a must be ≥ 0 Enzo Exposyto 22
  • 9. PROPERTY 0) Proof (n√a)m = (a1/n)m = am/n = n√am and (n√am)p = (am/n)p = am*p/n = n√am*p
 Enzo Exposyto 23
  • 10. PROPERTY 0) Example: (2√4)3 = 2√43 23 = 2√64 8 = 8 and (2√24)3 = 2√24*3 (2√16)3 = 2√24*3 43 = 2√212 64 = 212/2 64 = 26 64 = 64
 Enzo Exposyto 24
  • 11. PROPERTY 1) n√a * n√b = n√(a*b) IF n IS EVEN, a and b must both be ≥ 0 Enzo Exposyto 25
  • 12. PROPERTY 1) Proof n√a * n√b = a1/n * b1/n = (a*b)1/n = n√(a*b) Example: 2√4 * 2√9 = 2√(4 * 9) 2 * 3 = 2√36 6 = 6 Enzo Exposyto 26
  • 13. PROPERTY 1A) From PROPERTY 1) we get IF n IS EVEN, a and b must both be ≥ 0 Example: Enzo Exposyto 27
  • 14. PROPERTY 1B) From PROPERTY 1) we get a ≥ 0 Example: √4 * √4 = √(4 * 4) = √42 = (42)½ = 42/2 = 4 Enzo Exposyto 28
  • 15. PROPERTY 1C) From PROPERTY 1) we get Example: 3√8 * 3√8 * 3√8 = 3√(8 * 8 * 8) = 3√83 = (83)1/3 = 83/3 = 8 Enzo Exposyto 29
  • 16. PROPERTY 1D) From PROPERTY 1) we get IF n IS EVEN, a must be ≥ 0 Example: 5√3 * 5√3 * 5√3 * 5√3 * 5√3 = ... = 5√35 = (35)1/5 = 35/5 = 3 Enzo Exposyto 30
  • 17. PROPERTY 2) IF n IS EVEN, a must be ≥ 0 and b must be > 0 IF n IS ODD, a can be < = > 0 and b must be < > 0 b CAN’T BE ZERO, since we can't divide by zero Enzo Exposyto 31
  • 18. PROPERTY 2) PROOF n√( a ) = ( a )1/n b b = a1/n b1/n = n√a n√b Example: 
 Enzo Exposyto 32
  • 19. PROPERTY 2A) From PROPERTY 2) we get n√a = n√( a ) n√b b IF n IS EVEN, a must be ≥ 0 and b must be > 0 IF n IS ODD, a can be < = > 0 and b must be < > 0 b CAN’T BE ZERO, since we can't divide by zero
 Enzo Exposyto 33