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F PAT 1
( ˆ กF ก F ˆ กF ก )
. ก ก ก
( ก F )
F PAT 1
ˆ กF ก F ˆ กF ก
. ก ก ก ( ก F )
ก ก
1. (a + b)3 = a3 + 3a2b + 3ab2 + b3
2. (a − b)3 = a3 − 3a2b + 3ab2 − b3
3. a3 + b3 = (a + b)(a2 − ab + b2)
4. a3 − b3 = (a − b)(a2 + ab + b2)
กก
F ˈ m, n ˈ ก F Fa, b, am, bn a, b ≠ 0
1. am ⋅ an = am +n
2. am
an = am− n
3. (am)n = amn
4. (ab)n = anbn
5. 

a
b


n
= an
bn b ≠ 0
6. a−n = 1
an a ≠ 0
7. a
1
n = n a
8. a0 = 1 a ≠ 0
1
Exponential Function
ก F ˆ กF ก Ff = {(x, y) ∈ R × R+ /y = ax ; a > 0 a ≠ 1}
ก F F
1. ˆ กF ก F F ˈ ก F F 1
2. ˆ กF ก F R
3. F ˆ กF ก F R+
4. ˆ กF ก F ˈ ˆ กF F
5. F ˈ ˆ กF , F ˈ ˆ กFa > 1 0 < a < 1
Logarithmic Function ˈ ˆ กF F ˆ กF ก F
ก F ˆ กF กg = {(x, y) ∈ R+ × R/y = logax ; a > 0 a ≠ 1}
ก F F
1. ˆ กF ก F ˈ ก F F 1
2. ˆ กF ก R+
3. F ˆ กF ก R
4. ˆ กF ก ˈ ˆ กF F
5. F ˈ ˆ กF , F ˈ ˆ กFa > 1 0 < a < 1
log
1. 6.loga1 = 0 logbna = 1
n logba
2. 7.logaa = 1 alogam
= m
3. 8.loga(mn) = logam + logan alogbm
= mlogba
4. 9.loga


m
n

 = logam − logan logba =
logma
logmb
m > 0 m ≠ 1
5. 10.logbam = m logba logba = 1
logab
2
PROBLEMS
1. F x ก ก 23x+1 − 17 ⋅ 22x + 2x +3 = 0
2. F x F ก ก F F F6(25x) + 11(23x) − 3(2x) = 25x+1
1. 2. 3. 4.[−2,−3
4
] (−3
4
,0] [0, 7
8
] (7
8
, 3
2
]
3. ก x F ก ก
F F(2x − 4)3 + (4x − 2)3 = (4x + 2x − 6)3
1. 2 2. 2.5 3. 3 4. 3.5
3
4. ก F F F ก Fa = 248 , b = 336 c = 524
1. 1
b
> 1
c > 1
a
2. 1
a > 1
b
> 1
c
3. 1
b
> 1
a > 1
c
4. 1
a > 1
c > 1
b
5. ก F x y ˈ ก y ≠ 1
F F x F F ก F Flogy2x = a 2y = b
1. 1
2
(log2b)a
2. 2(log2b)a
3. a
2
(log2b)
4. 2a(log2b)
6. F ˈ ก Ff(x) = 10x , x a,b ∈ Rf
f−1(ab)
f−1(b)
F ก F F
1. log a
2. 1 + log a
3. 1 + logba
4. 1 + logab
4
7. F x ˈ F F F256x = (2x + 6)4 8x
8. ก ก F ก Flog3x9 + (log3x)2 = 2
1. 2. 3. 4. 1128
9
37
9
31
3
9. F F ff = {(x,y) y = log (x + 2) + log (x − 3) − log (4 − x)}
F F F
1. (3, 4) 2. (2 , 3) 3. (2, 4) 4. (0,2) ∪ (3,4)
5
10. F R F
C = x ∈ R (3x2 − 11x + 7)(3x2 + 4x +1) = 1
ก C F ก F
11. F R F
A = x ∈ R 32x − 34(15x−1) + 52x = 0
B = x ∈ R log5(5
1
x + 125) = log56 + 1 + 1
2x
F ก F ก FA ∪ B
6
12. ก F ก (log2x)3 + 12
logx2
= 7(log1
2
x)2
ก ก
13. ก ก16
(log
x2 x )
= x4 − 5x2 + 6
14. F M ˈ ก ( 1 + logx 27 )log3x + 1 = 0
ก M F F ก F F
1. 0 2. 1 3. 2 4. 3
7
15. ก F a x ˈ ก logax + logxa = 3
F (logax)2 + (logxa)2
16. F F x F ก Flog x = 1
3
log a − log b a = 27b6
1. 3b
2. 3 3 b2
3. 3b2
4. 3 3 b
17. Let a, b and c be positive numbers with both a and b greater than 1. Find the
solution of the equation logbx − logb(x − c) = a
1. cba
ba −1
2. aba
1 −ba
3. cba
1 +ba
4. aba
1 +bc
8
18. ก F Flog 2 = 0.3010 log510 +
log3
1
4
log35
+ (log 2)2
⋅
log5 e
loge
F F F
1. (0, 1]
2. (1, 2]
3. (2, 3]
4. (3, 4]
19. ก F f(x) = log4x , g(x) = 2x h(x) = (f + g−1)(x)
F x ˈ ก F F (foh)(x) = 1
2
1. 3
2
2. 3
4
3. 3
8
4. 3
16
20. F F F3x− y + (log x − log y)i = 27 − i i2 = − 1 89x−y
9
21. ก F x ˈ ก x + log(1 + 2x) = x log 5 + log 6
y ˈ ก log2y = 3(log89)(log910)(log1011)(log1112)
F x + y ก F
1. 9
2. 11
3. 13
4. 15
22. Let a and b be two positive integers such that b is a multiple of a.
If log 

b
a


b
2
+ log 

a
b


9a
= 1 then b2 − a2 = ?
1. 357
2. 396
3. 1600
4. 5967
10
23. ก F a b ˈ ก F ก
log4a − log32b3 = 19
Flog4b − log32a3 = 8 a
b
24. ก F 2 log2a − 3 log2b = 4 3 log2a − 4 log2b = 6
F F F(a2b + log2ab)
1
2
11
25. F R F
B = {x ∈ R log2(−x2 + 7x − 10) + 3 cos(π x2 + 7 ) − 1 = 1}
F ก ก B F ก F
26. F a b ˈ ก F ก log9(a) = log15(b) = log25(a + 2b)
F F F ก Fb
a
12
27. ก F

1
3


log2(x2+2)
> 

1
3


log2(4x− 1)
1. (1
4
,2)
2. (1,3)
3. (−∞, 1
4
] ∪ [2,∞)
4. (−∞,1] ∪ [3,∞)
28. F A 2(log3x − 1)
1
2 + log1
3
x3 + 4 > 0
F A ˈ F F
1. (0, 3)
2. (1, 4)
3. (2, 5)
4. (2, 9)
13
29. ก F A =


x ∈ R 22x − 2x+2 > 2
x+ 1
2 − 32



R ก ˈ R − A
F ก F F
1. 1 2. 2 3. 3 4. 4
30. ก ˈ F F72x + 72 < 23x +3 + 32x+2
1. 2.(log87,log98) (log98,log89)
3. 4.(log89,log78) (log910,log89)
14

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01062555 1611544156

  • 1. F PAT 1 ( ˆ กF ก F ˆ กF ก ) . ก ก ก ( ก F )
  • 2. F PAT 1 ˆ กF ก F ˆ กF ก . ก ก ก ( ก F ) ก ก 1. (a + b)3 = a3 + 3a2b + 3ab2 + b3 2. (a − b)3 = a3 − 3a2b + 3ab2 − b3 3. a3 + b3 = (a + b)(a2 − ab + b2) 4. a3 − b3 = (a − b)(a2 + ab + b2) กก F ˈ m, n ˈ ก F Fa, b, am, bn a, b ≠ 0 1. am ⋅ an = am +n 2. am an = am− n 3. (am)n = amn 4. (ab)n = anbn 5.   a b   n = an bn b ≠ 0 6. a−n = 1 an a ≠ 0 7. a 1 n = n a 8. a0 = 1 a ≠ 0 1
  • 3. Exponential Function ก F ˆ กF ก Ff = {(x, y) ∈ R × R+ /y = ax ; a > 0 a ≠ 1} ก F F 1. ˆ กF ก F F ˈ ก F F 1 2. ˆ กF ก F R 3. F ˆ กF ก F R+ 4. ˆ กF ก F ˈ ˆ กF F 5. F ˈ ˆ กF , F ˈ ˆ กFa > 1 0 < a < 1 Logarithmic Function ˈ ˆ กF F ˆ กF ก F ก F ˆ กF กg = {(x, y) ∈ R+ × R/y = logax ; a > 0 a ≠ 1} ก F F 1. ˆ กF ก F ˈ ก F F 1 2. ˆ กF ก R+ 3. F ˆ กF ก R 4. ˆ กF ก ˈ ˆ กF F 5. F ˈ ˆ กF , F ˈ ˆ กFa > 1 0 < a < 1 log 1. 6.loga1 = 0 logbna = 1 n logba 2. 7.logaa = 1 alogam = m 3. 8.loga(mn) = logam + logan alogbm = mlogba 4. 9.loga   m n   = logam − logan logba = logma logmb m > 0 m ≠ 1 5. 10.logbam = m logba logba = 1 logab 2
  • 4. PROBLEMS 1. F x ก ก 23x+1 − 17 ⋅ 22x + 2x +3 = 0 2. F x F ก ก F F F6(25x) + 11(23x) − 3(2x) = 25x+1 1. 2. 3. 4.[−2,−3 4 ] (−3 4 ,0] [0, 7 8 ] (7 8 , 3 2 ] 3. ก x F ก ก F F(2x − 4)3 + (4x − 2)3 = (4x + 2x − 6)3 1. 2 2. 2.5 3. 3 4. 3.5 3
  • 5. 4. ก F F F ก Fa = 248 , b = 336 c = 524 1. 1 b > 1 c > 1 a 2. 1 a > 1 b > 1 c 3. 1 b > 1 a > 1 c 4. 1 a > 1 c > 1 b 5. ก F x y ˈ ก y ≠ 1 F F x F F ก F Flogy2x = a 2y = b 1. 1 2 (log2b)a 2. 2(log2b)a 3. a 2 (log2b) 4. 2a(log2b) 6. F ˈ ก Ff(x) = 10x , x a,b ∈ Rf f−1(ab) f−1(b) F ก F F 1. log a 2. 1 + log a 3. 1 + logba 4. 1 + logab 4
  • 6. 7. F x ˈ F F F256x = (2x + 6)4 8x 8. ก ก F ก Flog3x9 + (log3x)2 = 2 1. 2. 3. 4. 1128 9 37 9 31 3 9. F F ff = {(x,y) y = log (x + 2) + log (x − 3) − log (4 − x)} F F F 1. (3, 4) 2. (2 , 3) 3. (2, 4) 4. (0,2) ∪ (3,4) 5
  • 7. 10. F R F C = x ∈ R (3x2 − 11x + 7)(3x2 + 4x +1) = 1 ก C F ก F 11. F R F A = x ∈ R 32x − 34(15x−1) + 52x = 0 B = x ∈ R log5(5 1 x + 125) = log56 + 1 + 1 2x F ก F ก FA ∪ B 6
  • 8. 12. ก F ก (log2x)3 + 12 logx2 = 7(log1 2 x)2 ก ก 13. ก ก16 (log x2 x ) = x4 − 5x2 + 6 14. F M ˈ ก ( 1 + logx 27 )log3x + 1 = 0 ก M F F ก F F 1. 0 2. 1 3. 2 4. 3 7
  • 9. 15. ก F a x ˈ ก logax + logxa = 3 F (logax)2 + (logxa)2 16. F F x F ก Flog x = 1 3 log a − log b a = 27b6 1. 3b 2. 3 3 b2 3. 3b2 4. 3 3 b 17. Let a, b and c be positive numbers with both a and b greater than 1. Find the solution of the equation logbx − logb(x − c) = a 1. cba ba −1 2. aba 1 −ba 3. cba 1 +ba 4. aba 1 +bc 8
  • 10. 18. ก F Flog 2 = 0.3010 log510 + log3 1 4 log35 + (log 2)2 ⋅ log5 e loge F F F 1. (0, 1] 2. (1, 2] 3. (2, 3] 4. (3, 4] 19. ก F f(x) = log4x , g(x) = 2x h(x) = (f + g−1)(x) F x ˈ ก F F (foh)(x) = 1 2 1. 3 2 2. 3 4 3. 3 8 4. 3 16 20. F F F3x− y + (log x − log y)i = 27 − i i2 = − 1 89x−y 9
  • 11. 21. ก F x ˈ ก x + log(1 + 2x) = x log 5 + log 6 y ˈ ก log2y = 3(log89)(log910)(log1011)(log1112) F x + y ก F 1. 9 2. 11 3. 13 4. 15 22. Let a and b be two positive integers such that b is a multiple of a. If log   b a   b 2 + log   a b   9a = 1 then b2 − a2 = ? 1. 357 2. 396 3. 1600 4. 5967 10
  • 12. 23. ก F a b ˈ ก F ก log4a − log32b3 = 19 Flog4b − log32a3 = 8 a b 24. ก F 2 log2a − 3 log2b = 4 3 log2a − 4 log2b = 6 F F F(a2b + log2ab) 1 2 11
  • 13. 25. F R F B = {x ∈ R log2(−x2 + 7x − 10) + 3 cos(π x2 + 7 ) − 1 = 1} F ก ก B F ก F 26. F a b ˈ ก F ก log9(a) = log15(b) = log25(a + 2b) F F F ก Fb a 12
  • 14. 27. ก F  1 3   log2(x2+2) >   1 3   log2(4x− 1) 1. (1 4 ,2) 2. (1,3) 3. (−∞, 1 4 ] ∪ [2,∞) 4. (−∞,1] ∪ [3,∞) 28. F A 2(log3x − 1) 1 2 + log1 3 x3 + 4 > 0 F A ˈ F F 1. (0, 3) 2. (1, 4) 3. (2, 5) 4. (2, 9) 13
  • 15. 29. ก F A =   x ∈ R 22x − 2x+2 > 2 x+ 1 2 − 32    R ก ˈ R − A F ก F F 1. 1 2. 2 3. 3 4. 4 30. ก ˈ F F72x + 72 < 23x +3 + 32x+2 1. 2.(log87,log98) (log98,log89) 3. 4.(log89,log78) (log910,log89) 14