Dividing
Exponential
Expressions
Write
37
33 in expanded notation.
3 . 3 . 3 . 3 . 3 . 3 . 3
3 . 3 . 3
How do we simplify?
3 . 3 . 3 . 3 . 3 . 3 . 3
3 . 3 . 3
=
3 . 3 . 3
1
= 34
Write
53
58 in expanded notation.
5 . 5 . 5
5 . 5 . 5 . 5 . 5 . 5 . 5 . 5
Simplify:
5 . 5 . 5
5 . 5 . 5 . 5 . 5 . 5 . 5 . 5
=
1
5 . 5 . 5 . 5 . 5
=
1
55
The Rule:
•So when we had
37
33, we have seven 3’s in the numerator
and three 3’s in the numerator and three 3’s in the
denominator. Upon simplifying, there are more 3’s in the
numerator than the denominator. All 3 threes in the
denominator were cancelled out together with the 3
threes in the numerator. They equate to 1. There are now
4 threes left in the numerator that are not cancelled out,
which is the final answer.
The Rule:
When dividing two numbers having different exponents
but the same bases, we simply copy the base and subtract
the denominator’s exponent from the numerator’s
exponent. the exponents.
37
33 = 37 − 3
= 34
xm
xn
= xm −𝑛

Math chapter 3 dividing exponential expressions

  • 1.
  • 2.
    Write 37 33 in expandednotation. 3 . 3 . 3 . 3 . 3 . 3 . 3 3 . 3 . 3 How do we simplify? 3 . 3 . 3 . 3 . 3 . 3 . 3 3 . 3 . 3 = 3 . 3 . 3 1 = 34
  • 3.
    Write 53 58 in expandednotation. 5 . 5 . 5 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 Simplify: 5 . 5 . 5 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 = 1 5 . 5 . 5 . 5 . 5 = 1 55
  • 4.
    The Rule: •So whenwe had 37 33, we have seven 3’s in the numerator and three 3’s in the numerator and three 3’s in the denominator. Upon simplifying, there are more 3’s in the numerator than the denominator. All 3 threes in the denominator were cancelled out together with the 3 threes in the numerator. They equate to 1. There are now 4 threes left in the numerator that are not cancelled out, which is the final answer.
  • 5.
    The Rule: When dividingtwo numbers having different exponents but the same bases, we simply copy the base and subtract the denominator’s exponent from the numerator’s exponent. the exponents. 37 33 = 37 − 3 = 34 xm xn = xm −𝑛