3. Data Interpretation (Time, Speed & Distance Based)
A Car and a Bus travel certain distances on five days of the week. The table
shows the distances travel by them and the sum of time taken by them to
cover the respective distances. It also shows the speeds of the Car and the Bus
on each day.
एक कार और एक बस सप्ताह क
े पााँच दिन ों में क
ु छ िू री तय करती हैं। तादिका उनक
े
द्वारा तय की गई िू री और सोंबोंदित िू री तय करने में उनक
े द्वारा दिए गए समय का य ग
िर्ााती है। यह प्रत्येक दिन कार और बस की गदत क भी िर्ााता है।
Days Distance
travelled by
car (in km)
Speed of car
(in km/hr)
Distance
travelled by bus
(in km)
Speed of bus
(in km/hr)
Total Time
Taken (in
hr)
Day 1 A 80 A+80 75 11.4
Day 2 B+60 60 B-80 80 14
Day 3 C-50 90 C+100 60 15
Day 4 D+60 120 D-150 90 8
Day 5 E-20 40 E 50 22
141
4. Q1. Find the value of (B × D × E) ÷ (A × C).
(B × D × E) ÷ (A × C) का मान ज्ञात कीदिए।
A. 240
B. 360
C. 400
D. 480
E. Cannot be determined
Q2. Which of the statements given below are False?
I. The distance travel by Car on Day 1 is 480 km.
II. The distance travel by Bus on Day 3 is 600 km.
III. The distance travel by Bus on Day 5 is 500 km.
नीचे दिए गए कौन से कथन गित हैं?
I. पहिे दिन कार द्वारा तय की गई िू री 480 दकमी है।
II. तीसरे दिन बस द्वारा यात्रा की िू री 600 दकमी है।
III. पाोंचवें दिन बस द्वारा यात्रा की िू री 500 दकमी है।
A. Only I
B. Only II
C. Both II & III
D. Both I & III
E. None of these are true
Q3. What is the difference between the average distance traveled by Car on all
five days together and the average distance traveled by Bus on all five days
together?
कार द्वारा सभी पाोंच दिन ों में तय की गई औसत िू री और बस द्वारा सभी पाोंच दिन ों में तय
की गई औसत िू री क
े बीच क्या अोंतर है?
5. A. 25 km
B. 30 km
C. 35 km
D. 40 km
E. None of these
Q4. If on Day 3, Speed of Car decreased by 20% and the speed of Bus increased by
25%, then find the difference between the total time taken by Car and Bus to
cover their respective journey.
यदि तीसरे दिन, कार की गदत 20% कम ह गई और बस की गदत 25% बढ़ गई, त कार
और बस द्वारा अपनी-अपनी यात्रा तय करने में दिए गए क
ु ि समय क
े बीच अोंतर ज्ञात
कीदिए।
A. 1.25 hours
B. 1.50 hours
C. 1.75 hours
D. 2.25
E. None of these
Q5. On Day 4 total time taken to travel same distance as before when speed of
Car is increase by 25% and speed of Bus decrease by 50% is what percentage
more/less than total time taken on Day 5 by Car to travel 'A' km and Bus to travel
'D' km?
चौथे दिन पहिे दितनी ही िू री तय करने में िगा क
ु ि समय, िब कार की गदत 25% बढ़
िाती है और बस की गदत 50% कम ह िाती है, कार द्वारा 'ए' दकमी की यात्रा करने में
और 'डी' दकमी की यात्रा क
े दिए बस दिन 5 पर दिए गए क
ु ि समय से दकतने प्रदतर्त
अदिक/कम है?
A. 17.5%
B. 22.5%
C. 24.5%
D. 27.5%
E. None of these
6. Answers
1. B
2. A
3. D
4. C
5. B
Solution
For Car A
[A/80] + [(A+80)/75] = 11.4
31A = 12,400
A = 400
Similarly solving,
B = 480, C = 500, D = 300, & E = 500
Day → Day 1 Day 2 Day 3 Day 4 Day 5
Distance travelled by
car (in km)
400 540 450 360 480
Time taken by car (in
hr)
5 9 5 3 12
Distance travelled by
bus (in km)
480 400 600 450 500
Time taken by bus (in
hr)
6.4 5 10 5 10
7. Q1.
(B × D × E) ÷ (A × C) = (480 × 300 × 500) ÷ (400 × 500) = 36
Q2.
From Statement I, Distance travelled by Car on Day 1 = 400 km (False)
From Statement II, Distance travelled by Bus on Day 3 = 600 km (True)
From Statement III, Distance travelled by Bus on Day 5 = 500 km (True)
Only I
Q3.
Average Distance travelled by Car = (400 + 540 + 450 + 360 + 480)/5
= 2230/5 = 446 km
Average Distance travelled by Bus = (480 + 400 + 600 + 450 + 500)/5
= 2430/5 = 486 km
Difference = 486 - 446 = 40 km
Q4.
On Day 3, Time taken by Car = 5/0.8 = 6.25 hours (since distance is constant, ratio
of time and speed will be inversely proportional)
Time taken by Bus = 10/1.25 = 8 hours
Difference = 8 - 6.25 = 1.75 hours
Q5.
On Day 4, Time taken by Car & Bus to travel with changed speed
= 3/1.25 + 5/0.5 = 2.4 + 10 = 12.4 hours
On Day 5, Time taken by Car to travel A km & Bus to travel D km
= 400/40 + 300/50 = 10 + 6 = 16 hours
Required % = (16 - 12.4)/16 × 100 = 22.5%
8. Data Interpretation (caselet)
Data given below about five vessels A, B, C, D & E contains mixture of different
liquid read the data carefully and answer the questions.
Vessel A contains mixture of milk and water, vessel B contains mixture of
water and tea, vessel C contains mixture of tea and Alcohol, vessel D contains
mixture of Alcohol and Coffee and vessel E contains mixture of Coffee and
Juice. Mixture of milk and water in vessel A in the ratio of 7 : 2 and quantity of
water in vessel B is equal to quantity of milk in vessel A. Mixture of tea and
Alcohol in the vessel C is in the ratio of 5 : 3 and total quantity of mixture in
vessel C is 60 litres more than total quantity of mixture in vessel B. Total
quantity of mixture in vessel E is 2/3 of total quantity of mixture in vessel A.
Total quantity of mixture in vessel C is 50% more than total quantity of
mixture in vessel D. Ratio of tea in vessel B and C is 7 : 15, while ratio of
Alcohol in vessel C and D is 3 : 2. Total quantity of Juice in vessel E is 60 litres
and total quantity of water in vessel A is 80 litres. Quantity of tea in vessel B is
140 litres.
पाोंच बतान ों A, B, C, D और E क
े बारे में नीचे दिए गए डेटा में दवदभन्न तरि पिाथों का
दमश्रण है, डेटा क ध्यान से पढ़ें और प्रश् ों क
े उत्तर िें। बतान A में िू ि और पानी का दमश्रण
है, बतान B में पानी और चाय का दमश्रण है, बतान C में चाय और अल्क हि का दमश्रण है,
बतान D में अल्क हि और कॉफी का दमश्रण है और बतान E में कॉफी और िूस का दमश्रण
है। बतान A में िू ि और पानी का दमश्रण 7:2 क
े अनुपात में है और बतान B में पानी की मात्रा
बतान A में िू ि की मात्रा क
े बराबर है। बतान C में चाय और अल्क हि का दमश्रण 5:3 क
े
अनुपात में है और बतान C में दमश्रण की क
ु ि मात्रा, बतान B में दमश्रण की क
ु ि मात्रा से 60
िीटर अदिक है। बतान E में दमश्रण की क
ु ि मात्रा, बतान A में दमश्रण की क
ु ि मात्रा का 2/3
है। बतान C में दमश्रण की क
ु ि मात्रा 50% है बतान D में दमश्रण की क
ु ि मात्रा से अदिक।
142
9. बतान B और C में चाय का अनुपात 7:15 है, िबदक बतान C और D में अल्क हि का
अनुपात 3:2 है। बतान E में िूस की क
ु ि मात्रा 60 िीटर है और क
ु ि मात्रा बतान A में पानी
80 िीटर है। बतान B में चाय की मात्रा 140 िीटर है।
Q1. If 144 litres of mixture from vessel A and 72 litres mixture from vessel B taken
out and mixed in another vessel F, then what will be ratio of milk, water and tea
in vessel F?
यदि बतान A से 144 िीटर दमश्रण और बतान B से 72 िीटर दमश्रण दनकािकर िू सरे बतान
F में दमिाया िाए, त बतान F में िू ि, पानी और चाय का अनुपात क्या ह गा?
A. 14:9:5
B. 14:10:3
C. 5:14:3
D. 2:5:7
E. None of these
Q2. 72 litres of mixture from vessel E taken out and mixed in a vessel G, which
contains 42 litres juice, what quantity of coffee should mixed in vessel G to obtain
ratio of coffee and juice 2 : 1?
बतान E से 72 िीटर दमश्रण दनकािकर बतान G में दमिाया िाता है, दिसमें 42 िीटर िूस
है, कॉफी और िूस का अनुपात 2:1 प्राप्त करने क
े दिए बतान G में दकतनी मात्रा में कॉफी
दमिाई िानी चादहए?
A. 55L
B. 66L
C. 77L
D. 88L
E. Cannot be determined
Q3. If vessel B and C are mixed together in a big vessel Z and 45 litres of mixture is
taken out from vessel Z, then find quantity of Alcohol in 45 litres of mixture.
10. यदि बतान B और C क एक बडे बतान Z में एक साथ दमिाया िाता है और बतान Z से 45
िीटर दमश्रण दनकािा िाता है, त 45 िीटर दमश्रण में अल्क हि की मात्रा ज्ञात कीदिये।
A. 3L
B. 6L
C. 9L
D. 11L
E. None of these
Q4. If 128 litres of mixture from vessel C, 96 litres of mixture from D and 120
litres of mixture from vessel E taken out and mixed together in vessel Y, find the
ratio of tea, alcohol, coffee and juice in vessel Y.
यदि बतान C से 128 िीटर दमश्रण, D से 96 िीटर दमश्रण और बतान E से 120 िीटर दमश्रण
दनकािकर बतान Y में एक साथ दमिाया िाता है, त बतान Y में चाय, र्राब, कॉफी और
िूस का अनुपात ज्ञात कीदिए।
A. 40:42:75:15
B. 41:76::42:15
C. 15:39:37:17
D. 40:42:75:17
E. None of these
Q5. If vessel D and E mixed together in a big vessel W and 56 litres of this mixture
taken out from vessel W, then find quantity of juice in 56 litres of mixture.
यदि बतान D और E क एक बडे बतान W में एक साथ दमिाया िाए और बतान W से 56
िीटर दमश्रण दनकािा िाए, त 56 िीटर दमश्रण में रस की मात्रा ज्ञात कीदिए।
A. 2L
B. 4L
C. 6L
D. 8L
E. None of these
11. Answers
1. B
2. B
3. C
4. A
5. C
Solution
Vessel A
Water = 80 L
So, Milk = 80 × 7/2 = 280 L
Total = 360 L
Thus, Water: Milk = 2: 7
Vessel B
Water = 280 L
Tea = 140 L
Total = 420 L,
Water: Tea = 2: 1
Vessel C
Total = 420 + 60 = 480 L
Tea = 480 × 5/8 = 300 L
Alcohol = 180 L
Tea: Alcohol = 5: 3
Vessel D
Total = 480/1.5 = 320 L
Alcohol = 180 × 2/3 = 120 L
Coffee = 200 L
Alcohol: Coffee = 3: 5
Vessel E
Total = 360 × 2/3 = 240 L
Juice = 60 L, Coffee = 180 L
Juice: Coffee = 60: 180 = 1: 3
12. Q1.
In Vessel F
Milk: Water: Tea = (144 × 7/9): (144 × 2/9 + 72 × 2/3): (72 × 1/3)
= 112: 80: 24
= 14: 10: 3
Q2.
Let x L coffee required to mixed then
(72 × 3/4 + x)/ (72 × 1/4 + 42) = 2/1
54 + x = 2(18 + 42)
x = 2 × 60 – 54 = 120 – 54 = 66
Q3.
In Vessel Z
Water: Tea: Alcohol = 280: (140 + 300): 180
= 280: 440: 180
= 14: 22: 9
In 45 L, Quantity of Alcohol = 45 × 9/45 = 9 L
Q4.
In Vessel Y
Tea: Alcohol: Coffee: Juice
= (128 × 5/8): (128 × 3/8 + 96 × 3/8): (96 × 5/8 + 120 × 3/4): (120 × 1/4)
= 80: 84: 150: 30
= 40: 42: 75: 15
Q5.
In Vessel W
Alcohol : Coffee : Juice = 120 : (200 + 180) : 60
= 120 : 380 : 60
= 6 : 19 : 3
In 56 L, Quantity of Juice = 56 × 3/28 = 6 L
13. Data Interpretation (Partnership)
Three friends invested in four different businesses. The bar graph shows the time (in
months) for which three friends invested money for four different businesses. The table
shows the ratio between their initial investments.
तीन ि स् ों ने चार अिग-अिग व्यवसाय ों में दनवेर् दकया। बार ग्राफ़ उस समय (महीन ों में) क िर्ााता है
दिसक
े दिए तीन ि स् ों ने चार अिग-अिग व्यवसाय ों क
े दिए पैसा दनवेर् दकया। तादिका उनक
े
प्रारोंदभक दनवेर् ों क
े बीच का अनुपात िर्ााती है।
0
5
10
15
20
25
30
A B C D
Naman
Tarun
Vinay
143
14. Q1. If the ratio between the profit earned by Naman from businesses A and B is 6:
5, then the profit earned by Tarun from business A is what percentage more/less
than that of business B?
यदि नमन द्वारा व्यवसाय A और B से अदिात िाभ क
े बीच का अनुपात 6:5 है, त व्यवसाय
A से तरुण द्वारा अदिात िाभ व्यवसाय B से दकतने प्रदतर्त अदिक/कम है?
A. 44%
B. 30%
C. 36%
D. 40%
E. Cannot be determined
Q2. If Tarun earned Rs. 3000 as profit from every business, then find the total
profit earned by all three friends.
यदि तरूण ने रु. प्रत्येक व्यवसाय से 3000 रुपये का िाभ हुआ, त तीन ों दमत्र ों द्वारा अदिात
क
ु ि िाभ ज्ञात कीदिए।
A. Rs. 24200
B. Rs. 27600
C. Rs. 28400
D. Rs. 32800
E. None of these
Businesses Naman: Tarun Tarun: Vinay
A 3:4 2:1
B 5:6 9:8
C 6:7 7:9
D 3:5 15:8
15. Q3. If the person who earned least profit from each business earns Rs. 7200, then
find the person who earned the most profit and from which business?
यदि प्रत्येक व्यवसाय से सबसे कम िाभ अदिात करने वािा व्यक्ति रु. 7200 है, त उस
व्यक्ति क ख िें दिसने सबसे अदिक िाभ कमाया और दकस व्यवसाय से?
A. Tarun, A
B. Naman, B
C. Vinay, C
D. Naman, D
E. None of these
Q4. If the initial investment of Vinay in all the businesses is same, then find the
ratio between total amount invested by Naman in businesses B and D to the total
amount invested by Tarun in businesses A and C.
यदि सभी व्यवसाय ों में दवनय का प्रारोंदभक दनवेर् समान है, त नमन द्वारा व्यवसाय B और
D में दनवेर् की गई क
ु ि रादर् और तरुण द्वारा व्यवसाय A और C में दनवेर् की गई क
ु ि
रादर् क
े बीच अनुपात ज्ञात कीदिए।
A. 299:403
B. 298:401
C. 297:400
D. 296:409
E. None of these
Q5. If in business B, Naman had increased his investment by 20% after 6 months,
Tarun had decreased his investment by 22.22% after 5 months and Vinay had
decreased his investment by 25% after 10 months from start of business. If the
profit earned by them is Rs. 37050, then find the increase/decrease in the profit
of Vinay.
यदि व्यवसाय B में, नमन ने 6 महीने क
े बाि अपना दनवेर् 20% बढ़ा दिया था, तरूण ने 5
महीने क
े बाि अपना दनवेर् 22.22% कम कर दिया था और दवनय ने व्यवसाय र्ुरू ह ने
क
े 10 महीने बाि अपना दनवेर् 25% कम कर दिया था। यदि उनक
े द्वारा अदिात िाभ रु.
37050 है, त दवनय क
े िाभ में वृक्ति/कमी ज्ञात कीदिए।
17. Answers
1. A
2. D
3. A
4. C
5. B
Solution
Profit Ratio in Business A
Naman: Tarun: Vinay
= (3 × 20) : (4 × 18) : (2 × 24)
= 5 : 6 : 4
Profit Ratio in Business B
Naman: Tarun : Vinay
= (15 × 12) : (18 × 10) : (16 × 15)
= 3 : 3 : 4
Profit Ratio in Business C
Naman : Tarun : Vinay
= (6 × 21) : (7 × 24) : (9 × 14)
= 3 : 4 : 3
Profit Ratio in Business D
Naman : Tarun : Vinay
= (9 × 16) : (15 × 12) : (8 × 18)
= 4 : 5 : 4
Q1.
Profit earned by Tarun,
From Business A = 6 × 6/5 = 7.2
From Business B = 5 × 3/3 = 5
Required % = (7.2 - 5)/5 × 100 = 44%
18. Q2.
Total Profit Earned by all 3 friends = 3000 × (15/6 + 10/3 + 10/4 + 13/5)
= 3000 × 164/15
= 32800 Rs.
Q3.
Person who earned most profit,
From Business A = 7200 × 6/4 = 10800 Rs. (Tarun)
From Business B = 7200 × 4/3 = 9600 Rs. (Vinay)
From Business C = 7200 × 4/3 = 9600 Rs. (Tarun)
From Business D = 7200 × 5/4 = 9000 Rs. (Tarun)
Thus Tarun earns the maximum from business A
Q4.
Required Ratio
Amount invested by Naman in Business B & D : Amount invested by Tarun in
Business A & C
= (15/16 + 9/8) : (4/2 + 7/9)
= 33/16 : 25/9 = 297 : 400
Q5.
In Business B
Investment of Naman
= 15 × (6 + 1.2 × 6)
= 15 × 6 × 2.2
= 198
Investment of Tarun
= 18 × (5 + 7/9 × 7)
= 18 × 94/9
= 188
Investment of Vinay
= 16 × (10 + 0.75 × 2)
= 16 × 11.5
= 184
19. Profit Ratio, Naman : Tarun : Vinay = 198 : 188 : 184 = 99 : 94 : 92
Actual Profit of Vinay = 37050 × 4/10 = 14820 Rs.
New Profit of Vinay = 37050 × 92/285 = 11960 Rs.
Difference = 14820 - 11960 = 2860 Rs.
20. Statement Based Arithmetic Questions
The question given below consists of a question and 2 or more statements given
below it. You must decide whether the data provided in the statements is
sufficient to answer the question.
Q1. A bag contains Green, Red and Orange balls in the ratio of 7 : 6 : 8,
respectively. Find total number of balls in the bag.
I. Probability of getting a Green ball from the bag is 1/3.
II. Probability of getting a Red ball and a Green ball together from the bag
is 8/41.
एक बैग में क्रमर्ः 7: 6: 8 क
े अनुपात में हरी, िाि और नारोंगी गेंिें हैं। बैग में गेंि ों की क
ु ि
सोंख्या ज्ञात कीदिए।
I. बैग से हरी गेंि दनकिने की प्रादयकता 1/3 है।
II. बैग से एक िाि गेंि और एक हरी गेंि एक साथ दनकिने की प्रादयकता 8/41
है।
A. Only I
B. Only II
C. Either of the statements are sufficient
D. Neither of the statements are sufficient
E. Both together are required to answer
Q2. If difference between length and breadth of a rectangle is 8 cm, then find the
area of the rectangle.
I. Ratio of the perimeter of rectangle to the perimeter of a square of side
15 cm is 8 : 15.
II. Length of diagonal of the rectangle is 4√10 cm.
144
21. यदि एक आयत की िोंबाई और चौडाई क
े बीच का अोंतर 8 सेमी है, त आयत का क्षेत्रफि
ज्ञात करें।
I. आयत क
े पररमाप का 15 सेमी भुिा वािे एक वगा क
े पररमाप से अनुपात 8:15
है।
II. आयत क
े दवकणा की िोंबाई 4√10 सेमी है।
A. Only I
B. Only II
C. Either of the statements are sufficient
D. Neither of the statements are sufficient
E. Both together are required to answer
Q3. A shopkeeper purchased an item for 'x' and sold that item to a customer, then
what is the profit percentage earned by the shopkeeper after selling that item to
the customer?
I. Shopkeeper sold that item to the customer at 'x + 335' after two
successive discounts of 15% and 25% after marking up that item with
70% above cost price?
II. The shopkeeper marked the price '44.5%' above cost price and sold to
the customer after allowing 25% discount on it.
III. The customer paid Rs. 5418.75 after 25% tax on the purchased price and
marked up amount and discount amount on the item is Rs. 600 and Rs.
265 respectively.
एक िुकानिार ने 'x' में एक वस्ु खरीिी और उस वस्ु क एक ग्राहक क बेच दिया, त
उस वस्ु क ग्राहक क बेचने क
े बाि िुकानिार द्वारा अदिात िाभ प्रदतर्त क्या है?
I. िुकानिार ने उस वस्ु क िागत मूल्य से 70% अदिक अोंदकत करने क
े बाि
15% और 25% की ि क्रदमक छ
ू ट ों क
े बाि ग्राहक क वह वस्ु 'x + 335' पर
बेची?
II. िुकानिार ने कीमत िागत मूल्य से '44.5%' अदिक अोंदकत की और उस पर
25% छ
ू ट िेने क
े बाि ग्राहक क बेच दिया।
III. ग्राहक ने रु. का भुगतान दकया. खरीिी गई कीमत और अोंदकत रादर् पर 25%
कर क
े बाि 5418.75 रुपये और वस्ु पर छ
ू ट रादर् रु. 600 और रु. क्रमर्ः
265.
22. A. Any two together
B. Only III
C. Any one of them is alone sufficient
D. Either I or II alone
E. Only I
Q4. A, B and C together can complete the work in 17 days. In how many days C
alone can complete the work?
I. B and C together can complete the work in 23 days
II. B is twice more efficient than A.
A, B और C दमिकर काया क 17 दिन ों में पूरा कर सकते हैं। C अक
े िे दकतने दिन ों में काया
पूरा कर सकता है
I. B और C दमिकर काम क 23 दिन ों में पूरा कर सकते हैं
II. B, A से ि गुना अदिक क
ु र्ि है।
A. Only I
B. Only II
C. Either of the statements are sufficient
D. Neither of the statements are sufficient
E. Both together are required to answer
Q5. What is the volume of the cuboid?
I. The ratio of length and breadth is 15 : 17 and the total surface area is
1790 cm².
II. The ratio of length and height is 3 : 4.
III. The volume of a cube, having length of its edge equal to the height of
given cuboid is 8000 cm³.
घनाभ का आयतन दकतना है?
I. िोंबाई और चौडाई का अनुपात 15 : 17 है और क
ु ि सतह क्षेत्रफि 1790 सेमी²
है।
II. िोंबाई और ऊ
ों चाई का अनुपात 3:4 है.
III. एक घन का आयतन, दिसक
े दकनारे की िोंबाई दिए गए घनाभ की ऊ
ों चाई क
े
बराबर है, 8000 सेमी³ है।
23. A. Only II & III together
B. I with either II or III
C. All statements are together required
D. Question cannot be answered even after using all the statements togther
E. None of these
24. Answers
1. B
2. C
3. C
4. E
5. C
Solution
Q1.
Green Balls = 7x, Violet Balls = 6x, Orange Balls = 8x, Total = 7x + 6x + 8x = 21x
From (II), (7x × 6x)/21x
C2 = 8/41
42x2
/ [(21x × (21x – 1)]/(1 × 2)] = 8/41
41 × x = 2(21x – 1)
41x = 42x – 2
x = 2
Total Balls = 21 × 2 = 42 Balls
Only data in Statement II alone is sufficient
Q2.
Length of Rectangle = x cm, Breadth of Rectangle = (x – 8) cm
x2
+ (x – 8)2
= (4√10)2
x2
+ x2
– 16x + 64 = 160
2x2
– 16x – 96 = 0
x2
– 8x – 48 = 0
(x – 12)(x + 4) = 0
x = 12
From (II), [2 × (x + x – 8)]/(4 × 15) = 8/15
2x – 8 = 16
2x = 24
x = 12
Area of Rectangle = 12 × (12 – 8) = 12 × 4 = 48 cm2
The data either in Statement I alone or in Statement II alone is sufficient
25. Q3.
From (I), x × 1.7 × 0.85 × 0.75 = x + 335
1.08375x – x = 335
x = 335/0.08375 = 4000 Rs.
From (II), CP = x Rs. , SP = x × 1.445 × 0.75 = 1.08375x Rs. ,
P% = (1.08375x – x)/x × 100 = 8.375%
From (III), (x + 335) × 1.25 = 5418.75
x + 335 = 4335
x = 4000
P% = 335/4000 × 100 = 8.375%
Any one of them alone is sufficient.
Q4.
Total Work = W = 17(a + b + c)
From I, W = 17(a + b + c) = 23(b + c)
From II, b = 2a
17(a + b + c) = 23(b + c) = xc
17(a + 2a + c) = 23(2a + c)
51a + 17c = 46a + 23c
5a = 6c
c = 5a/6
23(2a + 5a/6) = x × 5a/6
23 × 17/6 = x × 5/6
x = 391/5 = 78.2 days = Time taken by C alone
Both the statements together are necessary to answer.
Q5.
From (III), Side of Cube = Height of Cuboid = (8000)1/3
= 20 cm
From (II), Length of Cuboid = 20 × 3/4 = 15 cm
From (I), Breadth of Cuboid = 15 × 17/15 = 17 cm
Volume of Cuboid = 15 × 17 × 20 = 5100 cm2
All statements are required
26. Miscellaneous Type Question
Q1. If product of zeroes of a quadratic equation is (-6) and sum of zeroes is (-1).
What is the quadratic equation?
A. X2
-2x -15 = 0
B. x2
–x – 6 = 0
C. x2
– 4x – 5 = 0
D. x2
+ x -6 = 0
E. x2
–x + 6 = 0
Q2. If product of zeroes of a quadratic equation is (-5) and sum of zeroes is 4.
What is the quadratic equation?
A. x2
-x -5 = 0
B. x2
–x +5 = 0
C. x2
–4x – 5 = 0
D. None of these
E. No such equation is possible
Q3. Solve both the equations and mark the correct option.
I. 14x – 25 = 59-7x
II. (y+222)1/2
– (36)1/2
= (81)1/2
145
27. A. x>y
B. x<y
C. x<= y
D. y<=x
E. x=y or no relation can be established
Q4. Solve the question given below based on the series given below.
15360, 3840, 1920, 1440, 1440,___
53156.25 is the mth
term of this series.
Find ‘m’.
A. 10
B. 11
C. 13
D. 14
E. 15
Q5. Solve the given below series and determine the relation between ‘x’, ‘y’ and
‘z’.
I. 8, x, 26, 61, 124, 223
II. 12, y, 97, 209, 647, 1319
III. 4, 8, 24, z, 840, 9240
A. x<y<z
B. x>y=z
C. y>z>x
D. x=z<y
E. x<y>z
28. Answers
1. D
2. C
3. A
4. A
5. A
Solutions
Q1.Sum of Zeroes = -1
Product of zeroes = -6
We know’
P(x) = x2
– (sum of zeroes) x +(product of zeroes) = 0
Only option D satisfies P(x)
Q2.
Similar to the concept in question 1, we can say
Only option C fits.
Q3.
Eq 1: 14x – 25 = 59-7x
21x = 84
X = 4
Eq 2: (y+222)1/2
– (36)1/2
= (81)1/2
(y+222)1/2
= 9+6 = 15
(y+222) = 225
Y = 3. So, X>Y
