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Example 1
Example 1
Let’s try to find the limit:
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
=
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
¨
¨¨¨
¨¨¨B1√
a + h +
√
a
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
a + h − a
h
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
h
h
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
=
1
2
√
a
Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
=
1
2
√
a
Example 2
Example 2
lim
x→0
√
1 + x − 1
x
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
=
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
¨¨
¨¨¨
¨¨B1√
1 + x + 1
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
1 + x − 1
x
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
x
x
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
=
1
2
Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
=
1
2
Finding Limits of Square Root Functions

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Finding Limits of Square Root Functions

  • 1.
  • 2.
  • 4. Example 1 Let’s try to find the limit:
  • 5. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h
  • 6. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression.
  • 7. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate.
  • 8. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h =
  • 9. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0
  • 10. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h .
  • 11. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a
  • 12. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . ¨ ¨¨¨ ¨¨¨B1√ a + h + √ a √ a + h + √ a
  • 13. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a
  • 14. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a
  • 15. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 a + h − a h √ a + h + √ a
  • 16. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a
  • 17. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 h h √ a + h + √ a
  • 18. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 ¡h ¡h √ a + h + √ a
  • 19. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 ¡h ¡h √ a + h + √ a = lim h→0 1 √ a + h + √ a
  • 20. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 ¡h ¡h √ a + h + √ a = lim h→0 1 $$$$X √ a√ a + h + √ a
  • 21. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 ¡h ¡h √ a + h + √ a = lim h→0 1 $$$$X √ a√ a + h + √ a = 1 2 √ a
  • 22. Example 1 Let’s try to find the limit: lim h→0 √ a + h − √ a h We rationalize the expression. In this case by multiplying and dividing by the conjugate. lim h→0 √ a + h − √ a h = lim h→0 √ a + h − √ a h . √ a + h + √ a √ a + h + √ a = lim h→0 √ a + h 2 − √ a 2 h √ a + h + √ a = lim h→0 ¡a + h − ¡a h √ a + h + √ a = lim h→0 ¡h ¡h √ a + h + √ a = lim h→0 1 $$$$X √ a√ a + h + √ a = 1 2 √ a
  • 25. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method.
  • 26. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x =
  • 27. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x .
  • 28. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1
  • 29. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . ¨¨ ¨¨¨ ¨¨B1√ 1 + x + 1 √ 1 + x + 1
  • 30. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1
  • 31. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1
  • 32. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 1 + x − 1 x √ 1 + x + 1
  • 33. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1
  • 34. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 x x √ 1 + x + 1
  • 35. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 &x &x √ 1 + x + 1
  • 36. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 &x &x √ 1 + x + 1 = lim x→0 1 √ 1 + x + 1
  • 37. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 &x &x √ 1 + x + 1 = lim x→0 1 $$$$$X √ 1√ 1 + x + 1
  • 38. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 &x &x √ 1 + x + 1 = lim x→0 1 $$$$$X √ 1√ 1 + x + 1 = 1 2
  • 39. Example 2 lim x→0 √ 1 + x − 1 x We rationalize using the same method. lim x→0 √ 1 + x − 1 x = lim x→0 √ 1 + x − 1 x . √ 1 + x + 1 √ 1 + x + 1 = lim x→0 √ 1 + x 2 − 12 x √ 1 + x + 1 = lim x→0 ¡1 + x − ¡1 x √ 1 + x + 1 = lim x→0 &x &x √ 1 + x + 1 = lim x→0 1 $$$$$X √ 1√ 1 + x + 1 = 1 2