We solve limits by rationalizing. This is the second technique you may learn after limits by factoring. We solve two examples step by step.
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6. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
7. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
8. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
=
9. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
10. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
11. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
12. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
¨
¨¨¨
¨¨¨B1√
a + h +
√
a
√
a + h +
√
a
13. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
14. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
15. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
a + h − a
h
√
a + h +
√
a
16. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
17. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
h
h
√
a + h +
√
a
18. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
19. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
√
a + h +
√
a
20. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
21. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
=
1
2
√
a
22. Example 1
Let’s try to find the limit:
lim
h→0
√
a + h −
√
a
h
We rationalize the expression.
In this case by multiplying and dividing by the conjugate.
lim
h→0
√
a + h −
√
a
h
= lim
h→0
√
a + h −
√
a
h
.
√
a + h +
√
a
√
a + h +
√
a
= lim
h→0
√
a + h
2
−
√
a
2
h
√
a + h +
√
a
= lim
h→0
¡a + h − ¡a
h
√
a + h +
√
a
= lim
h→0
¡h
¡h
√
a + h +
√
a
= lim
h→0
1
$$$$X
√
a√
a + h +
√
a
=
1
2
√
a
26. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
=
27. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
28. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
29. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
¨¨
¨¨¨
¨¨B1√
1 + x + 1
√
1 + x + 1
30. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
31. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
32. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
1 + x − 1
x
√
1 + x + 1
33. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
34. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
x
x
√
1 + x + 1
35. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
36. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
√
1 + x + 1
37. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
38. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
=
1
2
39. Example 2
lim
x→0
√
1 + x − 1
x
We rationalize using the same method.
lim
x→0
√
1 + x − 1
x
= lim
x→0
√
1 + x − 1
x
.
√
1 + x + 1
√
1 + x + 1
= lim
x→0
√
1 + x
2
− 12
x
√
1 + x + 1
= lim
x→0
¡1 + x − ¡1
x
√
1 + x + 1
= lim
x→0
&x
&x
√
1 + x + 1
= lim
x→0
1
$$$$$X
√
1√
1 + x + 1
=
1
2