This document contains 7 questions about optics concepts like mirrors, lenses, and refraction. It provides the questions, formulas used, worked out calculations, and conclusions for each question about topics like: finding the position and type of an image formed by a convex mirror; using lens formulas to find image location and characteristics; determining focal length based on power; and calculating speed of light in a medium based on its refractive index.
reflection of light by plane and spherical mirror use of spherical mirror and use of mirror formula .the presentation is very useful for class X students who studying physics
reflection of light by plane and spherical mirror use of spherical mirror and use of mirror formula .the presentation is very useful for class X students who studying physics
To correct the vision of a person who is nearR sighted, we use a div.pdffsenterprises
To correct the vision of a person who is nearR sighted, we use a diverging lens to cause the rays
from the distant object to diverge slightly, as if they were coming from a closer object, allowing
the eye to focus the image on the retina. In this example, a nearRsighted eye has near and far
points of 12 cm and 17 cm, respectively. Assume that the prescribed lens is 2.0 cm from the eye.
a) What lens power is needed for this person to see a distant object clearly? For a distant object,
the lens must put the image at the far point of the eye so that the person can focus
on it.
i) What is the object distance?
ii) What is the image distance?
iii) Now you can use the thin lens equation to find the focal length of the lens that must be
prescribed:
iv) What is the power of the lens?
Solution
i) Object distance is u= infinity
ii) Now the image from the lens should be at the far point. Since the image is in front of the lens,
it is negative
Image distance is v= -15cm
iii) Thin lens equation => 1/f=1/u+1/v
=>1/f=1/inf+1/(-15)
=>f=-15cm
iv) Power =1/f(in m)=-1/0.15=-6.67D.
This PowerPoint presentation is for Grade 10 students. I have included all the topics in this presentation. Here you can know about Light, Types of lenses, Some terms related to lens, Prism, Ray diagrams, Numerical problems related to this chapter, Laws of reflection, refraction, diseases related to eyes. I have briefly described as notes, some examples and illustrations, proper diagrams and so on.
Periodic classification of elements 2
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To correct the vision of a person who is nearR sighted, we use a div.pdffsenterprises
To correct the vision of a person who is nearR sighted, we use a diverging lens to cause the rays
from the distant object to diverge slightly, as if they were coming from a closer object, allowing
the eye to focus the image on the retina. In this example, a nearRsighted eye has near and far
points of 12 cm and 17 cm, respectively. Assume that the prescribed lens is 2.0 cm from the eye.
a) What lens power is needed for this person to see a distant object clearly? For a distant object,
the lens must put the image at the far point of the eye so that the person can focus
on it.
i) What is the object distance?
ii) What is the image distance?
iii) Now you can use the thin lens equation to find the focal length of the lens that must be
prescribed:
iv) What is the power of the lens?
Solution
i) Object distance is u= infinity
ii) Now the image from the lens should be at the far point. Since the image is in front of the lens,
it is negative
Image distance is v= -15cm
iii) Thin lens equation => 1/f=1/u+1/v
=>1/f=1/inf+1/(-15)
=>f=-15cm
iv) Power =1/f(in m)=-1/0.15=-6.67D.
This PowerPoint presentation is for Grade 10 students. I have included all the topics in this presentation. Here you can know about Light, Types of lenses, Some terms related to lens, Prism, Ray diagrams, Numerical problems related to this chapter, Laws of reflection, refraction, diseases related to eyes. I have briefly described as notes, some examples and illustrations, proper diagrams and so on.
Periodic classification of elements 2
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Carbon part 1
For whole video YouTube link : https://youtu.be/NyKymxWbHYI
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Material and its properties 2
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Separation of substances class 9 - khushali thackerSourabh Soni
IS THE MATTER PURE AROUND US ?
When two or more elements and compounds mix together,
and do not interact chemically, then the resulting substance is
known as a mixture.
Class 10 acids, bases and salts - khushali thackerSourabh Soni
That's Chemistry :
ACIDS, BASES, AND SALTS
What's in there?
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• Reaction of acids with metal carbonates & bicarbonates
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Class 10 mendel's experiment - khushali thackerSourabh Soni
HEREDITY :Heredity is the process of passing the traits and
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MENDEL’S EXPERIMENT
It is the cross between two plants which have two pairs
of contrasting characteristics.
Model Attribute Check Company Auto PropertyCeline George
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Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
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This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
2. Mirror Lens
1/v + 1/u = 1/f
m = h’/h
= -v/u
1/v - 1/u = 1/f
m = h’/h
= v/u
R = 2f P = 1/f
3. 2. An object is placed at a distance of 10 cm from a
convex mirror of focal length 15 cm. Find the
position and nature of the image.
Answer
Focal length of convex mirror (f) = +15 cm
Object distance (u) = – 10 cm
According to the mirror formula,
4.
5. • The image is located at a distance of 6 cm from
the mirror on the other side of the mirror.
• The positive and a value of less than 1 of
magnification indicates that the image formed is
virtual and erect and diminished.
6. 3. An object of size 7.0 cm is placed at 27 cm in front of
a concave mirror of focal length 18 cm. At what
distance from the mirror should a screen be placed so
that a sharply focused image can be obtained? Find the
size and nature of the image.
Answer
Object distance (u) = – 27 cm
Object height (h) = 7 cm
Focal length (f) = – 18 cm
According to the mirror formula,
7.
8. • The negative value of image height indicates that
the image formed is inverted.
9. 4. An object 5 cm in length is held 25 cm away from a
converging lens of focal length 10 cm. Draw the ray
diagram and find the position, size and the nature of
the image formed.
Answer
Height of the Object, h0 = 5 cm
Distance of the object from converging lens, u = -25 cm
Focal length of a converging lens, f = 10 cm
Using lens formula,
10.
11. • Thus, the image is inverted and formed at a distance
of 16.7 cm behind the lens and measures 3.3 cm. The
ray diagram is shown below.
12. 5. A concave lens of focal length 15 cm forms an image
10 cm from the lens. How far is the object placed from
the lens? Draw the ray diagram.
Answer
Focal length of concave lens (OF1), f = – 15 cm
Image distance, v= – 10 cm
According to the lens formula,
13.
14. • The negative value of u indicates that the object is
placed 30 cm in front of the lens. This is shown in the
following ray diagram.
15. 6. Find the focal length of a lens of power -2.0 D.
What type of lens is this?
Answer
Power of lens (P) = 1/f
P = -2D
f = -1/2 = -0.5 m
A concave lens has a negative focal length.
Therefore, it is a concave lens.
16. 7. Light enters from air to glass having refractive index
1.50. What is the speed of light in the glass? The
speed of light in vacuum is 3 x 108 ms-1.
Refractive index of a medium (nm)
= Speed of light in vacuum/Speed of light in the medium
Speed of light in vacuum (c) = 3 × 108 m/s
Refractive index of glass (ng) = 1.50
17. Speed of light in the glass (v)
= Speed of light in vacuum/ Refractive index of
glass
= c/ng
= 3 × 108/1.50
= 2 x 108 ms-1.
