SURVIVAL AND LIFE TABLES
Nigel Paneth
THE FIRST FOUR COLUMNS
OF THE LIFE TABLE ARE:
1. AGE (x)
2. AGE-SPECIFIC MORTALITY RATE (qx)
3. NUMBER ALIVE AT BEGINNING OF
YEAR (lx)
4. NUMBER DYING IN THE YEAR (dx)
PROCEDURE:
We use column 2 multiplied by column 3 to
obtain column 4.
Then column 4 is subtracted from column 3 to
obtain the next row’s entry in column 3.
EXAMPLE:
100,000 births ( row 1, column 3) have an infant
mortality rate of 46.99/thousand (row 2, column 2),
so there are 4,699 infant deaths (row 3, column 4).
This leaves 95,301 left (100,000 – 4,699) to begin
the second year of life (row 2 column 3).
If we stopped with the first four columns, we
could still find out the probability of
surviving to any given age.
e.g. in this table, we see that 90.27% of non-
white males survived to age 30.
THE NEXT THREE COLUMNS OF
THE LIFE TABLE ARE:
Column:
5. THE NUMBER OF YEARS LIVED BY
THE POPULATION IN YEAR X (Lx)
6. THE NUMBER OF YEARS LIVED BY
THE POPULATION IN YEAR X AND IN
ALL SUBSEQUENT YEARS (Tx)
7. THE LIFE EXPECTANCY FROM THE
BEGINNING OF YEAR X (ex)
WE CALCULATE COLUMN 5
FROM COLUMNS 3 AND 4 IN THE
FOLLOWING WAY:
The total number of years lived in each year
is listed in column 5, Lx. It is based on two
sources. One source is persons who
survived the year, who are listed in column
3 of the row below. They each contributed
one year. Each person who died during the
year (column 4 of the same row) contributed
a part of year, depending on when they
died. For most purposes, we simply
assume they contributed ½ a year.
The entry for column 5, Lx in this table for age 8-9 is
94,321. Where does this number come from?
1. 94,291 children survived to age 9 (column 3 of
age 9-10), contributing 94,921 years.
2. 60 children died (column 4 of age 8-9) , so
they contributed ½ year each, or 30 years.
3. 94,921 + 30 = 94,321.
EXCEPTION TO THE ½
YEAR ESTIMATION RULE
Because deaths in year 1 are not
evenly distributed during the year
(they are closer to birth), infants
deaths contribute less than ½ a year.
Can you figure out what fraction of a
year are contributed by infant deaths
(0-1) in this table?
1. Lx = 96,254
2. 95,301 contributed one year
3. 96,254 - 95,301 = 953 years, which must come
from infants who died 0-1
4. 4,699 infants died 0-1
5. 953/4,699 = .202 or 1/5 of a year, or about 2.4 months
HOW DO WE GET COLUMN 6, Tx
The top line of Column 6, or Tx=0 , is
obtained by summing up all of
the rows in column 5. It is the total
number of years of life lived by all
members of the cohort.
This number is the key calculation in
life expectancy, because, if we divide it
by the number of people in the cohort,
we get the average life expectancy at
birth, ex=0, which is column 7.
COLUMN 7, LIFE
EXPECTANCY, or ex=0
For any year, column 6, Tx, provides
the number of years yet to be lived by
the entire cohort, and column 7, the
number of years lived on average by
any individual in the cohort. (Tx/lx)
Thus column 7 is the final product of
the life table, life expectancy at birth,
or life expectancy at any other
specified age.
WHAT IS LIFE
EXPECTANCY?
Life expectancy at birth in the US
now is 77.3 years. This means that a
baby born now will live 77.3 years
if…………..
that baby experiences the same age-
specific mortality rates as are
currently operating in the US.
Life expectancy is a shorthand
way of describing the current
age-specific mortality rates.
SOME OTHER MEASURES OF
SURVIVAL
AND
THE PROBLEM OF CENSORED
DATA
• 5-year survival. Number of people still
alive five years after diagnosis.
• Median survival. Duration of time until
50% of the population dies.
• Relative survival. 5-year survival in the
group of interest/5-year survival in all
people of the same age.
• Observed Survival. A life table approach
to dealing with censored data from
successive cohorts of people. Censoring
means that information on some aspect of
time or duration of events of interest is
missing.
THREE KINDS OF CENSORING
COMMONLY ENCOUNTERED
• Right censoring
• Left censoring
• Interval censoring
Censoring means that some
important information required to
make a calculation is not available to
us. i.e. censored.
RIGHT CENSORING
Right censoring is the most common
concern. It means that we are not
certain what happened to people after
some point in time. This happens when
some people cannot be followed the
entire time because they died or were
lost to follow-up.
LEFT CENSORING
Left censoring is when we are not
certain what happened to people
before some point in time. Commonest
example is when people already have
the disease of interest when the study
starts.
INTERVAL CENSORING
Interval censoring is when we know
that something happened in an interval
(i.e. not before time x and not after
time y), but do not know exactly when
in the interval it happened. For
example, we know that the patient was
well at time x and was diagnosed with
disease at time y, so when did the
disease actually begin? All we know is
the interval.
DEALING WITH RIGHT-
CENSORED DATA
Since right censoring is the
commonest problem, lets try to find
out what 5-year survival is now for
people receiving a certain treatment
for a disease.
OBSERVED SURVIVAL IN
375 TREATED PATIENTS
Number Number alive in
Treated 1999 00 01 02 03
1999 84 44 21 13 10 8
2000 62 31 14 10 6
2001 93 50 20 13
2002 60 29 16
2003 76 43
Total 375
WHAT IS THE PROBLEM
IN THESE DATA?
We have 5 years of survival data only
from the first cohort, those treated in
1999.
For each successive year, our data is
more right-censored. By 2003, we have
only one year of follow-up available.
What is survival in the first year after treatment?
It is:
(44 + 31 + 50 + 29 + 43 = 197)/375 = 52%
Number Number alive in
Treated 99 00 01 02 03
1999 84 44 21 13 10 8
2000 62 31 14 10 6
2001 93 50 20 13
2002 60 29 16
2003 76 43
Total 375
What is survival in year two, if the patient
survived year one?
(21 + 14 + 20 + 16 = 71)/154 = 46%
Note that 154 is also 197 (last slide’s numerator) –
43, the number for whom we have only one year of
data
Number Number alive in
Treated 96 97 98 99 00
1995 84 44 21 13 10 8
1996 62 31 14 10 6
1997 93 50 20 13
1998 60 29 16
1999 76 43
Total 375
By the same logic, survival in the third year
(for those who survived two years) is:
(13 + 10 + 13 = 36)/(71 - 16 = 55) = 65%
Number Number alive in
Treated 99 00 01 02 03
1999 84 44 21 13 10 8
2000 62 31 14 10 6
2001 93 50 20 13
2002 60 29 16
2003 76 43
Total 375
In year 4, survival is(10 + 6)/(36-13) = 70%
In year 5, survival is 8/16-6 = 80%
Number Number alive in
Treated 99 00 01 02 03
1999 84 44 21 13 10 8
2000 62 31 14 10 6
2001 93 50 20 13
2002 60 29 16
2003 76 43
Total 375
The total OBSERVED SURVIVAL over
the five years of the study is the
product of survival at each year:
.54 x .46 x .65 x .70 x .80 = .08 or 8.8%
Subsets of survival can also be
calculated, as for example:
2 year survival = .54 x .46
= .239 or 23.9%
Five-year survival is averaged over
the life of the study, and improved
treatment may produce differences in
survival during the life of the project.
The observed survival is an average
over the entire period.
Changes over time can be looked at within
the data. For example, note survival to
one year, by year of enrollment:
1999 - 52.3%
2000 - 50.0%
2001 - 53.7%
2002 - 48.3%
2003 - 56.6%
Little difference is apparent.
These data also do not include any
losses to follow-up, which would
make our observed survival
estimates less precise. The
calculation is only valid if those
lost to follow-up are similar in
survival rate to those observed.

Life Table.pptx

  • 1.
    SURVIVAL AND LIFETABLES Nigel Paneth
  • 3.
    THE FIRST FOURCOLUMNS OF THE LIFE TABLE ARE: 1. AGE (x) 2. AGE-SPECIFIC MORTALITY RATE (qx) 3. NUMBER ALIVE AT BEGINNING OF YEAR (lx) 4. NUMBER DYING IN THE YEAR (dx)
  • 4.
    PROCEDURE: We use column2 multiplied by column 3 to obtain column 4. Then column 4 is subtracted from column 3 to obtain the next row’s entry in column 3.
  • 5.
    EXAMPLE: 100,000 births (row 1, column 3) have an infant mortality rate of 46.99/thousand (row 2, column 2), so there are 4,699 infant deaths (row 3, column 4). This leaves 95,301 left (100,000 – 4,699) to begin the second year of life (row 2 column 3).
  • 6.
    If we stoppedwith the first four columns, we could still find out the probability of surviving to any given age. e.g. in this table, we see that 90.27% of non- white males survived to age 30.
  • 7.
    THE NEXT THREECOLUMNS OF THE LIFE TABLE ARE: Column: 5. THE NUMBER OF YEARS LIVED BY THE POPULATION IN YEAR X (Lx) 6. THE NUMBER OF YEARS LIVED BY THE POPULATION IN YEAR X AND IN ALL SUBSEQUENT YEARS (Tx) 7. THE LIFE EXPECTANCY FROM THE BEGINNING OF YEAR X (ex)
  • 8.
    WE CALCULATE COLUMN5 FROM COLUMNS 3 AND 4 IN THE FOLLOWING WAY: The total number of years lived in each year is listed in column 5, Lx. It is based on two sources. One source is persons who survived the year, who are listed in column 3 of the row below. They each contributed one year. Each person who died during the year (column 4 of the same row) contributed a part of year, depending on when they died. For most purposes, we simply assume they contributed ½ a year.
  • 9.
    The entry forcolumn 5, Lx in this table for age 8-9 is 94,321. Where does this number come from? 1. 94,291 children survived to age 9 (column 3 of age 9-10), contributing 94,921 years. 2. 60 children died (column 4 of age 8-9) , so they contributed ½ year each, or 30 years. 3. 94,921 + 30 = 94,321.
  • 10.
    EXCEPTION TO THE½ YEAR ESTIMATION RULE Because deaths in year 1 are not evenly distributed during the year (they are closer to birth), infants deaths contribute less than ½ a year. Can you figure out what fraction of a year are contributed by infant deaths (0-1) in this table?
  • 11.
    1. Lx =96,254 2. 95,301 contributed one year 3. 96,254 - 95,301 = 953 years, which must come from infants who died 0-1 4. 4,699 infants died 0-1 5. 953/4,699 = .202 or 1/5 of a year, or about 2.4 months
  • 12.
    HOW DO WEGET COLUMN 6, Tx The top line of Column 6, or Tx=0 , is obtained by summing up all of the rows in column 5. It is the total number of years of life lived by all members of the cohort. This number is the key calculation in life expectancy, because, if we divide it by the number of people in the cohort, we get the average life expectancy at birth, ex=0, which is column 7.
  • 13.
    COLUMN 7, LIFE EXPECTANCY,or ex=0 For any year, column 6, Tx, provides the number of years yet to be lived by the entire cohort, and column 7, the number of years lived on average by any individual in the cohort. (Tx/lx) Thus column 7 is the final product of the life table, life expectancy at birth, or life expectancy at any other specified age.
  • 14.
    WHAT IS LIFE EXPECTANCY? Lifeexpectancy at birth in the US now is 77.3 years. This means that a baby born now will live 77.3 years if………….. that baby experiences the same age- specific mortality rates as are currently operating in the US.
  • 15.
    Life expectancy isa shorthand way of describing the current age-specific mortality rates.
  • 16.
    SOME OTHER MEASURESOF SURVIVAL AND THE PROBLEM OF CENSORED DATA
  • 17.
    • 5-year survival.Number of people still alive five years after diagnosis. • Median survival. Duration of time until 50% of the population dies. • Relative survival. 5-year survival in the group of interest/5-year survival in all people of the same age. • Observed Survival. A life table approach to dealing with censored data from successive cohorts of people. Censoring means that information on some aspect of time or duration of events of interest is missing.
  • 18.
    THREE KINDS OFCENSORING COMMONLY ENCOUNTERED • Right censoring • Left censoring • Interval censoring Censoring means that some important information required to make a calculation is not available to us. i.e. censored.
  • 19.
    RIGHT CENSORING Right censoringis the most common concern. It means that we are not certain what happened to people after some point in time. This happens when some people cannot be followed the entire time because they died or were lost to follow-up.
  • 20.
    LEFT CENSORING Left censoringis when we are not certain what happened to people before some point in time. Commonest example is when people already have the disease of interest when the study starts.
  • 21.
    INTERVAL CENSORING Interval censoringis when we know that something happened in an interval (i.e. not before time x and not after time y), but do not know exactly when in the interval it happened. For example, we know that the patient was well at time x and was diagnosed with disease at time y, so when did the disease actually begin? All we know is the interval.
  • 22.
    DEALING WITH RIGHT- CENSOREDDATA Since right censoring is the commonest problem, lets try to find out what 5-year survival is now for people receiving a certain treatment for a disease.
  • 23.
    OBSERVED SURVIVAL IN 375TREATED PATIENTS Number Number alive in Treated 1999 00 01 02 03 1999 84 44 21 13 10 8 2000 62 31 14 10 6 2001 93 50 20 13 2002 60 29 16 2003 76 43 Total 375
  • 24.
    WHAT IS THEPROBLEM IN THESE DATA? We have 5 years of survival data only from the first cohort, those treated in 1999. For each successive year, our data is more right-censored. By 2003, we have only one year of follow-up available.
  • 25.
    What is survivalin the first year after treatment? It is: (44 + 31 + 50 + 29 + 43 = 197)/375 = 52% Number Number alive in Treated 99 00 01 02 03 1999 84 44 21 13 10 8 2000 62 31 14 10 6 2001 93 50 20 13 2002 60 29 16 2003 76 43 Total 375
  • 26.
    What is survivalin year two, if the patient survived year one? (21 + 14 + 20 + 16 = 71)/154 = 46% Note that 154 is also 197 (last slide’s numerator) – 43, the number for whom we have only one year of data Number Number alive in Treated 96 97 98 99 00 1995 84 44 21 13 10 8 1996 62 31 14 10 6 1997 93 50 20 13 1998 60 29 16 1999 76 43 Total 375
  • 27.
    By the samelogic, survival in the third year (for those who survived two years) is: (13 + 10 + 13 = 36)/(71 - 16 = 55) = 65% Number Number alive in Treated 99 00 01 02 03 1999 84 44 21 13 10 8 2000 62 31 14 10 6 2001 93 50 20 13 2002 60 29 16 2003 76 43 Total 375
  • 28.
    In year 4,survival is(10 + 6)/(36-13) = 70% In year 5, survival is 8/16-6 = 80% Number Number alive in Treated 99 00 01 02 03 1999 84 44 21 13 10 8 2000 62 31 14 10 6 2001 93 50 20 13 2002 60 29 16 2003 76 43 Total 375
  • 29.
    The total OBSERVEDSURVIVAL over the five years of the study is the product of survival at each year: .54 x .46 x .65 x .70 x .80 = .08 or 8.8%
  • 30.
    Subsets of survivalcan also be calculated, as for example: 2 year survival = .54 x .46 = .239 or 23.9%
  • 31.
    Five-year survival isaveraged over the life of the study, and improved treatment may produce differences in survival during the life of the project. The observed survival is an average over the entire period.
  • 32.
    Changes over timecan be looked at within the data. For example, note survival to one year, by year of enrollment: 1999 - 52.3% 2000 - 50.0% 2001 - 53.7% 2002 - 48.3% 2003 - 56.6% Little difference is apparent.
  • 33.
    These data alsodo not include any losses to follow-up, which would make our observed survival estimates less precise. The calculation is only valid if those lost to follow-up are similar in survival rate to those observed.