Hi-Tek Manufacturing- Incorporated- makes two types of industrial comp (2).pdf
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Hi-Tek Manufacturing, Incorporated, makes two types of industrial component parts-the B300 and the T500. An absorption costing income statement for the most recent period is shown: Hi- Tek produced and sold 60,100 units of B 300 at a price of $20 per unit and 12,700 units of T500 at a price of $39 per unit. The company's traditional cost system allocates manufacturing overhead to products using a plantwide overhead rate and direct labor dollars as the allocation base. Additional information relating to the company's two product lines is shown below: The company has created an activity-based costing system to evaluate the profitability of its products. Hi-Tek's ABC implementation team concluded that $58 , 000 and $105 , 000 of the company's advertising expenses could be directly traced to B300 and T500, respectively. The remainder of the selling and administrative expenses was organization-sustaining in nature. The A BC team also distributed the company's manufacturing overhead to four activities as shown below: Required: 1. Compute the product margins for the B300 and T500 under the company's traditional costing system. 2. Compute the product margins for B300 and T500 under the activity-based costing system. 3. Prepare a quantitative comparison of the traditional and activity-based cost assignments..
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Hi-Tek Manufacturing- Incorporated- makes two types of industrial comp.pdf
Hi-Tek Manufacturing produces two products, the B300 and T500. An absorption costing income statement shows it sold 70,000 B300 units for $20 each and 17,500 T500 units for $40 each. The company uses traditional costing with overhead allocated based on direct labor costs. An activity-based costing system was created and traced $50,000 of advertising to B300 and $100,000 to T500, distributing manufacturing overhead to four activities.
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How to fixed these provide listsort-asm assembly code as same as the l.pdf
How to fixed these provide listsort.asm assembly code as same as the listsort.c code with the
provide listmian.asm
1. Here is the listsort.asm I have now:
.globl recurSelectionSort
recurSelectionSort:
#struct Node* recurSelectionSort(struct Node* head) {
addi sp, sp, -16 # allocate space for the return address and saved registers
sw ra, 0(sp) # save the return address
sw s0, 4(sp) # save s0
sw s1, 8(sp) # save s1
# if (head->next == NULL)
lw t0, 0(a0) # Load head->next
beqz t0, endif1 # if (head->next == NULL)
# return head;
mv s0, a0 # save head to s0
addi sp, sp, 16 # deallocate space before returning
jr ra # return
endif1:
# struct Node* min = head;
mv s1, a0
# struct Node* beforeMin = NULL;
mv s0, x0
# struct Node* ptr;
mv t0, a0
# for (ptr = head; ptr->next != NULL; ptr = ptr->next) {
forinit:
lw t1, 4(t0) # Load ptr->next
beqz t1, endfor # for (ptr->next != NULL)
lw t2, 4(t1) # Load ptr->next->studentid
lw t3, 4(s1) # Load min->studentid
bge t3, t2, forloop # if (ptr->next->studentid < min->studentid )
mv s1, t1 # min = ptr->next;
mv s0, t0 # beforeMin = ptr;
forloop:
lw t0, 4(t0) # ptr = ptr->next;
lw t1, 0(t0) # Load ptr->next
bnez t1, forinit # for (ptr->next != NULL)
# if (ptr->next->studentid < min->studentid ) {
ifmin:
# min = ptr->next;
mv s1, t1
# beforeMin = ptr;
mv s0, t0
endifmin:
# }
endfor:
# }
if2:
# if (min != head)
bne s1, a0, if2
# swapNodes(&head, head, min, beforeMin);
jal swapNodes
lw t0, 0(a0) # Load head->next
endif2:
# head->next = recurSelectionSort(head->next);
jal recurSelectionSort
sw s0, 0(a0) # beforeMin->next = min->next (no need to swap if min is already at the head)
sw s1, 4(t0) # min->next = ptr
# return head;
mv s0, a0 # s0 = head
addi sp, sp, 16 # deallocate space before returning
jr ra # return
2. Here is the listmain.asm:
.text
.globl main
main:
addi sp,sp,-16
# studentlist = createList(studentArr, SIZE);
li a1,10
la a0, studentArr
jal createList
sw a0,12(sp)
# sort(&studentlist);
addi a0,sp,12
jal sort
# printList(studentlist);
lw a0,12(sp)
jal printList
# return
li a7, 10
ecall
.globl addStudent
# asm is nutty as the struct was passed in the registers.
addStudent:
addi sp,sp,-16
sw ra,12(sp)
sw s0,8(sp)
sw s1,4(sp)
mv s1,a0
mv s0,a1
li a0,20
jal malloc
lw a2,0(s0)
lw a3,4(s0)
lw a4,8(s0)
lw a5,12(s0)
sw a2,0(a0)
sw a3,4(a0)
sw a4,8(a0)
sw a5,12(a0)
sw s1,16(a0)
lw ra,12(sp)
lw s0,8(sp)
lw s1,4(sp)
addi sp,sp,16
jr ra
.globl createList
createList:
blez a1,endcreateList
addi sp,sp,-48
sw ra,44(sp)
sw s0,40(sp)
sw s1,36(sp)
mv s0,a0
slli s1,a1,2
add s1,s1,a1
slli s1,s1,2
add s1,a0,s1
li a0,0
cloop:
lw a1,0(s0)
lw a2,4(s0)
lw a3,8(s0)
lw a4,12(s0)
lw a5,16(s0)
sw a1,0(sp)
sw a2,4(sp)
sw a3,8(sp)
sw a4,12(sp)
sw a5,16(sp)
mv a1,sp
jal addStudent
addi s0,s0,20
bne s0,s1,cloop
lw ra,44(sp)
lw s0,40(sp)
lw s1,36(sp)
addi sp,sp,48
jr ra
endcreateList:
li a0,0
ret
.globl printList
printList:
beqz a0,endprintList
addi sp,sp,-16
sw ra,12(sp)
sw s0,8(sp)
mv s0,a0
lw a0,8(s0)
jal printint
li a0, 0x20
jal printch.
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Hi-Tek Manufacturing- Incorporated- makes two types of industrial comp.pdf
Hi-Tek Manufacturing produces two products, the B300 and T500. An absorption costing income statement shows it sold 70,000 B300 units for $20 each and 17,500 T500 units for $40 each. The company uses traditional costing with overhead allocated based on direct labor costs. An activity-based costing system was created and traced $50,000 of advertising to B300 and $100,000 to T500, distributing manufacturing overhead to four activities.
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How to fixed these provide listsort-asm assembly code as same as the l.pdf
How to fixed these provide listsort.asm assembly code as same as the listsort.c code with the
provide listmian.asm
1. Here is the listsort.asm I have now:
.globl recurSelectionSort
recurSelectionSort:
#struct Node* recurSelectionSort(struct Node* head) {
addi sp, sp, -16 # allocate space for the return address and saved registers
sw ra, 0(sp) # save the return address
sw s0, 4(sp) # save s0
sw s1, 8(sp) # save s1
# if (head->next == NULL)
lw t0, 0(a0) # Load head->next
beqz t0, endif1 # if (head->next == NULL)
# return head;
mv s0, a0 # save head to s0
addi sp, sp, 16 # deallocate space before returning
jr ra # return
endif1:
# struct Node* min = head;
mv s1, a0
# struct Node* beforeMin = NULL;
mv s0, x0
# struct Node* ptr;
mv t0, a0
# for (ptr = head; ptr->next != NULL; ptr = ptr->next) {
forinit:
lw t1, 4(t0) # Load ptr->next
beqz t1, endfor # for (ptr->next != NULL)
lw t2, 4(t1) # Load ptr->next->studentid
lw t3, 4(s1) # Load min->studentid
bge t3, t2, forloop # if (ptr->next->studentid < min->studentid )
mv s1, t1 # min = ptr->next;
mv s0, t0 # beforeMin = ptr;
forloop:
lw t0, 4(t0) # ptr = ptr->next;
lw t1, 0(t0) # Load ptr->next
bnez t1, forinit # for (ptr->next != NULL)
# if (ptr->next->studentid < min->studentid ) {
ifmin:
# min = ptr->next;
mv s1, t1
# beforeMin = ptr;
mv s0, t0
endifmin:
# }
endfor:
# }
if2:
# if (min != head)
bne s1, a0, if2
# swapNodes(&head, head, min, beforeMin);
jal swapNodes
lw t0, 0(a0) # Load head->next
endif2:
# head->next = recurSelectionSort(head->next);
jal recurSelectionSort
sw s0, 0(a0) # beforeMin->next = min->next (no need to swap if min is already at the head)
sw s1, 4(t0) # min->next = ptr
# return head;
mv s0, a0 # s0 = head
addi sp, sp, 16 # deallocate space before returning
jr ra # return
2. Here is the listmain.asm:
.text
.globl main
main:
addi sp,sp,-16
# studentlist = createList(studentArr, SIZE);
li a1,10
la a0, studentArr
jal createList
sw a0,12(sp)
# sort(&studentlist);
addi a0,sp,12
jal sort
# printList(studentlist);
lw a0,12(sp)
jal printList
# return
li a7, 10
ecall
.globl addStudent
# asm is nutty as the struct was passed in the registers.
addStudent:
addi sp,sp,-16
sw ra,12(sp)
sw s0,8(sp)
sw s1,4(sp)
mv s1,a0
mv s0,a1
li a0,20
jal malloc
lw a2,0(s0)
lw a3,4(s0)
lw a4,8(s0)
lw a5,12(s0)
sw a2,0(a0)
sw a3,4(a0)
sw a4,8(a0)
sw a5,12(a0)
sw s1,16(a0)
lw ra,12(sp)
lw s0,8(sp)
lw s1,4(sp)
addi sp,sp,16
jr ra
.globl createList
createList:
blez a1,endcreateList
addi sp,sp,-48
sw ra,44(sp)
sw s0,40(sp)
sw s1,36(sp)
mv s0,a0
slli s1,a1,2
add s1,s1,a1
slli s1,s1,2
add s1,a0,s1
li a0,0
cloop:
lw a1,0(s0)
lw a2,4(s0)
lw a3,8(s0)
lw a4,12(s0)
lw a5,16(s0)
sw a1,0(sp)
sw a2,4(sp)
sw a3,8(sp)
sw a4,12(sp)
sw a5,16(sp)
mv a1,sp
jal addStudent
addi s0,s0,20
bne s0,s1,cloop
lw ra,44(sp)
lw s0,40(sp)
lw s1,36(sp)
addi sp,sp,48
jr ra
endcreateList:
li a0,0
ret
.globl printList
printList:
beqz a0,endprintList
addi sp,sp,-16
sw ra,12(sp)
sw s0,8(sp)
mv s0,a0
lw a0,8(s0)
jal printint
li a0, 0x20
jal printch.
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Quit (q)
-> n
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Scanner scanner = new Scanner(System. in );
String key, value;
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key = scanner.nextLine();
System. out .print("Enter a address: ");
value = scanner.nextLine();
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// Lookup an entry in the address book
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key = scanner.nextLine();
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} else {
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// Delete an entry from the address book
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key = scanner.nextLine();
boolean deleted = addressBook.delete(key);
if (deleted) {
System. out .println("address deleted");
} else {
System. out .println("name not found");
}
}
}
public class Node {
private String key;
private String value;
private Node next;
Node() {
// add here ..
}
Node(String key, String value) {
// add here ..
this.key = key;
this.value = value;
this.next = null;
}
public String getKey() {
// add here ..
return this.key;
}
public void setKey(String key) {
// add here ..
this.key = key;
}
public String getValue() {
// add here ..
return this.value;
}
public void setValue(String value) {
// add here ..
this.value = value;
}
public Node getNext() {
// add here ..
return this.next;
}
public void setNext(Node next) {
// add here ..
this.next = next;
}
}
import java.util.Scanner;
public class Tablea {
private Node mark;
public Node getMark() {
return this.mark;
}
public void setMark(Node mark) {
this.mark = mark;
}
public boolean insert(String key, String value) {
Node newNode= new Node(key,value);
if (this.mark== null) {
this.mark = newNode;
}else {
newNode.setNext(this.mark.getNext());
this.mark.setNext(newNode);
}
return true;
}
public String lookUp(String key) {
Node current = this.mark;
while(current!=null) {
if (current.getKey().equals(key)) {
return current.getValue();
}
current = current.getNext();
}
return null;
}
public boolean delete(String key) {
Node current = this.mark;
Node prev = null;
while (current!= null) {
if (current.getKey().equals(key)) {
if (prev == null) {
this.mark = current.getNext();
}else {
prev.setNext(current.getNext());
}
return true;
}
prev = current;
current = current.getNext();
}
return false;
}
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Node current = this.mark;
while (current != null) {
if (current.getKey().equals(key)) {
current.setValue(newValue);
return true;
}
current = current.getNext();
}
return false;
}
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