The document outlines a lesson plan focused on projectile motion, emphasizing the identification of horizontal and vertical components, the equations of motion, and real-life applications. It includes activities for group work, assessment criteria, and a quiz to reinforce understanding. Key concepts include the roles of initial velocity and launch angle in two-dimensional motion.

2. Prayer

3. Greetings!

4. Checking of
Attendance

5. Classroom
Rules

6. Review of the
Past Lesson

7. Word Search

8. Word Search

9. OBJECTIVES

10. OBJECTIVES
Identify the horizontal and vertical
components of trajectory.
Determine the components of 2-
dimensional motion in terms of initial
velocity and angle of launch.
Relate the behavior of projectile by
giving real life examples.
01
02
03

11. OBJECTIVES
Identify the
horizontal and
vertical components
of trajectory.
01

12. OBJECTIVES
02
Determine the components
of 2-dimensional motion in
terms of initial velocity and
angle of launch.

13. OBJECTIVES
Relate the behavior of
projectile by giving real
life examples.
03

14. Complete Me!

15. projectile horizontal
constant acceleration
vertical

16. The (1.) _______ motion is the
combination of (2.) ______ motion
with (3.)_______ velocity and (4.)
_____ motion with constant
(5.)_________.

17. The (1.) projectile motion is the
combination of (2.) horizontal
motion with (3.)constant velocity
and (4.) vertical motion with
constant (5. acceleration.

18. Analyzing
the Trajectory

19. A boy throwing a piece of paper in a trash can.

20. Group Activity

21. Group 1 and 2 - Horizontal and
Vertical Components of the
Trajectory
Group 3 and 4 - Components of 2-
dimentional motion in terms of
initial velocity and angle of launch

22. Criteria 5
(Very Good)
4
(Good)
3
(Fair)
2
(Needs
Improvement)
Accuracy of the
content of the
output
All the details in
the given output
were correct
Commit 1-2
mistakes in the
accuracy of the
output
Commit 3-4
mistakes in the
accuracy of the
output
Commit 4 mistakes
in the accuracy of
the output
Presentation/
Explanation
Explanations
detailed and clear
Explanation are
clear but missed
to state 1-2
concept
Explanations
difficult to
understand
Explanations were
difficult to
understand and
missed all the
important details
Teamwork All members are
actively
participating in
the group activity
1-2 members are
actively
participating in
the group activity
3-4 members are
actively
participating in
the group activity
Only one member of
the group do the
entire task
Efficiency Finished on or
before the allotted
time
Finished 1-2
minutes late to
the given time
Finished 3-4
minutes late to
the given time
Finished 5 minutes
late to the given
time.

23. Group
Presentati

24. Horizontal and
Vertical
Components of
Trajectory

25. The horizontal
component of projectile
motion (with respect to
the x-axis) has an
acceleration equal to zero
(a = 0)
x

26. Since the horizontal
component of the
velocity of projectiles is
constant.

27. The vertical component of
acceleration is constant which
is equal to the acceleration
due to gravity of objects on
earth (a = -g) y

28. Where:
x – final position along x
x0 – initial position along x
Vox – initial velocity along the x-axis
y- final position along y
voy – initial velocity along the y-axis
t – time
g – acceleration due to gravity (9.81
m/s2)

29. X = x0+V0xt
Y = y0+V0yt-1/2gt2
Equation of Motion

30. x
V
0x
- initial velocity along the x-axis
V
y
- final velocity along the y-axis
V
0y
- initial velocity along the the y-axis
T- time
G- acceleration due to gravity (9.81m/s2)

31. V
x
=V
0x
Equation of Motion

32. Take note!
The height and range of an object reaches is
dependent upon
1.How fast it leaves its initial
position(initial velocity)
2.The angle at which it leaves from its
initial position (angle of launch)

33. Components of 2-
dimentional motion in
terms of initial velocity
and angle of launch

35. V
0x
=V
0
cos
θ
V
0y
=Vsin
θ

36. Where:
V0x- initial velocity along the x-
axis
V0y- initial velocity along the y-
axis
t- time
θ- angle between the initial
velocity and the x-axis

37. X= (V0cosθ)t
y= (V0sinθ)t –1/2gt2

38. x- final position along x-axis
y-final position along y-axis
V0- initial velocity
Vy- final velocity along y-axis
Vx- final velocity along x-axis
t- time
g- acceleration due to gravity (9.81
m/s2)

39. Vx= V0cosθ
Vy= V0sinθ –gt

40. Try Me!

41. Who among you played
it?
How will you relate into or
lesson today?

42. Who among you here
know the game
application “Angry
Bird”?

43. What does “Angry bird”
game application has
why it has been a perfect
example of projectile
motion?

44. Short Quiz

45. 1.At what axis is horizontal motion
usually associated?
A.x-axis
B.y-axis
C.z-axis
D.w-axis

46. 2. Which is TRUE in the following statement?
A.The projectile motion is the combination of horizontal
motion with constant axis and vertical motion with
constant acceleration.
B.The projectile motion is the combination of x and y
axis.
C.The projectile motion is the combination of position
and velocity.
D.The projectile motion is the combination of both height
and range.

47. 3. What is the right equations to
determine the motion in x and y-
axis?
A.𝑥 = 𝑥0 + 𝑣𝑜𝑥𝑡 and
B. x = x0 + V0xt
C. = (
𝑥 𝑣0 cos )
𝜃 𝑡
D. v = v cos θ

48. 4. What is the equations for the initial
velocity?
A.v0x= v0 cos θ and v0y= v0 sin θ
B.v0y= v0 sin θ only
C.v0x= v0 cos θ only
D.none of the above

49. 5. At what aspect of your
life where projectile
motion where observes
or occurs? (1 point)